CAT Linear Equations Questions\u00a0consists of important linear equations questions for CAT. This CAT questions will help in solving quantitative aptitude questions in CAT.<\/p>\n
Taking a free CAT mock test<\/a> and solving CAT past papers<\/a>\u00a0to score more in the Quant section of CAT.<\/p>\n You can download the\u00a0CAT Linear Equations Questions or you can go through the details below.<\/p>\n CAT Booster Videos for just Rs. 1999<\/a><\/p>\n CAT Linear Equations Questions:<\/strong><\/p>\n Question 1:<\/strong><\/p>\n I bought 5 pens, 7 pencils and 4 erasers. Rajan bought 6 pens, 8 erasers and 14 pencils for an amount which was half more what I had paid. What per cent of the total amount paid by me was paid for the pens?<\/p>\n A. 37.5%<\/p>\n B. 62.5%<\/p>\n C. 50%<\/p>\n D. None of these<\/p>\n Question 2:<\/strong><\/p>\n Out of two-thirds of the total number of basketball matches, a team has won 17 matches and lost 3 of them. What is the maximum number of matches that the team can lose and still win more than three- fourths of the total number of matches, if it is true that no match can end in a tie?<\/p>\n A. 4<\/p>\n B. 6<\/p>\n C. 5<\/p>\n D. 3<\/p>\n Question 3:<\/strong><\/p>\n A piece of string is 40 cm long. It is cut into three pieces. The longest piece is three times as long as the middle-sized and the shortest piece is 23 cm shorter than the longest piece. Find the length of the shortest piece.<\/p>\n A. 27<\/p>\n B. 5<\/p>\n C. 4<\/p>\n D. 9<\/p>\n Question 4:<\/strong><\/p>\n Mayank, Mirza, Little and Jaspal bought a motorbike for $60. Mayank paid one-half of the sum of the amounts paid by the other boys. Mirza paid one-third of the sum of the amounts paid by the other boys. Little paid one-fourth of the sum of the amounts paid by the other boys. How much did Jaspal have to pay?<\/p>\n A. $15<\/p>\n B. $13<\/p>\n C. $17<\/p>\n D. None of these<\/p>\n Question 5:<\/strong><\/p>\n Two full tanks, one shaped like a cylinder and the other like a cone, contain jet fuel. The cylindrical tank holds 500 litres more than the conical tank. After 200 litres of fuel has been pumped out from each tank the cylindrical tank contains twice the amount of fuel in the conical tank. How many litres of fuel did the cylindrical tank have when it was full?<\/p>\n A. 700<\/p>\n B. 1000<\/p>\n C. 1100<\/p>\n D. 1200<\/p>\n Download CAT maths Tricks PDF<\/a> and also download Linear equations concepts PDF<\/a><\/p>\n Download CAT Quantitative Aptitude Questions PDF<\/a><\/p>\n Answer and Solutions for CAT Linear Equations Questions:<\/strong><\/p>\n 1)<\/strong> Answer (B)<\/p>\n Let the cost of pen, pencil and eraer be x,y,z respectively 2)<\/strong> Answer (A)<\/p>\n Total matches played = 17+3\u00a0= 20 3)<\/strong> Answer (C)<\/p>\n Let the longest piece be x 4)<\/strong> Answer (B)<\/p>\n Let the amount paid by Mayank be x. So, amount paid by the other three = 2x 5)<\/strong> Answer (D)<\/p>\n Let the current capacity of conical flask be C. So, cylinder = C+500. Hope you will find this CAT Linear Equations Questions useful, you can also download all our CAT Verbal Ability PDF’s<\/a>\u00a0and CAT Quantitative Aptitude questions PDF<\/a>.<\/p>\n
\n5x+7y+4z = A
\n6x+8z+14y = 3A\/2
\n4x + 16\/3 z + 28\/3 y = A
\nComparing two equations
\n5x+7y+4z = 4x+16\/3 z + 28\/3 y
\nx = 7\/3 y + 4\/3 z
\n3x = 7y+4z
\nNow required percentage = $$\\frac{5x}{5x+7y+4z}*100 = \\frac{5x}{5x+3x} = 62.5%$$<\/p>\n
\nTotal matches = 20*$$\\frac{3}{2}$$ = 30
\nNumber of wins required = 75% of 30 = 22.5 = 23 wins
\n23-17 = 6 more wins are required out of 10 matches to maintain 75% win recor which means there would be 4 losses.<\/p>\n
\nShortest piece = x – 23
\nMiddle-sized piece = x\/3
\nSo, x + x – 23 + x\/3 = 40 => 7x\/3 = 63 => x = 27
\nShortest piece = 27 – 23 = 4<\/p>\n
\n=> Total bill = x+2x = 3x = 60 => x = 20. So, Mayank paid 20
\nSimilarly, amount paid by Mirza + 3*Amount paid by Mirza = 60
\n=> Amount paid by Mirza = 15
\nAmount paid by Little + 4*Amount paid by Little = 60
\n=> Amount paid by Little = 12
\nSo, amount paid by Jaspal = 60 – (20+15+12) = 60 – 47 = $13<\/p>\n
\nAfter pumping out 200 liters, C+300 = 2(C-200) => C = 700
\nSo, full capacity of cylinder = 700+500 = 1200<\/p>\n