{"id":39232,"date":"2019-12-13T17:56:18","date_gmt":"2019-12-13T12:26:18","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=39232"},"modified":"2019-12-13T17:56:18","modified_gmt":"2019-12-13T12:26:18","slug":"averages-questions-for-rrb-ntpc-set-3-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/averages-questions-for-rrb-ntpc-set-3-pdf\/","title":{"rendered":"Averages Questions for RRB NTPC Set-3 PDF"},"content":{"rendered":"

Averages Questions for RRB NTPC Set-3 PDF<\/strong><\/span><\/h1>\n

Download RRB NTPC Averages Questions Set-3 PDF. Top 10 RRB NTPC questions based on asked questions in previous exam papers very important for the Railway NTPC exam.<\/p>\n

Download Averages Questions Set-3 PDF<\/a><\/p>\n

Take a free mock test for RRB NTPC<\/a><\/p>\n

Download RRB NTPC Previous Papers PDF<\/a><\/p>\n\n

Question 1:\u00a0<\/b>Find the average of first 30 multiples of 7.<\/p>\n

a)\u00a094.8<\/p>\n

b)\u00a099.6<\/p>\n

c)\u00a0104.4<\/p>\n

d)\u00a0108.5<\/p>\n

Question 2:\u00a0<\/b>The average of 10 numbers is X and one of the number is 38. If 38 is replaced with 19, then what will be the new average?<\/p>\n

a)\u00a0$X – (\\frac{1}{2})$<\/p>\n

b)\u00a0$X – (\\frac{1}{19})$<\/p>\n

c)\u00a0$X – (\\frac{19}{10})$<\/p>\n

d)\u00a0$X – (\\frac{19}{9})$<\/p>\n

Question 3:\u00a0<\/b>The average height of A, B and C is 148 cm. If the average height of A and B is 136 cm and that of B and C is 125 cm, then what is the height (in cm) of B?<\/p>\n

a)\u00a056<\/p>\n

b)\u00a078<\/p>\n

c)\u00a0112<\/p>\n

d)\u00a0130<\/p>\n

Question 4:\u00a0<\/b>The average of two numbers is 10 and the product of two numbers is 96. Find the two numbers.<\/p>\n

a)\u00a03, 32<\/p>\n

b)\u00a012, 8<\/p>\n

c)\u00a01, 96<\/p>\n

d)\u00a024, 4<\/p>\n

Question 5:\u00a0<\/b>Average age of 4 daughters of a family is 12 years. The average age of daughters and their parents is 26 years. If the mother is 4 years older than the father, then what is the age (in years) of the father?<\/p>\n

a)\u00a056<\/p>\n

b)\u00a052<\/p>\n

c)\u00a048<\/p>\n

d)\u00a044<\/p>\n

RRB NTPC Previous Papers [Download PDF]<\/a><\/p>\n\n

Question 6:\u00a0<\/b>Average of 10 numbers is 14. If each number is multiplied by 6, then what will be the new average?<\/p>\n

a)\u00a070<\/p>\n

b)\u00a084<\/p>\n

c)\u00a056<\/p>\n

d)\u00a092<\/p>\n

Question 7:\u00a0<\/b>Average marks obtained by 19 boys of a college is 56. If the highest marks and lowest marks obtained are removed, then the average reduces by 2. What is the average of the highest and lowest marks obtained?<\/p>\n

a)\u00a077<\/p>\n

b)\u00a069<\/p>\n

c)\u00a073<\/p>\n

d)\u00a075<\/p>\n

Question 8:\u00a0<\/b>What will be the average of all the prime numbers before 19?<\/p>\n

a)\u00a08.28<\/p>\n

b)\u00a011.5<\/p>\n

c)\u00a05.34<\/p>\n

d)\u00a09.63<\/p>\n

Question 9:\u00a0<\/b>What is the average of 90, 250, 240, 204, and 616?<\/p>\n

a)\u00a0280<\/p>\n

b)\u00a0210<\/p>\n

c)\u00a0230<\/p>\n

d)\u00a0255<\/p>\n

Question 10:\u00a0<\/b>Average age of 6 boys is 14 years. Average age of 11 girls is 12 years. What is the average age (in years) of all boys and girls?<\/p>\n

a)\u00a012.7<\/p>\n

b)\u00a014.6<\/p>\n

c)\u00a019.3<\/p>\n

d)\u00a08.5<\/p>\n

Download General Science Notes PDF<\/a><\/p>\n

FREE RRB NTPC YOUTUBE VIDEOS<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

First thirty multiples of 7 will form an arithmetic progression : 7,14,21,…….,210<\/p>\n

First term, $a=7$ and common difference, $d=7$<\/p>\n

Sum of $n$ terms = $\\frac{n}{2}(a+l)$<\/p>\n

=> $S_{30}=\\frac{30}{2}(7+210)$<\/p>\n

= $15\\times217$<\/p>\n

Now, average of 30 terms = $\\frac{15\\times217}{30}$<\/p>\n

= $\\frac{217}{2}=108.5$<\/p>\n

=> Ans – (D)<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Average of 10 numbers\u00a0= $x$<\/p>\n

=> Sum of numbers = $10x$<\/p>\n

If 38 is replaced with 19, then\u00a0new average = $\\frac{10x-38+19}{10}$<\/p>\n

