{"id":42616,"date":"2020-09-11T15:14:59","date_gmt":"2020-09-11T09:44:59","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=42616"},"modified":"2020-09-11T15:20:46","modified_gmt":"2020-09-11T09:50:46","slug":"most-expected-number-series-questions-for-ibps-rrb-clerk-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/most-expected-number-series-questions-for-ibps-rrb-clerk-pdf\/","title":{"rendered":"Most Expected Number Series Questions for IBPS RRB Clerk PDF"},"content":{"rendered":"

Most Expected Number Series Questions for IBPS RRB Clerk PDF<\/strong><\/span><\/h1>\n

Download Top-15 Banking Exams Number Series Questions PDF. Banking Exams Number Series questions based on asked questions in previous exam papers very important for the Banking \u00a0exams.<\/p>\n

Download Most Expected Number Series Questions for IBPS RRB Clerk PDF<\/a><\/p>\n

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Instructions<\/b><\/p>\n

Find the wrong number in given series sequence.<\/p>\n

Question 1:\u00a0<\/b>1, 4, 15, 64, 325, 1955<\/p>\n

a)\u00a015<\/p>\n

b)\u00a064<\/p>\n

c)\u00a0325<\/p>\n

d)\u00a01955<\/p>\n

e)\u00a0None of these<\/p>\n

Question 2:\u00a0<\/b>6, 12, 21, 33, 49, 66<\/p>\n

a)\u00a021<\/p>\n

b)\u00a033<\/p>\n

c)\u00a049<\/p>\n

d)\u00a066<\/p>\n

e)\u00a0None of these<\/p>\n

Question 3:\u00a0<\/b>6, 11.5, 19, 28.5, 41<\/p>\n

a)\u00a06<\/p>\n

b)\u00a011.5<\/p>\n

c)\u00a041<\/p>\n

d)\u00a028.5<\/p>\n

e)\u00a0None of these<\/p>\n

Question 4:\u00a0<\/b>5, 26, 82, 214, 401, 702<\/p>\n

a)\u00a026<\/p>\n

b)\u00a082<\/p>\n

c)\u00a0214<\/p>\n

d)\u00a0401<\/p>\n

e)\u00a0None of these<\/p>\n

Question 5:\u00a0<\/b>5,20,73,274,1049<\/p>\n

a)\u00a020<\/p>\n

b)\u00a073<\/p>\n

c)\u00a0274<\/p>\n

d)\u00a01049<\/p>\n

e)\u00a0None of these<\/p>\n

Question 6:\u00a0<\/b>Which number comes in the place of the question mark (?)16, 25, 36, 49, 64, ?<\/p>\n

a)\u00a0121<\/p>\n

b)\u00a0100<\/p>\n

c)\u00a081<\/p>\n

d)\u00a0144<\/p>\n

e)\u00a0196<\/p>\n

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 <\/p>\n

Question 7:\u00a0<\/b>Which number comes in the place of the question mark (?)1, 27, 125, 343, ?<\/p>\n

a)\u00a0512<\/p>\n

b)\u00a01000<\/p>\n

c)\u00a0729<\/p>\n

d)\u00a0216<\/p>\n

e)\u00a01024<\/p>\n

Question 8:\u00a0<\/b>Which number comes in the place of the question mark (?)11, 44, 99, 176, ?<\/p>\n

a)\u00a0274<\/p>\n

b)\u00a0266<\/p>\n

c)\u00a0275<\/p>\n

d)\u00a0265<\/p>\n

e)\u00a0300<\/p>\n

Question 9:\u00a0<\/b>Which number comes in the place of the question mark (?)5, 25, 61, 113, ?<\/p>\n

a)\u00a0144<\/p>\n

b)\u00a0181<\/p>\n

c)\u00a0165<\/p>\n

d)\u00a0200<\/p>\n

e)\u00a0245<\/p>\n

Question 10:\u00a0<\/b>Which number comes in the place of the question mark (?)2, 6, 12, 20, 30, ?<\/p>\n

a)\u00a050<\/p>\n

b)\u00a044<\/p>\n

c)\u00a045<\/p>\n

d)\u00a042<\/p>\n

e)\u00a055<\/p>\n

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Instructions<\/b><\/p>\n

What should come in place of the question mark (?) in the following number series ?<\/p>\n

Question 11:\u00a0<\/b>353 354 351 356 349 ?<\/p>\n

a)\u00a0348<\/p>\n

b)\u00a0358<\/p>\n

c)\u00a0338<\/p>\n

d)\u00a0385<\/p>\n

e)\u00a0340<\/p>\n

Question 12:\u00a0<\/b>1 5 13 29 ? 125 253<\/p>\n

a)\u00a083<\/p>\n

b)\u00a069<\/p>\n

c)\u00a061<\/p>\n

d)\u00a065<\/p>\n

e)\u00a081<\/p>\n

Question 13:\u00a0<\/b>45 57 81 117 165 ?<\/p>\n

a)\u00a0235<\/p>\n

b)\u00a0215<\/p>\n

c)\u00a0205<\/p>\n

d)\u00a0245<\/p>\n

e)\u00a0225<\/p>\n

Question 14:\u00a0<\/b>17 18 26 53 117 ? 458<\/p>\n

a)\u00a0342<\/p>\n

b)\u00a0142<\/p>\n

c)\u00a0257<\/p>\n

d)\u00a0262<\/p>\n

e)\u00a0242<\/p>\n

Question 15:\u00a0<\/b>$\\frac{1}{4}, \\frac{1}{2}, \\frac{3}{4}, 1, 1\\frac{1}{4}, 1\\frac{1}{2}, 1 \\frac{3}{4}, ?$<\/p>\n

a)\u00a0$2$<\/p>\n

b)\u00a0$4$<\/p>\n

c)\u00a0$6$<\/p>\n

d)\u00a0$1\\frac{1}{5}$<\/p>\n

e)\u00a0$1\\frac{2}{3}$<\/p>\n

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 <\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

