{"id":40436,"date":"2020-02-05T17:44:48","date_gmt":"2020-02-05T12:14:48","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=40436"},"modified":"2020-02-05T17:44:48","modified_gmt":"2020-02-05T12:14:48","slug":"ap-gp-questions-for-ssc-cgl","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/ap-gp-questions-for-ssc-cgl\/","title":{"rendered":"AP GP Questions for SSC CGL"},"content":{"rendered":"<h2><span style=\"text-decoration: underline;\"><strong>AP GP Questions for SSC CGL<\/strong><\/span><\/h2>\n<p>Download SSC CGL AP &amp; GP Questions PDF based on previous papers very useful for SSC CGL exams. AP &amp; GP Questions for SSC exams.<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/downloads\/8442\" target=\"_blank\" class=\"btn btn-danger  download\">Download AP GP Questions for SSC CGL<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc-cgl-online-mock-tests\" target=\"_blank\" class=\"btn btn-info \">Take a free SSC CGL mock test<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc\/pricing\/ssc-unlimited\" target=\"_blank\" class=\"btn btn-primary \">Get 200 SSC mocks for just Rs. 249. Enroll here<\/a><\/p>\n<p>Take a <a href=\"https:\/\/cracku.in\/ssc-cgl-online-mock-tests\" target=\"_blank\" rel=\"noopener\">free mock test for SSC CGL<\/a><\/p>\n<p>Download <a href=\"https:\/\/cracku.in\/ssc-cgl-previous-papers\" target=\"_blank\" rel=\"noopener\">SSC CGL Previous Papers PDF<\/a><\/p>\n<p>More <a href=\"https:\/\/cracku.in\/blog\/ssc-cgl-questions-answers-pdf\/\" target=\"_blank\" rel=\"noopener\">SSC CGL Important Questions and Answers PDF<\/a><\/p>\n<p><b>Question 1:\u00a0<\/b>The 3rd and 9th term of an arithmetic progression are -8 and 10 respectively. What is the 16th term?<\/p>\n<p>a)\u00a034<\/p>\n<p>b)\u00a028<\/p>\n<p>c)\u00a025<\/p>\n<p>d)\u00a031<\/p>\n<p><b>Question 2:\u00a0<\/b>What is the sum of the first 12 terms of an arithmetic progression if the first term is -19 and last term is 36?<\/p>\n<p>a)\u00a0192<\/p>\n<p>b)\u00a0230<\/p>\n<p>c)\u00a0102<\/p>\n<p>d)\u00a0214<\/p>\n<p><b>Question 3:\u00a0<\/b>What is the sum of the first 12 terms of an arithmetic progression if the 3rd term is -13 and the 6th term is -4?<\/p>\n<p>a)\u00a067<\/p>\n<p>b)\u00a045<\/p>\n<p>c)\u00a0-30<\/p>\n<p>d)\u00a0-48<\/p>\n<p><b>Question 4:\u00a0<\/b>What is the sum of the first 17 terms of an arithmetic progression if the first term is -20 and last term is 28?<\/p>\n<p>a)\u00a068<\/p>\n<p>b)\u00a0156<\/p>\n<p>c)\u00a0142<\/p>\n<p>d)\u00a0242<\/p>\n<p><b>Question 5:\u00a0<\/b>If the 3rd and the 5th term of an arithmetic progression are 13 and 21, what is the 13th term?