{"id":39150,"date":"2019-12-11T18:41:12","date_gmt":"2019-12-11T13:11:12","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=39150"},"modified":"2019-12-11T18:41:12","modified_gmt":"2019-12-11T13:11:12","slug":"number-series-questions-for-ssc-cgl-set-2-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/number-series-questions-for-ssc-cgl-set-2-pdf\/","title":{"rendered":"Number Series Questions for SSC-CGL Set-2 PDF"},"content":{"rendered":"

Number Series Questions for SSC-CGL Set-2 PDF<\/strong><\/span><\/h1>\n

Download SSC CGL Number Series Questions with answers set-2 PDF based on previous papers very useful for SSC CGL exams. Very important Number Series Questions for SSC exams.<\/p>\n

Download Number Series questions PDF<\/a><\/p>\n

Take a free SSC CGL mock test<\/a><\/p>\n

Get 790+ mocks for Rs. 100 – Coupon GOVTJOB<\/a><\/p>\n

Instructions<\/b><\/p>\n

A series is given, with one from missing, Choose the correct alternative from the given ones that will complete the series.<\/p>\n

Question 1:\u00a0<\/b>OTE, PUF, QVG, RWH, ?<\/p>\n

a)\u00a0SXI<\/p>\n

b)\u00a0TXI<\/p>\n

c)\u00a0SYJ<\/p>\n

d)\u00a0SXJ<\/p>\n

Question 2:\u00a0<\/b>16, 61, 25, 52, 36, 63, 49, ?<\/p>\n

a)\u00a036<\/p>\n

b)\u00a094<\/p>\n

c)\u00a072<\/p>\n

d)\u00a046<\/p>\n

Question 3:\u00a0<\/b>AFKPU, BGLQV, CHMRW, ??<\/p>\n

a)\u00a0DINSX<\/p>\n

b)\u00a0VQLGB<\/p>\n

c)\u00a0KLMNO<\/p>\n

d)\u00a0UVWXY<\/p>\n

Instructions<\/b><\/p>\n

In the following question, select the related number from the given alternatives.<\/p>\n

Question 4:\u00a0<\/b>11 : 121 : : 12 : ?<\/p>\n

a)\u00a0144<\/p>\n

b)\u00a0169<\/p>\n

c)\u00a0196<\/p>\n

d)\u00a0154<\/p>\n

Question 5:\u00a0<\/b>15 : 256 : : 14 : ?<\/p>\n

a)\u00a0225<\/p>\n

b)\u00a0144<\/p>\n

c)\u00a025<\/p>\n

d)\u00a095<\/p>\n

SSC CGL Previous Papers Download PDF<\/a><\/p>\n

SSC CGL Free Mock Test<\/a><\/p>\n

Question 6:\u00a0<\/b>108 : 11664 : : 107 : ?<\/p>\n

a)\u00a011449<\/p>\n

b)\u00a010449<\/p>\n

c)\u00a010849<\/p>\n

d)\u00a011749<\/p>\n

Instructions<\/b><\/p>\n

In the following question, select the missing number from the given series.<\/p>\n

Question 7:\u00a0<\/b>2, 5, 11, 23, ?<\/p>\n

a)\u00a047<\/p>\n

b)\u00a045<\/p>\n

c)\u00a044<\/p>\n

d)\u00a043<\/p>\n

Question 8:\u00a0<\/b>2, 3, 7, 16, 32, ?<\/p>\n

a)\u00a057<\/p>\n

b)\u00a076<\/p>\n

c)\u00a062<\/p>\n

d)\u00a067<\/p>\n

Question 9:\u00a0<\/b>8, 11, 14, 17, 20, ?<\/p>\n

a)\u00a021<\/p>\n

b)\u00a022<\/p>\n

c)\u00a023<\/p>\n

d)\u00a027<\/p>\n

Question 10:\u00a0<\/b>18, 14, 10, 6, ?<\/p>\n

a)\u00a02<\/p>\n

b)\u00a03<\/p>\n

c)\u00a04<\/p>\n

d)\u00a05<\/p>\n

Instructions<\/b><\/p>\n

In the following question, select the missing number from the given series.<\/p>\n

