{"id":38655,"date":"2019-12-03T17:20:00","date_gmt":"2019-12-03T11:50:00","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=38655"},"modified":"2019-12-03T17:20:00","modified_gmt":"2019-12-03T11:50:00","slug":"time-speed-and-distance-questions-for-xat","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/time-speed-and-distance-questions-for-xat\/","title":{"rendered":"Time, Speed and Distance Questions for XAT"},"content":{"rendered":"

Time, Speed and Distance Questions for XAT<\/strong><\/span><\/h1>\n

Download important Time, Speed and Distance Questions for XAT PDF based on previously asked questions in XAT exam. Practice Time, Speed and Distance Questions PDF for XAT exam.<\/p>\n

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Instructions<\/b><\/p>\n

Directions for the following two questions: Cities A and B are in different time zones. A is located 3000 km east of B. The table below describes the schedule of an airline operating non-stop flights between A and B. All the times indicated are local and on the same day.<\/p>\n

Assume that planes cruise at the same speed in both directions. However, the effective speed is influenced by a steady wind blowing from east to west at 50 km per hour.<\/p>\n

\"\"<\/p>\n

Question 1:\u00a0<\/b>What is the time difference between A and B?<\/p>\n

a)\u00a01 hour and 30 minutes<\/p>\n

b)\u00a02 hours<\/p>\n

c)\u00a02 hours and 30 minutes<\/p>\n

d)\u00a01 hour<\/p>\n

e)\u00a0Cannot be determined<\/p>\n

Question 2:\u00a0<\/b>It takes six technicians a total of 10 hr to build a new server from Direct Computer, with each working at the same rate. If six technicians start to build the server at 11 am, and one technician per hour is added beginning at 5 pm, at what time will the server be completed?<\/p>\n

a)\u00a06.40 pm<\/p>\n

b)\u00a07 pm<\/p>\n

c)\u00a07.20 pm<\/p>\n

d)\u00a08 pm<\/p>\n

Question 3:\u00a0<\/b>Three small pumps and a large pump are filling a tank. Each of the three small pump works at 2\/3 the rate of the large pump. If all four pumps work at the same time, they should fill the tank in what fraction of the time that it would have taken the large pump alone?<\/p>\n

a)\u00a04\/7<\/p>\n

b)\u00a01\/3<\/p>\n

c)\u00a02\/3<\/p>\n

d)\u00a03\/4<\/p>\n

Question 4:\u00a0<\/b>Three machines, A, B and C can be used to produce a product. Machine A will take 60 hours to produce a million units. Machine B is twice as fast as Machine A. Machine C will take the same amount of time to produce a million units as A and B running together. How much time will be required to produce a million units if all the three machines are used simultaneously?<\/p>\n

a)\u00a012 hours<\/p>\n

b)\u00a010 hours<\/p>\n

c)\u00a08 hours<\/p>\n

d)\u00a06 hour<\/p>\n

Question 5:\u00a0<\/b>In a watch, the minute hand crosses the hour hand for the third time exactly after every 3 hr 18 min and 15s of normal time. What is the time gained or lost by this watch in one day?<\/p>\n

a)\u00a014 min 10 s lost<\/p>\n

b)\u00a013 min 48 s lost<\/p>\n

c)\u00a013 min 20 s gained<\/p>\n

d)\u00a014 min 40 s gained<\/p>\n

Question 6:\u00a0<\/b>Two boats, traveling at 5 and 10 kms per hour, head directly towards each other. They begin at a distance of 20 kms from each other. How far apart are they (in kms) one minute before they collide.<\/p>\n

a)\u00a01\/12<\/p>\n

b)\u00a01\/6<\/p>\n

c)\u00a01\/4<\/p>\n

d)\u00a01\/3<\/p>\n

Question 7:\u00a0<\/b>On a 20 km tunnel, connecting two cities A and B, there are three gutters (1, 2 and 3). The distance between gutters 1 and 2 is half the distance between gutters 2 and 3. The distance from city A to its nearest gutter, gutter 1, is equal to the distance of city B from gutter 3. On a particular day, the hospital in city A receives information that an accident has happened at gutter 3. The victim can be saved only if an operation is started within 40 min. An ambulance started from city A at 30 km\/hr and crossed gutter 1 after 5 min. If the driver had doubled the speed after that, what is the maximum amount of time would the doctor get to attend the patient at the hospital. Assume 1 min is elapsed for taking the patient into and out of the ambulance?<\/p>\n

