{"id":39074,"date":"2019-12-10T17:18:34","date_gmt":"2019-12-10T11:48:34","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=39074"},"modified":"2019-12-10T17:27:27","modified_gmt":"2019-12-10T11:57:27","slug":"mensuration-questions-for-ssc-cpo-set-3-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/mensuration-questions-for-ssc-cpo-set-3-pdf\/","title":{"rendered":"Mensuration Questions for SSC-CPO Set-3 PDF"},"content":{"rendered":"

Mensuration Questions for SSC-CPO Set-3 PDF<\/span><\/strong><\/span><\/h1>\n

Download SSC CPO Mensuration Questions with answers set-3 PDF based on previous papers very useful for SSC CPO exams. Very important Mensuration Questions for SSC exams.<\/p>\n

Download Mensuration Questions for SSC Cpo set-3 PDF<\/a><\/p>\n

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Question 1:\u00a0<\/b>The volume of a right circular cone is 2464 $cm^3$. If the height of cone is 12 cm, then what will be the radius of its base?<\/p>\n

a)\u00a012 cm<\/p>\n

b)\u00a08 cm<\/p>\n

c)\u00a014 cm<\/p>\n

d)\u00a010 cm<\/p>\n

Question 2:\u00a0<\/b>A hollow iron pipe is 10 cm long and its external diameter is 18 cm. If the thickness of the pipe is 2 cm and iron weighs 8.5 g\/cm$^3$, then the weight of the pipe from the following is closest to:<\/p>\n

a)\u00a08.54 kg<\/p>\n

b)\u00a09.54 kg<\/p>\n

c)\u00a07.54 kg<\/p>\n

d)\u00a05.54 kg<\/p>\n

Question 3:\u00a0<\/b>The ratio between the perimeter and the breadth of a rectangle is 3 : 1. If the area of the rectangle is 310 sq. cm, the length of the rectangle is nearly:<\/p>\n

a)\u00a011.45 cm<\/p>\n

b)\u00a010.45 cm<\/p>\n

c)\u00a012.45 cm<\/p>\n

d)\u00a013.45 cm<\/p>\n

Question 4:\u00a0<\/b>A circle, with radius 8 cm, which has the area equal to the area of a triangle with base 8 cm. Then the length of the corresponding altitude of triangle is:<\/p>\n

a)\u00a0$38 \\pi$ cm<\/p>\n

b)\u00a0$16 \\pi$ cm<\/p>\n

c)\u00a0$18 \\pi$ cm<\/p>\n

d)\u00a0$8 \\pi$ cm<\/p>\n

Question 5:\u00a0<\/b>A copper wire is bent in the form of an equilateral triangle of area $4 \\sqrt{3} cm^2$.If the same wire is bent into the form of a square, the area of the square will be:<\/p>\n

a)\u00a016 sq.cm<\/p>\n

b)\u00a09 sq. cm<\/p>\n

c)\u00a0144 sq. cm<\/p>\n

d)\u00a064 sq.cm<\/p>\n

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Question 6:\u00a0<\/b>The length, breadth and height of a room are in the ratio of 4 : 3 : 2. The cost of carpeting the floor at \u20b9 10 per square meter is \u20b9 480. The height of the room is:<\/p>\n

a)\u00a010 m<\/p>\n

b)\u00a02 m<\/p>\n

c)\u00a06 m<\/p>\n

d)\u00a04 m<\/p>\n

Question 7:\u00a0<\/b>Two concentric circles with radii p cm and (p+ 2) cm are drawn on a paper. The difference between their areas is 44 sq. cm What is the value of p?(Take $\\pi=\\frac{22}{7}$)<\/p>\n

a)\u00a01.5<\/p>\n

b)\u00a05<\/p>\n

c)\u00a06<\/p>\n

d)\u00a02.5<\/p>\n

Question 8:\u00a0<\/b>A rectangular farm has to be fenced on one long side, one short side and one diagonal. If the cost of fencing is \u20b9 10 per meter, the area of the farm is 4800 m$^2$ and the short side is 60 m long, the cost of doing the job will be:<\/p>\n

a)\u00a0\u20b92100<\/p>\n

b)\u00a0\u20b91800<\/p>\n

c)\u00a0\u20b92400<\/p>\n

d)\u00a0\u20b93600<\/p>\n

Question 9:\u00a0<\/b>A wall of 12 m $\\times$ 8 m has a door of 3 m $\\times$ 1.5 m and two windows each of 1.5 m $\\times$ 1.5 m. Find the area of wall that can be painted(free from doors and windows).<\/p>\n

a)\u00a080 sq.cm<\/p>\n

b)\u00a087 sq.cm<\/p>\n

c)\u00a096 sq.cm<\/p>\n

d)\u00a065 sq.cm<\/p>\n

Question 10:\u00a0<\/b>What will be the cost of fencing a circular garden of radius 35 m at the rate of \u20b916 per meter?(Take $\\pi = \\frac{22}{7}$)<\/p>\n

