{"id":39634,"date":"2019-12-20T16:43:52","date_gmt":"2019-12-20T11:13:52","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=39634"},"modified":"2019-12-20T16:43:52","modified_gmt":"2019-12-20T11:13:52","slug":"problems-on-ages-for-tissnet-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/problems-on-ages-for-tissnet-pdf\/","title":{"rendered":"Problems on Ages for TISSNET PDF"},"content":{"rendered":"

Problems on Ages for TISSNET PDF<\/strong><\/span><\/h1>\n

Download important TISSNET Ages Questions PDF based on previously asked questions in TISSNET and other MBA exams. Practice Ages Questions and answers for TISSNET and other exams.<\/p>\n

Download Problems on Ages for TISSNET PDF<\/a><\/p>\n

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Download TISSNET Previous Year Papers<\/a><\/p>\n

Question 1:\u00a0<\/b>Ten years ago, the ages of the members of a joint family of eight people added up to 231 years. Three years later, one member died at the age of 60 years and a child was born during the same year. After another three years, one more member died, again at 60, and a child was born during the same year. The current average age of this eight-member joint family is nearest to[CAT 2007]<\/p>\n

a)\u00a023 years<\/p>\n

b)\u00a022 years<\/p>\n

c)\u00a021 years<\/p>\n

d)\u00a025 years<\/p>\n

e)\u00a024 years<\/p>\n

Question 2:\u00a0<\/b>In a B-School there are three levels of faculty positions i.e. Professor, Associate Professor and Assistant Professor. It is found that the sum of the ages of all faculty present is 2160, their average age is 36; the average age of the Professor and Associate Professor is 39; of the Associate Professor and Assistant Professor is $32\\frac{8}{11}$; of the Professor and Assistant Professor is $36\\frac{2}{3}$; Had each professor been 1 year older, each Associate Professor 6 years older, and each Assistant Professor 7 years older, then their average age would increase by 5 years. What will be the number of faculty at each level and their average ages?<\/p>\n

a)\u00a0(16, 24, 20 : 45, 35, 30 years)<\/p>\n

b)\u00a0(18, 24, 20 : 42, 38, 30 years)<\/p>\n

c)\u00a0(16, 20, 24 : 50, 30, 30 years)<\/p>\n

d)\u00a0None of these<\/p>\n

Question 3:\u00a0<\/b>Mr. and Mrs. Gupta have three children – Pratik, Writtik and Kajol, all of whom were born in different cities. Pratik is 2 years elder to Writtik. Mr. Gupta was 30 years of age when Kajol was born in Hyderabad, while Mrs. Gupta was 28 years of age when Writtik was born in Bangalore. If Kajol was 5 years of age when Pratik was born in Mumbai, then what were the ages of Mr. and Mrs. Gupta respectively at the time of Pratik\u2019s birth?<\/p>\n

a)\u00a035 years, 26 years<\/p>\n

b)\u00a030 years, 21 years<\/p>\n

c)\u00a037 years, 28 years<\/p>\n

d)\u00a0None of the above<\/p>\n

Question 4:\u00a0<\/b>Ravindra and Rekha got married 10 years ago, their ages were in the ratio of 5 : 4. Today Ravindra\u2019s age is one sixth more than Rekha\u2019s age. After marriage, they had 6 children including a triplet and twins. The age of the triplets, twins and the sixth child is in the ratio of 3 : 2 : 1. What is the largest possible value of the present total age of the family?<\/p>\n

a)\u00a079<\/p>\n

b)\u00a093<\/p>\n

c)\u00a0101<\/p>\n

d)\u00a0107<\/p>\n

Question 5:\u00a0<\/b>Hari\u2019s family consisted of his younger brother (Chari), younger sister (Gouri), and their father and mother. When Chari was born, the sum of the ages of Hari, his father and mother was 70 years. The sum of the ages of four family members, at the time of Gouri\u2019s birth, was twice the sum of ages of Hari\u2019s father and mother at the time of Hari\u2019s birth. If Chari is 4 years older than Gouri, then find the difference in age between Hari and Chari.<\/p>\n

a)\u00a05 years<\/p>\n

b)\u00a06 years<\/p>\n

c)\u00a07 years<\/p>\n

d)\u00a08 years<\/p>\n

e)\u00a09 years<\/p>\n

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Question 6:\u00a0<\/b>In an apartment complex, the number of people aged 51 years and above is 30 and there are at most 39 people whose ages are below 51 years. The average age of all the people in the apartment complex is 38 years. What is the largest possible average age, in years, of the people whose ages are below 51 years?<\/p>\n

a)\u00a027<\/p>\n

b)\u00a025<\/p>\n

c)\u00a026<\/p>\n

d)\u00a028<\/p>\n

Question 7:\u00a0<\/b>At present Sofia is 1.5 times Shalu\u2019s age and twice Saloni\u2019s age. After six years Sofia will be 1.4 times Shalu\u2019s age and Satoni will be 0.8 times Shalu\u2019s age then. What is Salonfs present age<\/p>\n

