{"id":39446,"date":"2019-12-18T12:28:09","date_gmt":"2019-12-18T06:58:09","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=39446"},"modified":"2019-12-18T12:28:09","modified_gmt":"2019-12-18T06:58:09","slug":"time-and-work-questions-for-ssc-cpo-set-3-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/time-and-work-questions-for-ssc-cpo-set-3-pdf\/","title":{"rendered":"Time and Work Questions for SSC-CPO Set-3 PDF"},"content":{"rendered":"

Time and Work Questions for SSC-CPO Set-3 PDF<\/span><\/strong><\/span><\/h1>\n

Download SSC CPO Time and Work questions with answers PDF based on previous papers very useful for SSC CPO exams. Very important Time and Work Questions for SSC exams<\/p>\n

Download Time and Work Questions PDF<\/a><\/p>\n

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Question 1:\u00a0<\/b>A drum of kerosene is $\\frac{3}{4}$ full. When 30 litres of kerosene is drawn from it, it remains $\\frac{1}{2}$\u00a0full. The capacity of the drum is<\/p>\n

a)\u00a0120 litres<\/p>\n

b)\u00a0135 litres<\/p>\n

c)\u00a0150 litres<\/p>\n

d)\u00a0180 litres<\/p>\n

Question 2:\u00a0<\/b>By what least number should 675 be multiplied so as to obtain a perfect cube number ?<\/p>\n

a)\u00a03<\/p>\n

b)\u00a05<\/p>\n

c)\u00a024<\/p>\n

d)\u00a040<\/p>\n

Question 3:\u00a0<\/b>$0.\\overline{001}$ is equal to<\/p>\n

a)\u00a01\/1000<\/p>\n

b)\u00a01\/999<\/p>\n

c)\u00a01\/99<\/p>\n

d)\u00a01\/9<\/p>\n

Question 4:\u00a0<\/b>$\\frac{4.41 \\times 0.16}{2.1 \\times 1.6 \\times 0.21}$ is equal to<\/p>\n

a)\u00a01<\/p>\n

b)\u00a00.1<\/p>\n

c)\u00a00.01<\/p>\n

d)\u00a010<\/p>\n

Question 5:\u00a0<\/b>If a and b are two odd positive integers, by which of the following integers is $(a^4-b^4)$ always divisible ?<\/p>\n

a)\u00a03<\/p>\n

b)\u00a06<\/p>\n

c)\u00a08<\/p>\n

d)\u00a012<\/p>\n

FREE SSC EXAM YOUTUBE VIDEOS<\/a><\/p>\n

Download SSC CPO Previous Papers PDF<\/a><\/p>\n

Question 6:\u00a0<\/b>$\\frac{256 \\times 256 – 144 \\times 144}{112}$ is equal to<\/p>\n

a)\u00a0420<\/p>\n

b)\u00a0400<\/p>\n

c)\u00a0360<\/p>\n

d)\u00a0320<\/p>\n

Question 7:\u00a0<\/b>Buses start from a bus terminal with a speed of 20 km\/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes ?<\/p>\n

a)\u00a03 km\/hr<\/p>\n

b)\u00a04 km\/hr<\/p>\n

c)\u00a05 km\/hr<\/p>\n

d)\u00a07 km\/hr<\/p>\n

Question 8:\u00a0<\/b>A and B together can do a piece of work in 9 days. If A does thrice the work of B in a given time, the time A alone will take to finish the work is<\/p>\n

a)\u00a04 days<\/p>\n

b)\u00a06 days<\/p>\n

c)\u00a08 days<\/p>\n

d)\u00a012 days<\/p>\n

Question 9:\u00a0<\/b>If $a^3+\\frac{1}{a^3}=2$, then value of $\\frac{a^2+1}{a}$ is (a is a positive number)<\/p>\n

