{"id":38534,"date":"2019-11-29T18:27:40","date_gmt":"2019-11-29T12:57:40","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=38534"},"modified":"2019-11-29T18:27:40","modified_gmt":"2019-11-29T12:57:40","slug":"time-and-work-questions-for-ssc-cpo-set-2-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/time-and-work-questions-for-ssc-cpo-set-2-pdf\/","title":{"rendered":"Time and Work Questions for SSC CPO Set-2 PDF"},"content":{"rendered":"

Time and Work Questions for SSC CPO Set-2 PDF<\/strong><\/span><\/h2>\n

Download SSC CPO Time and work Questions with answers set-2 PDF based on previous papers very useful for SSC CPO exams. Very important time and work Questions for SSC exams.<\/p>\n

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Question 1:\u00a0<\/b>If A and B together can complete a piece of work in 15 days and B alone in 20 days, in how many days can A alone complete the work ?<\/p>\n

a)\u00a060<\/p>\n

b)\u00a045<\/p>\n

c)\u00a040<\/p>\n

d)\u00a030<\/p>\n

Question 2:\u00a0<\/b>By walking at 3\/4 of his usual speed, a man reaches his office 20 minutes later than his usual time. The usual time taken by him to reach his office is<\/p>\n

a)\u00a075 minutes<\/p>\n

b)\u00a060 minutes<\/p>\n

c)\u00a040 minutes<\/p>\n

d)\u00a030 minutes<\/p>\n

Question 3:\u00a0<\/b>A can complete a piece of work in 18 days, B in 20 days and C in 30 days. B and C together start the work and are forced to leave after 2 days. The time taken by A alone to complete the remaining work is<\/p>\n

a)\u00a010 days<\/p>\n

b)\u00a012 days<\/p>\n

c)\u00a015 days<\/p>\n

d)\u00a016 days<\/p>\n

Question 4:\u00a0<\/b>A can complete 1\/3 of a work in 5 days and B, 2\/5 of the work in 10 days. In how many days both A and B together can complete the work ?<\/p>\n

a)\u00a010<\/p>\n

b)\u00a09$\\frac{3}{8}$<\/p>\n

c)\u00a08$\\frac{4}{5}$<\/p>\n

d)\u00a07$\\frac{1}{2}$<\/p>\n

Question 5:\u00a0<\/b>7 men can complete a piece of work in 12 days. How many additional men will be required to complete double the work in 8 days ?<\/p>\n

a)\u00a028<\/p>\n

b)\u00a021<\/p>\n

c)\u00a014<\/p>\n

d)\u00a07<\/p>\n

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Question 6:\u00a0<\/b>One pipe fills a water tank three times faster than another pipe. If the two pipes together can fill the empty tank in 36 minutes, then how much time will the slower pipe alone take to fill the tank ?<\/p>\n

a)\u00a01 hour 21 minutes<\/p>\n

b)\u00a01 hour 48 minutes<\/p>\n

c)\u00a02 hours<\/p>\n

d)\u00a02 hour 24 minutes<\/p>\n

Question 7:\u00a0<\/b>Water flows into a tank which is 200m long and 150m wide, through a pipe of cross-section $0.3m \\times 0.2m$ at 20 km\/hour. Then the time (in minutes) for the water level in the tank to reach 8cm is<\/p>\n

a)\u00a050<\/p>\n

b)\u00a0120<\/p>\n

c)\u00a0150<\/p>\n

d)\u00a0200<\/p>\n

Question 8:\u00a0<\/b>A and B together can do a works in 12 days. B and C together do it in 15 days. If A’s efficiency is twice that of C, then the days required for B alone to finish the work is<\/p>\n

a)\u00a060<\/p>\n

b)\u00a030<\/p>\n

c)\u00a020<\/p>\n

d)\u00a015<\/p>\n

Question 9:\u00a0<\/b>A and B can do a work in 12 days, B and C can do the same work in 15 days, C and A can do the same time work in 20 days. The time taken by A, B and C to do the same work is<\/p>\n

