{"id":40325,"date":"2020-01-31T13:23:12","date_gmt":"2020-01-31T07:53:12","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=40325"},"modified":"2020-01-31T13:23:12","modified_gmt":"2020-01-31T07:53:12","slug":"probability-questions-for-sbi-clerk-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/probability-questions-for-sbi-clerk-pdf\/","title":{"rendered":"Probability Questions for SBI-Clerk PDF"},"content":{"rendered":"

Probability Questions for SBI-Clerk PDF:<\/strong><\/span><\/p>\n

Download SBI-Clerk Probability Questions based on previous papers very useful for SBI-Clerk Exams. Top-10 Very Important Questions for Banking Exams.<\/p>\n

Download Probability Questions <\/a><\/p>\n

105 SBI Clerk mocks for Rs. 199. Enroll here<\/a><\/p>\n

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Download SBI Clerk Previous Papers PDF<\/a><\/p>\n

SBI Clerk Free Mock Tests<\/a><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

Question 1:\u00a0<\/b>A bag A contains 4 green and 6 red balls. Another bag B contains 3 green and 4 red balls. If one
\nball is drawn from each bag, and the probability that both are green.<\/p>\n

a)\u00a013\/70<\/p>\n

b)\u00a01\/4<\/p>\n

c)\u00a06\/35<\/p>\n

d)\u00a08\/35<\/p>\n

e)\u00a0None of these<\/p>\n

Question 2:\u00a0<\/b>A bag contains 2 red, 3 green and 2 blue balls. 2 balls are to be drawn randomly. What is the probability that the balls drawn contain no blue ball ?<\/p>\n

a)\u00a05\/7<\/p>\n

b)\u00a010\/21<\/p>\n

c)\u00a02\/7<\/p>\n

d)\u00a011\/21<\/p>\n

e)\u00a0None of these<\/p>\n

Question 3:\u00a0<\/b>In how many different ways can the letters of the word “PRIDE” be arranged ?<\/p>\n

a)\u00a060<\/p>\n

b)\u00a0120<\/p>\n

c)\u00a015<\/p>\n

d)\u00a0360<\/p>\n

e)\u00a0None of these<\/p>\n

Question 4:\u00a0<\/b>There are 8 brown balls, 4 orange balls and 5 black balls in a bag. Five balls are chosen at random. What is the probability of their being 2 brown balls, 1 orange ball and 2 black balls ?<\/p>\n

a)\u00a0$\\frac{191}{1547}$<\/p>\n

b)\u00a0$\\frac{180}{1547}$<\/p>\n

c)\u00a0$\\frac{280}{1547}$<\/p>\n

d)\u00a0$\\frac{189}{1547}$<\/p>\n

e)\u00a0None of these<\/p>\n

Question 5:\u00a0<\/b>In a bag there are 4 white, 4 red and 2 green balls. Two balls are drawn at random. What is the probability that at least one ball is of green colour ?<\/p>\n

a)\u00a0$\\frac{4}{5}$<\/p>\n

b)\u00a0$\\frac{3}{5}$<\/p>\n

c)\u00a0$\\frac{1}{5}$<\/p>\n

d)\u00a0$\\frac{2}{5}$<\/p>\n

e)\u00a0None of these<\/p>\n

Download SBI Clerk Previous Papers PDF<\/a><\/p>\n

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Question 6:\u00a0<\/b>A bag contains 24 eggs out of which 8 are rotten. The remaining eggs are not rotten eggs. The two eggs are selected at random, What is the probability that one of the eggs is rotten?<\/p>\n

a)\u00a0$\\frac{11}{23}$<\/p>\n

b)\u00a0$\\frac{17}{23}$<\/p>\n

c)\u00a0$\\frac{13}{23}$<\/p>\n

d)\u00a0$\\frac{11}{17}$<\/p>\n

e)\u00a0$\\frac{11}{33}$<\/p>\n

Question 7:\u00a0<\/b>In a bag, there are 6 red balls and 9 green balls. Two balls are drawn at random, what is the probability that at least one of the balls drawn is red ?<\/p>\n

