{"id":41191,"date":"2020-03-24T18:44:38","date_gmt":"2020-03-24T13:14:38","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=41191"},"modified":"2020-03-24T18:44:38","modified_gmt":"2020-03-24T13:14:38","slug":"quadratic-equation-questions-for-sbi-po-2020-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/quadratic-equation-questions-for-sbi-po-2020-pdf\/","title":{"rendered":"Quadratic Equation Questions for SBI PO 2020 pdf"},"content":{"rendered":"<h1><span style=\"text-decoration: underline;\"><strong>Quadratic Equation Questions for SBI PO 2020 pdf<\/strong><\/span><\/h1>\n<p>Download SBI PO Quadratic Equation Questions &amp; Answers PDF for SBI PO Prelims and Mains exam. Very Important SBI PO Quadratic Equation Questions with solutions.<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/downloads\/8952\" target=\"_blank\" class=\"btn btn-danger  download\">Download Quadratic Equation Questions for SBI PO 2020 pdf<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/pay\/7H5pc\" target=\"_blank\" class=\"btn btn-info \">105 SBI PO mocks for Rs. 199. Enroll here<\/a><\/p>\n<div role=\"group\" aria-label=\"Message actions\">\n<div role=\"group\" aria-label=\"Message actions\">\n<div role=\"group\" aria-label=\"Message actions\">\n<div class=\"c-message__content c-message__content--feature_sonic_inputs\" data-qa=\"message_content\">\n<div class=\"c-message__message_blocks c-message__message_blocks--rich_text\">\n<div class=\"p-block_kit_renderer p-block_kit_renderer--absorb_margin\" data-qa=\"block-kit-renderer\">\n<div class=\"p-block_kit_renderer__block_wrapper p-block_kit_renderer__block_wrapper--first\">\n<div class=\"p-rich_text_block\" dir=\"auto\">\n<div class=\"c-message__content c-message__content--feature_sonic_inputs\" data-qa=\"message_content\">\n<div class=\"c-message__message_blocks c-message__message_blocks--rich_text\">\n<div class=\"p-block_kit_renderer p-block_kit_renderer--absorb_margin\" data-qa=\"block-kit-renderer\">\n<div class=\"c-message__content c-message__content--feature_sonic_inputs\" data-qa=\"message_content\">\n<div class=\"c-message__message_blocks c-message__message_blocks--rich_text\">\n<div class=\"p-block_kit_renderer p-block_kit_renderer--absorb_margin\" data-qa=\"block-kit-renderer\">\n<div class=\"p-block_kit_renderer__block_wrapper p-block_kit_renderer__block_wrapper--first\">\n<div class=\"c-message__content c-message__content--feature_sonic_inputs\" data-qa=\"message_content\">\n<div class=\"c-message__message_blocks c-message__message_blocks--rich_text\">\n<div class=\"p-block_kit_renderer p-block_kit_renderer--absorb_margin\" data-qa=\"block-kit-renderer\">\n<div class=\"p-block_kit_renderer__block_wrapper p-block_kit_renderer__block_wrapper--first\">\n<div class=\"c-message__content c-message__content--feature_sonic_inputs\" data-qa=\"message_content\">\n<div class=\"c-message__message_blocks c-message__message_blocks--rich_text\">\n<div class=\"p-block_kit_renderer p-block_kit_renderer--absorb_margin\" data-qa=\"block-kit-renderer\">\n<div class=\"p-block_kit_renderer__block_wrapper p-block_kit_renderer__block_wrapper--first\">\n<div