{"id":40309,"date":"2020-01-30T18:40:16","date_gmt":"2020-01-30T13:10:16","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=40309"},"modified":"2020-01-30T18:40:16","modified_gmt":"2020-01-30T13:10:16","slug":"average-questions-for-ssc-chsl-set-2-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/average-questions-for-ssc-chsl-set-2-pdf\/","title":{"rendered":"Average Questions for SSC-CHSL Set-2 PDF"},"content":{"rendered":"

Average Questions for SSC-CHSL Set-2 PDF<\/strong><\/span><\/h1>\n

Download SSC CHSL Average\u00a0 Questions with answers Set-2\u00a0 PDF based on previous papers very useful for SSC CHSL Exams. Top-15 Very Important Questions for SSC Exam<\/p>\n

Download Average Questions Set-2 PDF<\/a><\/p>\n

Get 200 SSC mocks for just Rs. 249. Enroll here<\/a><\/p>\n

Take a free mock test for SSC CHSL<\/a><\/p>\n

Download SSC CHSL Previous Papers<\/a><\/p>\n

More SSC CHSL Important Questions and Answers PDF<\/a><\/p>\n

Question 1:\u00a0<\/b>The average of odd numbers up to 100 is<\/p>\n

a)\u00a050.5<\/p>\n

b)\u00a050<\/p>\n

c)\u00a049.5<\/p>\n

d)\u00a049<\/p>\n

Instructions<\/b><\/p>\n

Directions: The pie chart given below show the spending of a family on various heads during a month. Study the graph and answer the questions.
\n\"\"<\/p>\n

Question 2:\u00a0<\/b>If the total income of the family is Rs. 25,000, then the amount spent on Rent and Food together is<\/p>\n

a)\u00a0Rs. 17,250<\/p>\n

b)\u00a0Rs. 14,750<\/p>\n

c)\u00a0Rs. 11,250<\/p>\n

d)\u00a0Rs. 8,500<\/p>\n

Question 3:\u00a0<\/b>The average of three consecutive odd numbers is 12 more than one-third of the first of these numbers. What is the last of the three numbers?<\/p>\n

a)\u00a015<\/p>\n

b)\u00a017<\/p>\n

c)\u00a019<\/p>\n

d)\u00a0Data inadequate<\/p>\n

Instructions<\/b><\/p>\n

Directions: Population of the five adjacent areas of a town, in the year of 2020, are represented in the following Pie-chart. The ratio of the numbers of males to that of females in these areas are stated in the table below. The total of the population in all the five areas is 72 lakh. Study the Pie-chart and the table and then answer the questions.<\/p>\n

<\/figure>\n

The ratio of number of males(M) to females(F)
\n\"\"
\nQuestion 4:\u00a0<\/b>The average of female population in all the five areas is lower than the female population in each of the areas<\/p>\n

a)\u00a0S1 and S2<\/p>\n

b)\u00a0S2 and S5<\/p>\n

c)\u00a0S2 and S4<\/p>\n

d)\u00a0S4 and S5<\/p>\n

Question 5:\u00a0<\/b>The average of the first nine integral multiples of 3 is<\/p>\n

a)\u00a012<\/p>\n

b)\u00a015<\/p>\n

c)\u00a018<\/p>\n

d)\u00a021<\/p>\n

SSC CHSL PREVIOUS PAPERS<\/a><\/p>\n\n

SSC CHSL Study Material<\/a> (FREE Tests)<\/p>\n

Question 6:\u00a0<\/b>The average of 6 consecutive natural numbers is K. If the next two natural numbers are also included, how much more than K will the average of these 8 numbers be?<\/p>\n

a)\u00a03<\/p>\n

b)\u00a01<\/p>\n

c)\u00a02<\/p>\n

d)\u00a01.8<\/p>\n

Question 7:\u00a0<\/b>What is the Arithmetic mean of the first \u2018n\u2019 natural numbers ?<\/p>\n

a)\u00a0$\\frac{n+1}{3}$<\/p>\n

b)\u00a0$\\frac{n+1}{2}$<\/p>\n

c)\u00a0$\\frac{n+1}{4}$<\/p>\n

d)\u00a02(n + 1)<\/p>\n

Question 8:\u00a0<\/b>Out of four numbers the average of the first three is 16 and that of the last three is 15. If the last number is 20 then the first number is<\/p>\n

a)\u00a023<\/p>\n

b)\u00a025<\/p>\n

c)\u00a028<\/p>\n

d)\u00a021<\/p>\n

Question 9:\u00a0<\/b>The average of 7, 11, 15, x, 14, 21, 25 is 15, then the value of x is<\/p>\n

a)\u00a013.3<\/p>\n

b)\u00a012<\/p>\n

c)\u00a03<\/p>\n

d)\u00a014.5<\/p>\n

Question 10:\u00a0<\/b>The average marks obtained by a student in 6 subjects is 88. On subsequent verification it was found that the marks obtained by him in a subject was wrongly copied as 86 instead of 68. The correct average of the marks obtained by him is<\/p>\n

a)\u00a087<\/p>\n

b)\u00a085<\/p>\n

c)\u00a084<\/p>\n

d)\u00a086<\/p>\n

Instructions<\/b><\/p>\n

Given here is a multiple bar diagram of the scores of four players in two innings. Study the diagram and answer the questions:<\/p>\n

