{"id":37771,"date":"2019-11-19T15:01:40","date_gmt":"2019-11-19T09:31:40","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=37771"},"modified":"2019-11-19T15:01:40","modified_gmt":"2019-11-19T09:31:40","slug":"algebra-questions-for-ssc-cgl-set-3-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/algebra-questions-for-ssc-cgl-set-3-pdf\/","title":{"rendered":"Algebra Questions for SSC CGL Set-3 PDF"},"content":{"rendered":"

Algebra Questions for SSC CGL Set-3 PDF<\/strong><\/span><\/h1>\n

Download SSC CGL Algebra Questions set-3 PDF. Top 10 SSC CGL questions based on asked questions in previous exam papers very important for the SSC exam.<\/p>\n

Download Algebra Questions for SSC CGL Set-3 PDF<\/a><\/p>\n

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Question 1:\u00a0<\/b>If xy = 56 and $x^{2} + y^{2} = 113$, then what will be the value of (x + y)?<\/p>\n

a)\u00a029<\/p>\n

b)\u00a021<\/p>\n

c)\u00a036<\/p>\n

d)\u00a015<\/p>\n

Question 2:\u00a0<\/b>If a + b = 11 and $a^2 + b^2$ = 61, then value of ab is<\/p>\n

a)\u00a012<\/p>\n

b)\u00a096<\/p>\n

c)\u00a024<\/p>\n

d)\u00a030<\/p>\n

Question 3:\u00a0<\/b>If 4(2x -4) – 2 > 3x – 1 \u2265 4x -7, then x can take which of the following values?<\/p>\n

a)\u00a07<\/p>\n

b)\u00a06<\/p>\n

c)\u00a02<\/p>\n

d)\u00a00<\/p>\n

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Question 4:\u00a0<\/b>Factors of $48x^{3} – 8x^{2} – 93x – 45$ are<\/p>\n

a)\u00a0(4x\u00a0+\u00a03)(4x\u00a0\u00ad- 3)(3x\u00a0\u00ad- 5)<\/p>\n

b)\u00a0(4x – 3)(4x\u00a0\u00ad- 3)(3x -\u00ad\u00a05)<\/p>\n

c)\u00a0(4x\u00a0+\u00a03)(4x\u00a0+\u00a03)(3x -\u00ad\u00a05)<\/p>\n

d)\u00a0(4x -\u00ad\u00a03)(4x\u00a0+\u00a03)(3x\u00a0+\u00a05)<\/p>\n

Question 5:\u00a0<\/b>Divide 32 into two parts such that the sum of the square of the parts is 674. What is the value of the parts?<\/p>\n

a)\u00a022, 10<\/p>\n

b)\u00a030, 2<\/p>\n

c)\u00a025, 7<\/p>\n

d)\u00a020, 12<\/p>\n

Question 6:\u00a0<\/b>If \u00a0(4x\u00a0\u00ad-5)\u00a0=\u00a0(3x\u00a0\u00ad-1),\u00a0then the numerical value of $(x + 4)^{2}$ is<\/p>\n

a)\u00a016<\/p>\n

b)\u00a064<\/p>\n

c)\u00a032<\/p>\n

d)\u00a08<\/p>\n

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Question 7:\u00a0<\/b>If 2(3x + 5) > 4x -\u00ad 5 < 3x + 2\u037e then x can take which of the following values?<\/p>\n

a)\u00a0-8<\/p>\n

b)\u00a06<\/p>\n

c)\u00a0\u00ad8<\/p>\n

d)\u00a0\u00ad10<\/p>\n

Question 8:\u00a0<\/b>If 51.97 -(81.18 \u00ad-x ) \u00ad-59.39 = 5.268, then value of x will be<\/p>\n

a)\u00a0\u00ad24.912<\/p>\n

b)\u00a0\u00ad68.492<\/p>\n

c)\u00a093.868<\/p>\n

d)\u00a0197.808<\/p>\n

Question 9:\u00a0<\/b>What should be added to 3(x\u00ad-2y)\u00a0to\u00a0obtain\u00a02(3x\u00a0+\u00a0y)\u00a0\u00ad- 5(2x\u00a0+\u00a03)?<\/p>\n

