{"id":39141,"date":"2019-12-11T16:07:43","date_gmt":"2019-12-11T10:37:43","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=39141"},"modified":"2019-12-11T16:07:43","modified_gmt":"2019-12-11T10:37:43","slug":"simple-and-compound-interest-questions-for-rrb-ntpc-set-3-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/simple-and-compound-interest-questions-for-rrb-ntpc-set-3-pdf\/","title":{"rendered":"Simple and Compound Interest Questions for RRB-NTPC (Set-3 PDF)"},"content":{"rendered":"

Simple and Compound Interest Questions for RRB NTPC Set-3 PDF<\/strong><\/span><\/h1>\n

Download RRB NTPC Simple & Compound Interest Questions Set-3 PDF. Top 10 RRB NTPC questions based on asked questions in previous exam papers very important for the Railway NTPC exam.<\/p>\n

Download Simple & Compound Interest Questions PDF<\/a><\/p>\n

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Download RRB NTPC Previous Papers PDF<\/a><\/p>\n\n

Question 1:\u00a0<\/b>The amount (in Rs) received at 10% per annum compound interest after 3 yrs is Rs 1,19,790. What was the principal?<\/p>\n

a)\u00a090000<\/p>\n

b)\u00a01,00,000<\/p>\n

c)\u00a080000<\/p>\n

d)\u00a075000<\/p>\n

Question 2:\u00a0<\/b>What is the total earning after 2 years from \u20b9 18,750 on variable compound interest if the rate of interest for the first 4 year is 4% and for the second, it is 8%?<\/p>\n

a)\u00a0\u20b9 1,740<\/p>\n

b)\u00a0\u20b9 1,760<\/p>\n

c)\u00a0\u20b9 1,670<\/p>\n

d)\u00a0\u20b9 2,310<\/p>\n

Question 3:\u00a0<\/b>In how many months will Rs 8,000 yield Rs 2,648 as compound interest at 20% per annum compounded semi-annually?<\/p>\n

a)\u00a018<\/p>\n

b)\u00a024<\/p>\n

c)\u00a012<\/p>\n

d)\u00a030<\/p>\n

Question 4:\u00a0<\/b>What is the rate of interest (in %) if simple interest earned on a certain sum for the 3rd year is Rs 2,000 and compound interest earned in 2 years is Rs 4,160?<\/p>\n

a)\u00a08<\/p>\n

b)\u00a010<\/p>\n

c)\u00a012<\/p>\n

d)\u00a06<\/p>\n

Question 5:\u00a0<\/b>On what sum of money. the interest for one year at 12% p.a. compounded half yearly is \u20b9 1,545?<\/p>\n

a)\u00a0\u20b9 12,500<\/p>\n

b)\u00a0\u20b9 12,875<\/p>\n

c)\u00a0\u20b9 25,750<\/p>\n

d)\u00a0\u20b9 24,300<\/p>\n

RRB NTPC Previous Papers [Download PDF]<\/a><\/p>\n\n

Question 6:\u00a0<\/b>A sum of \u20b9800 invested on simple interest becomes \u20b91200 in 8 years. What will be simple interest for 6 years on the sum at the same rate of interest?<\/p>\n

a)\u00a0\u20b9240<\/p>\n

b)\u00a0\u20b9210<\/p>\n

c)\u00a0\u20b9250<\/p>\n

d)\u00a0\u20b9300<\/p>\n

Question 7:\u00a0<\/b>A sum of \u20b92000 is invested on simple interest for three years at the rate of 10% per annum,then the amount will be:<\/p>\n

a)\u00a0\u20b92900<\/p>\n

b)\u00a0\u20b92600<\/p>\n

c)\u00a0\u20b92300<\/p>\n

d)\u00a0\u20b92500<\/p>\n

Question 8:\u00a0<\/b>A sum of \u20b9 4200 becomes \u20b9 5082 in 3 years rate simple interest. What is the rate of interest per annum?<\/p>\n

a)\u00a08%<\/p>\n

b)\u00a09%<\/p>\n

c)\u00a05%<\/p>\n

d)\u00a07%<\/p>\n

Question 9:\u00a0<\/b>The difference between simple and compound interests compounded annually, on a certain sum of money for 2 years at 6% pa is \u20b9 3.6. What is the sum?<\/p>\n

a)\u00a0\u20b9800<\/p>\n

b)\u00a0\u20b9750<\/p>\n

c)\u00a0\u20b91,000<\/p>\n

d)\u00a0\u20b91,250<\/p>\n

Question 10:\u00a0<\/b>The simple interest for the second year on a certain sum at a certain rate of interest is \u20b9 1000. What is the sum of the interest accrued on it for the $6^{th}, 7^{th}$ and $8^{th}$ years?<\/p>\n

a)\u00a0\u20b93200<\/p>\n

b)\u00a0\u20b93300<\/p>\n

c)\u00a0\u20b93000<\/p>\n

d)\u00a0\u20b93630<\/p>\n

Download General Science Notes PDF<\/a><\/p>\n

FREE RRB NTPC YOUTUBE VIDEOS<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$P(1+\\frac{R}{100})^{3}$=119790<\/p>\n

