{"id":39493,"date":"2019-12-18T17:27:07","date_gmt":"2019-12-18T11:57:07","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=39493"},"modified":"2019-12-18T17:27:20","modified_gmt":"2019-12-18T11:57:20","slug":"mixture-and-alligation-questions-for-ssc-cgl-set-3-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/mixture-and-alligation-questions-for-ssc-cgl-set-3-pdf\/","title":{"rendered":"Mixture and Alligation Questions for SSC-CGL Set-3 PDF"},"content":{"rendered":"

Mixture and Alligation Questions for SSC-CGL Set-3 PDF<\/strong><\/span><\/h1>\n

Download SSC-CGL\u00a0Mixtures and Alligations Questions with answers PDF based on previous papers very useful for SSC-CGL exams. Very important Mixtures and Alligations questions for SSC exams.<\/p>\n

Download Mixture and Alligation Questions PDF<\/a><\/p>\n

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Question 1:\u00a0<\/b>The ratio of the quantities on acid and water in a mixture is 1 : 3. If 5 liters of acid is further added to the mixture, the new ratio becomes 1: 2. The quantity of new mixture in liters is<\/p>\n

a)\u00a032<\/p>\n

b)\u00a040<\/p>\n

c)\u00a042<\/p>\n

d)\u00a045<\/p>\n

Question 2:\u00a0<\/b>The ratio of the volumes of water and glycerine in 240cc of a mixture is 1:3. The quantity of water (in cc that should be added to the mixture so that the new ratio of the volume of water and glycerine becomes 2:3 is<\/p>\n

a)\u00a055<\/p>\n

b)\u00a060<\/p>\n

c)\u00a062.5<\/p>\n

d)\u00a064<\/p>\n

Question 3:\u00a0<\/b>Two equal vessels are filled with the mixture of water and milk in the ratio of 3:4 and 5:3 respectively. If the mixtures are poured into a third vessel, the ratio of water and milk in the third vessel will be<\/p>\n

a)\u00a015:12<\/p>\n

b)\u00a053:59<\/p>\n

c)\u00a020:9<\/p>\n

d)\u00a059:53<\/p>\n

Question 4:\u00a0<\/b>The ratio of milk and water in mixtures of four containers are 5:3, 2:1, 3:2 and 7:4 respectively. In which container is the quantity of milk, relative to water, minimum?<\/p>\n

a)\u00a0First<\/p>\n

b)\u00a0Second<\/p>\n

c)\u00a0Third<\/p>\n

d)\u00a0Fourth<\/p>\n

Question 5:\u00a0<\/b>Three bottles of equal capacity have a mixture of milk and water in ratio 5 : 7, 7 : 9 and 2 : 1 respectively. These three bottles are emptied into a large bottle. What is the percentage of milk in the new mixture?<\/p>\n

a)\u00a049.6<\/p>\n

b)\u00a052.3<\/p>\n

c)\u00a051.2<\/p>\n

d)\u00a050.7<\/p>\n

SSC CGL Previous Papers Download PDF<\/a><\/p>\n

SSC CGL Free Mock Test<\/a><\/p>\n

Question 6:\u00a0<\/b>Three boxes of capacity 24 kg, 36 kg and 84 kg are completely filled with three varieties of wheat A, B and C respectively. All three boxes were emptied and the three types of wheat were thoroughly mixed and the mixture was put back in the three boxes. How many kg of type A wheat would be there in the third box (in kg)?<\/p>\n

a)\u00a010<\/p>\n

b)\u00a012<\/p>\n

c)\u00a014<\/p>\n

d)\u00a016<\/p>\n

Question 7:\u00a0<\/b>Three bottles of equal capacity containing a mixture of milk and water in ratio 2: 5, 3: 4 and 4: 5 respectively. These three bottles are emptied into a large bottle. What will be the ratio of milk and water respectively in the large bottle?<\/p>\n

a)\u00a073 : 106<\/p>\n

b)\u00a073 : 116<\/p>\n

c)\u00a073: 113<\/p>\n

d)\u00a073: 189<\/p>\n

Question 8:\u00a0<\/b>The ratio of syrup and water in a mixture is 3: 1, then the percentage of syrup in this mixture is:<\/p>\n

a)\u00a025%<\/p>\n

b)\u00a066 $\\ \\frac{2}{3}$%<\/p>\n

c)\u00a033 $\\ \\frac{1}{3}$%<\/p>\n

d)\u00a075%<\/p>\n

Question 9:\u00a0<\/b>20 liters of a mixture contains milk and water in the ratio 3: 1. Then the amount of milk to be added to the mixture so as to have milk and water in the ratio 4:1 is<\/p>\n