a)\u00a08y -7x -15<\/p>\n

b)\u00a08y-7x + 15<\/p>\n

c)\u00a08y + 7x + 15<\/p>\n

d)\u00a08y + 7x \u00ad-15<\/p>\n

Question 10:\u00a0<\/b>If 1\/6 of x – 7\/2 of 3\/7 equals – 7\/4, then the value of x is<\/p>\n

a)\u00a0-1.5<\/p>\n

b)\u00a03<\/p>\n

c)\u00a0-2.5<\/p>\n

d)\u00a06<\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Given\u00a0: $(x^2 + y^2) = 113$ and $xy = 56$<\/p>\n

Using $(x + y)^2 = x^2 + y^2 + 2xy$<\/p>\n

=> $(x + y)^2 = 113 + (2 \\times 56)$<\/p>\n

=> $(x + y)^2 = 113 + 112 = 225$<\/p>\n

=> $(x + y) = \\sqrt{225} = 15$<\/p>\n

=> Ans – (D)<\/p>\n

2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Given\u00a0: $(a + b) = 11$ and $a^2 + b^2 = 61$<\/p>\n

Using $(a + b)^2 = a^2 + b^2 + 2ab$<\/p>\n

=> $(11)^2 = 61 + (2 \\times ab)$<\/p>\n

=> $2 ab = 121 – 61 = 60$<\/p>\n

=> $ab = \\frac{60}{2} = 30$<\/p>\n

=> Ans – (D)<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression 1\u00a0:\u00a04(2x -4) – 2 > 3x – 1<\/p>\n

=> $8x-16-2$ > $3x-1$<\/p>\n

=> $8x-3x$ > $-1+18$<\/p>\n

=> $x$ > $\\frac{17}{5}$ ————(i)<\/p>\n

Expression 2 :\u00a03x – 1 \u2265 4x -7<\/p>\n

=> $4x-3x \\leq -1+7$<\/p>\n

=> $x \\leq 6$ ———–(ii)<\/p>\n

Combining inequalities (i) and (ii), we get\u00a0: $\\frac{17}{5}$\u00a0<\u00a0$x \\leq 6$<\/p>\n

The only value that $x$ can take among the options = 6<\/p>\n

=> Ans – (B)<\/p>\n

4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

(A) : (4x\u00a0+\u00a03)(4x\u00a0\u00ad- 3)(3x\u00a0\u00ad- 5)<\/p>\n

= $(16x^2 – 12x + 12x – 9)(3x – 5)$<\/p>\n

= $(16x^2 – 9)(3x – 5)$<\/p>\n

= $48x^3 – 80x^2 – 27x + 45$<\/p>\n

(B) :\u00a0(4x – 3)(4x\u00a0\u00ad- 3)(3x -\u00ad\u00a05)<\/p>\n

= $(16x^2 – 24x + 9)(3x – 5)$<\/p>\n

= $48x^3 – 80x^2 – 72x^2 + 120x + 27x – 45$<\/p>\n

= $48x^3 – 152x^2 + 147x – 45$<\/p>\n

(C) :\u00a0(4x\u00a0+\u00a03)(4x\u00a0+\u00a03)(3x -\u00ad\u00a05)<\/p>\n

= $(16x^2 + 24x + 9)(3x – 5)$<\/p>\n

= $48x^3 – 80x^2 + 72x^2 – 120x + 27x – 45$<\/p>\n

= $48x^3 – 8x^2 – 93x – 45$<\/p>\n

=> Ans – (C)<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the first part = $x$ and second part = $(32 – x)$<\/p>\n

According to ques, => $(x)^2 + (32 – x)^2 = 674$<\/p>\n

=> $x^2 + (x^2 + 1024 – 64x) = 674$<\/p>\n

=> $2x^2 – 64x + 1024 – 674 = 0$<\/p>\n

=> $x^2 – 32x + 175 = 0$<\/p>\n

=> $x^2 – 25x – 7x + 175 = 0$<\/p>\n

=> $x(x-25) – 7(x-25) = 0$<\/p>\n

=> $(x-25)(x-7) = 0$<\/p>\n

=> $x = 25,7$<\/p>\n

=> Ans – (C)<\/p>\n

6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Given\u00a0:\u00a0(4x\u00a0\u00ad- 5)\u00a0=\u00a0(3x\u00a0\u00ad-1)<\/p>\n