a)\u00a01<\/p>\n

b)\u00a02<\/p>\n

c)\u00a03<\/p>\n

d)\u00a04<\/p>\n

Question 10:\u00a0<\/b>The mean of 100 observations was calculated as 40. It was found later on that one of the observations was misread as 83 instead of 53. The correct mean is:<\/p>\n

a)\u00a039<\/p>\n

b)\u00a039.7<\/p>\n

c)\u00a040.3<\/p>\n

d)\u00a042.7<\/p>\n

FREE SSC EXAM YOUTUBE VIDEOS<\/a><\/p>\n

Question 11:\u00a0<\/b>The time taken by a train 160 m long, running at 72 km\/hr, in crossing an electric pole is<\/p>\n

a)\u00a08 sec<\/p>\n

b)\u00a09 sec<\/p>\n

c)\u00a06 sec<\/p>\n

d)\u00a04 sec<\/p>\n

Question 12:\u00a0<\/b>A and B start running at the same time and from the same point around a circle. If A can complete one round in 40 seconds and B in50 seconds, how many seconds will they take to reach the starting point simultaneously?<\/p>\n

a)\u00a010<\/p>\n

b)\u00a0200<\/p>\n

c)\u00a090<\/p>\n

d)\u00a02000<\/p>\n

Question 13:\u00a0<\/b>In what time will a 100 metre long train running with a speed of 50 km\/hr cross a pillar<\/p>\n

a)\u00a07.0 sec<\/p>\n

b)\u00a072 sec<\/p>\n

c)\u00a07.2 sec<\/p>\n

d)\u00a070 sec<\/p>\n

Question 14:\u00a0<\/b>A gun is fired at a distance of 6.64 km away from Ram. He hears the sound 20 seconds later. Then the speed of sound is<\/p>\n

a)\u00a0664 m\/s<\/p>\n

b)\u00a0664 km\/s<\/p>\n

c)\u00a0332 m\/s<\/p>\n

d)\u00a0332 km\/s<\/p>\n

Question 15:\u00a0<\/b>A train leaves a station A at 7 am and reaches another station B at 11 am. Another train leaves B at 8 am and reaches A at 11.30 am. The two trains cross one another at<\/p>\n

a)\u00a08:36 am<\/p>\n

b)\u00a08:56 am<\/p>\n

c)\u00a09:00 am<\/p>\n

d)\u00a09:24 am<\/p>\n

Free SSC Practice Tests<\/a><\/p>\n

Question 16:\u00a0<\/b>A can do a piece of work in 4 days and B can do it in 12 days. In how many days will they finish the work, both working together ?<\/p>\n

a)\u00a04 days<\/p>\n

b)\u00a06 days<\/p>\n

c)\u00a02 days<\/p>\n

d)\u00a03 days<\/p>\n

Question 17:\u00a0<\/b>A can do 1\/4 of a work in 10 days. B can do 1\/3 of the work in 20 days. In how many days can both A and B together do the work ?<\/p>\n

a)\u00a030 days<\/p>\n

b)\u00a032 days<\/p>\n

c)\u00a024 days<\/p>\n

d)\u00a025 days<\/p>\n

Question 18:\u00a0<\/b>A and B can together finish a work in 30 days. They worked at it for 20 days and then B left. The remaining work was done by A alone in 20 more days.A alone can finish the work in<\/p>\n

a)\u00a060 days<\/p>\n

b)\u00a054 days<\/p>\n

c)\u00a048 days<\/p>\n

d)\u00a050 days<\/p>\n

Question 19:\u00a0<\/b>P can do a piece of work in 9 days. Q is 50% more efficient than P. The number of days it takes for Q to do the same piece of work is<\/p>\n

a)\u00a0$3$<\/p>\n

b)\u00a0$13\\frac{1}{2}$<\/p>\n

c)\u00a0$4\\frac{1}{2}$<\/p>\n

d)\u00a0$6$<\/p>\n

Question 20:\u00a0<\/b>Sixteen men can complete a work in fifteen days, twenty-four children can do the same work in twenty days. In how many days will eight men and eight children, complete the same work ?<\/p>\n

a)\u00a0$18$ days<\/p>\n

b)\u00a0$16 days$<\/p>\n

c)\u00a0$13\\frac{1}{3}$ days<\/p>\n

d)\u00a0$20$ days<\/p>\n

Free SSC Practice Tests<\/a><\/p>\n

200+ Free GK Online Tests<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Drum is\u00a0$\\frac{3}{4}$ full.<\/p>\n

