{"id":39277,"date":"2019-12-13T18:46:51","date_gmt":"2019-12-13T13:16:51","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=39277"},"modified":"2019-12-13T18:46:51","modified_gmt":"2019-12-13T13:16:51","slug":"permutation-and-combination-questions-for-xat-set-2-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/permutation-and-combination-questions-for-xat-set-2-pdf\/","title":{"rendered":"Permutation and Combination Questions for XAT Set-2 PDF"},"content":{"rendered":"

Permutation and Combination Questions for XAT Set-2 PDF<\/strong><\/span><\/h1>\n

Download important Permutation and Combination Questions for XAT\u00a0 Set-2 PDF based on previously asked questions in the XAT exam. Practice Permutation and Combination Questions\u00a0 Set-2 PDF for the XAT exam.<\/p>\n

Download Permutation and Combination Questions for XAT Set-2 PDF<\/a><\/p>\n

Get 5 XAT mocks for Rs. 299. Enroll here<\/a><\/p>\n

Instructions<\/b>Instructions: Study the given information carefully to answer the questions that follows.<\/p>\n

An urn contains 4 green, 5 blue, 2 red and 3 yellow marbles.<\/p>\n

Question 1:\u00a0<\/b>If two marbles are drawn at random, what is the probability that both are red or at least one is red?<\/p>\n

a)\u00a0$\\frac{26}{91}$<\/p>\n

b)\u00a0$\\frac{1}{7}$<\/p>\n

c)\u00a0$\\frac{199}{364}$<\/p>\n

d)\u00a0$\\frac{133}{191}$<\/p>\n

e)\u00a0None of these<\/p>\n

Question 2:\u00a0<\/b>What is the number of words formed from the letters of the word \u2018JOKE\u2019 So that the vowels and consonants alternate?<\/p>\n

a)\u00a04<\/p>\n

b)\u00a08<\/p>\n

c)\u00a012<\/p>\n

d)\u00a018<\/p>\n

e)\u00a0None of these<\/p>\n

Instructions<\/b><\/p>\n

Study the given information carefully and answer the question that follow:
\nA committee of five members is to be formed out of 3 trainees 4 professors and 6 research associates In how many different ways can this be done if____<\/p>\n

Question 3:\u00a0<\/b>The committee should have all 4 professors and 1 research associate or all 3 trainees and 2 professors ?<\/p>\n

a)\u00a012<\/p>\n

b)\u00a013<\/p>\n

c)\u00a024<\/p>\n

d)\u00a052<\/p>\n

e)\u00a0None of these<\/p>\n

Question 4:\u00a0<\/b>In how many different ways can the letters of the word BAKERY be arranged ?<\/p>\n

a)\u00a02400<\/p>\n

b)\u00a02005<\/p>\n

c)\u00a0720<\/p>\n

d)\u00a05040<\/p>\n

e)\u00a0None of these<\/p>\n

Instructions<\/b><\/p>\n

Answer the following questions based on the information given below.
\nA bowl contains 4 red, 3 green, 2 blue and 5 black marbles.<\/p>\n

Question 5:\u00a0<\/b>If four marbles are drawn at random, what is the probability that two are red and two are blue ?<\/p>\n

a)\u00a0$\\frac{6}{1001}$<\/p>\n

b)\u00a0$\\frac{1}{143}$<\/p>\n

c)\u00a0$\\frac{1}{13}$<\/p>\n

d)\u00a0$\\frac{6}{91}$<\/p>\n

e)\u00a0None of these<\/p>\n

XAT Solved Previous papers<\/a><\/p>
\n

Take XAT Mock Test<\/a><\/p><\/p>\n

Question 6:\u00a0<\/b>In a sample , if a person is picked up randomly, the probability that the person is a smoker is $\\frac{3}{5}$, and that of the person being male is $\\frac{1}{2}$ .What is the probability that the person is both male as well as a smoker ?<\/p>\n

a)\u00a0$\\frac{10}{11}$<\/p>\n

b)\u00a0$\\frac{1}{5}$<\/p>\n

c)\u00a0$\\frac{3}{5}$<\/p>\n

d)\u00a0Cannot be determined<\/p>\n

e)\u00a0None of these<\/p>\n

Question 7:\u00a0<\/b>A committee of 6 members is to be selected from a group of 8 men and 6 women in such as way that at least 3 men are there in the committee. In how many different ways can it be done ?<\/p>\n

a)\u00a02506<\/p>\n

b)\u00a02534<\/p>\n

c)\u00a01120<\/p>\n

d)\u00a01050<\/p>\n

e)\u00a0None of these<\/p>\n

Question 8:\u00a0<\/b>In how many different ways can the letters of the word \u2018QUOTED\u2019 be arranged<\/p>\n

a)\u00a0720<\/p>\n

b)\u00a0360<\/p>\n

c)\u00a01440<\/p>\n

d)\u00a0320<\/p>\n

e)\u00a0None of these<\/p>\n

Instructions<\/b><\/p>\n

Study the given information carefully and answer the questions that follow:
\nAn urn contains 3 red, 6 blue, 2 green and 4 yellow marbles.<\/p>\n