a)\u00a029\/35<\/p>\n

b)\u00a07\/15<\/p>\n

c)\u00a023\/35<\/p>\n

d)\u00a02\/5<\/p>\n

e)\u00a019\/35<\/p>\n

Question 8:\u00a0<\/b>A bag contains 4 red balls, 6 green balls and 5 blue balls. If three balls are picked at random, what is the probability that two of them are green and one of them is blue in colour ?<\/p>\n

a)\u00a0$\\frac{20}{91}$<\/p>\n

b)\u00a0$\\frac{10}{91}$<\/p>\n

c)\u00a0$\\frac{15}{91}$<\/p>\n

d)\u00a0$\\frac{5}{91}$<\/p>\n

e)\u00a0$\\frac{25}{91}$<\/p>\n

Question 9:\u00a0<\/b>A bag contains 16 eggs out of which 5 are rotten. The remaining eggs are in good condition. If two eggs are drawn randomly, what is the probability that exactly one of the eggs drawn is rotten ?<\/p>\n

a)\u00a0$\\frac{11}{24}$<\/p>\n

b)\u00a0$\\frac{13}{24}$<\/p>\n

c)\u00a0$\\frac{65}{12}$<\/p>\n

d)\u00a0$\\frac{17}{24}$<\/p>\n

e)\u00a0$\\frac{7}{12}$<\/p>\n

Question 10:\u00a0<\/b>A bag contains 3 white balls and 2 black balls. Another bag contains 2 white and 4 black balls. A bag and a ball are picked at random. What is the probability that the ball drawn is white ?<\/p>\n

a)\u00a0$\\frac{7}{11}$<\/p>\n

b)\u00a0$\\frac{7}{30}$<\/p>\n

c)\u00a0$\\frac{5}{11}$<\/p>\n

d)\u00a0$\\frac{7}{15}$<\/p>\n

e)\u00a0$\\frac{8}{15}$<\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Total balls in bag A = 4 + 6 = 10<\/p>\n

Probability that ball is green = $\\frac{4}{10}$<\/p>\n

Total balls in bag B = 3 + 4 = 7<\/p>\n

Probability that ball is green = $\\frac{3}{7}$<\/p>\n

=> Required probability = $\\frac{4}{10} \\times \\frac{3}{7}$<\/p>\n

= $\\frac{6}{35}$<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Total number of balls = 2 + 3 + 2 = 7<\/p>\n

Total number of outcomes = Drawing 2 balls out of 7<\/p>\n

= $C^7_2 = \\frac{7 \\times 6}{1 \\times 2} = 21$<\/p>\n

Favourable outcomes = Drawing 2 balls out of 5 (so that none is blue)<\/p>\n

=\u00a0$C^5_2 = \\frac{5 \\times 4}{1 \\times 2} = 10$<\/p>\n

=> Required probability = $\\frac{10}{21}$<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The word ‘PRIDE’ consists of 5 distinct letters<\/p>\n

=> Number of arrangements = $5!$<\/p>\n

= $5 \\times 4 \\times 3 \\times 2 \\times 1 = 120$<\/p>\n

4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Total number of balls in the bag = 8 + 4 + 5 = 17<\/p>\n

P(S) = Total possible outcomes<\/p>\n

= Selecting 5 balls at random out of 17<\/p>\n

=> $P(S) = C^{17}_5 = \\frac{17 \\times 16 \\times 15 \\times 14 \\times 13}{1 \\times 2 \\times 3 \\times 4 \\times 5}$<\/p>\n

= $6188$<\/p>\n

P(E) = Favorable outcomes<\/p>\n

= Selecting 2 brown, 1 orange and 2 black balls.<\/p>\n

=> $P(E) = C^8_2 \\times C^4_1 \\times C^5_2$<\/p>\n

= $\\frac{8 \\times 7}{1 \\times 2} \\times 4 \\times \\frac{5 \\times 4}{1 \\times 2}$<\/p>\n

= $28 \\times 4 \\times 10 = 1120$<\/p>\n

$\\therefore$ Required probability = $\\frac{P(E)}{P(S)}$<\/p>\n

= $\\frac{1120}{6188} = \\frac{280}{1547}$<\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

There are 4 white, 4 red and 2 green balls and two balls are drawn at random.<\/p>\n

Total possible outcomes = Selection of 2 balls out of 10 balls<\/p>\n

= $C^{10}_2 = \\frac{10 * 9}{1 * 2} = 45$<\/p>\n

Favourable outcomes = 1 green ball and 1 ball of other colour + 2 green balls<\/p>\n

