{"id":40156,"date":"2020-01-27T15:12:54","date_gmt":"2020-01-27T09:42:54","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=40156"},"modified":"2020-01-27T15:12:54","modified_gmt":"2020-01-27T09:42:54","slug":"quadratic-equations-questions-for-sbi-clerk-set-2","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/quadratic-equations-questions-for-sbi-clerk-set-2\/","title":{"rendered":"Quadratic Equations Questions for SBI-Clerk Set-2"},"content":{"rendered":"

Quadratic Equations Questions for SBI Clerk Set-2<\/strong><\/span><\/h2>\n

Download SBI Clerk Quadratic Equations\u00a0 Questions & Answers Set-2 PDF for SBI Clerk Prelims and Mains exam. Very Important SBI Clerk Quadratic Equations Questions with solutions.<\/p>\n

Download Quadratic Equations Questions Set-2<\/a><\/p>\n

105 SBI Clerk mocks for Rs. 199. Enroll here<\/a><\/p>\n

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Download SBI Clerk Previous Papers PDF<\/a><\/p>\n

SBI Clerk Free Mock Tests<\/a><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

Instructions<\/b><\/p>\n

In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a & b
\nMark answer if
\na) a<b
\n<\/b<\/p>\n

<b
\n<\/b
\n<b
\nb) $a\\leq b$
\nc) relationship between a & b cannot be established
\nd) a>b
\ne) $a\\geq b$<\/p>\n

Question 1:\u00a0<\/b>I.$a^{2}+5a+6=0$
\nII.$b^{2}+7b+12=0$<\/p>\n

a)\u00a0$a<b$<\/b><\/p>\n

b)\u00a0$a \\leq b$<\/p>\n

c)\u00a0Relationship between $a$ & $b$ cannot be established<\/p>\n

d)\u00a0$a>b$<\/p>\n

e)\u00a0$a \\geq b$<\/p>\n

Instructions<\/b><\/p>\n

For the two given equations I and II—-<\/p>\n

Question 2:\u00a0<\/b>I. $6p^{2}+5p+1=0$
\nII. $20q^{2}+9q=-1$<\/p>\n

a)\u00a0Give answer (A) if p is greater than q.<\/p>\n

b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n

c)\u00a0Give answer (C) if p is equal to q.<\/p>\n

d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n

e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n

Instructions<\/b><\/p>\n

In the following questions two equations numbered I and
\nII are given. You have to solve both the equations and
\na: if x > y
\nb: if x \u2265 y
\nc: if x < y
\nd: if x \u2264 y
\ne: if x = y or the relationship cannot be established.<\/p>\n

Question 3:\u00a0<\/b>I. $x^{2}=49$
\nII. $y^{2}-4y-21=0$<\/p>\n

a)\u00a0if x > y<\/p>\n

b)\u00a0if x \u2265 y<\/p>\n

c)\u00a0if x < y<\/p>\n

d)\u00a0if x \u2264 y<\/p>\n

e)\u00a0if x = y or the relationship cannot be established.<\/p>\n

Instructions<\/b><\/p>\n

In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. Give answer<\/p>\n

Question 4:\u00a0<\/b>I. $4x^2 + 15x + 14 = 0$
\nII. $6y^2 + 10y = 0$<\/p>\n

a)\u00a0If x < y<\/p>\n

b)\u00a0If x > y<\/p>\n

c)\u00a0If x \u2264 y<\/p>\n

d)\u00a0If x \u2265 y<\/p>\n

e)\u00a0If relationship between x and y cannot be determined<\/p>\n

Instructions<\/b><\/p>\n

<p “=””>In these questions two equations numbered I and II are given. You have to solve both the equations and give answer<\/p>\n

a: if x < y
\nb: if x > y
\nc: if x = y
\nd: if x = y
\ne: if x= y or relationship between x and y cannot be established<\/p>\n

Question 5:\u00a0<\/b>I. $3x^{2} + 23x+ 44 = 0$
\nII. $3y^{2} + 20y + 33 = 0$<\/p>\n

a)\u00a0if x < y<\/p>\n

b)\u00a0if x > y<\/p>\n

c)\u00a0if x => y<\/p>\n

d)\u00a0if x <= y<\/p>\n

e)\u00a0if x= y or relationship between x and y cannot be established<\/p>\n

Download SBI Clerk Previous Papers PDF<\/a><\/p>\n

SBI Clerk free mock test<\/a><\/p>\n

Instructions<\/b><\/p>\n

In the following questions three equations numbered I, II and III are given.
\nYou have to solve all the equations either together or separately, or two together and one
\nseparately, or by any other method and Give answer
\na: x< y=z
\nb: x \u2264 y < z
\nc: x < y > z
\nd: x = y > z
\ne: x = y = z or if none of the above relationship is established<\/p>\n