4 = 1*2+2 ; 15 = 4*3+3 ; 64 = 15*4+4 ; 325 = 64*5+5 ; 1956 = 325*6+6<\/p>\n

The nth term is of the form,<\/p>\n

$T_n=(T_{n-1}\\times n)+n$<\/p>\n

The last term does not follow the pattern and is thus the wrong number in the sequence.<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

6+6 = 12
\n12+9 = 21
\n21+12 = 33
\n33+15 =\u00a048<\/strong>
\n48+18 = 66.
\nHence, 49 is wrong number and it should be 48.<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

1.5*2 + 3 = 6<\/p>\n

2.5*3 + 4 = 11.5<\/p>\n

3.5*4 + 5 = 19<\/p>\n

4.5*5 + 6 = 28.5<\/p>\n

5.5*6 + 7 = 40<\/p>\n

4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

1*2+3=5 ; 4*5+6 = 26 ; 8*9+10 = 82 ; 13*14+15 = 212<\/strong> ; 19*20 + 21 =401 ; 26*27 +28 = 702
\nAll the numbers except 214 are following a pattern of $n\\times (n+1) + (n+2)$. Hence, 214 is wrong number.<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

1^2 + 4= 5 ; 2^2 + 16 = 20 ; 3^2 + 64 = 73 ; 4^2 + 256 = 272 ; 5^2 + 1024 = 1049<\/p>\n

6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$4^2 = 16$ ; $5^2=25$ ; $6^2 = 36$ ; $7^2=49$ ; $8^2 = 64$ ; $9^2 = 81$<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$1^3 = 1$ ; $3^3 = 27$ ; $5^3 = 125$ ; $7^3=343$ ; $9^3 = 729$<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$1 \\times11 = 11$ ; $2 \\times 22=44$ ; $3 \\times 33=99$ ; $4 \\times 44=176$ ; $5 \\times 55=275$<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$1^2 + 2^2 = 5 $; $3^2 + 4^2 = 25$ ; $5^2 +6^2 = 61$ , $7^2 + 8^2 = 113$ ; $9^2 + 10^2 = 181$<\/p>\n

10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

2+4=6 ; 6+6 = 12 ; 12+8 = 20 ; 20+10=30 ; 30+12 = 42<\/p>\n

11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

There are two arithmetic progression series,<\/p>\n

With 353,351,349\u2026 having a difference of -2<\/p>\n

and 354, 356\u2026 having a difference of 2<\/p>\n

Hence, the required term is 358<\/p>\n

12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

The generalized formula for nth term is, previous term + 2^n<\/p>\n

Here the required term is 5th in the series.<\/p>\n

Hence, 29 + 2^5 = 61<\/p>\n

13)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

For the series the nth term is ‘last term + 12*(n-1)’<\/p>\n

In the series, we are required to find, 6th term.<\/p>\n

Hence, 6th term is 165+12*(5) = 225.<\/p>\n

14)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Here, each sucessive nth term is ‘previous term + (n-1)\u00b3’<\/p>\n

We are supposed to find 6th term.<\/p>\n

Hence, 6th term = 117 + (6-1)^3 = 117 + 125 = 242<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The given series is Arithmetic Progression with common difference $\\frac{1}{4}$.<\/p>\n

Hence, the next term will be $1\\frac{3}{4}$ + $\\frac{1}{4}$ = 2<\/p>\n

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We hope this Number Series Questions for IBPS RRB Clerk\u00a0 will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Most Expected Number Series Questions for IBPS RRB Clerk PDF Download Top-15 Banking Exams Number Series Questions PDF. Banking Exams Number Series questions based on asked questions in previous exam papers very important for the Banking \u00a0exams. Download IBPS RRB Clerk Previous Papers PDF Take a IBPS RRB Clerk free mock test Instructions Find the […]<\/p>\n","protected":false},"author":49,"featured_media":42623,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3167,125,229,228,1127,2067,2071,2069],"tags":[1129,3260,4125],"class_list":{"0":"post-42616","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads-en","8":"category-featured","9":"category-ibpsclerk","10":"category-ibpspo","11":"category-ibps-rrb","12":"category-ibps-rrb-clerk","13":"category-ibps-rrb-clerk-en","14":"category-ibps-rrb-po","15":"tag-ibps-rrb-clerk","16":"tag-number-series-questions","17":"tag-number-series-questions-for-ibps-rrb-clerk"},"better_featured_image":{"id":42623,"alt_text":"Most Expected Number Series Questions for IBPS RRB Clerk 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