<\/p>\n<p>a)\u00a053<\/p>\n<p>b)\u00a049<\/p>\n<p>c)\u00a057<\/p>\n<p>d)\u00a061<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc-cgl-previous-papers\" target=\"_blank\" class=\"btn btn-alone \">SSC CGL Previous Papers Download PDF<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc-cgl-online-mock-tests\" target=\"_blank\" class=\"btn btn-danger \">SSC CGL Free Mock Test<\/a><\/p>\n<p><b>Question 6:\u00a0<\/b>The greatest number,that divides 43, 91 and 183 so as to leave the same remainder in each case, is<\/p>\n<p>a)\u00a09<\/p>\n<p>b)\u00a08<\/p>\n<p>c)\u00a04<\/p>\n<p>d)\u00a03<\/p>\n<p><b>Question 7:\u00a0<\/b>The greatest number among\u00a0$\\sqrt{5}$,$\\sqrt[3]{4}$,$\\sqrt[5]{2}$,$\\sqrt[7]{3}$ is<\/p>\n<p>a)\u00a0$\\sqrt[3]{4}$<\/p>\n<p>b)\u00a0$\\sqrt[7]{3}$<\/p>\n<p>c)\u00a0$\\sqrt{5}$<\/p>\n<p>d)\u00a0$\\sqrt[5]{2}$<\/p>\n<p><b>Question 8:\u00a0<\/b>What is the greatest number which when divides 460, 491 and 553, leave 26 as remainderin each case?<\/p>\n<p>a)\u00a033<\/p>\n<p>b)\u00a027<\/p>\n<p>c)\u00a035<\/p>\n<p>d)\u00a031<\/p>\n<p><b>Question 9:\u00a0<\/b>If the 10-digit number 897359y7x2 is divisible by 72, then what is the value of(3x-y), for the possible greatest value of y ?<\/p>\n<p>a)\u00a03<\/p>\n<p>b)\u00a08<\/p>\n<p>c)\u00a07<\/p>\n<p>d)\u00a05<\/p>\n<p><b>Question 10:\u00a0<\/b>If the Arithmetic mean of 7, 5, 13, x and 9 is 10, then the value of x is<\/p>\n<p>a)\u00a010<\/p>\n<p>b)\u00a012<\/p>\n<p>c)\u00a014<\/p>\n<p>d)\u00a016<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc-study-material\" target=\"_blank\" class=\"btn btn-alone \">18000+ Questions &#8211; Free SSC Study Material<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/www.youtube.com\/channel\/UCVFahh7Fd1b4sPUpq2mtxpg?sub_confirmation=1\" target=\"_blank\" class=\"btn btn-warning \">FREE SSC EXAM YOUTUBE VIDEOS<\/a><\/p>\n<p><span style=\"text-decoration: underline;\"><strong>Answers &amp; Solutions:<\/strong><\/span><\/p>\n<p><strong>1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>Let the first term of an AP = $a$ and the common difference = $d$<\/p>\n<p>3th term of AP = $A_3=a+2d=-8$ &#8212;&#8212;&#8212;-(i)<\/p>\n<p>9th term = $A_9=a+8d=10$ &#8212;&#8212;&#8211;(ii)<\/p>\n<p>Subtracting equation (i) from (ii), we get\u00a0:<\/p>\n<p>=&gt; $8d-2d=10-(-8)$<\/p>\n<p>=&gt; $6d=18$<\/p>\n<p>=&gt; $d=\\frac{18}{6}=3$<\/p>\n<p>Substituting it in equation (ii), =&gt; $a=10-8(3)=10-24=-14$<\/p>\n<p>$\\therefore$ 16th term = $A_{16}=a+15d$<\/p>\n<p>= $-14+15(3)=-14+45=31$<\/p>\n<p>=&gt; Ans &#8211; (D)<\/p>\n<p><strong>2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>First term of AP = $a=-19$ and last term = $l=36$<\/p>\n<p>Number of terms = $n=12$<\/p>\n<p>Sum of AP = $\\frac{n}{2}(a+l)$<\/p>\n<p>= $\\frac{12}{2}(-19+36)$<\/p>\n<p>= $17 \\times 6=102$<\/p>\n<p>=&gt; Ans &#8211; (C)<\/p>\n<p><strong>3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>$T_{3}$ = a + 2d = -13&#8212;&#8212;-(1)<\/p>\n<p>$T_{6}$ = a + 5d = -4&#8212;&#8212;-(2)<\/p>\n<p>on solving (1) and (2)<\/p>\n<p>d = 3 &amp; a = -19<\/p>\n<p>$S_{n}=\\frac{n}{2}[2a+(n-1)d]$<\/p>\n<p>$S_{12}=\\frac{12}{2}[2(-19)+(12-1)(3)]$<\/p>\n<p>$S_{12}=(6)[-38+33]$<\/p>\n<p>$S_{12}=-30$<\/p>\n<p>So the answer is option C.