a)\u00a06 liters<\/p>\n

b)\u00a05 liters<\/p>\n

c)\u00a04 liters<\/p>\n

d)\u00a07 liters<\/p>\n

Question 10:\u00a0<\/b>A vessel contains 60 liters of milk. 12 liters of milk taken out from it and replaced by water. Then again from the mixture, 12 liters are again taken out and replaced by water. The ratio of milk and water in the resultant mixture is:<\/p>\n

a)\u00a016 : 10<\/p>\n

b)\u00a09 : 5<\/p>\n

c)\u00a015 : 10<\/p>\n

d)\u00a016 : 9<\/p>\n

Question 11:\u00a0<\/b>A mixture contains milk and water in the ratio 5 : 1. On adding 5 liters of water, the ratio of milk and water becomes 5 : 2. The quantity of milk in the mixture is<\/p>\n

a)\u00a025 liters<\/p>\n

b)\u00a016 liters<\/p>\n

c)\u00a022.75 liters<\/p>\n

d)\u00a032.5 liters<\/p>\n

Question 12:\u00a0<\/b>Two vessels contain a mixture of petrol and kerosene in the ratio 4 : 3 and 3 : 5 respectively. The ratio of the volumes of the quantities from the two vessels to be mixed together so that the new mixture may contain the same volume of petrol and kerosene is<\/p>\n

a)\u00a09 : 6<\/p>\n

b)\u00a08 : 2<\/p>\n

c)\u00a07 : 8<\/p>\n

d)\u00a07 : 4<\/p>\n

Question 13:\u00a0<\/b>In a mixture, sugar and milk are in the ratio 4 : 5. If 7 litres of milk is added to it, then the ratio of sugar and milk in the new mixture becomes 2 : 3. What is the total quantity (In litres) of sugar in new mixture?<\/p>\n

a)\u00a035<\/p>\n

b)\u00a028<\/p>\n

c)\u00a042<\/p>\n

d)\u00a024<\/p>\n

Question 14:\u00a0<\/b>In 250 litres mixture of soda and water the ratio of amount of soda to that of water is 7 : 18. In order to make this ratio 2 : 3, how many more litres of soda should be added?<\/p>\n

a)\u00a037.5<\/p>\n

b)\u00a042.5<\/p>\n

c)\u00a045<\/p>\n

d)\u00a050<\/p>\n

Question 15:\u00a0<\/b>A mixture contains acid and water in the ratio of 7 : 3. If 4 litres of water is added to it, then the ratio of acid and water becomes 7 : 4. What is the quantity (in litres) of acid in the mixture?<\/p>\n

a)\u00a028<\/p>\n

b)\u00a022<\/p>\n

c)\u00a020<\/p>\n

d)\u00a032<\/p>\n

FREE SSC EXAM YOUTUBE VIDEOS<\/a><\/p>\n

18000+ Questions – Free SSC Study Material<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let’ say previously mixture has $x$ acid and $3x$ water.
\nSo after adding 5 liters of acid ratio will be $(x+5)$ : $3x$ = 1:2
\nAfter solving for $x$ , we will get its value as 10
\nSo new values will be 15 and 30 , total will be 45<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let’s say we added $x$ cc of water.
\nAccording to previous ratio amount of water in mixture is $240 \\times \\frac{1}{4}$ = 60
\nSo after adding amount of water = $60+x$
\namount of glycerine = $240 \\times \\frac{3}{4} = 180$
\nHence new ratio will be = $\\frac{60+x}{180} = \\frac{2}{3}$
\nor $x$ will be 60.<\/p>\n

3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let’s say amounts in first vessel are 3x and 4x
\nin second vessel = 5y and 3y
\nSo 7x = 8y (given) \u00a0 (eq. (1))
\nPouring them together , new amounts will be 3x+5y and 4x+3y
\nso new ratio will be $\\frac{3x+5y}{4x+3y}$ \u00a0(eq. 2)
\nputting ratio of x and y from eq. (1) in eq. (2) and solving we will get new ratio as 59:53<\/p>\n