Question 11:\u00a0<\/b>3, 7, 13, 27, 53, ?<\/p>\n

a)\u00a0107<\/p>\n

b)\u00a0111<\/p>\n

c)\u00a0109<\/p>\n

d)\u00a0105<\/p>\n

Question 12:\u00a0<\/b>35, 50, 63, 82, ?, 122<\/p>\n

a)\u00a0101<\/p>\n

b)\u00a099<\/p>\n

c)\u00a0100<\/p>\n

d)\u00a0None of these<\/p>\n

Question 13:\u00a0<\/b>14, 22, 37, 61, 96, ?<\/p>\n

a)\u00a0152<\/p>\n

b)\u00a0132<\/p>\n

c)\u00a0144<\/p>\n

d)\u00a0162<\/p>\n

Question 14:\u00a0<\/b>263, 277, 290, 302, 313, ?<\/p>\n

a)\u00a0323<\/p>\n

b)\u00a0329<\/p>\n

c)\u00a0321<\/p>\n

d)\u00a0331<\/p>\n

Instructions<\/b><\/p>\n

In the following question, select the related number from the given alternatives.<\/p>\n

Question 15:\u00a0<\/b>431 : 12 : : 345 : ?<\/p>\n

a)\u00a012<\/p>\n

b)\u00a060<\/p>\n

c)\u00a045<\/p>\n

d)\u00a0105<\/p>\n

FREE SSC EXAM YOUTUBE VIDEOS<\/a><\/p>\n

18000+ Questions – Free SSC Study Material<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Series\u00a0:\u00a0OTE, PUF, QVG, RWH, ?<\/p>\n

The pattern followed in each letter of the terms is\u00a0:<\/p>\n

1st letter\u00a0: O (+1 letter) = P\u00a0(+1 letter) =\u00a0Q\u00a0(+1 letter) =\u00a0R\u00a0(+1 letter) =\u00a0S<\/p>\n

2nd letter\u00a0: T\u00a0(+1 letter) =\u00a0U\u00a0(+1 letter) =\u00a0V\u00a0(+1 letter) =\u00a0W\u00a0(+1 letter) =\u00a0X<\/p>\n

3rd letter : E\u00a0(+1 letter) =\u00a0F\u00a0(+1 letter) =\u00a0G\u00a0(+1 letter) =\u00a0H\u00a0(+1 letter) =\u00a0I<\/p>\n

Thus, missing term = SXI<\/strong><\/p>\n

=> Ans – (A)<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Series :\u00a016, 61, 25, 52, 36, 63, 49, ?<\/p>\n

In pairs of two, square of natural numbers and their reverse is written.<\/p>\n

Eg\u00a0:- 16 and 61, 25 and 52, 36 and 63<\/p>\n

Similarly, reverse of 49 =\u00a094<\/strong><\/p>\n

=> Ans – (B)<\/p>\n

3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Series\u00a0:\u00a0AFKPU, BGLQV, CHMRW, ??<\/p>\n

The pattern followed in each letter of the terms is\u00a0:<\/p>\n

1st letter\u00a0: A (+1 letter) = B\u00a0(+1 letter) =\u00a0C\u00a0(+1 letter) =\u00a0D<\/p>\n

2nd letter\u00a0: F\u00a0(+1 letter) =\u00a0G\u00a0(+1 letter) =\u00a0H\u00a0(+1 letter) =\u00a0I<\/p>\n

3rd letter : K\u00a0(+1 letter) =\u00a0L\u00a0(+1 letter) =\u00a0M\u00a0(+1 letter) =\u00a0N<\/p>\n

4th letter\u00a0: P\u00a0(+1 letter) =\u00a0Q\u00a0(+1 letter) =\u00a0R\u00a0(+1 letter) =\u00a0S<\/p>\n

5th letter\u00a0: U\u00a0(+1 letter) =\u00a0V\u00a0(+1 letter) =\u00a0W\u00a0(+1 letter) =\u00a0X<\/p>\n

Thus, missing term =\u00a0DINSX<\/strong><\/p>\n

=> Ans – (A)<\/p>\n

4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Expression =\u00a011 : 121 : : 12 : ?<\/p>\n

The pattern followed is = $x:x^2$<\/p>\n

Eg\u00a0:-\u00a0$11:(11)^2=11:121$<\/p>\n

Similarly, $(12)^2=144$<\/p>\n

=> Ans – (A)<\/p>\n

5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Expression =\u00a015 : 256 : : 14 : ?<\/p>\n

The pattern followed is = $x:(x+1)^2$<\/p>\n

Eg\u00a0:-\u00a0$15:(15+1)^2=15:256$<\/p>\n

Similarly, $(14+1)^2=(15)^2=225$<\/p>\n

=> Ans – (A)<\/p>\n

6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Expression =\u00a0108 : 11664 : : 107 : ?<\/p>\n

