{"id":38192,"date":"2019-11-26T18:05:09","date_gmt":"2019-11-26T12:35:09","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=38192"},"modified":"2019-11-26T18:05:09","modified_gmt":"2019-11-26T12:35:09","slug":"mensuration-questions-for-ssc-cgl-set-3-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/mensuration-questions-for-ssc-cgl-set-3-pdf\/","title":{"rendered":"Mensuration Questions for SSC CGL Set-3 PDF"},"content":{"rendered":"

Mensuration Questions for SSC CGL Set-3 PDF<\/strong><\/span><\/h2>\n

Download SSC CGL Mensuration questions with answers PDF based on previous papers very useful for SSC CGL exams. Very important Geometry questions for SSC exams.<\/p>\n

Download Mensuaration Questions for SSC CGL Set-3 PDF<\/a><\/p>\n

Take a free SSC CGL mock test<\/a><\/p>\n

Get 790+ mocks for Rs. 100 – Coupon GOVTJOB<\/a><\/p>\n

Question 1:\u00a0<\/b>The circumference of a circle is 88 cm. Find its radius (in cm).<\/p>\n

a)\u00a028<\/p>\n

b)\u00a015<\/p>\n

c)\u00a014<\/p>\n

d)\u00a030<\/p>\n

Question 2:\u00a0<\/b>The volume of a hemisphere is 19404 cm3. Find its diameter (in cm).<\/p>\n

a)\u00a042<\/p>\n

b)\u00a021<\/p>\n

c)\u00a084<\/p>\n

d)\u00a063<\/p>\n

Question 3:\u00a0<\/b>If the perimeter of a semicircle is 36 cm, then find its area (in $cm^{2}$)<\/p>\n

a)\u00a0154<\/p>\n

b)\u00a035<\/p>\n

c)\u00a077<\/p>\n

d)\u00a070<\/p>\n

Question 4:\u00a0<\/b>The lengths of the two diagonals of a rhombus are 7 cm and 24 cm. Find the length of its perimeter (in cm).<\/p>\n

a)\u00a025<\/p>\n

b)\u00a0100<\/p>\n

c)\u00a075<\/p>\n

d)\u00a050<\/p>\n

Question 5:\u00a0<\/b>Find the total surface area (in $cm^{2}$) of a right circular cone of diameter 21 cm and slant height 11 cm.<\/p>\n

a)\u00a0467.5<\/p>\n

b)\u00a0384<\/p>\n

c)\u00a0724<\/p>\n

d)\u00a0709.5<\/p>\n

SSC CGL Previous Papers Download PDF<\/a><\/p>\n

SSC CGL Free Mock Test<\/a><\/p>\n

Question 6:\u00a0<\/b>Calculate the area (in $cm^{2}$) of a circle of radius 17.5 cm.<\/p>\n

a)\u00a01925<\/p>\n

b)\u00a0962.5<\/p>\n

c)\u00a0809.5<\/p>\n

d)\u00a01619<\/p>\n

Question 7:\u00a0<\/b>The area of an equilateral triangle is 25\u221a3 $cm^{2}$. Find its side (in cm).<\/p>\n

a)\u00a010<\/p>\n

b)\u00a05<\/p>\n

c)\u00a020<\/p>\n

d)\u00a030<\/p>\n

Question 8:\u00a0<\/b>Find the total surface area $(in cm^2)$ of a cuboid of length, breadth and height of 10.5 cm, 8 cm and 9 cm respectively.<\/p>\n

a)\u00a0607<\/p>\n

b)\u00a0767<\/p>\n

c)\u00a0769<\/p>\n

d)\u00a0501<\/p>\n

Question 9:\u00a0<\/b>The length of the diagonal and the breadth of a rectangle is 26 cm and 10 cm respectively. Calculate its area $(in cm^2)$<\/p>\n

a)\u00a0480<\/p>\n

b)\u00a096<\/p>\n

c)\u00a0240<\/p>\n

d)\u00a0192<\/p>\n

Question 10:\u00a0<\/b>Find the total surface area (in cm\u00b2) of a right circular cylinder of diameter 42 cm and height 14 cm.<\/p>\n

a)\u00a04488<\/p>\n

b)\u00a04250<\/p>\n

c)\u00a04010<\/p>\n

d)\u00a04620<\/p>\n

FREE SSC EXAM YOUTUBE VIDEOS<\/a><\/p>\n

18000+ Questions – Free SSC Study Material<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let radius of circle = $r$ cm<\/p>\n

=> Circumference = $2\\pi r=88$<\/p>\n

=> $2\\times\\frac{22}{7}\\times r=88$<\/p>\n

=> $r=88\\times\\frac{7}{44}$<\/p>\n

=> $r=2\\times7=14$ cm<\/p>\n

=> Ans – (C)<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let radius of hemisphere = $r$ cm<\/p>\n

Volume of hemisphere = $\\frac{2}{3}\\times\\pi r^3$<\/p>\n

=> $\\frac{2}{3}\\times\\frac{22}{7}\\times(r)^3=19404$<\/p>\n

=> $(r)^3=19404\\times\\frac{21}{44}$<\/p>\n

=> $(r)^3=441\\times21$<\/p>\n

=> $r=\\sqrt[3]{21\\times21\\times21}=21$ cm<\/p>\n

$\\therefore$ Diameter = $2\\times21=42$ cm<\/p>\n

=> Ans – (A)<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let radius of semi circle = $r$ cm<\/p>\n