a)\u00a0\u20b93520<\/p>\n

b)\u00a0\u20b93240<\/p>\n

c)\u00a0\u20b92850<\/p>\n

d)\u00a0\u20b93160<\/p>\n

Question 11:\u00a0<\/b>A hall is 15 m long and 12 m broad.If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, the volume(in $m^3$) of the\u00a0 hall is:<\/p>\n

a)\u00a01600<\/p>\n

b)\u00a0900<\/p>\n

c)\u00a01200<\/p>\n

d)\u00a0720<\/p>\n

Question 12:\u00a0<\/b>A circle, with radius 8 cm, which has the area equal to the area of a triangle with base 8 cm. Then the length of the corresponding altitude of triangle is:<\/p>\n

a)\u00a0$38\\ \\pi\\ cm$<\/p>\n

b)\u00a0$16\\ \\pi\\ cm$<\/p>\n

c)\u00a0$8\\ \\pi\\ cm$<\/p>\n

d)\u00a0$18\\ \\pi\\ cm$<\/p>\n

Question 13:\u00a0<\/b>The curved surface area of a right circular cylinder of height 28 cm is 176 $cm^2$ . The volume(in $cm^3$) of cylinder is (Take $\\pi = \\frac{22}{7}$)<\/p>\n

a)\u00a066<\/p>\n

b)\u00a0110<\/p>\n

c)\u00a088<\/p>\n

d)\u00a0176<\/p>\n

Question 14:\u00a0<\/b>The area of an equilateral triangular park is equal to $5\\sqrt{3}$ times the area of a triangular field with sides 18 m, 80 m and 82 m. What is the side of the triangular park?<\/p>\n

a)\u00a0125 m<\/p>\n

b)\u00a0120 m<\/p>\n

c)\u00a0140 m<\/p>\n

d)\u00a0100 m<\/p>\n

Question 15:\u00a0<\/b>The diagonal of a square is 14 cm. What will be the length of the diagonal of the square whose area is double of the area of first square?<\/p>\n

a)\u00a0$28\\surd2\u00a0 cm$<\/p>\n

b)\u00a0$14\\surd2\u00a0 cm$<\/p>\n

c)\u00a0$28\u00a0 cm$<\/p>\n

d)\u00a0$21\\surd2\u00a0 cm$<\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Volume of right circular cone = $\\dfrac{1}{3} \\pi r^2 h$
\nGiven, h = 12 cm and Volume = $2464 cm^3$
\nThen, $\\dfrac{1}{3} \\times \\dfrac{22}{7} \\times r^2 \\times 12 = 2464$<\/p>\n

=> $r^2 = 196$
\n=> r = 14 cm
\nTherefore, Radius of the cone = 14 cm<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

External radius of the pipe = 9 cm
\nInternal radius of the pipe = 9-2 = 7cm
\nVolume of the pipe = $\\pi \\times (9^2 – 7^2) \\times 10 = 1005.71 cm^3$
\nWeight of the pipe per $cm^3 = 8.5 gm$
\nThen, Total weight = 1005.71*8.5 = 8548 gm = 8.54 kg<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the length and breath of the rectangle be l cm and b cm
\nGiven, $\\dfrac{2(l+b)}{b} = \\dfrac{3}{1}$
\n=> 2(l+b) = 3b
\n=> 2l+2b = 3b
\n=> b = 2l
\nGiven, lb = 310
\nSubstituting b = 2l in above equation
\n$l\\times 2l = 310$
\n$2l^2 = 310$
\n=> $l^2 = 155$
\nWe know that $12^2 = 144$ and $13^2 = 169$.
\nHence, The value of l lies in between 12 and 13.
\nTherefore, From the options, l = 12.45 cm<\/p>\n

4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Area of a circle=$\\pi*r*r$
\nArea of a triangle=(1\/2)*b*h
\nh=64$\\pi$*2*b\/8
\nh=16$\\pi$<\/p>\n

5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Area of a equilateral triangle=$\\sqrt{3}a^{2}\/4$
\n$\\sqrt{3}a^{2}\/4$=$4\\sqrt{3}$
\na=4 cm
\nTotal length =3*4
\n=12 cm
\nSide of each square=12\/4
\n=3 cm
\nArea=9 sqcm<\/p>\n

6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let length,breath and height be 4x,3x and 2x respectively
\nArea of the floor=12$x^{2}$
\nTotal cost of flooring=12$x^{2}$*10
\n12$x^{2}$*10=480
\nx=2
\nl=8 cm,b=6 cm and h=4 cm<\/p>\n