Question 6:\u00a0<\/b>I. 8x+ 7y = 135
\nII. 5x + 6y = 99
\nIII. 9y + 8z = 121<\/p>\n

a)\u00a0x< y=z<\/p>\n

b)\u00a0x \u2264 y < z<\/p>\n

c)\u00a0x < y > z<\/p>\n

d)\u00a0x = y > z<\/p>\n

e)\u00a0x = y = z or if none of the above relationship is established<\/p>\n

Instructions<\/b><\/p>\n

In the following questions two equations numbered I and II are given. You have to solve both the equations and
\nGive answer a: if x >y
\nGive answer b: if x \u2265 y
\nGive answer c: if x < y
\nGive answer d: if x \u2264 y
\nGive answer e: if x = y or the relationship between x and y cannot be established.<\/p>\n

Question 7:\u00a0<\/b>I.$3x^{2}-13x-10=0$
\nII.$3y^{2}+10y-8=0$<\/p>\n

a)\u00a0if x >y<\/p>\n

b)\u00a0if x \u2265 y<\/p>\n

c)\u00a0if x < y<\/p>\n

d)\u00a0if x \u2264 y<\/p>\n

e)\u00a0if x = y or the relationship between x and y cannot be established.<\/p>\n

Instructions<\/b><\/p>\n

In the following questions two equations numbered I and II are given. You have to solve both the equations and
\nGive answer a: if x > y
\nGive answer b: if x \u2265 y
\nGive answer c: if x < y
\nGive answer d: if x \u2264 y
\nGive answer e: if x = y or the relationship cannot be established.<\/p>\n

Question 8:\u00a0<\/b>I.\u00a0 $2x^{2}+21x+10=0$
\nII.\u00a0$3y^{2}+13y+14=0$<\/p>\n

a)\u00a0if x > y<\/p>\n

b)\u00a0if x \u2265 y<\/p>\n

c)\u00a0if x < y<\/p>\n

d)\u00a0if x \u2264 y<\/p>\n

e)\u00a0if x = y or the relationship cannot be established.<\/p>\n

Instructions<\/b><\/p>\n

In the given questions, two quantities are given, one as Quantity I and another as Quantity II. You have to determine relationship between two quantities and choose the appropriate option.<\/p>\n

a: If quantity I \u2265 quantity II
\nb: If quantity I > quantity II
\nc: If quantity I < quantity II
\nd: If quantity I = quantity II or the relationship cannot be established from the information that is given
\ne: If quantity quantity II<\/p>\n

Question 9:\u00a0<\/b>Three equal circles are drawn on a triangle ABC, with points A, B and C as the centres. Radius of each of the
\ncircle is equal to half of the side of the triangle ABC. (Figure not to the scale)Area of shaded region 1 = $128\\frac{1}{3}cm^{2}$
\nQuantity :<\/strong>
\nI. The area of the shaded region 2 ( in cm^{2} )
\nII. 30 cm^{2}<\/p>\n

a)\u00a0If quantity I \u2265 quantity II<\/p>\n

b)\u00a0If quantity I > quantity II<\/p>\n

c)\u00a0If quantity I < quantity II<\/p>\n

d)\u00a0If quantity I = quantity II or the relationship cannot be established from the information that is given<\/p>\n

e)\u00a0If quantity quantity II<\/p>\n

Question 10:\u00a0<\/b>There are three positive numbers- a, b and c. The average of a and b is less than the average of b and c by 1.
\nQuantity :
\nI. Value of c.
\nII. Value of a<\/p>\n

a)\u00a0If quantity I \u2265 quantity II<\/p>\n

b)\u00a0If quantity I > quantity II<\/p>\n

c)\u00a0If quantity I < quantity II<\/p>\n

d)\u00a0If quantity I = quantity II or the relationship cannot be established from the information that is given<\/p>\n

e)\u00a0If quantity quantity II<\/p>\n

SBI Clerk free mock test<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

$a^{2}+5a+6=0$
\ni.e (a+2)(a+3)=0
\ni.e a=-2, a=-3<\/p>\n

.$b^{2}+7b+12=0$
\ni.e (b+4)(b+3)=0
\ni.e b=-4, b=-3<\/p>\n

Hence, we can deduce that $a \\geq b$.
\nTherefore, option E is correct.<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$6p^2+5p+1 = 0$
\n$(2p+1)(3p+1) = 0$
\n$p = -\\frac{1}{2}, -\\frac{1}{3}$<\/p>\n

$20q^2+9q+1 = 0$
\n$(4q+1)(5q+1) = 0$
\n$q = -\\frac{1}{4}, -\\frac{1}{5}$<\/p>\n

$p < q$<\/p>\n

3)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

$x^2 = 49$
\n$x = -7, 7$<\/p>\n

$y^2-4y-21 = 0$
\n$(y-7)(y+3) = 0$
\n$y = -3, 7$<\/p>\n

Hence, pairs of (x,y) are (-7,-3), (-7,7), (7,-3) and (7,7). Hence, in some x is less than y and in some x is greater than y. Thus no relation can be established.<\/p>\n