4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

In first container quantity of milk relative to water is $\\frac{5}{3} \\times100$ = 166.65%
\nIn second container quantity of milk relative to water is\u00a0$\\frac{2}{1} \\times100$ = 200%
\nIn third container quantity of milk relative to water is\u00a0$\\frac{2}{1} \\times100$ = 150%
\nIn fourth container quantity of milk relative to water is\u00a0$\\frac{7}{4} \\times100$ = 175%
\nhence third container has least ratio<\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let the capacity of each bottle = 48 litres \u00a0 \u00a0[L.C.M.(12,16,3)]<\/p>\n

Ratio of milk and water in the three bottles respectively = 5:7 , 7:9 , 2:1<\/p>\n

Milk in 1st bottle = $\\frac{5}{(5+7)}\\times48=20$ litres<\/p>\n

and water in 1st bottle = $48-20=28$ litres<\/p>\n

Similarly, milk in 2nd bottle = $\\frac{7}{16}\\times48=21$ litres<\/p>\n

and water in 2nd bottle = $48-21=27$ litres<\/p>\n

Similarly, milk in 3rd bottle = $32$ litres and water = $16$ litres<\/p>\n

=> Total milk = $20+21+32=73$ litres<\/p>\n

and total water = $28+27+16=71$ litres<\/p>\n

$\\therefore$ Percentage of milk in the new mixture = $\\frac{73}{(73+71)}\\times100$<\/p>\n

= $\\frac{7300}{144}=50.69 \\approx 50.7\\%$<\/p>\n

=> Ans – (D)<\/p>\n

6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Capacity of box containing wheat A = 24 kg , B = 36 kg and C = 84 kg<\/p>\n

Ratio of weights of boxes containing wheats A, B and C = 24 : 36 : 84 = 2\u00a0: 3\u00a0: 7<\/p>\n

=> Quantity of type A wheat in third box = $\\frac{2}{(2+3+7)}\\times84$<\/p>\n

= $\\frac{84}{6}=14$ kg<\/p>\n

=> Ans – (C)<\/p>\n

7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the capacity of each bottle = 63 litres \u00a0 \u00a0[L.C.M.(7,7,9)]<\/p>\n

Ratio of milk and water in the three bottles respectively = 2:5 , 3:4 and 4:5<\/p>\n

Milk in 1st bottle = $\\frac{2}{(2+5)}\\times63=18$ litres<\/p>\n

and water in 1st bottle = $63-18=45$ litres<\/p>\n

Similarly, milk in 2nd bottle = $\\frac{3}{7}\\times63=27$ litres<\/p>\n

and water in 2nd bottle = $63-27=36$ litres<\/p>\n

Similarly, milk in 3rd bottle = $28$ litres and water = $35$ litres<\/p>\n

=> Total milk = $18+27+28=73$ litres<\/p>\n

and total water = $45+36+35=116$ litres<\/p>\n

$\\therefore$ Required ratio = $\\frac{73}{116}$<\/p>\n

=> Ans – (B)<\/p>\n

8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Ratio of syrup and water in a mixture\u00a0= 3 : 1<\/p>\n

=> Percentage of syrup in this mixture\u00a0= $\\frac{1}{(3+1)}\\times100$<\/p>\n

= $\\frac{100}{4}=25\\%$<\/p>\n

=> Ans – (A)<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Ratio of milk and water in 20 litres mixture = 3:1<\/p>\n

=> Quantity of milk = $\\frac{3}{(3+1)}\\times20=15$ litres<\/p>\n

=> Quantity of water = $20-15=5$ litres<\/p>\n

Let amount of milk added = $x$ litres<\/p>\n

According to ques,<\/p>\n

=> $\\frac{15+x}{5}=\\frac{4}{1}$<\/p>\n

=> $15+x=20$<\/p>\n

=> $x=20-15=5$<\/p>\n

$\\therefore$ The amount of milk to be added to the mixture so as to have milk and water in the ratio 4 :1\u00a0=\u00a05 litres<\/strong><\/p>\n

=> Ans – (B)<\/p>\n

10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Initial quantity of milk = 60 litres<\/p>\n

When\u00a012 liters of milk taken out from it and replaced by water, then quantity of milk = $60-12=48$ litres and water = $12$ litres<\/p>\n

(Total mixture still remains 60 litres)<\/p>\n

Again, 12 litres of mixture is taken out, => Fraction of mixture taken out = $\\frac{12}{60}=\\frac{1}{5}^{th}$<\/p>\n

