{"id":40538,"date":"2020-02-14T18:04:06","date_gmt":"2020-02-14T12:34:06","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=40538"},"modified":"2020-02-14T18:04:09","modified_gmt":"2020-02-14T12:34:09","slug":"ssc-questions-on-trigonometry-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/ssc-questions-on-trigonometry-pdf\/","title":{"rendered":"SSC Questions on Trigonometry PDF"},"content":{"rendered":"<h1><span style=\"text-decoration: underline;\"><strong>SSC Questions on Trigonometry PDF<\/strong><\/span><\/h1>\n<p>Download SSC Trigonometry Questions with answers PDF based on previous papers very useful for SSC&nbsp; exams. Top-10 Very Important Questions for SSC Exams.<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc-cgl-online-mock-tests\" target=\"_blank\" class=\"btn btn-info \">Take a free SSC CGL mock test<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc\/pricing\/ssc-unlimited\" target=\"_blank\" class=\"btn btn-primary \">Get 200 SSC mocks for just Rs. 249. Enroll here<\/a><\/p>\n<p>Take a <a href=\"https:\/\/cracku.in\/ssc-cgl-online-mock-tests\" target=\"_blank\" rel=\"noopener noreferrer\">free mock test for SSC CGL<\/a><\/p>\n<p>Download <a href=\"https:\/\/cracku.in\/ssc-cgl-previous-papers\" target=\"_blank\" rel=\"noopener noreferrer\">SSC CGL Previous Papers PDF<\/a><\/p>\n<p>More <a href=\"https:\/\/cracku.in\/blog\/ssc-cgl-questions-answers-pdf\/\" target=\"_blank\" rel=\"noopener noreferrer\">SSC CGL Important Questions and Answers PDF<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/downloads\/8565\" target=\"_blank\" class=\"btn btn-danger  download\">Download SSC Questions on Trigonometry PDF<\/a><\/p>\n<p><b>Question 1:&nbsp;<\/b>$5tan\\theta = 4$, then the value of&nbsp;$(\\frac{5sin\\theta &#8211; 3cos\\theta}{5sin\\theta + 3cos\\theta})$ is<\/p>\n<p>a)&nbsp;$\\frac{1}{7}$<\/p>\n<p>b)&nbsp;$\\frac{2}{7}$<\/p>\n<p>c)&nbsp;$\\frac{5}{7}$<\/p>\n<p>d)&nbsp;$\\frac{2}{5}$<\/p>\n<p><b>Question 2:&nbsp;<\/b>The least value of $(4sec^2\\theta + 9cosec^2\\theta)$ is<\/p>\n<p>a)&nbsp;1<\/p>\n<p>b)&nbsp;19<\/p>\n<p>c)&nbsp;25<\/p>\n<p>d)&nbsp;7<\/p>\n<p><b>Question 3:&nbsp;<\/b>If $x=cosec\\theta-sin\\theta$ and $y=sec\\theta-cos\\theta$, then the value of $x<sup>2<\/sup>y<sup>2<\/sup>(x<sup>2<\/sup> + y<sup>2<\/sup> + 3)$<\/p>\n<p>a)&nbsp;0<\/p>\n<p>b)&nbsp;1<\/p>\n<p>c)&nbsp;2<\/p>\n<p>d)&nbsp;3<\/p>\n<p><b>Question 4:&nbsp;<\/b>If $ 0 \\leq \\theta \\leq \\frac{\\pi}{2}$, $2ycos\\theta=sin\\theta$ and $\\frac{x}{2cosec\\theta}=y$, then the value of $x^2-4y^2$&nbsp;is<\/p>\n<p>a)&nbsp;1<\/p>\n<p>b)&nbsp;2<\/p>\n<p>c)&nbsp;3<\/p>\n<p>d)&nbsp;4<\/p>\n<p><b>Question 5:&nbsp;<\/b>If $sin\\theta + \\sin^2\\theta = 1$, then the value of cos<sup>12<\/sup>$\\theta$ + 3cos<sup>10<\/sup>$\\theta$ + cos<sup>6<\/sup>$\\theta$ + &nbsp;3cos<sup>8<\/sup>$\\theta$&nbsp; &#8211; 1&nbsp;is<\/p>\n<p>a)&nbsp;0<\/p>\n<p>b)&nbsp;1<\/p>\n<p>c)&nbsp;-1<\/p>\n<p>d)&nbsp;2<\/p>\n<p><b>Question 6:&nbsp;<\/b>The value of $\\frac{1}{cosec\\theta &#8211; cot\\theta} &#8211; \\frac{1}{sin\\theta}$<\/p>\n<p>a)&nbsp;$cot\\theta$<\/p>\n<p>b)&nbsp;$cosec\\theta$<\/p>\n<p>c)&nbsp;$tan\\theta$<\/p>\n<p>d)&nbsp;$1$<\/p>\n<p><b>Question 7:&nbsp;<\/b>If&nbsp;$\\cos\\theta + \\sin\\theta = \\sqrt{2}\\cos\\theta$, then $\\cos\\theta &#8211; \\sin\\theta$ is<\/p>\n<p>a)&nbsp;-$\\sqrt{2}\\cos\\theta$<\/p>\n<p>b)&nbsp;-$\\sqrt{2}\\sin\\theta$<\/p>\n<p>c)&nbsp;$\\sqrt{2}\\sin\\theta$<\/p>\n<p>d)&nbsp;$\\sqrt{2}\\tan\\theta$<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc-cgl-previous-papers\" target=\"_blank\" class=\"btn btn-alone \">SSC CGL Previous Papers Download PDF<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc-cgl-online-mock-tests\" target=\"_blank\" class=\"btn btn-danger \">SSC CGL Free Mock Test<\/a><\/p>\n<p><b>Question 8:&nbsp;<\/b>If $cos^4\\theta-sin^4\\theta=\\frac{2}{3}$, then the value of $1-2sin^2\\theta$ is,<\/p>\n<p>a)&nbsp;0<\/p>\n<p>b)&nbsp;$\\frac{2}{3}$<\/p>\n<p>c)&nbsp;$\\frac{1}{3}$<\/p>\n<p>d)&nbsp;$\\frac{4}{3}$<\/p>\n<p><b>Question 9:&nbsp;<\/b>If $tan\\theta$ = 3\/4 and $\\theta$ is acute, then $cosec\\theta$ is equal to<\/p>\n<p>a)&nbsp;$\\frac{5}{3}$<\/p>\n<p>b)&nbsp;$2$<\/p>\n<p>c)&nbsp;$\\frac{1}{2}$<\/p>\n<p>d)&nbsp;$4$<\/p>\n<p><b>Question 10:&nbsp;<\/b>The value of $\\frac{1}{1 + tan^2\\theta}$ + $\\frac{1}{1 + cot^2\\theta}$ is<\/p>\n<p>a)&nbsp;1<\/p>\n<p>b)&nbsp;2<\/p>\n<p>c)&nbsp;$\\frac{1}{2}$<\/p>\n<p>d)&nbsp;$\\frac{1}{4}$<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/www.youtube.com\/channel\/UCVFahh7Fd1b4sPUpq2mtxpg?sub_confirmation=1\" target=\"_blank\" class=\"btn btn-warning \">FREE SSC EXAM YOUTUBE VIDEOS<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc-study-material\" target=\"_blank\" class=\"btn btn-primary \">18000+ Questions &#8211; Free SSC Study Material<\/a><\/p>\n<p><span style=\"text-decoration: underline;\"><strong>Answers &amp; Solutions:<\/strong><\/span><\/p>\n<p><strong>1)&nbsp;Answer&nbsp;(A)<\/strong><\/p>\n<p>Taking $cos\\theta$ outside in numerator and in denominator and making $tan\\theta$<br \/>\nhence eq will be&nbsp;&nbsp;$(\\frac{5tan\\theta &#8211; 3}{5tan\\theta + 3})$<br \/>\nAs it is given that $5tan\\theta$ = 4<br \/>\nafter putting values and solving we will get the equation reduced to 1\/7.<\/p>\n<p><strong>2)&nbsp;Answer&nbsp;(A)<\/strong><\/p>\n<p>$4sec^2\\theta+9cosec^2\\theta$<br \/>\nor $4+4tan^2\\theta+9+9cot^2\\theta$<br \/>\nor $13+4tan^2\\theta+9cot^2\\theta$<br \/>\nor $ 13+4tan^2\\theta+\\frac{9}{tan^2\\theta} $<br \/>\nor $ &nbsp;13-12+(2tan\\theta+\\frac{3}{tan\\theta})^2 $ &nbsp; &nbsp;(eq. (1) )<br \/>\nor now above expression to be minimum, equation $(2tan\\theta+\\frac{3}{tan\\theta})^2$ should be minimum.<br \/>\nSo applying $A.M.\\geq G.M. $<br \/>\n$\\frac{(2tan\\theta +\\frac{3}{tan\\theta})}{2} \\geq \\sqrt{6}$<br \/>\nor&nbsp;${(2tan\\theta+\\frac{3}{tan\\theta})}=2\\sqrt{6}$ ( for value to be minimum)<br \/>\nAfter putting above value in eq.(1) , we will get least value of expression as 25.<\/p>\n<p><strong>3)&nbsp;Answer&nbsp;(B)<\/strong><\/p>\n<p>$x=cosec\\theta &#8211; sin\\theta=\\frac{cos^2\\theta}{sin\\theta}=cot\\theta cos\\theta$<br \/>\nSimilarly $y=tan\\theta sin\\theta$<br \/>\n$xy=sin\\theta cos\\theta$<br \/>\n$x^2+y^2+3=(sec^2\\theta +cosec^2\\theta )$<br \/>\nNow putting above values in given equation, and after solving it will be reduced to 1<\/p>\n<p><strong>4)&nbsp;Answer&nbsp;(A)<\/strong><\/p>\n<p>$2y=tan\\theta$<br \/>\n$x=2ycosec\\theta$<br \/>\nHence value of $x^2 &#8211; 4y^2 $ = $4y^2(cosec^2\\theta &#8211; 1)$<br \/>\nor $tan^2\\theta cot^2\\theta$ = 