<\/p>\n

 <\/p>\n

Question 11:\u00a0<\/b>The average runs in two innings of the player who has scored minimum in the second innings are :<\/p>\n

a)\u00a030<\/p>\n

b)\u00a060<\/p>\n

c)\u00a050<\/p>\n

d)\u00a040<\/p>\n

Question 12:\u00a0<\/b>The average marks obtained by 40 students of a class is 86. If the 5 highest marks are removed, the average reduces by one mark. The average marks of the top 5 students is<\/p>\n

a)\u00a092<\/p>\n

b)\u00a096<\/p>\n

c)\u00a093<\/p>\n

d)\u00a097<\/p>\n

Question 13:\u00a0<\/b>The average salary, per head, of all the workers of an institution is 60. The average salary of 12 officers is = 400; the average salary, per head, of the rest is 56. The total number of workers in the institution is<\/p>\n

a)\u00a01030<\/p>\n

b)\u00a01035<\/p>\n

c)\u00a01020<\/p>\n

d)\u00a01032<\/p>\n

Question 14:\u00a0<\/b>The average of 50 numbers is 38. If two numbers, namely 45 and 55 are discarded, the average of the remaining numbers is<\/p>\n

a)\u00a037.5<\/p>\n

b)\u00a037.9<\/p>\n

c)\u00a036.5<\/p>\n

d)\u00a037.0<\/p>\n

Question 15:\u00a0<\/b>The average of 20 numbers is 15 and the average of first five is 12. The average of the rest is<\/p>\n

a)\u00a016<\/p>\n

b)\u00a015<\/p>\n

c)\u00a014<\/p>\n

d)\u00a013<\/p>\n

SSC CHSL FREE MOCK TEST<\/a><\/p>\n

FREE SSC STUDY MATERIAL<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Require sum of 1+3+5+7+9….99
\nApplying formula for summation of n digits with a as first digit and d is the difference
\nsum =\u00a0$\\frac{n}{2} (2a + (n-1) d)$
\nor this formula can be reduced to\u00a0$\\frac{n}{2}\u00a0\\frac{a + l}{2} $hence for calculating avg. it will be
\n$\\frac{a + l}{2}$ (where $l$ is last term)
\nso\u00a0$\\frac{1\u00a0+ 99}{2}$ = 50<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Total share percentage on food and rent = 45+14 = 59%
\nHence price will be = $25000 \\times {59}{100} = 14750$<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let’s say numbers are $a, a+2, a+4$
\nSo avg. will be $\\frac{(a+a+2+a+4)}{3} = \\frac{a}{3} +12$
\nOr a = 15
\nSo numbers will be 15, 17, 19<\/p>\n

4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

As we know average of numbers which are in A.P. is = $\\frac{a+l}{2}$ (where a is first term and l is last term)
\nHere a=3
\nand l= 27
\nHence average will be 15<\/p>\n

6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the 6 consecutive numbers be a-3,a-2,a-1,a,a+1,a+2<\/p>\n

average = $\\frac{SumofElements}{NumberofElements}$<\/p>\n

It is given that average of 6 consecutive numbers be k and hence<\/p>\n

k = $\\frac{a-3+a-2+a-1+a+a+1+a+2}{6}$ = $\\frac{6a-3}{6}$ = a – $\\frac{1}{2}$<\/p>\n

now next two numbers (a+3, a+4) are also added<\/p>\n

Sum of 8 numbers = a-3+a-2+a-1+a+a+1+a+2+a+3+a+4 = 8a +4 <\/span><\/p>\n

average of 8 numbers = $\\frac{8a+4}{8}$ = a + $\\frac{1}{2}$ = k + 1<\/span><\/span><\/span><\/p>\n

so average of 8 numbers is more than average of 6 numbers by = k+1 – K = 1<\/span><\/span><\/span><\/p>\n

7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Arithmetic Mean = $\\frac{Sumof Elements}{NumberofElements}$<\/p>\n

Sum of first n natural numbers = $\\frac{n(n+1)}{2}$<\/p>\n

Arithmetic Mean of first n natural numbers = $\\frac{n(n+1)}{2\\times n}$ = $\\frac{n+1}{2}$<\/p>\n

8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

let the four numbers be a,b,c,d<\/p>\n

Using formula average = $\\frac{SumofElements}{NumberofElements}$<\/p>\n

Now, the average of first 3 numbers = 16<\/p>\n

=> Sum of first 3 numbers=a+b+c = 16 \u00d7 3 = 48………. (1)<\/p>\n

Also, average of last three numbers = 15<\/p>\n

=> Sum of last three numbers = b+c+d = 15 \u00d7 3 = 45……(2)<\/p>\n

Subtracting equation (2) from (1)<\/p>\n

=> a – d = 3<\/p>\n

Since, d = 20<\/p>\n

=> a – 20 = 3<\/p>\n

=> a = 23<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

we know that average =$\\frac {sum of elements}{numberof elements} $<\/p>\n

Number of elements =7<\/p>\n

Sum of elements = 7+11+15+14+21+25+x = 93+x<\/p>\n

=> Average = $\\frac {93+x}{7} $<\/p>\n

=> 15 = $\\frac {93+x}{7} $<\/p>\n

=> x = 12<\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Average = $\\frac{Sum of Elements}{Number of Elements}$<\/p>\n