a)\u00a04 min<\/p>\n

b)\u00a02.5 min<\/p>\n

c)\u00a01.5 min<\/p>\n

d)\u00a0The patient died before reaching the hospital<\/p>\n

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Question 8:\u00a0<\/b>A train approaches a tunnel AB. Inside the tunnel is a cat located at a point that is 3\/8 of the distance AB measured from the entrance A. When the train whistles the cat runs. If the cat moves to the entrance of the tunnel A, the train catches the cat exactly at the entrance. If the cat moves to the exit B, the train catches the cat at exactly the exit. What is the ratio of speed of train and cat ?<\/p>\n

a)\u00a03 : 1<\/p>\n

b)\u00a04 :1<\/p>\n

c)\u00a05 : 1<\/p>\n

d)\u00a0None of these<\/p>\n

Question 9:\u00a0<\/b>City Bus Corporation runs two buses from terminus A to terminus B,one from each of the terminuses such that each bus makes 5 round trips in a day. There are no stops in between. These buses ply back and forth on the same route at different but uniform speeds. Each morning the buses start at 7 AM from the respective terminuses. They meet for the first time at a distance of 7 km from terminus A. Their next meeting is at a distance of 4 km from terminus B, while travelling in opposite directions. Assuming that the time taken by the buses at the terminuses is negligibly small, and the cost of running a bus is 20 per km, find the daily cost of running the buses (in )<\/p>\n

a)\u00a03200<\/p>\n

b)\u00a06800<\/p>\n

c)\u00a04000<\/p>\n

d)\u00a06400<\/p>\n

e)\u00a0None of the above<\/p>\n

Question 10:\u00a0<\/b>A ping pong ball is dropped from a 45 metres high multi-storey building. The ball bounces back three fifth of the distance each time before coming to rest. The total distance traversed by the ball is:<\/p>\n

a)\u00a0150 m<\/p>\n

b)\u00a0180 m<\/p>\n

c)\u00a0175 m<\/p>\n

d)\u00a0None of the above<\/p>\n

Question 11:\u00a0<\/b>The speed of a boat when travelling downstream is 32 Kms. \/ Hr. , whereas when travelling upstream it is 28 kms\/hr. What is the speed of the boat in still water ?<\/p>\n

a)\u00a027 Kms.\/Hr.<\/p>\n

b)\u00a029 Kms.\/ Hr.<\/p>\n

c)\u00a031 Kms.\/ Hr.<\/p>\n

d)\u00a0Cannot be determined<\/p>\n

e)\u00a0None of these<\/p>\n

Question 12:\u00a0<\/b>A boat\u2019s speed with the current is 15 kmph and the boat\u2019s speed against the current is 5 kmph. What is the speed of the current?<\/p>\n

a)\u00a015 kmph<\/p>\n

b)\u00a010 kmph<\/p>\n

c)\u00a05 kmph<\/p>\n

d)\u00a020 kmph<\/p>\n

e)\u00a0None of the above<\/p>\n

Question 13:\u00a0<\/b>A train 350 m long takes 36 seconds to cross a man running at a speed of 5 km\/h in the direction opposite to that of train. What is the speed of the train?<\/p>\n

a)\u00a030 km\/h<\/p>\n

b)\u00a040 km\/h<\/p>\n

c)\u00a024 km\/h<\/p>\n

d)\u00a034 km\/h<\/p>\n

e)\u00a0Other than those given as options<\/p>\n

Question 14:\u00a0<\/b>The speeds of a boat downstream and upstream are 18 km\/hr and 8 km\/hr respectively. What is the speed of the stream?<\/p>\n

a)\u00a02 km\/hr<\/p>\n

b)\u00a03 km\/hr<\/p>\n

c)\u00a04 km\/hr<\/p>\n

d)\u00a05 km\/hr<\/p>\n

e)\u00a0None of these<\/p>\n

Question 15:\u00a0<\/b>Two trains crosses each other in 14 sec when they are moving in opposite direction, and when they are moving in same direction they crosses each other in 3 min 2 sec. Find the speed of the faster train by what percent more than the speed of the slower train ?<\/p>\n