=> $4x – 3x = 5 – 1$<\/p>\n

=> $x = 4$<\/p>\n

To find\u00a0:\u00a0$(x + 4)^2$<\/p>\n

= $(4 + 4)^2 = 8^2 = 64$<\/p>\n

=> Ans – (B)<\/p>\n

7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression 1\u00a0:\u00a02(3x + 5) > 4x -\u00ad 5<\/p>\n

=> $6x+10$ > $4x-5$<\/p>\n

=> $6x-4x$ > $-5-10$<\/p>\n

=> $2x$ > $-15$<\/p>\n

=> $x$ > $\\frac{-15}{2}$ ——–(i)<\/p>\n

Expression 2\u00a0:\u00a04x -\u00ad 5 < 3x + 2<\/p>\n

=> $4x-3x$ < $2+5$<\/p>\n

=> $x$ < $7$ ———(ii)<\/p>\n

Combining inequalities (i) and (ii), we get\u00a0: $\\frac{-15}{2}$ < $x$ < $7$<\/p>\n

The only value that $x$ can take = 6<\/p>\n

=> Ans – (B)<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Expression\u00a0:\u00a051.97 -(81.18 \u00ad-x ) \u00ad-59.39 = 5.268<\/p>\n

=> 51.97 – 81.18 + x = 5.268 + 59.39<\/p>\n

=>\u00a0-29.21 + x = 64.658<\/p>\n

=> x = 64.658 + 29.21<\/p>\n

=> x = 93.868<\/p>\n

=> Ans – (C)<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let $m$ should be added to\u00a03(x\u00ad-2y)\u00a0to\u00a0obtain\u00a02(3x\u00a0+\u00a0y)\u00a0\u00ad- 5(2x\u00a0+\u00a03)<\/p>\n

=> $(m) + [3(x-2y)] = 2(3x+y)-5(2x+3)$<\/p>\n

=> $m + 3x-6y=6x+2y-10x-15$<\/p>\n

=> $m = (2y+6y)+(-4x-3x)-15$<\/p>\n

=> $m=8y-7x-15$<\/p>\n

=> Ans – (A)<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

According to ques,<\/p>\n

=> $(\\frac{1}{6} \\times x) – (\\frac{7}{2} \\times \\frac{3}{7}) = \\frac{-7}{4}$<\/p>\n

=> $\\frac{x}{6} – \\frac{3}{2} = \\frac{-7}{4}$<\/p>\n

=> $\\frac{x}{6} = \\frac{3}{2} – \\frac{7}{4}$<\/p>\n

=> $\\frac{x}{6} = \\frac{-1}{4}$<\/p>\n

=> $x = \\frac{-6}{4} = -1.5$<\/p>\n

=> Ans – (A)<\/p>\n

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We hope this Algebra Questions set-3 pdf for SSC CGL exam will be highly useful for your Preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Algebra Questions for SSC CGL Set-3 PDF Download SSC CGL Algebra Questions set-3 PDF. Top 10 SSC CGL questions based on asked questions in previous exam papers very important for the SSC exam. Download All SSC CGL Questions & Tricks PDF Take a free mock test for SSC CGL Question 1:\u00a0If xy = 56 and […]<\/p>\n","protected":false},"author":41,"featured_media":37773,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,9,504,1493,1741,1441],"tags":[462,1719,3043],"class_list":{"0":"post-37771","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-ssc","10":"category-ssc-cgl","11":"category-ssc-cpo","12":"category-ssc-mts","13":"category-stenographer","14":"tag-ssc-cgl","15":"tag-ssc-cgl-mocks","16":"tag-ssc-maths-questions"},"better_featured_image":{"id":37773,"alt_text":"Algebra Questions for SSC CGL Set-3 PDF","caption":"Algebra Questions for SSC CGL Set-3 PDF","description":"Algebra Questions for SSC CGL Set-3 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