a)\u00a05 days<\/p>\n

b)\u00a010 days<\/p>\n

c)\u00a015 days<\/p>\n

d)\u00a020 days<\/p>\n

Question 10:\u00a0<\/b>A sum of money becomes eight times in 3 years, if the rate is compounded annually. In how much time will the same amount at the same compound rate become sixteen times?<\/p>\n

a)\u00a06 years<\/p>\n

b)\u00a04 years<\/p>\n

c)\u00a08 years<\/p>\n

d)\u00a05 years<\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

B does complete work in 20 days
\nhence in unit time amount of work done will be $\\frac{1}{20}$
\nsuppose in unit time amount of work done by A will be $x$
\nhence when they are working together amount of work done in unit time will be
\n$x$ +\u00a0$\\frac{1}{20}$ =\u00a0$\\frac{1}{15}$ (given)
\n$x$=\u00a0$\\frac{1}{60}$
\nit means A does\u00a0$\\frac{1}{60}$ amount of work in unit time
\nnow unit work will be done ,when A alone is working, in 60 days<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

As distance is constant and we know s =\u00a0\\frac{d}{t} (where s is distance and t is time)
\nhence st = constant
\nor $s_{1}t_{1}$= $s_{2}t_{2}$
\nor $s_{1}t_{1}$=$ \\frac{3}{4}s_{1}(t_{1}+ 20)$
\nhence $t_{1}$ = 60<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Amount of work done by B and C together in unit time will be $\\frac{1}{20}+\\frac{1}{30}$=$\\frac{5}{60}$<\/p>\n

hence in two days amount of work done by B and C together =\u00a0$\\frac{10}{60}$
\n=$\\frac{1}{6}$
\nremaining work =\u00a0$\\frac{5}{6}$<\/p>\n

A does\u00a0$\\frac{1}{18}$ amount of work in unit time<\/p>\n

hence\u00a0\u00a0$\\frac{5}{6}$ amount of work will be done in 15 days.<\/p>\n

4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

A does 1\/3 of work in 5 days
\nhence in 1 day it will do 1\/15 amount of work<\/p>\n

similarly B will do 2\/50 amount of work in one day<\/p>\n

Together they will do\u00a0$\\frac{1}{15} + \\frac{2}{50}$ = $\\frac{16}{150}$ amount of work in one day<\/p>\n

hence unit work will be done in\u00a0$\\frac{150}{16}$ days or\u00a09$\\frac{3}{8}$ days<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

In 12 days unit work is done by 7 men
\nhence in 1 day\u00a0$\\frac{1}{12}$ amount of work is done by 7 men
\nso 1 man does\u00a0$\\frac{1}{12\\times7}$ amount of work in one day.
\nwe have to find no of man to do double the work\u00a0in 8 days with above efficiency
\nlet’s say we have $x$ men
\nnow total work done in single day will be\u00a0$\\frac{1}{12\\times7} \\times x $
\nhence in 8 days =\u00a0$\\frac{1}{12\\times7} \\times 8x $ = 2 ( as work is doubled)
\n$x$ = 21
\nadditional man required = 14<\/p>\n

6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

let’s say slower pipe fills tank in $x$min. so in 1 min. it fills $\\frac{1}{x}$
\nand faster one will fill in $\\frac{x}{3}$ min. so in 1 min. it fills $\\frac{3}{x}$
\ntogether in 1 min. they will fill ($\\frac{1}{x}$+$\\frac{3}{x}$) of tank
\nas it is given that together they will fill the tank in 36 min.
\nso
\n$(\\frac{1}{x}+\\frac{3}{x})\\times36$ = 1
\nor $x$ = 144 min.<\/p>\n

7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Volume of water in time t to reach at 8 cm. height will be equal to volume of tank till height 8 cm.
\nhence volume of water in time t to reach at height 8 cm. =$ .3\\times .2\\times \\frac{2000}{6}\\times$( spped in per minute)
\nwhich is equal to volume of tank =$ 200\\times150\\times \\frac{8}{100}$<\/p>\n

equating both and after solving we will get t = 120 min.<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