a)\u00a030 years<\/p>\n

b)\u00a036 years<\/p>\n

c)\u00a024 years<\/p>\n

d)\u00a018 years<\/p>\n

e)\u00a0None of these<\/p>\n

Question 8:\u00a0<\/b>12 years ago, the ages of A and B were in the ratio 15 : 13 respectively. 19 years from now the respective ratio of their ages will be 23 : 22. What is the sum of their ages at present ?<\/p>\n

a)\u00a057 years<\/p>\n

b)\u00a054 years<\/p>\n

c)\u00a052 years<\/p>\n

d)\u00a059 years<\/p>\n

e)\u00a0None of these<\/p>\n

Question 9:\u00a0<\/b>The ages of Shirish and Kunder are in the ratio of 5 : 6 respectively. After 8 years the ratio of their ages will be 7 : 8. What is the difference in their ages<\/p>\n

a)\u00a04 years<\/p>\n

b)\u00a08 years<\/p>\n

c)\u00a010 years<\/p>\n

d)\u00a012 years<\/p>\n

e)\u00a0None of these<\/p>\n

Question 10:\u00a0<\/b>Jayesh is twice as old as Vijay and half as old as Suresh .If sum of Suresh\u2019s and Vijay\u2019s age is 85 years what is the Jayesh\u2019s age in years?<\/p>\n

a)\u00a034<\/p>\n

b)\u00a036<\/p>\n

c)\u00a068<\/p>\n

d)\u00a0Cannot determined<\/p>\n

e)\u00a0None of these<\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Ten years ago, the total age of the family is 231 years.<\/p>\n

Seven years ago, (Just before the death of the first person), the total age of the family would have been 231+8*3 = 231+24 = 255.
\nAfter the death of one member and the birth of a child, the total age is 195 years.<\/p>\n

Four years ago, after the death of one member and birth of another child, the total age of the family is 195+24-60 = 159 years.<\/p>\n

The current total age of the family is = 8×4 + 159 = 191 years<\/p>\n

The average age is 191\/8 = 23.875 years = 24 years (approx)<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the number of professors, associate professors and assistant professors be x, y and z respectively and their average ages be a, b and c respectively.
\nxa + yb + zc = 2160\u00a0\u00a0 ——————-(1)<\/p>\n

Average age =36<\/p>\n

$\\therefore$ x+y+z=60<\/p>\n

xa + yb = 39 (x + y)
\n11(yb + zc) = 360(y + z)
\n3(xa + zc) = 110(x + z)
\nx(a + 1) + y(b + 6) + z(c + 7) = 2160 + 5*(60) ——-(2) \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 [$\\because$ Average increases by 5]<\/p>\n

Eq 2- Eq 1<\/p>\n

We get x+6y+7z=300<\/p>\n

Lets solve the options one by one
\nOption A: x = 16 , y = 24, z = 20<\/p>\n

16+6*24+7*20=300 which satisfies the equations.<\/p>\n

So either A or C can be the answer.<\/p>\n

Now check for the values of a, b, c<\/p>\n

a=45, b=35, c=30<\/p>\n

ax+by+cz = 45*16+35*24+30*20<\/p>\n

=2160<\/p>\n

Hence, option A is the correct answer.<\/p>\n

3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Mr. and Mrs. Gupta have three children – Pratik, Writtik and Kajol, all of whom were born in different cities. Pratik is 2 years elder to Writtik. Mr. Gupta was 30 years of age when Kajol was born in Hyderabad, while Mrs. Gupta was 28 years of age when Writtik was born in Bangalore. If Kajol was 5 years of age when Pratik was born in Mumbai, then what were the ages of Mr. and Mrs. Gupta respectively at the time of Pratik\u2019s birth.<\/p>\n

It is given that\u00a0Pratik is 2 years elder to Writtik and\u00a0Kajol was 5 years of age when Pratik was born in Mumbai. Hence, we can say that Kajol is the eldest and Writtik is the youngest.<\/p>\n

Mrs. Gupta was 28 years of age when Writtik was born in Bangalore. Hence, at the time of Pratik’s birth Mrs. Gupta would have been two years younger i.e. 28 – 2 = 26 years old.<\/p>\n

Mr. Gupta was 30 years of age when Kajol was born. Hence, at the time of Pratik’s birth Mr. Gupta would have been 5 years older i.e. 30 + 5 = 35 years old.<\/p>\n

Hence, option A is the correct answer.<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

10 years ago, Let age of Ravindra be 5x and Rekha be 4x<\/p>\n

At present, Ravindra is 7\/6 times of Rekha’s age.<\/p>\n

5x + 10 = $\\frac{7}{6}$ (4x + 10)<\/p>\n

Solving, x =5<\/p>\n

Ravindra was 25 years (10 years ago) and Rekha was 20 years (10 years ago)<\/p>\n

