{"id":42601,"date":"2020-09-10T17:25:39","date_gmt":"2020-09-10T11:55:39","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=42601"},"modified":"2020-09-10T18:22:39","modified_gmt":"2020-09-10T12:52:39","slug":"arithmetic-questions-for-railway-exams-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/arithmetic-questions-for-railway-exams-pdf\/","title":{"rendered":"Arithmetic Questions for Railway Exams PDF"},"content":{"rendered":"

Arithmetic Questions for Railway Exams PDF<\/strong><\/span><\/h2>\n

Download Top-15 Railway Exams Arithmetic Questions PDF. Railway Exams Arithmetic questions based on asked questions in previous exam papers very important for the Railway\u00a0 exams.<\/p>\n

Download Arithmetic Questions for Railway Exams PDF<\/a><\/p>\n\n

Download RRB Group-D Previous Papers PDF<\/a><\/p>\n

Take a RRB Group-D free mock test<\/a><\/p>\n

Question 1:\u00a0<\/b>36% of 4800 x 0.2% of 1320 =?<\/p>\n

a)\u00a04535.52<\/p>\n

b)\u00a04551.36<\/p>\n

c)\u00a04561.92<\/p>\n

d)\u00a04572.48<\/p>\n

Question 2:\u00a0<\/b>Evaluate :- $\\frac{16 \\times2^{n+1 }-4\\times2^{n}}{16\\times 2^{n+2}-2\\times2^{n+2}}$<\/p>\n

a)\u00a0$\\frac{1}{2}$<\/p>\n

b)\u00a0$0$<\/p>\n

c)\u00a0$4$<\/p>\n

d)\u00a0$\\frac{1}{3}$<\/p>\n

Question 3:\u00a0<\/b>$\\sqrt{6400}$ = ?<\/p>\n

a)\u00a040<\/p>\n

b)\u00a080<\/p>\n

c)\u00a060<\/p>\n

d)\u00a0None of these<\/p>\n

Question 4:\u00a0<\/b>3251 + 587 + 369 – ? = 3007<\/p>\n

a)\u00a01250<\/p>\n

b)\u00a01300<\/p>\n

c)\u00a01375<\/p>\n

d)\u00a01200<\/p>\n

Question 5:\u00a0<\/b>The square root of 19881 is:<\/p>\n

a)\u00a0149<\/p>\n

b)\u00a0129<\/p>\n

c)\u00a0141<\/p>\n

d)\u00a0131<\/p>\n

Take a free mock test for RRB Group-D<\/a><\/p>\n

770 Mocks (cracku Pass) Just Rs.199<\/a><\/p>\n\n

Question 6:\u00a0<\/b>Find the square root of 15625 ?<\/p>\n

a)\u00a0125<\/p>\n

b)\u00a0145<\/p>\n

c)\u00a0150<\/p>\n

d)\u00a0135<\/p>\n

Question 7:\u00a0<\/b>Which of the following is NOT a perfect square?<\/p>\n

a)\u00a01250<\/p>\n

b)\u00a016641<\/p>\n

c)\u00a02025<\/p>\n

d)\u00a09801<\/p>\n

Question 8:\u00a0<\/b>Select the option that can replace the question mark (?) in the following equation.
\n$\u00a02 + 5\\div [5+8\\div( 1+\\frac{1}{3}) – 1] $ = ?<\/p>\n

a)\u00a0$\u00a0\\frac{1}{2} $<\/p>\n

b)\u00a0$\u00a0\\frac{5}{2} $<\/p>\n

c)\u00a0$\u00a0\\frac{3}{2} $<\/p>\n

d)\u00a02<\/p>\n

Question 9:\u00a0<\/b>$\u00a04 + \\frac{1}{6} \\times $ [ { $\u00a0– 12 \\times ( 24 – 13 – 3) $ } $\u00a0\\div ( 20 – 4) $ ] = ?<\/p>\n

a)\u00a04<\/p>\n

b)\u00a06<\/p>\n

c)\u00a05<\/p>\n

d)\u00a03<\/p>\n

Question 10:\u00a0<\/b>If $ \\sqrt{(x-1) +(y+2)} = 7 $ , then find the values of x and y.<\/p>\n

a)\u00a012, 16<\/p>\n

b)\u00a08, 5<\/p>\n

c)\u00a015, 12<\/p>\n

d)\u00a050, 47<\/p>\n

RRB Group D previous year papers<\/a><\/p>\n

Daily Free RRB Online Test<\/a><\/p>\n

Question 11:\u00a0<\/b>If $x = \\left(\\sqrt{2} + 1\\right)^{\\frac{-1}{3}}$, then find the value of $x^3 – \\frac{1}{x^3}$.<\/p>\n

