{"id":42857,"date":"2020-09-23T17:04:05","date_gmt":"2020-09-23T11:34:05","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=42857"},"modified":"2020-09-23T17:04:05","modified_gmt":"2020-09-23T11:34:05","slug":"wrong-number-series-questions-for-ibps-po-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/wrong-number-series-questions-for-ibps-po-pdf\/","title":{"rendered":"Wrong number series questions for IBPS PO PDF"},"content":{"rendered":"

Wrong number series questions for IBPS PO PDF<\/strong><\/span><\/h2>\n

Download Top-15 Banking Exams Wrong number series questions PDF. Banking Exams Wrong number series questions based on asked questions in previous exam papers very important for the Banking \u00a0exams.<\/p>\n

Download wrong number series questions for ibps po pdf<\/a><\/p>\n

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Take a IBPS PO free mock test<\/a><\/p>\n

Instructions<\/b><\/p>\n

Find the next term in the series.<\/p>\n

Question 1:\u00a0<\/b>442, 378, 346, 330, 322<\/p>\n

a)\u00a0320<\/p>\n

b)\u00a0318<\/p>\n

c)\u00a0310<\/p>\n

d)\u00a0314<\/p>\n

e)\u00a0316<\/p>\n

Question 2:\u00a0<\/b>20,40,61,84,111<\/p>\n

a)\u00a0138<\/p>\n

b)\u00a0146<\/p>\n

c)\u00a0136<\/p>\n

d)\u00a0144<\/p>\n

e)\u00a0None of these<\/p>\n

Question 3:\u00a0<\/b>1,7,17,31,49,71<\/p>\n

a)\u00a091<\/p>\n

b)\u00a086<\/p>\n

c)\u00a097<\/p>\n

d)\u00a087<\/p>\n

e)\u00a0None of these<\/p>\n

Question 4:\u00a0<\/b>2,4,8,14,22,32<\/p>\n

a)\u00a046<\/p>\n

b)\u00a040<\/p>\n

c)\u00a042<\/p>\n

d)\u00a044<\/p>\n

e)\u00a0None of these<\/p>\n

Question 5:\u00a0<\/b>2,12,36,80,150<\/p>\n

a)\u00a0252<\/p>\n

b)\u00a0246<\/p>\n

c)\u00a0254<\/p>\n

d)\u00a0244<\/p>\n

e)\u00a0None of these<\/p>\n

Instructions<\/b><\/p>\n

In the following number series, only one number is \u2018\u2018wrong\u2019\u2019. Find out the \u2018\u2019wrong\u2019\u2019 number.<\/p>\n

Question 6:\u00a0<\/b>13, 15, 17, 18, 21, 23<\/p>\n

a)\u00a017<\/p>\n

b)\u00a015<\/p>\n

c)\u00a021<\/p>\n

d)\u00a018<\/p>\n

e)\u00a0None of these<\/p>\n

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Question 7:\u00a0<\/b>3.5, 4, 14, 56, 782, 43904<\/p>\n

a)\u00a014<\/p>\n

b)\u00a056<\/p>\n

c)\u00a0782<\/p>\n

d)\u00a043904<\/p>\n

e)\u00a0None of these<\/p>\n

Question 8:\u00a0<\/b>128, 640, 981, 1199, 1324, 1388<\/p>\n

a)\u00a0640<\/p>\n

b)\u00a01199<\/p>\n

c)\u00a01324<\/p>\n

d)\u00a01388<\/p>\n

e)\u00a0None of these<\/p>\n

Question 9:\u00a0<\/b>12, 114, 600, 2428, 7272, 14550<\/p>\n

a)\u00a02428<\/p>\n

b)\u00a07272<\/p>\n

c)\u00a0600<\/p>\n

d)\u00a0114<\/p>\n

e)\u00a0None of these<\/p>\n

Question 10:\u00a0<\/b>828, 424, 220, 116, 64, 33<\/p>\n

a)\u00a0220<\/p>\n

b)\u00a064<\/p>\n

c)\u00a033<\/p>\n

d)\u00a0116<\/p>\n

e)\u00a0None of these<\/p>\n

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IBPS PO\u00a0 previous year papers<\/a><\/p>\n

Instructions<\/b><\/p>\n

In each of these questions, a number series is given. Only one number is wrong in each series. You have to find out the wrong number<\/p>\n

Question 11:\u00a0<\/b>10, 15, 24, 35, 54, 75, 100<\/p>\n

a)\u00a035<\/p>\n

b)\u00a075<\/p>\n

c)\u00a024<\/p>\n

d)\u00a015<\/p>\n

e)\u00a054<\/p>\n

Question 12:\u00a0<\/b>1 3 4 7 11 18 27 47<\/p>\n

a)\u00a04<\/p>\n

b)\u00a011<\/p>\n

c)\u00a018<\/p>\n

d)\u00a07<\/p>\n

e)\u00a027<\/p>\n

Question 13:\u00a0<\/b>3, 2, 3, 6, 12, 37.5, 115.5<\/p>\n

a)\u00a037.5<\/p>\n

b)\u00a03<\/p>\n

c)\u00a06<\/p>\n

d)\u00a02<\/p>\n

e)\u00a012<\/p>\n

Question 14:\u00a0<\/b>2, 8, 32, 148, 765, 4626, 32431<\/p>\n

a)\u00a0765<\/p>\n

b)\u00a0148<\/p>\n

c)\u00a08<\/p>\n

d)\u00a032<\/p>\n

e)\u00a04626<\/p>\n

Question 15:\u00a0<\/b>2 3 11 38 102 229 443<\/p>\n

a)\u00a011<\/p>\n

b)\u00a0229<\/p>\n

c)\u00a0102<\/p>\n

d)\u00a038<\/p>\n

e)\u00a03<\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

In the given series the sum of two consecutive terms are in GP
\n442-378 = 64
\n378-346 = 32
\n346-330 = 16
\n330-322 = 8
\n322-x = 4
\nx = 318<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