a)\u00a016.67%<\/p>\n

b)\u00a017.33%<\/p>\n

c)\u00a016.33%<\/p>\n

d)\u00a017.67%<\/p>\n

e)\u00a018.33%<\/p>\n

XAT Decision making practice questions<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let the speed of the plane be p Kmph.
\nSo the speed of plane from A to B will be ‘p+50’ and the speed from B to A will be ‘p-50’.
\nWe notice that the plane goes from B to A stays there for 1 hr and again come back to B with total time duration 12 hrs.
\nSo we have $\\frac{3000}{p-50} + 1 + \\frac{3000}{p+50} = 12$.
\nWe can clearly see that speed of the plane is 550 which satisfies the above equation.
\nSo from going to A from B the plane takes $\\frac{3000}{550-50} = 6$ hrs.
\nSo time at B when plane reaches at A is 2 pm .
\nHence the time difference between A and B is 1 hr.<\/p>\n

 <\/p>\n

Alternatively,
\nLet speed of flight be s,
\nSince A is to the east of B, A is ahead of be in time
\nLet A be ahead of B in time by a hours
\nDeparture from A = 4PM, Arrival at B = 8PM
\nTravel time = 8 – 4 +a = 4 + a
\nSince City B is behind city A by ‘a’ hours, the actual travel time is ‘a’ hours more than the difference of local times.
\nSimilarly when one travels from B to A, since B is ahead of A by ‘a’ hrs, actual travel time is ‘a’ hours less than total
\ni.e. B->A Travel time = (3PM – 8AM) – a = 7 -a
\nTotal distance travelled = Speed $\\times$ Time taken ….(1)
\nFrom A to B, the wind is favourable \/ in same direction as flight
\nHence from (1), we have
\nA->B >>> $3000 = (s+50)(4+a) => 3000(7-a) = (s+50)(4+a)(7-a)$ …(2)
\nB->A >>> $3000 = (s-50)(7-a) => 3000(4+a) = (s-50)(7-a)(4+a)$ …(3)
\n(2) – (3) => $3000(3-2a) = 100(7-a)(4+a) => a^2-63a+62=0 => a=1\/62$
\nHence the time difference between A and B is 1 hr.<\/p>\n

2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let the work done by each technician in one hour be 1 unit.
\nTherefore, total work to be done = 60 units.
\nFrom 11 AM to 5 PM, work done = 6*6 = 36 units.
\nWork remaining = 60 – 36 = 24 units.
\nWork done in the next 3 hours = 7 units + 8 units + 9 units = 24 units.
\nTherefore, the work gets done by 8 PM.<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the work done by the big pump in one hour be 3 units.
\nTherefore, work done by each of the small pumps in one hour = 2 units.
\nLet the total work to be done in filling the tank be 9 units.
\nTherefore, time taken by the big pump if it operates alone = 9\/3 = 3 hours.
\nIf all the pumps operate together, the work done in one hour = 3 + 2*3 = 9 units.
\nTogether, all of them can fill the tank in 1 hour.
\nRequired ratio = 1\/3<\/p>\n

4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

As machine B’s efficiency is twice as of A’s, Hence, it will complete its work in 30 hours.
\nAnd C’s efficiency is putting A and B together i.e. = 20 hours $( (\\frac{1}{60} + \\frac{1}{30})^{-1})$
\nNow if all three work together, then it will be completed in x (say) days.<\/p>\n

$\\frac{1}{x} = \\frac{1}{20} + \\frac{1}{30} + \\frac{1}{60}$<\/p>\n

or x = 10 hours<\/p>\n

5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

In a normal watch, the minute hand crosses the hour’s hand after every 1 hour 5 minutes and 27 seconds.
\nSo, the third time the hour’s hand crosses the minute’s hand is after 3 hours 16 minutes and 21 seconds.<\/p>\n