$P(1+\\frac{10}{100})^{3}$=119790<\/p>\n

$P(\\frac{11}{10})^{3}$=119790<\/p>\n

P=119790*1000\/1331
\nP=Rs 90000<\/p>\n

2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

P=18750<\/p>\n

1st year = 4%<\/p>\n

2nd year = 8%<\/p>\n

Interest for 1st year $= \\frac{18750\\times 4\\times 1}{100} = 750$<\/p>\n

Principal after 1st year $= 18750+750 = 19500$<\/p>\n

Interest for 2nd year $=\\frac{19500\\times 8\\times 1}{100} = 1560$<\/p>\n

Total interest = 750+1560 = 2310<\/p>\n

Option D is correct.<\/p>\n

3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$P(1+\\frac{R\/2}{100})^{2n}-P$=2648
\n$(1+\\frac{R\/2}{100})^{2n}-1=2648\/8000<\/p>\n

4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$PTR\/100$=2000
\n$PR$=200000
\n$P(1+\\frac{R}{100}^{2})-P$=4160
\n$P((200+R)(R))$=4160
\nDividing both the equations we have
\n1\/(R+200) =20\/4160
\nR+200=208
\nR=8%<\/p>\n

5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

In compound interest,<\/p>\n

Final amount,A$=P(1+r\/n)^nt$.<\/p>\n

where P is principal amount,r is rate of interest,n is number of times interest applied and t is number of times period elapsed.<\/p>\n

So,interest gain$=A-P.$<\/p>\n

So,$P(1+0.12\/2)^2-P=1545.$<\/p>\n

or,$P\u00d71.1236-P=1545.$<\/p>\n

or,$P=(1545\/0.1236).$<\/p>\n

or,$P=12500.$<\/p>\n

A is correct choice.<\/p>\n

 <\/p>\n

6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

SI= (P*R*T)\/100<\/p>\n

Given , P= 800 RS<\/p>\n

T= 8 years<\/p>\n

SI= Amount – P= 1200-800 = 400 Rs<\/p>\n

SI = (400*R*8)\/100<\/p>\n

R = (25\/4) or 6.25<\/p>\n

Now, given , T= 6 Years, P = 800 Rs, R= 6.25%<\/p>\n

SI = (800*6*6.25)\/100 =\u00a0\u20b9300<\/p>\n

 <\/p>\n

7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Simple Interest (SI) is given as = $\\frac{PRT}{100}$, where P is Principle amount, R is Rate of Interest,T is Time period<\/p>\n

Here, P = 2000, R = 10 % So, SI =$\\frac{(2000)(10)(3)}{100}$ = 600<\/p>\n

Hence the total amount will be SI + P = 2000 + 600 = 2600.<\/p>\n

8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let the rate of interest be R%.
\nSimple Interest = Rs.5082 – Rs.4200 = Rs.882
\n$\\dfrac{4200\\times R\\times3}{100} = 882$
\n=> 3R = 21 => R = 7
\nTherefore, Rate of interest = 7%<\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the principal be Rs.10000x
\nSimple Interest for 1 year at 6% per annum = Rs.600x
\nSimple Interest for 2 years at 6% per annum = Rs.600*2 = Rs.1200x
\nAmount of Compound Interest for 2 years at 6% per annum = $10000x \\times \\dfrac{106}{100} \\times \\dfrac{106}{100} = Rs.11236x
\nCompound Interest = Rs.11236x – Rs.10000x = Rs.1236x
\nDifference between SI and CI = 1236x – 1200x = Rs.36x
\nGiven, 36x = Rs.3.6
\n=> x = 0.1
\nTherefore, Principal = Rs.10000x = Rs.10000*0.1 = Rs.1000<\/p>\n

10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Simple interest on every year is same and so for any one year it will be 1000 as given
\nSo for the three years given it will be 3*1000=3000<\/p>\n\n

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We hope this Simple & Compound Interest Questions set-3 pdf for RRB NTPC exam will be highly useful for your Preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Simple and Compound Interest Questions for RRB NTPC Set-3 PDF Download RRB NTPC Simple & Compound Interest Questions Set-3 PDF. Top 10 RRB NTPC questions based on asked questions in previous exam papers very important for the Railway NTPC exam. Download RRB NTPC Previous Papers PDF Question 1:\u00a0The amount (in Rs) received at 10% per 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