The pattern followed is = $x:x^2$<\/p>\n

Eg\u00a0:-\u00a0$108:(108)^2=108:11664$<\/p>\n

Similarly, $(107)^2=11449$<\/p>\n

=> Ans – (A)<\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The pattern followed is\u00a0that numbers of the form $(3\\times2^n)$ are added.<\/p>\n

2 $+(3\\times2^0)$ = 5<\/p>\n

5\u00a0$+(3\\times2^1)$ =\u00a011<\/p>\n

11\u00a0$+(3\\times2^2)$ =\u00a023<\/p>\n

23\u00a0$+(3\\times2^3)$ =\u00a047<\/strong><\/p>\n

=> Ans – (A)<\/p>\n

8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The pattern followed is :<\/p>\n

2 $+(1)^2$ = 3<\/p>\n

3\u00a0$+(2)^2$ =\u00a07<\/p>\n

7\u00a0$+(3)^2$ =\u00a016<\/p>\n

16\u00a0$+(4)^2$ =\u00a032<\/p>\n

32\u00a0$+(5)^2$ =\u00a057<\/strong><\/p>\n

=> Ans – (A)<\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

The pattern followed is\u00a0:<\/p>\n

8\u00a0+ 3 =\u00a011<\/p>\n

11\u00a0+ 3 =\u00a014<\/p>\n

14\u00a0+ 3 =\u00a017<\/p>\n

17\u00a0+ 3 =\u00a020<\/p>\n

20 + 3 =\u00a023<\/strong><\/p>\n

=> Ans – (C)<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

<\/u>The pattern followed is\u00a0:<\/p>\n

18\u00a0– 4 =\u00a014<\/p>\n

14\u00a0– 4 =\u00a010<\/p>\n

10\u00a0– 4 =\u00a06<\/p>\n

6 – 4 =\u00a02<\/strong><\/p>\n

=> Ans – (A)<\/p>\n

11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The pattern followed is\u00a0:<\/p>\n

3 $\\times2+1$ = 7<\/p>\n

7\u00a0$\\times2-1$ =\u00a013<\/p>\n

13\u00a0$\\times2+1$ =\u00a027<\/p>\n

27\u00a0$\\times2-1$ =\u00a053<\/p>\n

53\u00a0$\\times2+1$ =\u00a0107<\/strong><\/p>\n

=> Ans – (A)<\/p>\n

12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The pattern followed is\u00a0:<\/p>\n

$(6)^2-1$ = 35<\/p>\n

$(7)^2+1$ =\u00a050<\/p>\n

$(8)^2-1$ =\u00a063<\/p>\n

$(9)^2+1$ =\u00a082<\/p>\n

$(10)^2-1$ =\u00a099<\/strong><\/p>\n

$(11)^2+1$ =\u00a0122<\/p>\n

=> Ans – (B)<\/p>\n

13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

The pattern followed is\u00a0:<\/p>\n

14 $+(3)^2-1$ = 22<\/p>\n

22\u00a0$+(4)^2-1$ =\u00a037<\/p>\n

37\u00a0$+(5)^2-1$ =\u00a061<\/p>\n

61\u00a0$+(6)^2-1$ =\u00a096<\/p>\n

96\u00a0$+(7)^2-1$ =\u00a0144<\/strong><\/p>\n

=> Ans – (C)<\/p>\n

14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The pattern followed is\u00a0:<\/p>\n

263 + 14 = 277<\/p>\n

277 + 13 = 290<\/p>\n

290 + 12 = 302<\/p>\n

302 + 11 = 313<\/p>\n

313 + 10 =\u00a0323<\/strong><\/p>\n

=> Ans – (A)<\/p>\n

15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression =\u00a0431 : 12 : : 345 : ?<\/p>\n

The pattern followed is that the second number is the product of digits of first number.<\/p>\n

Eg\u00a0:- $4\\times3\\times1=12$<\/p>\n

Similarly,\u00a0$3\\times4\\times5=60$<\/p>\n

=> Ans – (B)<\/p>\n

SSC Free Previous Papers App<\/a><\/p>\n

We hope this Number Series Questions for SSC CGL Exam preparation is so helpful to you.<\/p>\n","protected":false},"excerpt":{"rendered":"

Number Series Questions for SSC-CGL Set-2 PDF Download SSC CGL Number Series Questions with answers set-2 PDF based on previous papers very useful for SSC CGL exams. Very important Number Series Questions for SSC exams. Instructions A series is given, with one from missing, Choose the correct alternative from the given ones that will complete 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