Question 9:\u00a0<\/b>If three marbles are picked at random, what is the probability that two are blue and one is yellow ?<\/p>\n

a)\u00a02\/15<\/p>\n

b)\u00a06\/91<\/p>\n

c)\u00a012\/91<\/p>\n

d)\u00a03\/15<\/p>\n

e)\u00a0None of these<\/p>\n

Question 10:\u00a0<\/b>In how many different ways can the letters of the word “PRIDE” be arranged ?<\/p>\n

a)\u00a060<\/p>\n

b)\u00a0120<\/p>\n

c)\u00a015<\/p>\n

d)\u00a0360<\/p>\n

e)\u00a0None of these<\/p>\n

XAT Decision making practice questions<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Out of two red marbles two can be choosen in 2<\/sup>C2<\/sub> ways
\nOut of two red marbles one can be choosen in 2<\/sup>C1<\/sub> ways
\nSum of blue, yellow and green marbles = 12
\nOut of 12 marbles one can be choosen in 12<\/sup>C1<\/sub> ways
\nThe probability that both are red or atleast one is red = [2<\/sup>C2<\/sub> + (2<\/sup>C1<\/sub> x 12<\/sup>C1<\/sub>)]\/14<\/sup>C2<\/sub>\u00a0= $\\frac{25}{91}$<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Word name: \u2018JOKE\u2019 Vowels: O, E
\nConsonants: J, K
\n\u2234 Possible arrangement beginning with consonant: JOKE, KOJE, JEKO, KEJO = 4 Numbers
\nbeginning with vowel: OJEK, OKEJ, EJOK, EKOJ = 4 Numbers
\nRequired number = 4+4 = 8 numbers<\/p>\n

3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

4 professors and 1 resarch associate can be selected in $^4C_4*^6C_1 = 6$ ways<\/p>\n

Similarly 3 trainees and 2 professors would be selected in $^3C_3*^4C_2$ ways = 6<\/p>\n

Total ways = 6+6 = 12<\/p>\n

4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

As there are 6 different letters in the word “Bakery” hence, total number of ways of arranging it will be = 6! = 720<\/p>\n

5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Probability of drawing two red and two blue balls = $^4C_2 * ^2C_2 \/ ^{14}C_4$ = 6 \/ 1001<\/p>\n

Option a) is the correct answer.<\/p>\n

XAT Quant formulas PDF<\/a><\/p>
\n

Take XAT Mock Test<\/a><\/p><\/p>\n

6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let’s assume the sample size is 100. Let the number of male smokers be x.<\/p>\n

Total number of smokers = 3\/5 * 100 = 60<\/p>\n

Number of men = 1\/2 * 100 = 50<\/p>\n

Hence, number of male non-smokers is 50-x. Number of female smokers is 60-x and number of female non-smokers is x-10.<\/p>\n

Hence, probability of a person picked at random being a smoker and a male = x\/100<\/p>\n

As we do not know the value of x, we cannot determine the probability. Hence, option D.<\/p>\n

7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

There are a total of 8 men and 6 women.<\/p>\n

Number of ways in which the committee has exactly 3 men is $^8C_3 \\times ^6C_3 = 1120$
\nNumber of ways in which the committee has exactly 4 men is $^8C_4 \\times ^6C_2 = 1050$
\nNumber of ways in which the committee has exactly 5 men is $^8C_5 \\times ^6C_1 = 336$
\nNumber of ways in which the committee has exactly 6 men is $^8C_6 \\times ^6C_0 = 28$<\/p>\n

Hence, the total is $1120 + 1050 + 336 + 28 = 2534$<\/p>\n

8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Total number of arrangement= 6!=720<\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Total number of marbles in the urn = 15<\/p>\n

P(S) = Total possible outcomes<\/p>\n

= Selecting 3 marbles at random out of 15<\/p>\n

=> $P(S) = ^{15} C_3 = \\frac{15 \\times 14 \\times 13}{1 \\times 2 \\times 3}$<\/p>\n

= $455$<\/p>\n

P(E) = Favorable outcomes<\/p>\n

= Selecting 2 blue and 1 yellow marble.<\/p>\n

=> $P(E) =C^6_2 \\times C^4_1$<\/p>\n

= $\\frac{6 \\times 5}{1 \\times 2} \\times 4$<\/p>\n

= $60$<\/p>\n

$\\therefore$ Required probability = $\\frac{P(E)}{P(S)}$<\/p>\n

= $\\frac{60}{455} = \\frac{12}{91}$<\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The word ‘PRIDE’ consists of 5 distinct letters<\/p>\n

=> Number of arrangements = $5!$<\/p>\n

= $5 \\times 4 \\times 3 \\times 2 \\times 1 = 120$<\/p>\n

XAT Solved Previous papers<\/a><\/p>
\n

Take XAT Mock Test<\/a><\/p><\/p>\n

We hope this Permutation and Combination Questions Set-2 PDF for XAT with Solutions will be helpful to you.<\/p>\n","protected":false},"excerpt":{"rendered":"

Permutation and Combination Questions for XAT Set-2 PDF Download important Permutation and Combination Questions for XAT\u00a0 Set-2 PDF based on previously asked questions in the XAT exam. Practice Permutation and Combination Questions\u00a0 Set-2 PDF for the XAT exam. InstructionsInstructions: Study the given information carefully to answer the questions that follows. An urn contains 4 green, […]<\/p>\n","protected":false},"author":42,"featured_media":39284,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3,3167,125,350,362,366],"tags":[3284,1425],"class_list":{"0":"post-39277","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-cat","8":"category-downloads-en","9":"category-featured","10":"category-iift","11":"category-snap","12":"category-xat","13":"tag-permutation-and-combination-questions-for-xat","14":"tag-xat"},"better_featured_image":{"id":39284,"alt_text":"Permutation and Combination Questions for XAT Set-2 PDF","caption":"Permutation and Combination Questions for XAT Set-2 PDF\n","description":"Permutation and Combination Questions for XAT Set-2 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