class=\"p-rich_text_block\" dir=\"auto\">\n<p>Download <a href=\"https:\/\/cracku.in\/sbi-po-previous-papers\" target=\"_blank\" rel=\"noopener noreferrer\">SBI PO Previous Papers PDF<\/a><\/p>\n<p><a href=\"https:\/\/cracku.in\/sbi-po-online-mock-tests\" target=\"_blank\" rel=\"noopener noreferrer\">SBI PO Free Mock Tests<\/a><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p><b>Instructions<\/b><\/p>\n<p>In each of these question two equations I &amp; II with variables a &amp; b are given You have to solve both the equations to find the values of a &amp; b<br \/>\nMark answer if<br \/>\na) a&lt;b<br \/>\n&lt;\/b<\/p>\n<p>&lt;b<br \/>\n&lt;\/b<br \/>\n&lt;b<br \/>\nb) $a\\leq b$<br \/>\nc) relationship between a &amp; b cannot be established<br \/>\nd) a&gt;b<br \/>\ne) $a\\geq b$<\/p>\n<p><b>Question 1:\u00a0<\/b>I.$2a^{2}+a-1=0$<br \/>\nII.$12b^{2}-17b+6=0$<\/p>\n<p>a)\u00a0$a&lt;b$<b><\/b><\/p>\n<p>b)\u00a0$a\\leq b$<\/p>\n<p>c)\u00a0Relationship between $a$ &amp; $b$ cannot be established<\/p>\n<p>d)\u00a0$a&gt;b$<\/p>\n<p>e)\u00a0$a\\geq b$<\/p>\n<p><b>Question 2:\u00a0<\/b>I.$a^{2}-5a+6=0$<br \/>\nII. $2b^{2}-13b+21=0$<\/p>\n<p>a)\u00a0$a&lt;b$<b><\/b><\/p>\n<p>b)\u00a0$a\\leq b$<\/p>\n<p>c)\u00a0Relationship between $a$ &amp; $b$ cannot be established<\/p>\n<p>d)\u00a0$a&gt;b$<\/p>\n<p>e)\u00a0$a\\geq b$<\/p>\n<p><b>Question 3:\u00a0<\/b>Consider the following statements:<br \/>\nA.Sachin received 2\/9 of what Saurav and Viru together received.<br \/>\nB.Saurav received 3\/11 of what Sachin and Viru together received.<br \/>\nAmong Sachin, Saurav and Viru, who received the minimum amount?<\/p>\n<p>a)\u00a0Statement A alone is sufficient to answer the question, but not B<\/p>\n<p>b)\u00a0Statement B alone is sufficient to answer the question, but not A<\/p>\n<p>c)\u00a0Both statements together are sufficient to answer the question but not independently<\/p>\n<p>d)\u00a0Both statements together are not sufficient to answer the question.<\/p>\n<p><b>Instructions<\/b><\/p>\n<p>In each of these question two equations I &amp; II with variables a &amp; b are given You have to solve both the equations to find the values of a &amp; b<br \/>\nMark answer if<br \/>\na) a&lt;b<br \/>\n&lt;\/b<\/p>\n<p>&lt;b<br \/>\n&lt;\/b<br \/>\n&lt;b<br \/>\nb) $a\\leq b$<br \/>\nc) relationship between a &amp; b cannot be established<br \/>\nd) a&gt;b<br \/>\ne) $a\\geq b$<\/p>\n<p><b>Question 4:\u00a0<\/b>I.$16a^{2}=1$<br \/>\nII.$3b^{2}+7b+2=0$<\/p>\n<p>a)\u00a0$a&lt;b$<b><\/b><\/p>\n<p>b)\u00a0$a\\leq b$<\/p>\n<p>c)\u00a0Relationship between $a$ &amp; $b$ cannot be established<\/p>\n<p>d)\u00a0$a&gt;b$<\/p>\n<p>e)\u00a0$a\\geq b$<\/p>\n<p><b>Question 5:\u00a0<\/b>What is the remainder when $19^{100}$ is divided by 360?<\/p>\n<p>a)\u00a00<\/p>\n<p>b)\u00a01<\/p>\n<p>c)\u00a04<\/p>\n<p>d)\u00a018<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/sbi-po-previous-papers\" target=\"_blank\" class=\"btn btn-danger \">Download SBI PO Previous Papers PDF<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/sbi-po-mock-test\" target=\"_blank\" class=\"btn btn-info \">SBI PO free mock test<\/a><\/p>\n<p><b>Instructions<\/b><\/p>\n<p>In each of the following question two equations are given you have to solve them and<br \/>\nGive answer (a)if p&lt;q<br \/>\n&lt;\/q<br \/>\nGive answer (b)if p&gt;q<br \/>\nGive answer (c)if $p\\leq$q<br \/>\nGive answer(d)if $p\\geq$q<br \/>\nGive answer (e)if p=q<\/p>\n<p><b>Question 6:\u00a0<\/b>I.