When 30 liters are drawn out of it, it becomes\u00a0$\\frac{1}{2}$\u00a0full.
\nTherefore\u00a0$\\frac{3}{4}$ –\u00a0$\\frac{1}{2}$ of drum = 30
\n$\\frac{1}{4}$ of drum = 30
\nTotal capacity of drum = 30 $\\times$ 4 = 120 litres<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Factorising 675 we get
\n675 = 5 $\\times$ 5\u00a0$\\times$ 3\u00a0$\\times$ 3\u00a0$\\times$ 3
\nThere in order to make 675 a perfect cube, it has to be multiplied by 5.<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let $x =0.\\overline{001}$ be the first equation<\/p>\n

$1000x = 1000 \\times 0.\\overline001$<\/p>\n

= $1.\\overline{001}$<\/p>\n

Let $1000x = 1.\\overline{001}$ be second equation<\/p>\n

Subtracting equation 1 from 2<\/p>\n

$999x = 1$<\/p>\n

$ x = \\frac{1}{999}$<\/p>\n

4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$\\frac{4.41 \\times 0.16}{2.1 \\times 1.6 \\times 0.21}$<\/p>\n

= $\\frac{{2.1}^2 \\times 0.16}{2.1 \\times 0.16 \\times 10 \\times 0.21}$<\/p>\n

=$\\frac{{2.1}^21 \\times 0.16}{2.1 \\times 0.16 \\times 2.1}$<\/p>\n

=$\\frac{{2.1}^2 \\times 0.16}{{2.1}^2 \\times 0.16}$<\/p>\n

=1<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$(a^4-b^4) = (a^2+b^2)\\times(a^2-b^2)$
\n= $(a^2+b^2)\\times(a+b)\\times(a-b)$<\/p>\n

Let a = 5 , b= 3
\n54 <\/sup>– 34<\/sup>\u00a0= (52<\/sup>\u00a0+ 32<\/sup>)(5 + 3)(5 – 3) = 34 x 8 x 2\u00a0which is divisible by 8
\nLet a \u00a0= 7 and b = 5
\n74<\/sup>\u00a0– 54\u00a0<\/sup>= (72<\/sup>\u00a0+ 52<\/sup>)(7 + 5)(7\u00a0– 5) = 74 x 12 x 2 which is also divisible by 8<\/p>\n

6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$\\frac{256 \\times 256 – 144 \\times 144}{112} = \\frac{256^2 – 144^2}{112} = \\frac{(256 – 144)(256 + 144)}{112} = \\frac{(112)(400)}{112} = 400$<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Distance between buses will $20\\times\\frac{10}{60}$ = $\\frac{10}{3}$ km.
\nNow man is travelling this distance in 8 min. with the relative speed of (20+$x$) (let’s assume speed of man is $x$ km\/hr )
\nhence\u00a0(20+$x$) = $\\frac{\\frac{10}{3}}{\\frac{8}{60}}$
\n$x$= 5<\/p>\n

8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

A does thrice the work of B in a given time.<\/p>\n

Let B’s efficiency = $x$ units\/day<\/p>\n

=> A’s\u00a0efficiency = $3x$ units\/day<\/p>\n

Thus, (A+B)’s 1 day’s work = $x+3x=4x$ units\/day<\/p>\n

=> Total work done by them in 9 days = $4x \\times 9=36x$ units<\/p>\n

$\\therefore$ Time taken by A alone to finish the work = $\\frac{36x}{3x}=12$ days<\/p>\n

=> Ans – (D)<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Given\u00a0:\u00a0$a^3+\\frac{1}{a^3}=2$<\/p>\n