a)\u00a0$\\sqrt3$<\/p>\n

b)\u00a0-2<\/p>\n

c)\u00a00<\/p>\n

d)\u00a02<\/p>\n

Question 12:\u00a0<\/b>If the midvalue of a class is 20 and the width of the class is 5, find the lower and upper limits of the class.<\/p>\n

a)\u00a017 – 23<\/p>\n

b)\u00a017 – 22<\/p>\n

c)\u00a017.5 – 22.5<\/p>\n

d)\u00a018 – 22<\/p>\n

Question 13:\u00a0<\/b>Find the value of $5y \\sqrt{y^3 – y^2}$ when $y = 5$<\/p>\n

a)\u00a0500<\/p>\n

b)\u00a0250<\/p>\n

c)\u00a0$50\\sqrt{2}$<\/p>\n

d)\u00a050<\/p>\n

Question 14:\u00a0<\/b>simplify $\\sqrt{25+10\\sqrt{6}}+\u00a0\\sqrt{25-10\\sqrt{6}}$?<\/p>\n

a)\u00a0$2\\sqrt{15}$<\/p>\n

b)\u00a0$2\\sqrt{5}$<\/p>\n

c)\u00a0$\\sqrt{50}$<\/p>\n

d)\u00a0$\\sqrt{55}$<\/p>\n

Question 15:\u00a0<\/b>$45-[38-(80\\div4-(8-12\\div3)\\div4)]=?$<\/p>\n

a)\u00a025<\/p>\n

b)\u00a027<\/p>\n

c)\u00a026<\/p>\n

d)\u00a028<\/p>\n

General Science Notes for RRB Exams (PDF)<\/a><\/p>\n\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

36% of 4800 = 1728<\/p>\n

.2% of 1320 = 2.64<\/p>\n

So, 36% of 4800 * .2% of 1320 = 1728 *2.64 = 4561.92<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$\\frac{16 \\times2^{n+1 }-4\\times2^{n}}{16\\times 2^{n+2}-2\\times2^{n+2}}$<\/p>\n

=$\\frac{2^{n}(32-4)}{2^{n+2}(16-2)}$<\/p>\n

=$\\frac{28}{4(14)}$=$\\frac{1}{2}$<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$ \\sqrt{6400} = \\sqrt {80 \\times 80} $ = 80<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let’s assume\u00a0? = Y.<\/p>\n

3251 + 587 + 369 – Y = 3007<\/p>\n

4207 – Y = 3007<\/p>\n

4207 – 3007 = Y<\/p>\n

Y = 1200<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$\\sqrt{\\ 19881}=141$<\/p>\n

Hence option ‘C’ is correct.<\/p>\n

6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

For finding square root, first obtain the multiple of a number.<\/p>\n

15625 = $5\\times5\\times5\\times5\\times5\\times5$<\/p>\n

Now pairing the number and got\u00a0$5\\times5\\times5$. Which is equal to 125.<\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

1250 (It is not a perfect square of any number.)<\/p>\n

16641 (It is a perfect square of 129.)<\/p>\n

2025 (It is a perfect square of 45.)<\/p>\n

9801\u00a0(It is a perfect square of 99.)<\/p>\n

8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

= $\u00a02 + 5\\div [5+8\\div( 1+\\frac{1}{3}) – 1] $<\/p>\n

= $ 2 + 5\\div [5+8\\div( \\frac{4}{3}) – 1] $<\/p>\n

= $ 2 + 5\\div [5+8 \\times \\frac{3}{4} – 1] $<\/p>\n

= $ 2 + 5\\div 10 $<\/p>\n

= $\u00a0\\frac{5}{2} $<\/p>\n

Hence, option B is the correct answer.<\/p>\n

9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$\u00a04 + \\frac{1}{6} \\times $ [ { $\u00a0– 12 \\times ( 24 – 13 – 3) $ } $\u00a0\\div ( 20 – 4) $ ]
\n=$\u00a04 + \\frac{1}{6} \\times $ [ { $\u00a0– 12 \\times 8 $ } $\u00a0\\div 16 $ ]
\n=$\u00a04 + \\frac{1}{6} \\times\u00a0 -6$
\n=4-1
\n=3<\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Substituting y=5<\/p>\n

Equation becomes<\/p>\n

$ 5 \\times 5 \\sqrt{5^3-5^2} $<\/p>\n

$ = 25 \\sqrt{125-25} $<\/p>\n

$ = 25 \\sqrt{100} $<\/p>\n

$ = 25 \\times 10 $<\/p>\n

=250<\/p>\n

14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$45-[38-(80\\div4-(8-12\\div3)\\div4)] = 45 – (38 – (20 – \\dfrac{8-4}{4}))$
\n$= 45 – (38 -(20-\\dfrac{4}{4})) = 45-(38-(20-1))$
\n$= 45-(38-19) = 45-19 = 26$<\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