$p^{2}-7p=-12$<br \/>\nII.$q^{2}-3q+2=0$<\/p>\n<p>a)\u00a0if p&lt;q<q><\/q><\/p>\n<p>b)\u00a0if p&gt;q<\/p>\n<p>c)\u00a0if $p\\leq$q<\/p>\n<p>d)\u00a0if $p\\geq$q<\/p>\n<p>e)\u00a0if p=q<\/p>\n<p><b>Question 7:\u00a0<\/b>I. $12p^{2}-7p=-1$<br \/>\nII. $6q^{2}-7q+2=0$<\/p>\n<p>a)\u00a0if $p &lt; q$<q><\/q><\/p>\n<p>b)\u00a0if $p &gt; q$<\/p>\n<p>c)\u00a0if $p\\leq q$<\/p>\n<p>d)\u00a0if $p\\geq q$<\/p>\n<p>e)\u00a0if $p = q$<\/p>\n<p><b>Question 8:\u00a0<\/b>I.$p^{2}+12p+35=0$<br \/>\nII.$2q^{2}+22q+56=0$<\/p>\n<p>a)\u00a0if p &lt; q<q><\/q><\/p>\n<p>b)\u00a0if p&gt;q<\/p>\n<p>c)\u00a0if $p \\leq q$<\/p>\n<p>d)\u00a0if $p\\geq q$<\/p>\n<p>e)\u00a0if p=q or no relationship can be established<\/p>\n<p><b>Question 9:\u00a0<\/b>I.$p^{2}-8p+15=0$<br \/>\nII.$q^{2}-5q=-6$<\/p>\n<p>a)\u00a0if p &lt; q<q><\/q><\/p>\n<p>b)\u00a0if p&gt;q<\/p>\n<p>c)\u00a0if $p\\leq q$<\/p>\n<p>d)\u00a0if $p\\geq q$<\/p>\n<p>e)\u00a0if p=q<\/p>\n<p><b>Question 10:\u00a0<\/b>I.$2p^{2}+20p+50=0$<br \/>\nII.$q^{2}=25$<\/p>\n<p>a)\u00a0if p&lt;q <q><\/q><\/p>\n<p>b)\u00a0if p&gt;q<\/p>\n<p>c)\u00a0if $p \\leq q$<\/p>\n<p>d)\u00a0if $p\\geq q $<\/p>\n<p>e)\u00a0if p = q<\/p>\n<p><b>Instructions<\/b><\/p>\n<p>For the two given equations I and II&#8212;-<\/p>\n<p><b>Question 11:\u00a0<\/b>I. $6p^{2}+5p+1=0$<br \/>\nII. $20q^{2}+9q=-1$<\/p>\n<p>a)\u00a0Give answer (A) if p is greater than q.<\/p>\n<p>b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n<p>c)\u00a0Give answer (C) if p is equal to q.<\/p>\n<p>d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n<p>e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n<p><b>Question 12:\u00a0<\/b>I. $3p^{2}+2p-1=0$ II. $2q^{2}+7q+6=0$<\/p>\n<p>a)\u00a0Give answer (A) if p is greater than q.<\/p>\n<p>b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n<p>c)\u00a0Give answer (C) if p is equal to q.<\/p>\n<p>d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n<p>e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n<p><b>Question 13:\u00a0<\/b>I. $3p^2+15p=-18$ II. $q^2+7q+12=0$<\/p>\n<p>a)\u00a0Give answer (A) if p is greater than q.<\/p>\n<p>b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n<p>c)\u00a0Give answer (C) if p is equal to q.<\/p>\n<p>d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n<p>e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n<p><b>Question 14:\u00a0<\/b>I. $p=\\frac{\\sqrt{4}}{\\sqrt{9}}$ II. $9q^{2}-12q+4=0$<\/p>\n<p>a)\u00a0Give answer (A) if p is greater than q.<\/p>\n<p>b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n<p>c)\u00a0Give answer (C) if p is equal to q.<\/p>\n<p>d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n<p>e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n<p><b>Question 15:\u00a0<\/b>I. $p^{2}+13p+42=0$ II. $q^{2}=36$<\/p>\n<p>a)\u00a0Give answer (A) if p is greater than q.