To find\u00a0:\u00a0$\\frac{a^2+1}{a}=(a+\\frac{1}{a}) = x = ?$<\/p>\n

We know that, $(a+\\frac{1}{a})^3=a^3+\\frac{1}{a^3}+3(a)(\\frac{1}{a})(a+\\frac{1}{a})$<\/p>\n

=> $(a+\\frac{1}{a})^3=2+3(a+\\frac{1}{a})$<\/p>\n

=> $x^3=2+3x$<\/p>\n

=> $x^3-3x=2$<\/p>\n

=> $x(x^2-3)=2 \\times 1$<\/p>\n

Thus, the only value that satisfy above equation is $x=2$<\/p>\n

=> Ans – (B)<\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Mean of 100 observations\u00a0= 40<\/p>\n

=> Sum of 100 observations = $100 \\times 40=4000$<\/p>\n

Now, replacing 53 instead of 83<\/p>\n

=> Correct sum = $4000-83+53=3970$<\/p>\n

$\\therefore$ Correct mean = $\\frac{3970}{100}=39.7$<\/p>\n

=> Ans – (B)<\/p>\n

200+ Free GK Online Tests<\/a><\/p>\n

11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Speed of train = 72 km\/hr<\/p>\n

= $(72 \\times \\frac{5}{18})$ m\/s = $20$ m\/s<\/p>\n

Length of train = 160 m<\/p>\n

Using, time = distance\/speed<\/p>\n

=> Time taken = $\\frac{160}{20}=8$ sec<\/p>\n

=> Ans – (A)<\/p>\n

12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Time taken by A to complete 1 round = 40 seconds and by B = 50 seconds<\/p>\n

=> Time taken by them\u00a0to reach the starting point simultaneously = L.C.M.(40,50)<\/p>\n

= 200 seconds<\/p>\n

=> Ans – (B)<\/p>\n

13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Speed of train = 50 km\/hr<\/p>\n

= $(50 \\times \\frac{5}{18})$ m\/s = $\\frac{125}{9}$ m\/s<\/p>\n

Length of train = 100 m<\/p>\n

Using, time = distance\/speed<\/p>\n

=> Time taken = $100\\div \\frac{125}{9}$<\/p>\n

= $100 \\times \\frac{9}{125}$<\/p>\n

= $\\frac{36}{5}=7.2$ sec<\/p>\n

=> Ans – (C)<\/p>\n

14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Distance of gun from Ram = 6.64 km = 6640 m<\/p>\n

Time = 20 seconds<\/p>\n

=> Speed of sound = distance\/time<\/p>\n

= $\\frac{6640}{20}=332$ m\/s<\/p>\n

=> Ans – (C)<\/p>\n

15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Time taken by 1st train to travel from A to B = 11-7 = 4 hours<\/p>\n

Time taken by 2nd train to travel from B to A = 11:30-8 = 3.5 hours<\/p>\n

=> ratio of time taken by 1st train to 2nd train = $4 : \\frac{7}{2}$ = 8 : 7<\/p>\n

Since, speed is inversely proportion to time<\/p>\n

=> Ratio of speeds of 1st train to 2nd train = 7 : 8<\/p>\n

Let the speed of 1st train = $7x$ and 2nd train = $8x$ km\/hr<\/p>\n

Distance between the two stations = time * speed = $7x * 4 = 28x$ km<\/p>\n

We know that, 1st train starts one hour early, thus it will cover $7x$ distance till the time 2nd train starts.<\/p>\n

So, at 8.00 a.m., remaining distance between two trains = $28x-7x = 21x$ km<\/p>\n

Also, the two trains are moving in opposite directions, =>relative speed of two trains = $8x+7x = 15$ km\/hr<\/p>\n