Now, ages of their children is 3:2:1<\/p>\n

Maximum possible ages of children is 9,6,3 years.<\/p>\n

Total age of family is: 35 + 30 + 9*3 + 6*2 + 3 = 107 years.<\/p>\n

5)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Let the age of the father be ‘f’, mother be ‘m’, Hari be ‘h’, Chari be ‘c’. It has been given that Chari is 4 years older than Gouri. Therefore, the age of Gouri is c-4.<\/p>\n

When Chari was born, the sum of the ages of Hari, his father and mother was 70 years.
\nIf Chari’s age is ‘c’ now, then Chari’s father’s age when Chari was born would have been ‘f-c’ (i.e, Current age – the number of years that has passed after Chari’s birth). The same holds true for all the family members.<\/p>\n

=> f – c +\u00a0m – c +\u00a0h – c = 70
\nf+m+h-3c = 70 ————-(1)<\/p>\n

The sum of the ages of the 4 family members when Gouri was born was twice the sum of the ages of the father and mother at the time of Hari’s birth.<\/p>\n

=> f-(c-4) + m -(c-4) + h -(c-4) + c – (c-4) = 2(f-h+m-h)
\n=> f + m + h + c – 4(c-4) = 2f + 2m – 4h
\nf+m+h-3c + 16 = 2f+2m-4h
\nSubstituting (1), we get,
\n70 +16 = 2f+2m-4h
\n43 + 2h= f+m —————(2)
\nSubstituting (2) in (1), we get,
\n43 + 2h + h – 3c = 70
\n3h – 3c = 27
\n=> h-c = 9
\nTherefore, the difference between the age of Hari and Chari is 9 years. Therefore, option E is the right answer.<\/p>\n

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6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

In an apartment complex, the number of people aged 51 years and above is 30 and there are at most 39 people whose ages are below 51 years. The average age of all the people in the apartment complex is 38 years. What is the largest possible average age, in years, of the people whose ages are below 51 years?<\/p>\n

The possible average age of people\u00a0whose ages are below 51 years will be maximum if the average age of the number of people aged\u00a051 years and above is minimum. Hence, we can say that that there are 30 people having same age 51 years.<\/p>\n

Let ‘x’ be the maximum average age of people whose ages are below 51.<\/p>\n

Then we can say that,<\/p>\n

$\\dfrac{51*30+39*x}{30+39} = 38$<\/p>\n

$\\Rightarrow$ $1530+39x = 2622$<\/p>\n

$\\Rightarrow$ $x = 1092\/39 = 28$<\/p>\n

Hence, we can say that option D is the correct answer.<\/p>\n

7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let Sofia’s present age be x<\/p>\n

Let Shalu’s present age be y<\/p>\n

Let Saloni’s present age be z<\/p>\n

From given conditions,<\/p>\n

x = 1.5y = 2z<\/p>\n

x+6 = 1.4(y+6)<\/p>\n

z+6 = 0.8(y+6)<\/p>\n

x= 2z and y =4z\/3<\/p>\n

Substituting these conditions, we get z = 18<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

REASONING<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let present ages of Shirish and Kunder be $5x$ and $6x$ years respectively.<\/p>\n

Acc. to ques, ratio of their ages after 8 years<\/p>\n

=> $\\frac{5x + 8}{6x + 8} = \\frac{7}{8}$<\/p>\n

=> $40x + 64 = 42x + 56$<\/p>\n

=> $42x – 40x = 64 – 56$<\/p>\n

=> $2x = 8$<\/p>\n

=> $x = \\frac{8}{2} = 4$<\/p>\n

$\\therefore$\u00a0Difference in their ages = $6x – 5x = x$<\/p>\n

= 4 years<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let Vijay’s age = $x$ years<\/p>\n

=> Jayesh’s age = $2x$ years and Suresh’s age = $4x$ years<\/p>\n

Sum of Suresh’s and Vijay’s ages = $(4x+x)=85$<\/p>\n

=> $x=\\frac{85}{5}=17$<\/p>\n

$\\therefore$ Jayesh’s age = $2x=2 \\times 17=34$ years<\/p>\n

=> Ans – (A)<\/p>\n

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We hope this Ages Questions PDF for TISSNET with Solutions will be helpful to you.<\/p>\n","protected":false},"excerpt":{"rendered":"

Problems on Ages for TISSNET PDF Download important TISSNET Ages Questions PDF based on previously asked questions in TISSNET and other MBA exams. Practice Ages Questions and answers for TISSNET and other exams. Download TISSNET Previous Year Papers Question 1:\u00a0Ten years ago, the ages of the members of a joint family of eight people added […]<\/p>\n","protected":false},"author":42,"featured_media":39641,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3,3167,125,350,362,3313,366],"tags":[3375,3299],"class_list":{"0":"post-39634","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-cat","8":"category-downloads-en","9":"category-featured","10":"category-iift","11":"category-snap","12":"category-tissnet","13":"category-xat","14":"tag-problems-on-ages-for-tissnet","15":"tag-tissnet"},"better_featured_image":{"id":39641,"alt_text":"Problems on Ages for TISSNET PDF","caption":"Problems on Ages for TISSNET PDF\n","description":"Problems on Ages for TISSNET 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