7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Given $\\pi R^{2}-\\pi r^{2}$=44
\n$R^{2}-r^{2}$=14
\nR=p+2,r=p
\nR-r=2 R+r=2p+2
\n(R+r)(R-r)=14
\n2p+2=7
\np=2.5<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Area of the farm=4800
\nl*b=4800
\ngiven b=60 m
\nl*60=4800
\nl=80 m
\nIn a rectangle diagonal=$\\sqrt{(l^{2}+b^{2})}$
\n=$\\sqrt{(80^{2}+60^{2})}$
\n=$\\sqrt{(10000)}$
\n=100 m
\nSo total fencing required=100+80+60=240 m
\nCost of fencing each meter=Rs 10
\nFor 240m it is 240*10=Rs 2400<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Area of the wall=96 sq cm
\nArea of door=3*1.5=4.5 sq cm
\nArea of two windows=2*1.5*1.5
\n=4.5 cm
\nTherefore required area=96-(4.5+4.5)
\n=96-9
\n=87 sq cm<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Circumference of the circular garden =$2\\pi r$
\nArea=2*(22\/7)*35
\n=220 sq mt
\nCost for each each mt=Rs 16
\nCost for whole garden=220*16
\n=Rs 3520<\/p>\n

11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Area of the floor and ceiling will be same and it is equal
\ni.e l*b=15*12=180 sq m
\nArea of four walls will be 2*l*h+2*b*h=2h(l+b)
\n2h(l+b)=360
\nh(12+15)=180
\nh=180\/27
\nh=20\/3
\nVolume=l*b*h=12*15*20\/3
\n=1200 cubic meters<\/p>\n

12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Area of a circle=$\\pi r^{2}$
\nArea of a triangle=(1\/2)bh
\nGiven both are equal
\nTherefore $\\pi r^{2}$=(1\/2)bh
\n$\\pi\u00a08^{2}$=(1\/2)8h
\nh=$16\\pi$<\/p>\n

13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Lateral surface area of a cylinder=$2\\pi r h$
\nTherefore 2*(22\/7)*r*28=176
\nr=8\/8
\nr=1 cm
\nVolume of a cylinder=$(\\pi) r^{2}h$
\n=22*1*1*28\/7
\n=88 sq cm<\/p>\n

14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Given sides of the triangle are 18,80 and 82 cm
\nthese are the sides of a right angled triangle as 9,40,41 is a Pythagorean triplet
\nSo area of a right angled triangle=(1\/2)bh
\n=(1\/2)*80*18
\n=720 sq cm
\nGiven area a equilateral triangle=$5\\sqrt{3}$*720
\n$\\sqrt{3}a^{2}\/4$=$5\\sqrt{3}$*720
\n$a^{2}$=36*100*4
\na=6*10*2
\na=120 cm<\/p>\n

15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Diagonal of first square = 14 cm
\n$\\sqrt{2}a = 14 => a = \\dfrac{14}{\\sqrt{2}}$ where a = side of first square
\nArea of first square $= (\u00a0\\dfrac{14}{\\sqrt{2}})^2 = \\dfrac{196}{2} = 98 cm^2$
\nArea of second square $= 2\\times98 = 196 cm^2$
\nSide of second square $ = \\sqrt{196} = 14 cm$
\nDiagonal of second square $=14\\times\\sqrt{2}$ = $14\\sqrt{2} cm$.<\/p>\n

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We hope this Mensuration Set-3 PDF Questions for SSC CPO Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Mensuration Questions for SSC-CPO Set-3 PDF Download SSC CPO Mensuration Questions with answers set-3 PDF based on previous papers very useful for SSC CPO exams. Very important Mensuration Questions for SSC exams. Take a free mock test for SSC CPO Download SSC CPO Previous Papers PDF Question 1:\u00a0The volume of a right circular cone is […]<\/p>\n","protected":false},"author":49,"featured_media":39082,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3165,8,1254,471,3167,125,2999,229,228,1127,2067,2071,2069,277,255,1665,31,3171,243,1701,1679,1897,1605,1603,1601,1673,232,231,9,504,378,1493,1459,1611,1741,1268,1441,1],"tags":[3202,3117],"class_list":{"0":"post-39074","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-banking-en","8":"category-banking","9":"category-competitive-exams","10":"category-current-affairs-2","11":"category-downloads-en","12":"category-featured","13":"category-ibps-en","14":"category-ibpsclerk","15":"category-ibpspo","16":"category-ibps-rrb","17":"category-ibps-rrb-clerk","18":"category-ibps-rrb-clerk-en","19":"category-ibps-rrb-po","20":"category-ibps-so","21":"category-ibps-specialist-officer-so","22":"category-lic","23":"category-railways","24":"category-railways-en","25":"category-rbi","26":"category-rpf-si-and-constable","27":"category-rrb-group-d","28":"category-rrb-group-d-2","29":"category-rrb-je","30":"category-rrb-ntpc","31":"category-rrb-ntpc-je","32":"category-rrb-para-medical-categories","33":"category-sbiclerk","34":"category-sbipo","35":"category-ssc","36":"category-ssc-cgl","37":"category-ssc-chsl","38":"category-ssc-cpo","39":"category-ssc-gd","40":"category-ssc-je","41":"category-ssc-mts","42":"category-ssc-stenographer","43":"category-stenographer","44":"category-uncategorized","45":"tag-mensuration-questions","46":"tag-ssc-cpo-exam"},"better_featured_image":{"id":39082,"alt_text":"Mensuration 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