Now, time taken to meet = $\\frac{21x}{15x} = \\frac{7}{5}$ hours<\/p>\n

=> $\\frac{7}{5} * 60$ = 84 minutes after 8.00 a.m.<\/p>\n

=> Time when they meet = 8.00 a.m. + 84 min = 9:24 a.m.<\/strong><\/p>\n

Download SSC CPO Previous Papers PDF<\/a><\/p>\n

16)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

A’s 1 day’s work=$\\frac{1}{4}$
\nB’s 1 day’s work=$\\frac{1}{12}$
\n(A+B)’s 1 day’s work=$\\frac{1}{4}+\\frac{1}{12}$
\n$=\\frac{3+1}{12}$
\n$=\\frac{4}{12}$
\n$=\\frac{1}{3}$
\n$\\therefore$ A and B together does the work in $3$ days.
\nHence,Option D is correct.<\/p>\n

17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

A does$\\frac{1}{4}$ work in 10 days.
\n$\\therefore$A will complete the work in $10\\times4=40$ days.
\nSimilarly, B will complete the work in $20\\times3=60$ days.
\n(A+B)’s 1 day’s work=$\\frac{1}{40}+\\frac{1}{60}$
\n$=\\frac{3+2}{120}$
\n$=\\frac{1}{24}$
\n$\\therefore$ time taken by A and B together to complete the work=$24$ days.
\nHence, Correct option is C.<\/p>\n

18)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

(A+B)together do the work in 30 days.
\n$\\therefore$ (A+B)’s 1 day’s work=$\\frac{1}{30}$
\n$\\therefore$ (A+B)’s 20 days’ work=$\\frac{20}{30}$$=\\frac{2}{3}$
\nRemaining Work=$1-\\frac{2}{3}$
\n=$\\frac{1}{3}$
\n$\\because$ Time taken by A in doing $\\frac{1}{3}$ work=20 days
\n$\\therefore$ Time taken by A to complete the work=$20\\times3$
\n=$60$days
\nHence, Option A is correct.<\/p>\n

19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

P can do a piece of work in 9 days.<\/p>\n

let efficiency of p is 100%<\/p>\n

then efficiency of Q will be 150%<\/p>\n

let Q can do the same piece of work in x days.<\/p>\n

work is constant. so<\/p>\n

efficiency*no of days = constant<\/p>\n

100*9 = 150*x<\/p>\n

x = 6.<\/p>\n

answer is option D.<\/p>\n

20)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

16 men can complete a work in 15 days<\/p>\n

1 man can complete the work in (16*15) days<\/p>\n

24 children can do the same work in 20 days<\/p>\n

1 child can complete the work in (24*20) days<\/p>\n

let x be the no.of days taken by 8 men and 8 children to complete the work, then<\/p>\n

1\/x = 8\/(16*15) + 8\/(24*20)<\/p>\n

1\/x = 1\/30 + 1\/60<\/p>\n

1\/x = 3\/60<\/p>\n

x = 20<\/p>\n

answer is option D.<\/p>\n

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DOWNLOAD APP FOR SSC FREE MOCKS<\/a><\/p>\n

We hope this Time and Work questions for SSC CPO Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Time and Work Questions for SSC-CPO Set-3 PDF Download SSC CPO Time and Work questions with answers PDF based on previous papers very useful for SSC CPO exams. Very important Time and Work Questions for SSC exams Take a Free mock test for SSC CPO Download SSC CPO Previous Papers PDF Question 1:\u00a0A drum of […]<\/p>\n","protected":false},"author":21,"featured_media":39450,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,1493],"tags":[500,3323,3327,3321,3325],"class_list":{"0":"post-39446","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-ssc-cpo","10":"tag-ssc-cpo","11":"tag-ssc-cpo-free-mock","12":"tag-ssc-cpo-free-tests","13":"tag-ssc-cpo-notification","14":"tag-ssc-cpo-previous-papers"},"better_featured_image":{"id":39450,"alt_text":"Time and Work Questions for SSC CPO set-3 pdf","caption":"Time and Work Questions for SSC CPO set-3 pdf","description":"Time and Work Questions for SSC 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