20 = 19+1
\n40 = (19*2)+2
\n61 = (19*3)+4
\n84 = (19*4)+8
\n111 = (19*5)+16
\nNext term = (19*6)+32 = 146<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

1 =$2(1)^2-1$
\n7 =$2(2)^2-1$
\n17 =$2(3)^2-1$
\n31 =$2(4)^2-1$
\n49 =$2(5)^2-1$
\n71 =$2(6)^2-1$
\nNext terms =$2(7)^2-1 = 97$<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

4-2 = 2
\n8-4 = 4
\n14-8 = 6
\n22-14 = 8
\n32-22 = 10
\nNext term = 32+12 = 44<\/p>\n

5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

2 =$n^3+n^2$
\n12 =$2^3+2^2$
\n36 =$3^3+3^2$
\n80 =$4^3+4^2$
\n150 =$5^3+5^2$
\nNext term =$6^3+6^2 = 252$<\/p>\n

6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

The difference between any two consecutive numbers is 2. So, the number that is wrong in the series is 18.<\/p>\n

The correct series is 13 15 17 19 21 23.<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$3.5 \\times 4 = 14$<\/p>\n

$4 \\times 14 = 56$<\/p>\n

$14 \\times 56 = 784$<\/p>\n

$56 \\times 784 = 43904$<\/p>\n

The odd one out in the given sequence is 782.<\/p>\n

8)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Let us find the difference between consecutive terms of the series.<\/p>\n

The terms are 128, 640, 981, 1199, 1324 and 1388
\nAnd the difference between consecutive terms is 512, 341, 218, 125, 64<\/p>\n

We notice that if 981 is replaced by 983, the difference in the terms will be perfect cubes i.e 512, 343, 216, 125 and 64.
\nHence, the number which is wrong in the series is 983<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

2428. All others are divisible by 3.<\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

424 = 828\/2 + 10<\/p>\n

220 = 424\/2 + 8<\/p>\n

116 = 220\/2 + 6<\/p>\n

The next number should be 116\/2 + 4 = 62<\/p>\n

So, 64 is the wrong number in the series.<\/p>\n

11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let us find the difference between consecutive terms of the series.
\nThe numbers in the series are 10, 15, 24, 35, 54, 75, 100
\nAnd their differences are 5, 9, 11, 19, 21, 25. There is no obvious pattern in this.<\/p>\n

But if we replace 35 with 37, we see the following numbers 10, 15, 24, 35, 54, 75, 100
\nAnd the differences are 5, 9, 13, 17, 21, 25 which is a symmetric pattern.<\/p>\n

Hence, the term which is wrong in the series is 35<\/p>\n

12)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

The given series is a Fibonacci series with each term equal to the sum of the previous two terms.<\/p>\n

For example, 1 + 3 = 4
\n3 + 4 = 7
\n4 + 7 = 11
\n7 + 11 = 18
\n11 + 18 = 29
\n18 + 29 = 47<\/p>\n

Hence, the incorrect term in the series is 27 (it should have been 29)<\/p>\n

13)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

The numbers are based on the following pattern.<\/p>\n

3*0.5 + 0.5 = 2
\n2*1 + 1 = 3
\n3*1.5 + 1.5 = 6
\n6*2 + 2 = 14
\n14*2.5 + 2.5 = 37.5
\n37.5*3 + 3 = 115.5<\/p>\n

In the series given, we notice that 14 is replaced by 12 and hence the wrong term in the series is 12<\/p>\n

14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$32431 = 7 \\times 4626 + 7^2$
\n$4626 = 6 \\times 765 + 6^2$
\n$765 = 5 \\times 148 + 5^2$
\nFollowing the same pattern,
\n$148 = 4 \\times 33 + 4^2$
\n$33 = 3 \\times 8 + 3^2$
\n$8 = 2 \\times 2 + 2^2$<\/p>\n

32 is the wrong number here.<\/p>\n

15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$3-2 = 1 = 1^3$
\n$11-3 = 8 = 2^3$
\n$38 -11 = 27 = 3^3$
\n$102-38 = 64 = 4^3$
\n$229-102 = 127 \\neq 5^3$
\nBut $227-102 = 125 = 5^3$
\n$443-227 = 216 = 6^3$<\/p>\n

229 is the wrong number<\/p>\n

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We hope this Wrong number series questions for IBPS PO\u00a0 will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Wrong number series questions for IBPS PO PDF Download Top-15 Banking Exams Wrong number series questions PDF. Banking Exams Wrong number series questions based on asked questions in previous exam papers very important for the Banking \u00a0exams. Download IBPS PO Previous Papers PDF Take a IBPS PO free mock test Instructions Find the next term […]<\/p>\n","protected":false},"author":49,"featured_media":42863,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[8,169,3167,125,229,228,2067,2071,2069],"tags":[48,353,4189],"class_list":{"0":"post-42857","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-banking","8":"category-downloads","9":"category-downloads-en","10":"category-featured","11":"category-ibpsclerk","12":"category-ibpspo","13":"category-ibps-rrb-clerk","14":"category-ibps-rrb-clerk-en","15":"category-ibps-rrb-po","16":"tag-ibps-po","17":"tag-number-series","18":"tag-wrong-number-series"},"better_featured_image":{"id":42863,"alt_text":"Wrong number series questions for IBPS PO PDF","caption":"Wrong number series questions for 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