<\/p>\n<p>b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n<p>c)\u00a0Give answer (C) if p is equal to q.<\/p>\n<p>d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n<p>e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n<p><b>Instructions<\/b><\/p>\n<p>In these questions, two equations numbered I and II are given. You have to solve both the equations and select the appropriate option.<\/p>\n<p><b>Question 16:\u00a0<\/b>I. $2x^{2}+19x+45=0$<br \/>\nII. $2y^{2}+11y+12=0$<\/p>\n<p>a)\u00a0x = y<\/p>\n<p>b)\u00a0x&gt; y<\/p>\n<p>c)\u00a0x &lt; y<\/p>\n<p>d)\u00a0relationship between xand y cannot be determined<\/p>\n<p>e)\u00a0x + y<\/p>\n<p><b>Question 17:\u00a0<\/b>I. $3x^{2}-13x+12=0$<br \/>\nII. $2y^{2}-15y+28=0$<\/p>\n<p>a)\u00a0x&gt; y<\/p>\n<p>b)\u00a0x= y<\/p>\n<p>c)\u00a0x &lt; y<\/p>\n<p>d)\u00a0relationship between x and y cannot be determined<\/p>\n<p>e)\u00a0x\u2264 y<\/p>\n<p><b>Question 18:\u00a0<\/b>I. $x^{2}=16$<br \/>\nII. $2y^{2}-17y+36=0$<\/p>\n<p>a)\u00a0x &gt; y<\/p>\n<p>b)\u00a0x &gt; y<\/p>\n<p>c)\u00a0x &lt; y<\/p>\n<p>d)\u00a0relationship between x and y cannot be determined<\/p>\n<p>e)\u00a0$x \\leq y$<\/p>\n<p><b>Question 19:\u00a0<\/b>I. $6x^{2}+19x+15=0$<br \/>\nII. $3y^{2}+11y+10=0$<\/p>\n<p>a)\u00a0x = y<\/p>\n<p>b)\u00a0x &gt; y<\/p>\n<p>c)\u00a0x &lt; y<\/p>\n<p>d)\u00a0$x \\geq y$<\/p>\n<p>e)\u00a0$x \\leq y$<\/p>\n<p><b>Question 20:\u00a0<\/b>I. $2x^{2}-11x+15=0$<br \/>\nII. $2y^{2}-11y+14=0$<\/p>\n<p>a)\u00a0x &gt; y<\/p>\n<p>b)\u00a0x&gt; y<\/p>\n<p>c)\u00a0x &lt; y<\/p>\n<p>d)\u00a0relationship between x and y cannot be determined<\/p>\n<p>e)\u00a0x \u2264 y<\/p>\n<p><b>Instructions<\/b><\/p>\n<p>In the following questions two equations numbered I and<br \/>\nII are given. You have to solve both the equations and<br \/>\na: if x &gt; y<br \/>\nb: if x \u2265 y<br \/>\nc: if x &lt; y<br \/>\nd: if x \u2264 y<br \/>\ne: if x = y or the relationship cannot be established.<\/p>\n<p><b>Question 21:\u00a0<\/b>I. $x^{2}+x-12=0$<br \/>\nII. $y^{2}+2y-8=0$<\/p>\n<p>a)\u00a0if x &gt; y<\/p>\n<p>b)\u00a0if x \u2265 y<\/p>\n<p>c)\u00a0if x &lt; y<\/p>\n<p>d)\u00a0if x \u2264 y<\/p>\n<p>e)\u00a0if x = y or the relationship cannot be established.<\/p>\n<p><span style=\"text-decoration: underline;\"><strong>Answers &amp; Solutions:<\/strong><\/span><\/p>\n<p><strong>1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<p>$2a^{2}+a-1=0$<br \/>\nWe get the factor as:<br \/>\na=-1, a=0.5<\/p>\n<p>$12b^{2}-17b+6=0$<br \/>\nSolving, we get the factor as,<br \/>\nb= 1.5, b= .75<\/p>\n<p>Hence, b&gt;a<br \/>\nOption A is correct option.<\/p>\n<p><strong>2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<p>Soving the quadratic equations we get,<br \/>\n$a^{2}-5a+6=0$<br \/>\ni.e (a-2)(a-3)=0<br \/>\ni.e a=2, a=3<\/p>\n<p>$2b^{2}-13b+21=0$<br \/>\ni.e (b-3.5)(b-3)=0<br \/>\ni.e b= 3.5 and b=3<\/p>\n<p>Hence, we can deduce that $a\\leq b$<br \/>\nTherefore, option B is correct.