=> Perimeter of semi circle = $\\pi r+2r=36$<\/p>\n

=> $r(\\frac{22}{7}+2)=36$<\/p>\n

=> $r(\\frac{22+14}{7})=36$<\/p>\n

=> $r=36\\times\\frac{7}{36}=7$ cm<\/p>\n

$\\therefore$ Area of semi-circle = $\\frac{1}{2} \\pi r^2$<\/p>\n

= $\\frac{1}{2}\\times\\frac{22}{7}\\times(7)^2$<\/p>\n

= $11\\times7=77$ $cm^2$<\/p>\n

=> Ans – (C)<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

<\/figure>\n

Given : ABCD is a rhombus and AC = 24 cm and BD = 7 cm<\/p>\n

To find\u00a0: Perimeter of ABCD<\/p>\n

Solution\u00a0: Diagonals of a rhombus bisect each other at right angle.<\/p>\n

=> BE = $\\frac{7}{2}=3.5$ cm and AE = $\\frac{24}{2}=12$ cm<\/p>\n

Thus, in right $\\triangle$ AEB,<\/p>\n

=> $(AB)^2=(AE)^2+(BE)^2$<\/p>\n

=> $(AB)^2=(12)^2+(3.5)^2$<\/p>\n

=> $(AB)^2=144+12.25=156.25$<\/p>\n

=> $AB=\\sqrt{156.25}=12.5$ cm<\/p>\n

$\\therefore$ Perimeter of rhombus ABCD = $4\\times12.5=50$ cm<\/p>\n

=> Ans – (D)<\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Radius of cone, $r=\\frac{21}{2}=10.5$ cm and slant height, $l=11$ cm<\/p>\n

Total surface area of cone = $\\pi r(l+r)$<\/p>\n

= $\\frac{22}{7}\\times10.5\\times(10.5+11)$<\/p>\n

= $33\\times21.5=709.5$ $cm^2$<\/p>\n

=> Ans – (D)<\/p>\n

6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Radius of circle = $r=17.5$ cm<\/p>\n

=> Area = $\\pi r^2$<\/p>\n

= $\\frac{22}{7}\\times17.5\\times17.5$<\/p>\n

= $22\\times2.5\\times17.5=962.5$ $cm^2$<\/p>\n

=> Ans – (B)<\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let side of equilateral triangle = $s$ cm<\/p>\n

=> Area = $\\frac{\\sqrt3}{4} s^2=25\\sqrt3$<\/p>\n

=> $\\frac{s^2}{4}=25$<\/p>\n

=> $s^2=25\\times4=100$<\/p>\n

=> $s=\\sqrt{100}=10$ cm<\/p>\n

=> Ans – (A)<\/p>\n

8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Length, $l=10.5$ cm, breadth, $b=8$ cm and height, $h=9$ cm<\/p>\n

Total surface area of cuboid = $2(lb+bh+hl)$<\/p>\n

= $2[(10.5\\times8)+(8\\times9)+(9\\times10.5)]$<\/p>\n

= $2\\times(84+72+94.5)$<\/p>\n

= $2\\times250.5=501$ $cm^2$<\/p>\n

=> Ans – (D)<\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the length of rectangle = $l$ cm and breadth, $b=10$ cm<\/p>\n

=> Diagonal, $d^2=l^2+b^2$<\/p>\n

=> $l^2=(26)^2-(10)^2$<\/p>\n

=> $l^2=676-100=576$<\/p>\n

=> $l=\\sqrt{576}=24$ cm<\/p>\n

$\\therefore$ Area = $24\\times10=240$ $cm^2$<\/p>\n

=> Ans – (C)<\/p>\n

10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Height of cylinder, $h=14$ cm and radius, $r=\\frac{42}{2}=21$ cm<\/p>\n

Total surface area of cylinder = $2\\pi r(r+h)$<\/p>\n

= $2\\times\\frac{22}{7}\\times21\\times(21+14)$<\/p>\n

= $132\\times35=4620$ $cm^2$<\/p>\n

=> Ans – (D)<\/p>\n

SSC Free Previous Papers App<\/a><\/p>\n

We hope this Mensuration Questions blog will definitely help at the time of your preparation. Download the cracku app for daily test.<\/p>\n","protected":false},"excerpt":{"rendered":"

Mensuration Questions for SSC CGL Set-3 PDF Download SSC CGL Mensuration questions with answers PDF based on previous papers very useful for SSC CGL exams. Very important Geometry questions for SSC exams. Question 1:\u00a0The circumference of a circle is 88 cm. Find its radius (in cm). a)\u00a028 b)\u00a015 c)\u00a014 d)\u00a030 Question 2:\u00a0The volume of a […]<\/p>\n","protected":false},"author":41,"featured_media":38194,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,9,504,1268],"tags":[462],"class_list":{"0":"post-38192","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-ssc","10":"category-ssc-cgl","11":"category-ssc-stenographer","12":"tag-ssc-cgl"},"better_featured_image":{"id":38194,"alt_text":"Mensuration Questions for SSC CGL Set-3 PDF","caption":"Mensuration Questions for SSC CGL Set-3 PDF","description":"Mensuration Questions for SSC CGL Set-3 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