= $\\frac{10x-19}{10}$<\/p>\n

= $x – (\\frac{19}{10})$<\/p>\n

=> Ans – (C)<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let height of A, B and C be $a,b,c$ cm respectively.<\/p>\n

Average height of A, B and C\u00a0= $\\frac{(a+b+c)}{3}=148$<\/p>\n

=> $a+b+c=148\\times3=444$ ————(i)<\/p>\n

Also, average height of A and B =\u00a0$\\frac{(a+b)}{2}=136$<\/p>\n

=> $a+b=272$\u00a0 ————(ii)<\/p>\n

Similarly, $b+c=250$ ———–(iii)<\/p>\n

Adding equations (ii) and (iii), => $a+2b+c=522$ ———-(iv)<\/p>\n

Subtracting equation (i) from (iv), we get\u00a0:<\/p>\n

=> $b=522-444=78$<\/p>\n

$\\therefore$ Height of B =\u00a078<\/strong> cm<\/p>\n

=> Ans – (B)<\/p>\n

4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the numbers be $x$ and $y$<\/p>\n

Average = $\\frac{(x+y)}{2}=10$<\/p>\n

=> $x+y=10\\times2=20$ ————(i)<\/p>\n

Product = $xy=96$ ————(ii)<\/p>\n

Solving above equations, we get\u00a0: $x=12$ and $y=8$<\/p>\n

=> Ans – (B)<\/p>\n

5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Average age of 4 daughters of a family\u00a0= 12 years<\/p>\n

=> Sum of daughter’s age = $12\\times4=48$ years<\/p>\n

Average age of daughters and their parents\u00a0= 26 years<\/p>\n

=> Sum of ages of 4 daughters and 2 parents = $26\\times6=156$ years<\/p>\n

=> Sum of parents age = $156-48=108$ years ————(i)<\/p>\n

Let father’s age = $x$ years, => Mother’s age = $(x+4)$ years<\/p>\n

Substituting in equation (i),<\/p>\n

=> $x+x+4=108$<\/p>\n

=> $2x=108-4=104$<\/p>\n

=> $x=\\frac{104}{2}=52$ years<\/p>\n

=> Ans – (B)<\/p>\n

6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Average of 10 numbers is\u00a0= 14<\/p>\n

If each number is multiplied by 6, then\u00a0the average will also be multiplied by 14.<\/p>\n

=> New average = $6\\times14=84$<\/p>\n

=> Ans – (B)<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Average marks obtained by 19 boys of a college\u00a0= 56<\/p>\n

=> Total marks obtained = $56\\times19=1064$<\/p>\n

Let the highest marks and lowest marks respectively be $x$ and $y$<\/p>\n

According to ques,<\/p>\n

=> $\\frac{1064-x-y}{17}=56-2$<\/p>\n

=> $1064-(x+y)=54\\times17=918$<\/p>\n

=> $(x+y)=1064-918=146$<\/p>\n

Dividing both sides by 2, we get\u00a0:<\/p>\n

=> $\\frac{(x+y)}{2}=\\frac{146}{2}=73$<\/p>\n

$\\therefore$ Average of the highest and lowest marks obtained =\u00a073<\/strong><\/p>\n

=> Ans – (C)<\/p>\n

8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Sum\u00a0of all the prime numbers before 19<\/p>\n

= $2+3+5+7+11+13+17=58$<\/p>\n

=> Average = $\\frac{58}{7}=8.28$<\/p>\n

=> Ans – (A)<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Sum of numbers = 90 + 250 + 240 + 204 + 616 = 1400<\/p>\n

=> Average = $\\frac{1400}{5}=280$<\/p>\n

=> Ans – (A)<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Average age of 6 boys\u00a0= 14 years<\/p>\n

=> Total age of 6 boys = $6\\times14=84$ years<\/p>\n

Similarly, total age of 11 girls\u00a0= $11\\times12=132$ years<\/p>\n

$\\therefore$ Average age (in years) of all boys and girls = $\\frac{(84+132)}{(6+11)}$<\/p>\n

= $\\frac{216}{17}=12.7$<\/p>\n

=> Ans – (A)<\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

We hope this Averages Questions set-3 pdf for RRB NTPC exam will be highly useful for your Preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Averages Questions for RRB NTPC Set-3 PDF Download RRB NTPC Averages Questions Set-3 PDF. Top 10 RRB NTPC questions based on asked questions in previous exam papers very important for the Railway NTPC exam. Download RRB NTPC Previous Papers PDF Question 1:\u00a0Find the average of first 30 multiples of 7. a)\u00a094.8 b)\u00a099.6 c)\u00a0104.4 d)\u00a0108.5 Question […]<\/p>\n","protected":false},"author":41,"featured_media":39281,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,3171,31,1701,1679,1897,1605,1603,1601,1673],"tags":[3286,1593],"class_list":{"0":"post-39232","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways-en","10":"category-railways","11":"category-rpf-si-and-constable","12":"category-rrb-group-d","13":"category-rrb-group-d-2","14":"category-rrb-je","15":"category-rrb-ntpc","16":"category-rrb-ntpc-je","17":"category-rrb-para-medical-categories","18":"tag-averages-questions-for-rrb-ntpc-set-3-pdf","19":"tag-rrb-ntpc"},"better_featured_image":{"id":39281,"alt_text":"Averages Questions for RRB NTPC Set-3 PDF","caption":"Averages Questions for RRB NTPC Set-3 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