A and B will do in 1 day, $\\frac{1}{12}$ amount of work
\nB and C will do in 1 day,\u00a0$\\frac{1}{15}$ amount of work
\nHence adding up above two equations
\nA+2B+C will do in 1 day,\u00a0$\\frac{9}{60}$ amount of work
\nas it is mentioned A=2C (i.e. efficiency of A is twice of C)
\nSo 2C+2B+C will do in 1 day\u00a0$\\frac{9}{60}$ amount of work
\nor 2(B+C) + C =\u00a0$\\frac{9}{60}$
\nor C = $\\frac{1}{60}$ (as B+C =\u00a0$\\frac{1}{15}$ )
\nor B =\u00a0$\\frac{1}{15}$ –\u00a0$\\frac{1}{60}$ =\u00a0$\\frac{1}{20}$
\nSo B alone will do work in 20 days.<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

A+B will do $\\frac{1}{12}$ amount of work in a day.
\nB+C will do $\\frac{1}{15}$ amount of work.
\nC+A will do $\\frac{1}{20}$ amount of work.
\nAdding above 3 equation 2(A+B+C) = $\\frac{1}{5}$
\nor (A+B+C) =\u00a0$\\frac{1}{10}$
\nHence together A,B and C will do complete work in 10 days.<\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$P(1+ \\frac{r}{100})^3 = 8P$ (Where P is principal amount , r is rate)
\nSo $(1+ \\frac{r}{100}) = 2$
\nNow for 16 times
\n$P(1+ \\frac{r}{100})^t = 16P$
\nor $2^t = 16$
\nor $t = 4$<\/p>\n

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We hope this time and work Questions for SSC CPO Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Time and Work Questions for SSC CPO Set-2 PDF Download SSC CPO Time and work Questions with answers set-2 PDF based on previous papers very useful for SSC CPO exams. Very important time and work Questions for SSC exams. Take a free mock test for SSC CPO Download SSC CPO Previous Papers PDF Question 1:\u00a0If […]<\/p>\n","protected":false},"author":41,"featured_media":38539,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[1911,1627,1244,1629,8,1254,169,125,1585,2999,229,228,1127,2071,2067,2069,277,255,285,1665,31,243,1701,1679,1897,1605,1603,1601,1673,232,231,9,504,378,1493,1459,1611,1741,1268,1441,1],"tags":[2002,3043],"class_list":{"0":"post-38534","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-ap-exams-en","8":"category-ap-si","9":"category-appsc","10":"category-apslprb","11":"category-banking","12":"category-competitive-exams","13":"category-downloads","14":"category-featured","15":"category-ib-security-assistant-answer-key","16":"category-ibps-en","17":"category-ibpsclerk","18":"category-ibpspo","19":"category-ibps-rrb","20":"category-ibps-rrb-clerk-en","21":"category-ibps-rrb-clerk","22":"category-ibps-rrb-po","23":"category-ibps-so","24":"category-ibps-specialist-officer-so","25":"category-latest-jobs","26":"category-lic","27":"category-railways","28":"category-rbi","29":"category-rpf-si-and-constable","30":"category-rrb-group-d","31":"category-rrb-group-d-2","32":"category-rrb-je","33":"category-rrb-ntpc","34":"category-rrb-ntpc-je","35":"category-rrb-para-medical-categories","36":"category-sbiclerk","37":"category-sbipo","38":"category-ssc","39":"category-ssc-cgl","40":"category-ssc-chsl","41":"category-ssc-cpo","42":"category-ssc-gd","43":"category-ssc-je","44":"category-ssc-mts","45":"category-ssc-stenographer","46":"category-stenographer","47":"category-uncategorized","48":"tag-ssc-exam","49":"tag-ssc-maths-questions"},"better_featured_image":{"id":38539,"alt_text":"Time 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