{"id":42902,"date":"2020-09-25T18:46:17","date_gmt":"2020-09-25T13:16:17","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=42902"},"modified":"2020-09-25T18:46:17","modified_gmt":"2020-09-25T13:16:17","slug":"time-and-distance-questions-for-ssc-cgl-tier-2-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/time-and-distance-questions-for-ssc-cgl-tier-2-pdf\/","title":{"rendered":"Time and Distance Questions for SSC CGL Tier 2 PDF"},"content":{"rendered":"

Time and Distance Questions for SSC CGL Tier 2 PDF<\/strong><\/span><\/h2>\n

Download SSC CGL Tier 2 Time and Distance Questions PDF. Top 10 SSC CGL Tier 2 Time and Distance questions based on asked questions in previous exam papers very important for the SSC exam.<\/p>\n

Download Time and Distance Questions for SSC CGL Tier 2 PDF<\/a><\/p>\n

Get 10 SSC CGL Tier-2 Mocks for Rs. 149<\/a><\/p>\n

Take SSC CGL Tier-2 Mock Tests<\/a><\/p>\n

Download SSC CGL Tier-2 Previous Papers PDF<\/a><\/p>\n

Question 1:\u00a0<\/b>Four runners started running simultaneously from a point on a circular track. They took 200 seconds, 300 seconds, 360 seconds and 450 seconds to complete the round. After how much time to they meet at the starting point for the first time?<\/p>\n

a)\u00a01800 seconds<\/p>\n

b)\u00a03600 seconds<\/p>\n

c)\u00a02400 seconds<\/p>\n

d)\u00a04800 seconds<\/p>\n

Question 2:\u00a0<\/b>Walking at 6\/7th of this usual speed a man is 25 minutes too late. His usual time to cover this distance is<\/p>\n

a)\u00a02 hours 30 minutes<\/p>\n

b)\u00a02 hours 15 minutes<\/p>\n

c)\u00a02 hours 25 minutes<\/p>\n

d)\u00a02 hours 10 minutes<\/p>\n

Question 3:\u00a0<\/b>With average speed of 40 km\/hour, a train reaches its destination in time. If it goes with an average speed of 35 km hour, it is late by 15 minutes. The total journey is<\/p>\n

a)\u00a030 km<\/p>\n

b)\u00a040 km<\/p>\n

c)\u00a070 km<\/p>\n

d)\u00a080 km<\/p>\n

Question 4:\u00a0<\/b>Three men A. B and C working together can do a job in 6 hours less time than A alone, in 1 hour less time than B alone and in one half the time needed by C when working alone. Then A and B together can do the Job in<\/p>\n

a)\u00a02\/3 hour<\/p>\n

b)\u00a03\/4 hour<\/p>\n

c)\u00a03\/2 hour<\/p>\n

d)\u00a04\/3 hour<\/p>\n

Question 5:\u00a0<\/b>A takes three times as long as B and C together to do a job. B takes four times as long as A and C together to do the work. If all the three, working together can complete the job in 24 days, then the number of days, A alone will take to finish the job is<\/p>\n

a)\u00a0100<\/p>\n

b)\u00a096<\/p>\n

c)\u00a095<\/p>\n

d)\u00a090<\/p>\n

Take SSC CGL Tier-2 Mock Tests<\/a><\/p>\n

Download SSC CGL Tier-2 Previous Papers PDF<\/a><\/p>\n

Question 6:\u00a0<\/b>Walking at 5 km\/hr a student reaches his school from his house 15 minutes early and walking at 3 km\/hr he is late by 9 minutes. What is the distance between his school and his house?<\/p>\n

a)\u00a05 km<\/p>\n

b)\u00a08 km<\/p>\n

c)\u00a03 km<\/p>\n

d)\u00a02 km<\/p>\n

Question 7:\u00a0<\/b>The speed of a boat in still water is 6 km\/h. If it takes four times as much time as going upstream as in going same distance downstream, the speed of the stream is:<\/p>\n

a)\u00a02.5 km\/h<\/p>\n

b)\u00a03.6 km\/h<\/p>\n

c)\u00a05 km\/h<\/p>\n

d)\u00a04.2 km\/h<\/p>\n

Question 8:\u00a0<\/b>The speed of a car increases by 2 km\/hr after every one hour. If the distance travelled in the first one hour was 35 km, what was the total distance travelled in 12 hours?<\/p>\n

a)\u00a0558 km<\/p>\n

b)\u00a0650 km<\/p>\n

c)\u00a0560 km<\/p>\n

d)\u00a0552 km<\/p>\n

Question 9:\u00a0<\/b>A wheel makes 4000 revolution is covering a distance of 60km. The radius of the wheel is:<\/p>\n

a)\u00a08m<\/p>\n

b)\u00a08.25m<\/p>\n

c)\u00a04.68m<\/p>\n

d)\u00a02.39m<\/p>\n

Question 10:\u00a0<\/b>A train is moving at 72 km\/hrs. The distance covers in 15 minutes by the train is:<\/p>\n