Number of subjects = 6<\/p>\n

wrong average = 88<\/p>\n

sum of marks calculated wrongly in all subjects = 88 x 6 = 528<\/p>\n

Correct Marks = 528 – 86 + 68 = 510<\/p>\n

Correct Average of marks = $\\frac{510}{6}$ = 85<\/p>\n

11)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

In 2nd inning Cheteswar Pujara has scored minimum ,<\/p>\n

runs in 1st innings = 70<\/p>\n

runs in 2nd innings = 10<\/p>\n

Average = $\\frac{SumofElements}{NumberofElements}$<\/p>\n

average runs = $\\frac{70+10}{2}$ = 40<\/p>\n

12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Average = $\\frac{SumofElements}{NumberofElements}$<\/p>\n

Given that average marks of 40 students in a class = 86<\/p>\n

Hence total marks of 40 students = 40 x 86 = 3440<\/p>\n

Now when the top 5 highest marks are removed than the average reduces by 1 and hence it become = 86-1 = 85<\/p>\n

and number of students now becomes = 40-5 = 35<\/p>\n

So total of remaining students = 35 x 85 = 2975<\/p>\n

So total marks of top 5 students = 3440 – 2975 = 465<\/p>\n

average of 5 students = $\\frac{465}{5}$ = 93<\/p>\n

13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let the total number of members in the institution be z<\/p>\n

average = $\\frac{SumofElements}{NumberofElements}$<\/p>\n

Average salary of institution = Rs 60<\/p>\n

total salary of Institution =Rs 60z<\/p>\n

Given that out of z persons , there are 12 officers and there average salary is = Rs 400<\/p>\n

and so total salary of 12 officers = 12 x 400 =Rs 4800<\/p>\n

So total salary of other (z-12) members =Rs ( 60z – 4800 )…………..(1)<\/p>\n

It is given that average salary of (z-12) persons = Rs 56<\/p>\n

and hence from here the total salary of (z-12) people = Rs 56(z-12)……….(2)<\/p>\n

Equation 1 and 2 are equal<\/p>\n

60z – 4800 = 56z – 672<\/p>\n

4z = 4128<\/p>\n

z = 1032<\/p>\n

14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Average = $\\frac{Sum of Elements}{Number of Elements}$<\/p>\n

Given that Initially Number of Elements = 50<\/p>\n

Initial Average = 38<\/p>\n

Sum of Elements = 50 x 38 = 1900<\/p>\n

Now as two numbers are discarded, hence number of elements left = 48<\/p>\n

Sum of elements after discarding numbers = 1900 – 55 – 45 = 1800<\/p>\n

Hence New Average = $\\frac{1800}{48}$ = 37.5<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Given that average of 20 numbers = 15<\/p>\n

using average = $\\frac{Sum}{Numberof Elements}$<\/p>\n

Sum of all numbers = 20 x 15 = 300<\/p>\n

Average of first five numbers = 12<\/p>\n

So sum of first five numbers = 12×5 = 60<\/p>\n

Sum of numbers left = 300 – 60 = 240<\/p>\n

Number of numbers left = 20 – 5 = 15<\/p>\n

So average of left numbers = $\\frac{240}{15}$ = 16<\/p>\n

DOWNLOAD APP TO ACESSES DIRECTLY ON MOBILE<\/a><\/p>\n

SSC CHSL Important Q&A PDF<\/a><\/p>\n

We hope this Average Questions for SSC CHSL Exam preparation is so helpful to you.<\/p>\n","protected":false},"excerpt":{"rendered":"

Average Questions for SSC-CHSL Set-2 PDF Download SSC CHSL Average\u00a0 Questions with answers Set-2\u00a0 PDF based on previous papers very useful for SSC CHSL Exams. Top-15 Very Important Questions for SSC Exam Take a free mock test for SSC CHSL Download SSC CHSL Previous Papers More SSC CHSL Important Questions and Answers PDF Question 1:\u00a0The […]<\/p>\n","protected":false},"author":49,"featured_media":40316,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3167,125,9,504,378,1493,1459,1611,1741,1441,1],"tags":[3573,358],"class_list":{"0":"post-40309","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads-en","8":"category-featured","9":"category-ssc","10":"category-ssc-cgl","11":"category-ssc-chsl","12":"category-ssc-cpo","13":"category-ssc-gd","14":"category-ssc-je","15":"category-ssc-mts","16":"category-stenographer","17":"category-uncategorized","18":"tag-average-questions","19":"tag-ssc-chsl"},"better_featured_image":{"id":40316,"alt_text":"Average Questions for SSC CHSL Set-2 PDF","caption":"Average Questions for SSC CHSL Set-2 PDF","description":"Average Questions for SSC CHSL Set-2 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