<\/p>\n<p><strong>4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<p>First term of AP = $a=-20$ and last term = $l=28$<\/p>\n<p>Number of terms = $n=17$<\/p>\n<p>Sum of AP = $\\frac{n}{2}(a+l)$<\/p>\n<p>= $\\frac{17}{2}(-20+28)$<\/p>\n<p>= $17 \\times 4=68$<\/p>\n<p>=&gt; Ans &#8211; (A)<\/p>\n<p><strong>5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<p>$T_{3}$ = a + 2d = 13&#8212;&#8212;-(1)<\/p>\n<p>$T_{5}$ = a + 4d = 21&#8212;&#8212;-(2)<\/p>\n<p>on solving (1) AND (2)<\/p>\n<p>d = 4 &amp; a = 5<\/p>\n<p>$T_{13}$ = a + 12d = 5 + 12(4) = 5 + 48 = 53<\/p>\n<p>So the answer is option A.<\/p>\n<p><strong>6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>3 numbers are 43,91,183<\/p>\n<p>largest number is 183<\/p>\n<p>smallest number is 43<\/p>\n<p>subtract smallest number from both the highest number<\/p>\n<p>so 183 &#8211; 43 = 140<\/p>\n<p>91 &#8211; 43 = 48<\/p>\n<p>91 is smaller than 183, so subtract 91 from 183<\/p>\n<p>183 &#8211; 91 = 92<\/p>\n<p>now we have 3 numbers 140,48,92<\/p>\n<p>so HCF of 140,48,92 = 4<\/p>\n<p>thus\u00a0the\u00a0greatest number,that divides 43, 91 and 183 so as to leave the same remainder in each case, is 4<\/p>\n<p><strong>7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p><strong>8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>Subtract each number by 26<\/p>\n<p>so we get<\/p>\n<p>460 &#8211; 26 = 434<\/p>\n<p>491 &#8211; 26 = 465<\/p>\n<p>553 &#8211; 26 = 527<\/p>\n<p>now taking HCF (434, 465 , 527) = 31 (\u00a0 since 31 divides all the 3 numbers)<\/p>\n<p><strong>9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p><strong>10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>Arithmetic mean of 7, 5, 13, x and 9 = 10<\/p>\n<p>=&gt; $\\frac{(7+5+13+x+9)}{5}=10$<\/p>\n<p>=&gt; $34+x=10 \\times 5=50$<\/p>\n<p>=&gt; $x=50-34=16$<\/p>\n<p>=&gt; Ans &#8211; (D)<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ssc\/pricing\/ssc-unlimited\" target=\"_blank\" class=\"btn btn-info \">Get 200 SSC mocks for just Rs. 249. Enroll here<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.cracku.app&amp;hl=en_IN\" target=\"_blank\" class=\"btn btn-danger \">SSC Free Previous Papers App<\/a><\/p>\n<p>We hope this AP &amp; GP questions for SSC Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>AP GP Questions for SSC CGL Download SSC CGL AP &amp; GP Questions PDF based on previous papers very useful for SSC CGL exams. AP &amp; GP Questions for SSC exams. Take a free mock test for SSC CGL Download SSC CGL Previous Papers PDF More SSC CGL Important Questions and Answers PDF Question 1:\u00a0The [&hellip;]<\/p>\n","protected":false},"author":42,"featured_media":40444,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[1254,3167,125,9,504],"tags":[3613,462],"class_list":{"0":"post-40436","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-competitive-exams","8":"category-downloads-en","9":"category-featured","10":"category-ssc","11":"category-ssc-cgl","12":"tag-arithmetic-progression-geometric-progression-questions-for-ssc-cgl","13":"tag-ssc-cgl"},"better_featured_image":{"id":40444,"alt_text":"AP GP Questions for SSC CGL","caption":"AP GP Questions for SSC CGL\n","description":"AP GP Questions for SSC 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