In this watch, the time taken for this to happen is 3 hours 18 minutes and 15 seconds.
\nHence, the watch loses 1 minute and 54 seconds after every 3 hours 18 minutes and 15 seconds.
\n18 minutes and 15 seconds = 1095 seconds = 1095\/3600 $\\approx$ .304 hours.
\n=> 3 hours 18 minutes and 15 seconds = 3.304 hours
\nSo, time lost in a day is $1\\frac{54}{60}*\\frac{24}{3.304} = \\frac{114}{60}*\\frac{24}{3.304} \\approx 13.8$
\nSo, the time lost by the watch in a day is approximately equal to 13 minutes and 48 seconds.<\/p>\n

6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

The relative speed is 15 km\/hr = 15 km\/60 min = 0.25 km\/min = 250 m\/min.
\nTherefore, one minute before they collide, they are at a distance of 250m.<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the distance between gutter 1 and A be x and between gutter 1 and 2 be y.<\/p>\n

Hence, x + y + 2y + x = 20 => 2x+3y=20<\/p>\n

Also x = 30kmph * 5\/60 = 2.5km<\/p>\n

Hence, y = 5km<\/p>\n

After the ambulance doubles its speed it goes at 60kmph i.e. 1km per min. Hence, time taken for the rest of the journey = 15*2 + 2.5 = 32.5<\/p>\n

It takes 1 min to load and unload the patient.<\/p>\n

Hence, total time = 5 + 32.5 + 1 = 38.5 mins<\/p>\n

So, the doctor would get 1.5 min to attend to the patient.<\/p>\n

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8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the length of the tunnel be x and distance of the train to entrance A be y. Let the speeds of train and cat be t and c respectively.<\/p>\n

Hence, when the cat runs 3x\/8, the train covers y.<\/p>\n

=> (3x\/8)\/c = y\/t — (1)<\/p>\n

When the cat runs 5x\/8 to the other end, the train covers x+y<\/p>\n

=>(5x\/8)\/c = (x+y)\/t —(2)<\/p>\n

Taking ratio of (1) to (2)<\/p>\n

3\/5 = y\/(x+y) => 3x = 2y —(3)<\/p>\n

Substituting (3) in (1)<\/p>\n

(2y\/8)\/c = y\/t<\/p>\n

=> t = 4c<\/p>\n

Hence the ratio t:c is 4:1.<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the distance between two termini = $P$ km
\nLet the speed of the bus started from Terminus A be x and that of the bus started from terminus B be y.
\nThe two buses met at a distance of 7km from Terminus A
\nSince the time of travel for both buses is the same.
\n$\\frac{7}{x}$=$\\frac{P-7}{y}$
\n$\\frac{x}{y}$=$\\frac{7}{P-7}$\u00a0\u00a0\u00a0\u00a0\u00a0———– Eq (1)
\nThey met again at a distance of 4 km from terminus B.
\nDistance travelled by bus which started from Terminus A = P+4
\nDistance travelled by bus which started from Terminus A = 2P-4
\nSo $\\frac{x}{y}$ = $\\frac{P+4}{2P-4}$\u00a0\u00a0\u00a0–Eg (2)
\nOn solving Eq 1& 2, we get P=17 km
\nEach bus covers a distance of 17*2=34 km on a round trip.
\nEach bus makes 5 round trips in a day =34*5=170 km
\nCost of running one bus = $170 \\times 20 = 3400$
\n$\\therefore$ Cost of running both buses = $3400 \\times 2 = Rs. 6,800$<\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

When the ball is dropped from 45m height it will cover a distance of 45m while going down after rebound it’ll cover a distance of $45*\\frac{3}{5}$ while going up and\u00a0a distance of $45*\\frac{3}{5}$ while going down again. after 2nd rebound it’ll cover a distance of\u00a0$45*\\frac{3}{5}*\\frac{3}{5}$\u00a0while going up and\u00a0a distance of $45*\\frac{3}{5}*\\frac{3}{5}$ while going down again and so on<\/p>\n

i.e. total distance traveled by the ball is 45 + $45*\\frac{3}{5}$ +\u00a0$45*\\frac{3}{5}$ +\u00a0$45*\\frac{3}{5}*\\frac{3}{5}$ +\u00a0$45*\\frac{3}{5}*\\frac{3}{5}$ +………..<\/p>\n

this form 2 infinite GPs as\u00a045 + $45*\\frac{3}{5}$ +\u00a0$45*\\frac{3}{5}*\\frac{3}{5}$+……. and\u00a0$45*\\frac{3}{5}$+$45*\\frac{3}{5}*\\frac{3}{5}$+….<\/p>\n