= $C^2_1 \\times C^8_1 + C^2_2$<\/p>\n

= 2*8 + 2 = 18<\/p>\n

$\\therefore$ Required probability = $\\frac{18}{45} = \\frac{2}{5}$<\/p>\n

6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Number of rotten eggs = 8
\nNumber of non-rotten eggs = 16
\nRequired probability = $\\frac{^8C_1 . ^{16}C_1}{^{24}C_2} + \\frac{^8C_2}{^{24}C_2}$
\n= $\\frac{8 \\times 16 + 28}{276}$
\n= $\\frac{13}{23}$<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Probability that at least 1 ball is red = 1 – probability that none of them is red.
\nProbability that none if the two balls is red = (9\/15)(8\/14)
\nProbability that at least 1 ball is red = 1 – probability that none of them is red. = 1- [(9\/15)(8\/14)] = (210-72)\/210
\n= 138\/210
\n=23\/35
\nOption C is the correct answer.<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Probability of drawing blue ball in first attempt = 5\/15<\/p>\n

Probability of drawing two green balls in the next two attempts = (6\/14)(5\/13)
\nProbability of drawing 2 green and 1 blue ball = (5\/15)(6\/14)(5\/13) = 150\/2730<\/p>\n

Probability of drawing green ball in first attempt = 6\/15
\nProbability of drawing blue ball in the next attempt = (5\/14)
\nProbability of drawing green ball in the next attempt = (5\/13)
\nProbability of drawing 2 red and 1 green ball = (6\/15)(5\/14)(5\/13) = 150\/2730<\/p>\n

Probability of drawing two green balls in first two attempts = (6\/15)(5\/14)
\nProbability of drawing blue ball in the next attempt =(5\/13)
\nProbability of drawing 2 red and 1 green ball = (6\/15)(5\/14)(5\/13) = 150\/2730<\/p>\n

Probability of drawing 2 red balls and 1 green ball= 150\/2730 + 150\/2730 + 150\/2730 = 3(150\/2730) = 150\/910 = 15\/91<\/span><\/span>
\nOption C is the correct answer<\/span><\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Out of the 16 eggs, 5 eggs are rotten and 11 eggs are in good condition.<\/p>\n

According to the question, out of the two eggs drawn one is rotten and the other is in good condition.<\/p>\n

Hence, required probability = $ \\frac{^5C_{1} * ^{11}C_{1}}{^{16}C_{2}} = \\frac{5*11}{16*15\/2} = \\frac{11}{24}$<\/p>\n

Hence, option A is the right choice.<\/p>\n

10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Probability of choosing bag 1 = (1\/2)
\nProbability of choosing bag 2 = (1\/2)
\nProbability of choosing white ball from bag 1 = 3\/5
\nProbability of choosing white ball from bag 2 = 2\/6
\nProbability of choosing bag 1 and white ball from it = (1\/2)(3\/5) = 3\/10
\nProbability of choosing bag 2 and white ball from it = (1\/2)(2\/6) = 2\/12
\nProbability of choosing a bag and drawing a white ball = (3\/10) + (2\/12) = (28\/60) = (7\/15)
\nOption D is the correct answer.<\/span><\/span><\/p>\n

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We hope this Probability Questions for SBI Clerk Exam is so helpful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Probability Questions for SBI-Clerk PDF: Download SBI-Clerk Probability Questions based on previous papers very useful for SBI-Clerk Exams. Top-10 Very Important Questions for Banking Exams. Download SBI Clerk Previous Papers PDF SBI Clerk Free Mock Tests Question 1:\u00a0A bag A contains 4 green and 6 red balls. Another bag B contains 3 green and 4 […]<\/p>\n","protected":false},"author":21,"featured_media":40334,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3165,3167,125,232,3525,1],"tags":[3579,49],"class_list":{"0":"post-40325","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-banking-en","8":"category-downloads-en","9":"category-featured","10":"category-sbiclerk","11":"category-sbi-clerk","12":"category-uncategorized","13":"tag-probability-questions","14":"tag-sbi-clerk"},"better_featured_image":{"id":40334,"alt_text":"Probability Questions for sbi clerk","caption":"Probability Questions for sbi clerk","description":"Probability Questions for sbi 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