<\/p>\n<p><strong>3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>From statement 1 alone, we do not know if Saurav or Viru has got less than Sachin, from statement 2 alone we cannot know if Sachin or Viru got less than Saurav. Let the total number of quantities be 9*11*14 = 1386. From statement 1, we know that Sachin received 252 quantities. From 2, we know that Saurav received 287 quantities. Therefore, from both the statements, we know that Sachin received the least amount (though we do not know the absolute value of the quantity received, we can still answer the question ).<\/p>\n<p><strong>4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>$16a^{2}=1$<br \/>\nSolving we get, a=-.25, a=+.25<\/p>\n<p>$3b^{2}+7b+2=0$<br \/>\nSolving we get, b= -2. b = -1\/3<\/p>\n<p>Hence, a&gt;b. Option D is correct.<\/p>\n<p><strong>5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<p>We know that when $19^2$ =361 is divided by 360 the remainder is 1. Hence, $19^{100} = 19^2 * 19^2 . . . 50$ times .<\/p>\n<p>Hence the remainder is Rem (1*1*1. . . 50 times)\/361 = 1.<\/p>\n<p><strong>6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<p>$p^2-7p+12 = 0$<br \/>\n$(p-3)(p-4) = 0$<br \/>\n$p = 3, 4$<\/p>\n<p>$q^2-3q+2 = 0$<br \/>\n$(q-1)(q-2) = 0$<br \/>\n$q = 1, 2$<\/p>\n<p>$\\therefore p &gt; q$<\/p>\n<p><strong>7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<p>$12p^2-7p+1 = 0$<br \/>\n$(4p-1)(3p-1) = 0$<br \/>\n$p = \\frac{1}{3}, \\frac{1}{4}$<\/p>\n<p>$6q^2-7q+2 = 0$<br \/>\n$(2q-1)(3q-2) = 0$<br \/>\n$q = \\frac{1}{2}, \\frac{2}{3}$<\/p>\n<p>$\\therefore p &lt; q$<\/p>\n<p><strong>8)\u00a0Answer\u00a0(E)<\/strong><\/p>\n<p>$p^2+12p+35 = 0$<br \/>\n$(p+5)(p+7) = 0$<br \/>\n$p = -5, -7$<\/p>\n<p>$2q^2+22q+56 = 0$<br \/>\n$q^2+11q+28 = 0$<br \/>\n$(q+4)(q+7) = 0$<br \/>\n$q = -4, -7$<\/p>\n<p>As we can see $p$ can be greater than, less than or equal to $q$. No relationship can be established between $p$ and $q$ and hence, option E is the right answer.<\/p>\n<p><strong>9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>$p^2-8p+15 = 0$<br \/>\n$(p-3)(p-5) = 0$<br \/>\n$p = 3, 5$<\/p>\n<p>$q^2-5q+6 = 0$<br \/>\n$(q-2)(q-3) = 0$<br \/>\n$q = 2, 3$<\/p>\n<p>$p\\geq q$<\/p>\n<p><strong>10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>$2p^2+20p+50 = 0$<br \/>\n$p^2+10p+25 = 0$<br \/>\n$(p+5)^2 = 0$<br \/>\n$p = -5$<\/p>\n<p>$q^2 = 25$<br \/>\n$q = 5, -5$<\/p>\n<p>$p\\leq q$<\/p>\n<p><strong>11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<p>$6p^2+5p+1 = 0$<br \/>\n$(2p+1)(3p+1) = 0$<br \/>\n$p = -\\frac{1}{2}, -\\frac{1}{3}$<\/p>\n<p>$20q^2+9q+1 = 0$<br \/>\n$(4q+1)(5q+1) = 0$<br \/>\n$q = -\\frac{1}{4}, -\\frac{1}{5}$<\/p>\n<p>$p &lt; q$<\/p>\n<p><strong>12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<p>$3p^2+2p-1 = 0$<br \/>\n$(3p-1)(p+1) = 0$<br \/>\n$p = -1, \\frac{1}{3}$<\/p>\n<p>$2q^2+7q+6 = 0$<br \/>\n$(2q+3)(q+2) = 0$<br \/>\n$q = -2, -\\frac{3}{2}$<\/p>\n<p>p &gt; q<\/p>\n<p><strong>13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>$3p^2+15p+18 = 0$<br \/>\n$p^2+5p+6 = 0$<br \/>\n$(p+2)(p+3) = 0$<br \/>\n$p = -3, -2$<\/p>\n<p>$q^2+7q+12 = 0$<br \/>\n$(q+4)(q+3) = 0$<br \/>\n$q = -4, -3$<\/p>\n<p>$p\\geq q$<\/p>\n<p><strong>14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>$p = \\frac{\\sqrt{4}}{\\sqrt{9}}$<br \/>\n$p = \\frac{2}{3}$<\/p>\n<p>$9q^2-12q+4 = 0$<br \/>\n${(3q-2)}^2 = 0$<br \/>\n$q = \\frac{2}{3}$<\/p>\n<p>p = q<\/p>\n<p><strong>15)\u00a0Answer\u00a0(E)<\/strong><\/p>\n<p>$p^2+13p+42 = 0$<br \/>\n$(p+6)(p+7) = 0$<br \/>\n$p = -6, -7$<\/p>\n<p>$q^2 = 36$<br \/>\n$q = -6, 6$<\/p>\n<p>$p\\leq q$<\/p>\n<p><strong>16)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>$2x^2+19x+45 = 0$<br \/>\n$(2x+9)(x+5) = 0$<br \/>\n$x = -5, -\\frac{9}{2}$<\/p>\n<p>$2y^2+11y+12 = 0$<br \/>\n$(2y+3)(y+4) = 0$<br \/>\n$y = -4, -\\frac{3}{2}$<\/p>\n<p>x &lt; y<\/p>\n<p><strong>17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>$3x^2-13x+12 = 0$<br \/>\n$(3x-4)(x-3) = 0$<br \/>\n$x = \\frac{4}{3}, 3$<\/p>\n<p>$2y^2-15y+28 = 0$<br \/>\n$(2y-7)(y-4) = 0$<br \/>\n$y = \\frac{7}{2}, 4$<\/p>\n<p>x &lt; y<\/p>\n<p><strong>18)\u00a0Answer\u00a0(E)<\/strong><\/p>\n<p>$x^2 = 16$<br \/>\n$x = 4, -4$<\/p>\n<p>$2y^2-17y+36 = 0$<br \/>\n$(2y-9)(y-4) = 0$<br \/>\n$y = \\frac{9}{2}, 4$<\/p>\n<p>$x \\leq y$<\/p>\n<p><strong>19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>$6x^2+19x+15 = 0$<br \/>\n$(3x+5)(2x+3) = 0$<br \/>\n$x = -\\frac{5}{3}, -\\frac{3}{2}$<\/p>\n<p>$3y^2+11y+10 = 0$<br \/>\n$(3y+5)(y+2) = 0$<br \/>\n$y = -\\frac{5}{3}, -2$<\/p>\n<p>$x\\geq y$<\/p>\n<p><strong>20)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>$2x^2-11x+15 = 0$<br \/>\n$(2x-5)(x-3) = 0$<br \/>\n$x = 3, \\frac{5}{2}$<\/p>\n<p>$2y^2-11y+14 = 0$<br \/>\n$(2y-7)(y-2) = 0$<br \/>\n$y = 2, \\frac{7}{2}$<\/p>\n<p>relationship between x and y cannot be established<\/p>\n<p><strong>21)\u00a0Answer\u00a0(E)<\/strong><\/p>\n<p>$x^2+x-12 = 0$<br \/>\n$(x-3)(x+4) = 0$<br \/>\n$x = -4, 3$<\/p>\n<p>$y^2+2y-8 = 0$<br \/>\n$(y-2)(y+4) = 0$<br \/>\n$y = -4, 2$<\/p>\n<p>Hence, a relationship can not be established between $x$ and $y$<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/pay\/7H5pc\" target=\"_blank\" class=\"btn btn-info \">105 SBI PO mocks for Rs. 199. Enroll here<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.cracku.app&amp;hl=en_IN\" target=\"_blank\" class=\"btn btn-danger \">Download SBI Free Preparation App<\/a><\/p>\n<p>We hope this Quadratic Equation Questions &amp; Answers\u00a0 PDF of SBI PO is very Useful for preparation of SBI PO Exams.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Quadratic Equation Questions for SBI PO 2020 pdf Download SBI PO Quadratic Equation Questions &amp; Answers PDF for SBI PO Prelims and Mains exam. Very Important SBI PO Quadratic Equation Questions with solutions. Download SBI PO Previous Papers PDF SBI PO Free Mock Tests Instructions In each of these question two equations I &amp; II [&hellip;]<\/p>\n","protected":false},"author":49,"featured_media":41196,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,231,3525],"tags":[3731,47],"class_list":{"0":"post-41191","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-sbipo","10":"category-sbi-clerk","11":"tag-quadratic-equation-questions","12":"tag-sbi-po"},"better_featured_image":{"id":41196,"alt_text":"Quadratic Equation Questions for SBI PO 2020 pdf","caption":"Quadratic Equation Questions for SBI PO 2020 pdf","description":"Quadratic Equation Questions for SBI PO 2020 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