For 1st GP a=45 and r=$\\frac{3}{5}$ therefore sum of this infinite GP is $\\frac{45}{1-\\frac{3}{5}}$ = $\\frac{225}{2}$<\/p>\n

For 2nd GP a=45*$\\frac{3}{5}$\u00a0 and r=$\\frac{3}{5}$ therefore sum of this infinite GP is\u00a0 $\\frac{45*\\frac{3}{5}}{1-\\frac{3}{5}}$ = $\\frac{145}{2}$<\/p>\n

Therefore our answer =\u00a0$\\frac{225}{2}+\\frac{145}{2}$ = 180 m i.e. option ‘B’<\/p>\n

11)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Let the speed of boat in still water be v and the speed of water be x.<\/p>\n

Boat speed while going upstream = v-x = 28<\/p>\n

Boat speed while going downstream = v+x = 32<\/p>\n

=> 2v = 60 => v = 30<\/p>\n

Hence, none of these is the correct answer.<\/p>\n

12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

With the current => downstream
\nAgainst the current => upstream
\nLet the speed of the boat be \u2018s\u2019 and the speed of the river be \u2018r\u2019.
\nSo, s – r = 5 and s + r = 15
\n=>2s = 20 => s = 10 and r = 5 kmph
\nSpeed of the current = 5 kmph<\/p>\n

13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let the speed of the train be x m\/s
\nSpeed of the man = 5km\/hr = 1.388m\/s
\nRelative speed of man when he is running in opposite direction = (x+1.388)
\nHowever train crossess him in 36 seconds = 350\/36 =\u00a0 9.722 m\/s
\nx+1.388 = 9.722
\nx = 8.334 m\/s
\nx = 30 km\/hr<\/p>\n

14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let the speed of the boat in still water be \u2018u\u2019.
\nLet the speed of the stream be \u2018v\u2019.
\nThe speed of the boat upstream = u-v
\nThe speed of the boat downstream = u+v
\nIt is given that,
\nu-v = 8 and u+v = 18
\nSolving them we get, u = 13 and v = 5.
\nThus the speed of the stream is 5 km\/hr.
\nHence the answer to this question is Option D.<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

let the speed of faster train be F m\/s<\/p>\n

And slower train be S m\/s<\/p>\n

When they move in same direction relative speed = (F -S) m\/s<\/p>\n

Time taken = 14 sec<\/p>\n

When they move in opposite direction = (F+S) m\/s<\/p>\n

Time taken in this case = 182 sec<\/p>\n

In both cases they are covering same distance<\/p>\n

So , (F+S )\u00d7 14 = (F-S ) \u00d7 182<\/p>\n

12 F = 14 S<\/p>\n

F = $\\frac{7}{6}$ S<\/p>\n

so faster train is 1\/6 more than the slower one which means it is 16.67% faster than the slower train.<\/p>\n

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We hope this Time, Speed and Distance\u00a0 Questions PDF for XAT with Solutions will be helpful to you.<\/p>\n","protected":false},"excerpt":{"rendered":"

Time, Speed and Distance Questions for XAT Download important Time, Speed and Distance Questions for XAT PDF based on previously asked questions in XAT exam. Practice Time, Speed and Distance Questions PDF for XAT exam. Instructions Directions for the following two questions: Cities A and B are in different time zones. A is located 3000 […]<\/p>\n","protected":false},"author":42,"featured_media":38662,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3,3167,169,350,1352,362,366],"tags":[3176,1346],"class_list":{"0":"post-38655","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-cat","8":"category-downloads-en","9":"category-downloads","10":"category-iift","11":"category-iift-en","12":"category-snap","13":"category-xat","14":"tag-time-speed-and-distance-questions-for-xat","15":"tag-xat-2019"},"better_featured_image":{"id":38662,"alt_text":"Time Speed and Distance Questions for XAT","caption":"Time Speed and Distance Questions for XAT\n","description":"Time Speed and Distance Questions for 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