We hope this Arithmetic Questions PDF for Railway Exams will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Arithmetic Questions for Railway Exams PDF Download Top-15 Railway Exams Arithmetic Questions PDF. Railway Exams Arithmetic questions based on asked questions in previous exam papers very important for the Railway\u00a0 exams. Download RRB Group-D Previous Papers PDF Take a RRB Group-D free mock test Question 1:\u00a036% of 4800 x 0.2% of 1320 =? a)\u00a04535.52 b)\u00a04551.36 […]<\/p>\n","protected":false},"author":42,"featured_media":42610,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3167,125,31,1679,1605,1603],"tags":[2356,214,4117,491,492,1593],"class_list":{"0":"post-42601","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads-en","8":"category-featured","9":"category-railways","10":"category-rrb-group-d","11":"category-rrb-je","12":"category-rrb-ntpc","13":"tag-arithmetic","14":"tag-quant","15":"tag-railway-exams","16":"tag-rrb","17":"tag-rrb-group-d","18":"tag-rrb-ntpc"},"better_featured_image":{"id":42610,"alt_text":"Arithmetic Questions for Railway Exams PDF","caption":"Arithmetic Questions for Railway Exams PDF\n","description":"Arithmetic Questions for Railway Exams PDF\n","media_type":"image","media_details":{"width":960,"height":504,"file":"2020\/09\/fig-10-09-2020_09-59-58.jpg","sizes":{"medium":{"file":"fig-10-09-2020_09-59-58-300x158.jpg","width":300,"height":158,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-300x158.jpg"},"thumbnail":{"file":"fig-10-09-2020_09-59-58-150x150.jpg","width":150,"height":150,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-150x150.jpg"},"medium_large":{"file":"fig-10-09-2020_09-59-58-768x403.jpg","width":768,"height":403,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-768x403.jpg"},"tiny-lazy":{"file":"fig-10-09-2020_09-59-58-30x16.jpg","width":30,"height":16,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-30x16.jpg"},"td_218x150":{"file":"fig-10-09-2020_09-59-58-218x150.jpg","width":218,"height":150,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-218x150.jpg"},"td_324x400":{"file":"fig-10-09-2020_09-59-58-324x400.jpg","width":324,"height":400,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-324x400.jpg"},"td_696x0":{"file":"fig-10-09-2020_09-59-58-696x365.jpg","width":696,"height":365,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-696x365.jpg"},"td_0x420":{"file":"fig-10-09-2020_09-59-58-800x420.jpg","width":800,"height":420,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-800x420.jpg"},"td_80x60":{"file":"fig-10-09-2020_09-59-58-80x60.jpg","width":80,"height":60,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-80x60.jpg"},"td_100x70":{"file":"fig-10-09-2020_09-59-58-100x70.jpg","width":100,"height":70,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-100x70.jpg"},"td_265x198":{"file":"fig-10-09-2020_09-59-58-265x198.jpg","width":265,"height":198,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-265x198.jpg"},"td_324x160":{"file":"fig-10-09-2020_09-59-58-324x160.jpg","width":324,"height":160,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-324x160.jpg"},"td_324x235":{"file":"fig-10-09-2020_09-59-58-324x235.jpg","width":324,"height":235,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-324x235.jpg"},"td_356x220":{"file":"fig-10-09-2020_09-59-58-356x220.jpg","width":356,"height":220,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-356x220.jpg"},"td_356x364":{"file":"fig-10-09-2020_09-59-58-356x364.jpg","width":356,"height":364,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-356x364.jpg"},"td_533x261":{"file":"fig-10-09-2020_09-59-58-533x261.jpg","width":533,"height":261,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-533x261.jpg"},"td_534x462":{"file":"fig-10-09-2020_09-59-58-534x462.jpg","width":534,"height":462,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-534x462.jpg"},"td_696x385":{"file":"fig-10-09-2020_09-59-58-696x385.jpg","width":696,"height":385,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-696x385.jpg"},"td_741x486":{"file":"fig-10-09-2020_09-59-58-741x486.jpg","width":741,"height":486,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58-741x486.jpg"}},"image_meta":{"aperture":"0","credit":"","camera":"","caption":"","created_timestamp":"0","copyright":"","focal_length":"0","iso":"0","shutter_speed":"0","title":"","orientation":"0"}},"post":null,"source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2020\/09\/fig-10-09-2020_09-59-58.jpg"},"yoast_head":"\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\n\n\n