a)\u00a018 km<\/p>\n

b)\u00a027 km<\/p>\n

c)\u00a036 km<\/p>\n

d)\u00a028 km<\/p>\n

18000+ Questions – Free SSC Study Material<\/a><\/p>\n

Free SSC Preparation (Videos Youtube)<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Meeting at the first time will be L.C.M. of time taken by individuals to complete
\ni.e. L.C.M. of 200,300,360 and 450 will be equal to 1800 sec.<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the initial speed and time be s,t\u00a0 respectively,
\nthen speed and time in the next case are 6s\/7 and (t+25)
\nAs distance = speed * time, and distance travelled in both cases is the same,
\n(6s\/7)*(t+25) = s*t
\nSolving the\u00a0 above equation results in\u00a0 t=150min<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the time and distance be t mins and d km respectively,
\nIf it goes with an average speed of 40 km\/hour, a train reaches its destination in time.
\nSo, distance = (40*t)\/60
\nIf it goes with an average speed of 35 km hour, it is late by 15 minutes.
\nSo, distance = 35*(t+15)\/60
\nIn both the cases, distance is same,
\nSo,\u00a0 40*t = 35*(t+15)
\nSolving the above equation gives t = 105
\nand d = (40*105)\/60 = 70<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let time taken by A alone = $x$ hours<\/p>\n

=> Time taken by A, B & C together = $(x-6)$ hours<\/p>\n

=> Time taken by B alone = $(x-5)$ hours<\/p>\n

=> Time taken by C alone = $2(x-6)$ hours<\/p>\n

Now, rate of work of A + rate of work of B + rate of work of C = rate of work of A,B,C together<\/p>\n

=> $\\frac{1}{x} + \\frac{1}{x-5} + \\frac{1}{2(x-6)} = \\frac{1}{x-6}$<\/p>\n

On solving above equation ,we get $x = 3 , \\frac{40}{6}$<\/p>\n

When $x = 3$ , the expression $(x-6)$ becomes negative, thus it’s not possible.<\/p>\n

=> $x = \\frac{40}{6}$<\/p>\n

Time taken by A & B together = $\\frac{1}{\\frac{3}{20} + \\frac{3}{5}}$<\/p>\n

= $\\frac{4}{3}$ hours<\/p>\n

5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let time taken by B and C = $x$ days<\/p>\n

=> Time taken by A = $3x$ days<\/p>\n

Thus, part of work done by A, B & C in 1 day<\/p>\n

= $\\frac{1}{x} + \\frac{1}{3x} = \\frac{4}{3x}$<\/p>\n

Acc to ques :<\/p>\n

=> $\\frac{4}{3x} = \\frac{1}{24}$<\/p>\n

=> $x = \\frac{4\\times24}{3} = 32$ days<\/p>\n

=> Time taken by A alone = 32*3 = 96 days<\/p>\n

Download SSC CGL General Science Notes PDF<\/a><\/p>\n

6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the time and distance be t mins and d respectively,
\nIn the first case:
\nTotal time taken = (t – 15) mins = (t-15)\/60 hrs.
\nDistance travelled\u00a0 =\u00a0 5*(t-15)\/60
\nIn the second case:
\nTotal time taken = (t + 9) mins = (t+9)\/60 hrs.
\nDistance travelled\u00a0 = 3*(t+9)\/60<\/p>\n

So, 5*(t-15)\/60 = 3*(t+9)\/60,
\nSolving the above equation we get, t=51
\nSo, d=3*(51+9)\/60
\n=3 KMs
\n7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

The distances travelled by the car in each hour will be 35,37,39,….
\nThe distance travelled in the last hour will be 35+(12-1)2 = 35+12 = 57 km
\nThen, Total distance travelled in 12 hours = $\\dfrac{12}{2}(35+57) = 6\\times92 = 552$ km<\/p>\n

9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Distance covered in 1 revolution $=\u00a0\\frac{60\\times1000}{4000} = 12.5 m $<\/p>\n

According to the question,<\/p>\n

$2\\times \\pi \\times r = 15$
\n$\\Rightarrow r = 2.39$<\/p>\n

Option D is correct<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

A train is moving at 72 km\/hrs.<\/p>\n

72 km\/h in 60 minutes = $\\frac{72}{60} = 1.2 $km per minute<\/p>\n

So in 15 minutes it will cover $1.2\\times 15 = 18 kms$<\/p>\n

Option A is correct.<\/p>\n

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We hope this Time and Distance Questions pdf for SSC CGL Tier 2 exam will be highly useful for your Preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Time and Distance Questions for SSC CGL Tier 2 PDF Download SSC CGL Tier 2 Time and Distance Questions PDF. Top 10 SSC CGL Tier 2 Time and Distance questions based on asked questions in previous exam papers very important for the SSC exam. Take SSC CGL Tier-2 Mock Tests Download SSC CGL Tier-2 Previous […]<\/p>\n","protected":false},"author":42,"featured_media":42905,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3167,125,9,504,378,3794,1493,1459,1611,1741,1268,1441],"tags":[4197,462,4111,358,500,461,1461],"class_list":{"0":"post-42902","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads-en","8":"category-featured","9":"category-ssc","10":"category-ssc-cgl","11":"category-ssc-chsl","12":"category-ssc-cpo-en","13":"category-ssc-cpo","14":"category-ssc-gd","15":"category-ssc-je","16":"category-ssc-mts","17":"category-ssc-stenographer","18":"category-stenographer","19":"tag-quant-time-and-distance","20":"tag-ssc-cgl","21":"tag-ssc-cgl-tier-2","22":"tag-ssc-chsl","23":"tag-ssc-cpo","24":"tag-ssc-exams","25":"tag-ssc-gd"},"better_featured_image":{"id":42905,"alt_text":"Time and 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