=> Milk left = $48-(\\frac{1}{5}\\times48)=38.4$ litres<\/p>\n

=> Water left = $60-38.4=21.6$ litres<\/p>\n

$\\therefore$ Required ratio = $\\frac{38.4}{21.6}=\\frac{64}{36}=16:9$<\/p>\n

=> Ans – (D)<\/p>\n

11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let quantity of water in mixture = $x$ litres, => Quantity of milk = $5x$ litres<\/p>\n

According to ques, => $\\frac{5x}{x+5}=\\frac{5}{2}$<\/p>\n

=> $\\frac{x}{x+5}=\\frac{1}{2}$<\/p>\n

=> $2x=x+5$<\/p>\n

=> $2x-x=5$<\/p>\n

=> $x=5$<\/p>\n

$\\therefore$ Quantity of milk = $5\\times5=25$ litres<\/p>\n

=> Ans – (A)<\/p>\n

12)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Ratio of petrol and whole mixture in 1st vessel = $\\frac{4}{7}$<\/p>\n

Ratio of petrol and whole mixture in 2nd vessel = $\\frac{3}{8}$<\/p>\n

Also,\u00a0ratio of petrol and whole mixture in the final mixture = $\\frac{1}{2}$<\/p>\n

By alligation method,<\/p>\n

<\/figure>\n

=> Petrol : Kerosene = $\\frac{1}{8}:\\frac{1}{14}=14:8$<\/p>\n

= $7:4$<\/p>\n

=> Ans – (D)<\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let quantity of milk and sugar be $4x$ and $5x$ litres respectively.<\/p>\n

According to ques,<\/p>\n

=> $\\frac{4x}{5x+7}=\\frac{2}{3}$<\/p>\n

=> $12x=10x+14$<\/p>\n

=> $12x-10x=2x=14$<\/p>\n

=> $x=\\frac{14}{2}=7$<\/p>\n

$\\therefore$ Total quantity of sugar = $4\\times7=28$ litres<\/p>\n

=> Ans – (B)<\/p>\n

14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Amount of soda in 250 litres mixture = $\\frac{7}{(7+18)}\\times250=70$ litres<\/p>\n

=> Amount of water = $250-70=180$ litres<\/p>\n

Let $x$ litres of soda is added.<\/p>\n

=> $\\frac{70+x}{180}=\\frac{2}{3}$<\/p>\n

=> $210+3x=360$<\/p>\n

=> $3x=360-210=150$<\/p>\n

=> $x=\\frac{150}{3}=50$<\/p>\n

$\\therefore$\u00a050 litres<\/span><\/strong> of soda should be added.<\/p>\n

=> Ans – (D)<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let quantity of acid and water be $7x$ and $3x$ litres respectively.<\/p>\n

According to ques,<\/p>\n

=> $\\frac{7x}{3x+4}=\\frac{7}{4}$<\/p>\n

=> $28x=21x+28$<\/p>\n

=> $28x-21x=7x=28$<\/p>\n

=> $x=\\frac{28}{7}=4$<\/p>\n

$\\therefore$ Total quantity of acid = $7\\times4=28$ litres<\/p>\n

=> Ans – (A)<\/p>\n

SSC Free Previous Papers App<\/a><\/p>\n

We hope this\u00a0Mixtures and Alligations Questions PDF for SSC CGL Exam preparation is so helpful to you.<\/p>\n","protected":false},"excerpt":{"rendered":"

Mixture and Alligation Questions for SSC-CGL Set-3 PDF Download SSC-CGL\u00a0Mixtures and Alligations Questions with answers PDF based on previous papers very useful for SSC-CGL exams. Very important Mixtures and Alligations questions for SSC exams. Question 1:\u00a0The ratio of the quantities on acid and water in a mixture is 1 : 3. If 5 liters of […]<\/p>\n","protected":false},"author":49,"featured_media":39507,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3167,125,9,504,378,1493,1459,1611,1741,1441],"tags":[3342,462],"class_list":{"0":"post-39493","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads-en","8":"category-featured","9":"category-ssc","10":"category-ssc-cgl","11":"category-ssc-chsl","12":"category-ssc-cpo","13":"category-ssc-gd","14":"category-ssc-je","15":"category-ssc-mts","16":"category-stenographer","17":"tag-mixture-and-alligation-questions","18":"tag-ssc-cgl"},"better_featured_image":{"id":39507,"alt_text":"Mixture and Alligation Questions for SSC_CGL set-3 PDF","caption":"Mixture and Alligation Questions for SSC_CGL set-3 PDF","description":"Mixture and Alligation Questions for SSC_CGL 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