4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

I : 4$x^{2}$ + 15x + 14 = 0<\/p>\n

=> 4$x^{2}$ + 8x + 7x + 14 = 0<\/p>\n

=> 4x ( x + 2) + 7 ( x + 2) = 0<\/p>\n

=> (4x + 7) (x + 2) = 0<\/p>\n

=> x = -7\/4 , -2<\/p>\n

II : 6$y^{2}$ + 10y = 0<\/p>\n

=> y (6y + 10) = 0<\/p>\n

=> y = 0 , -5\/3<\/p>\n

Since, 0 > -7\/4 , -2 & -5\/3 > -7\/4 , -2<\/p>\n

=> y > x<\/strong><\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$3x^{2} + 23x + 44 = 0$.
\n$x=\\frac{-23\\pm\\sqrt{23^{2}-4\\times44\\times3}}{2\\times3}$
\n$x=\\frac{-23\\pm1}{6}$.
\n$x=\\frac{-11}{3},-4$.
\n$3y^{2} + 20y + 33 =0$.
\n<\/span>$y=\\frac{-20\\pm\\sqrt{20^{2}-4\\times33\\times3}}{2\\times3}$.
\n$y=\\frac{-20\\pm2}{6}$.
\n$y=-3,\\frac{(-11)}{3}$.
\nClearly,
\nx <= y
\nHence, Option D is correct.<\/p>\n

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6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Applying the operation\u00a0: Eqn(II) $\\times 8$ – Eqn(I) $\\times 5$<\/p>\n

=> $(40x – 40x) + (48y – 35y) = (792 – 675)$<\/p>\n

=> $13y = 117$<\/p>\n

=> $y = \\frac{117}{13} = 9$<\/p>\n

Putting in Eqn (I), we get\u00a0:<\/p>\n

=> $8x + 63 = 135$<\/p>\n

=> $8x = 135 – 63 = 72$<\/p>\n

=> $x = \\frac{72}{8} = 9$<\/p>\n

From Eqn(III)<\/p>\n

=> $9 \\times 9 + 8z = 121$<\/p>\n

=> $8z = 121 – 81 = 40$<\/p>\n

=> $z = \\frac{40}{8} = 5$<\/p>\n

$\\therefore x = y > z$<\/p>\n

7)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

I.$3x^{2} – 13x – 10 = 0$<\/p>\n

=> $3x^2 – 15x + 2x – 10 = 0$<\/p>\n

=> $3x (x – 5) + 2 (x – 5) = 0$<\/p>\n

=> $(x – 5) (3x + 2) = 0$<\/p>\n

=> $x = 5 , \\frac{-2}{3}$<\/p>\n

II.$3y^{2} + 10y – 8 = 0$<\/p>\n

=> $3y^2 + 12y – 2y – 8 = 0$<\/p>\n

=> $3y (y + 4) – 2 (y + 4) = 0$<\/p>\n

=> $(y + 4) (3y – 2) = 0$<\/p>\n

=> $y = -4 , \\frac{2}{3}$<\/p>\n

$\\therefore$ No relation can be established.<\/p>\n

8)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

I.$2x^{2} + 21x + 10 = 0$<\/p>\n

=> $2x^2 + x + 20x + 10 = 0$<\/p>\n

=> $x (2x + 1) + 10 (2x + 1) = 0$<\/p>\n

=> $(x + 10) (2x + 1) = 0$<\/p>\n

=> $x = -10 , \\frac{-1}{2}$<\/p>\n

II.$3y^{2} + 13y + 14 = 0$<\/p>\n

=> $3y^2 + 6y + 7y + 14 = 0$<\/p>\n

=> $3y (y + 2) + 7 (y + 2) = 0$<\/p>\n

=> $(y + 2) (3y + 7) = 0$<\/p>\n

=> $y = -2 , \\frac{-7}{3}$<\/p>\n

$\\therefore$\u00a0No relation can be established.<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Average of a and b is less than the average of b and c by 1<\/p>\n

=> $\\frac{b + c}{2} – \\frac{a + b}{2} = 1$<\/p>\n

=> $(b + c) – (a + b) = 2$<\/p>\n

=> $c – a = 2$<\/p>\n

$\\because$ Difference between c and a is positive.<\/p>\n

=> $c > a$<\/p>\n

$\\therefore$ Quantity I > Quantity II<\/p>\n

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We hope this Quadratic Equations Questions & Answers set-2 PDF of SBI Clerk is very Useful for preparation of SBI Clerk Exams.<\/p>\n","protected":false},"excerpt":{"rendered":"

Quadratic Equations Questions for SBI Clerk Set-2 Download SBI Clerk Quadratic Equations\u00a0 Questions & Answers Set-2 PDF for SBI Clerk Prelims and Mains exam. Very Important SBI Clerk Quadratic Equations Questions with solutions. Download SBI Clerk Previous Papers PDF SBI Clerk Free Mock Tests Instructions In each of these question two equations I & II […]<\/p>\n","protected":false},"author":42,"featured_media":40166,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3165,3167,125,232],"tags":[3517,49],"class_list":{"0":"post-40156","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-banking-en","8":"category-downloads-en","9":"category-featured","10":"category-sbiclerk","11":"tag-quadratic-equations-questions-for-sbi-clerk","12":"tag-sbi-clerk"},"better_featured_image":{"id":40166,"alt_text":"Quadratic Equations Questions for SBI Clerk Set-2","caption":"Quadratic Equations Questions for SBI Clerk Set-2\n","description":"Quadratic Equations Questions for SBI Clerk 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