1<\/p>\n<p><strong>5)&nbsp;Answer&nbsp;(A)<\/strong><\/p>\n<p>Given equation can be written as $(cos^4\\theta + cos^2\\theta)^3 -1$<br \/>\nas $sin\\theta + sin^2\\theta = 1$<br \/>\nor $sin\\theta = cos^2\\theta$<br \/>\nputting above value in given equation it will be<br \/>\n$(sin^2\\theta + sin\\theta)^3 -1 = 0$<\/p>\n<p><strong>6)&nbsp;Answer&nbsp;(A)<\/strong><\/p>\n<p>$\\frac{sin\\theta}{1-cos\\theta} &#8211; \\frac{1}{sin\\theta}$<\/p>\n<p>or $\\frac{cos\\theta &#8211; cos^2\\theta}{(1-cos\\theta)sin\\theta}$ = $cot\\theta$<\/p>\n<p><strong>7)&nbsp;Answer&nbsp;(C)<\/strong><\/p>\n<p>$\\sin^2 \\theta + \\cos^2 \\theta = 1$<br \/>\nSo, $\\sin^2 \\theta + \\cos^2 \\theta + 2\\sin\\theta * \\cos \\theta = 2 \\cos^2\\theta$<br \/>\nHence, $\\cos^2 \\theta &#8211; \\sin^2 \\theta = 2 \\sin\\theta*\\cos\\theta$<br \/>\nSo, $\\cos\\theta &#8211; \\sin\\theta = \\sqrt{2}\\sin\\theta$<\/p>\n<p><strong>8)&nbsp;Answer&nbsp;(B)<\/strong><\/p>\n<p>$cos^4\\theta-sin^4\\theta=(cos^2\\theta-sin^2\\theta)(cos^2\\theta+sin^2\\theta)=cos^2\\theta-sin^2\\theta=\\frac{2}{3}$<br \/>\n$cos^2\\theta-sin^2\\theta =1-2sin^2\\theta=\\frac{2}{3}$<\/p>\n<p><strong>9)&nbsp;Answer&nbsp;(A)<\/strong><\/p>\n<p>$\\frac{sin \\theta}{cos \\theta} = \\frac{3}{4}$<br \/>\nSo, $\\frac{sin^2\\theta}{cos^2\\theta}=\\frac{9}{16}$<br \/>\nHence, $sin^2 \\theta = \\frac{9}{9+16}=\\frac{9}{25}$<br \/>\nSo, $cosec \\theta = \\frac{5}{3}$<\/p>\n<p><strong>10)&nbsp;Answer&nbsp;(A)<\/strong><\/p>\n<p>$1 + \\tan ^2 \\theta = \\sec ^2 \\theta$<br \/>\n$1 + \\cot ^2 \\theta = \\csc ^2 \\theta$<br \/>\nSo, the given fraction becomes,<\/p>\n<p>$\\frac{1}{\\sec ^2 \\theta} + \\frac{1}{\\csc ^2 \\theta} = \\sin^2\\theta + \\cos^2 \\theta = 1$<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc\/pricing\/ssc-unlimited\" target=\"_blank\" class=\"btn btn-info \">Get 200 SSC mocks for just Rs. 249. Enroll here<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.cracku.app&amp;hl=en_IN\" target=\"_blank\" class=\"btn btn-danger \">SSC Free Previous Papers App<\/a><\/p>\n<p>We hope this Trigonometry Questions for SSC&nbsp; Exam preparation is so helpful to you.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>SSC Questions on Trigonometry PDF Download SSC Trigonometry Questions with answers PDF based on previous papers very useful for SSC&nbsp; exams. Top-10 Very Important Questions for SSC Exams. Take a free mock test for SSC CGL Download SSC CGL Previous Papers PDF More SSC CGL Important Questions and Answers PDF Question 1:&nbsp;$5tan\\theta = 4$, then [&hellip;]<\/p>\n","protected":false},"author":49,"featured_media":40544,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3167,125,9,504,378,1493,1459,1611,1741,1441],"tags":[3638,165],"class_list":{"0":"post-40538","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads-en","8":"category-featured","9":"category-ssc","10":"category-ssc-cgl","11":"category-ssc-chsl","12":"category-ssc-cpo","13":"category-ssc-gd","14":"category-ssc-je","15":"category-ssc-mts","16":"category-stenographer","17":"tag-questions-on-trigonometry","18":"tag-ssc"},"better_featured_image":{"id":40544,"alt_text":"SSC Questions on Trigonometry 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Top-10 Very Important Questions for SSC Exams. 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