{"id":37695,"date":"2019-11-18T14:20:00","date_gmt":"2019-11-18T08:50:00","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=37695"},"modified":"2019-11-18T14:20:00","modified_gmt":"2019-11-18T08:50:00","slug":"quadratic-equation-questions-for-ibps-clerk-set-3-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/quadratic-equation-questions-for-ibps-clerk-set-3-pdf\/","title":{"rendered":"Quadratic Equation Questions for IBPS Clerk Set-3 PDF"},"content":{"rendered":"<h2><span style=\"text-decoration: underline;\"><strong>Quadratic Equation Questions for IBPS Clerk Set-3 PDF<\/strong><\/span><\/h2>\n<p>Download important\u00a0 Quadratic Equation Questions set-3 PDF based on previously asked questions in IBPS Clerk and other Banking Exams. Practice Scheduling Questions and Answers for IBPS Clerk Exam.<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/downloads\/7226\" target=\"_blank\" class=\"btn btn-danger  download\">Download Quadratic Equation Questions for IBPS Clerk Set-3 PDF<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/pay\/6VXp5\" target=\"_blank\" class=\"btn btn-info \">Get 25 IBPS Clerk mocks for Rs. 149. Enroll here<\/a><\/p>\n<p><a href=\"https:\/\/cracku.in\/ibps-clerk-online-mock-tests\">Take Free IBPS Clerk Mock Test<\/a><\/p>\n<p>Download <a href=\"https:\/\/cracku.in\/ibps-clerk-previous-papers\" target=\"_blank\" rel=\"noopener\">IBPS Clerk Previous papers PDF<\/a><\/p>\n<p><b>Instructions<\/b><\/p>\n<p>&lt;p &#8220;=&#8221;&#8221;&gt;In these questions two equations numbered I and II are given. You have to solve both the equations and give answer<\/p>\n<p>a: if x &lt; y<br \/>\nb: if x &gt; y<br \/>\nc: if x = y<br \/>\nd: if x = y<br \/>\ne: if x= y or relationship between x and y cannot be established<\/p>\n<p><b>Question 1:\u00a0<\/b>I. $3x^{2} + 23x+ 44 = 0$<br \/>\nII. $3y^{2} + 20y + 33 = 0$<\/p>\n<p>a)\u00a0if x &lt; y<\/p>\n<p>b)\u00a0if x &gt; y<\/p>\n<p>c)\u00a0if x =&gt; y<\/p>\n<p>d)\u00a0if x &lt;= y<\/p>\n<p>e)\u00a0if x= y or relationship between x and y cannot be established<\/p>\n<p><b>Question 2:\u00a0<\/b>I. $4x^{2} &#8211; 29x + 45 = 0$<br \/>\nII. $3y^{2} &#8211; 19y + 28 = 0$<\/p>\n<p>a)\u00a0if x &lt; y<\/p>\n<p>b)\u00a0if x &gt; y<\/p>\n<p>c)\u00a0if x =&gt; y<\/p>\n<p>d)\u00a0if x &lt;= y<\/p>\n<p>e)\u00a0if x= y or relationship between x and y cannot be established<\/p>\n<p><b>Question 3:\u00a0<\/b>I. $2x^{2} &#8211; 13x + 21 = 0$<br \/>\nII. $5y^{2} &#8211; 22y + 21 =0$<\/p>\n<p>a)\u00a0if x &lt; y<\/p>\n<p>b)\u00a0if x &gt; y<\/p>\n<p>c)\u00a0if x =&gt; y<\/p>\n<p>d)\u00a0if x &lt;= y<\/p>\n<p>e)\u00a0if x= y or relationship between x and y cannot be established<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ibps-clerk-online-mock-tests\" target=\"_blank\" class=\"btn btn-danger \">IBPS Clerk Online Mock Test<\/a><\/p>\n<p>Go to Free <a href=\"https:\/\/cracku.in\/banking-study-material\" target=\"_blank\" rel=\"noopener\">Banking Study Material<\/a> (15,000 Solved Questions)<\/p>\n<p><b>Instructions<\/b><\/p>\n<p>In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. Give answer :<br \/>\na:If x &lt; y<br \/>\nb: If x &gt; y<br \/>\nc: If x \u2264 y<br \/>\nd: If x \u2265 y<br \/>\ne: If relationship between x and y cannot be determined ,<\/p>\n<p><b>Question 4:\u00a0<\/b>I. $15x^{2} + 26x + 8 = 0$<br \/>\nII. $25y^{2} + 15y + 2 = 0$<\/p>\n<p>a)\u00a0If x &lt; y<\/p>\n<p>b)\u00a0If x &gt; y<\/p>\n<p>c)\u00a0If x \u2264 y<\/p>\n<p>d)\u00a0If x \u2265 y<\/p>\n<p>e)\u00a0If relationship between x and y cannot be determined<\/p>\n<p><b>Question 5:\u00a0<\/b>I. $10x^{2} + 21x + 8 = 0$<br \/>\nII. $5y^{2} + 19y + 18 = 0$<\/p>\n<p>a)\u00a0If x &lt; y<\/p>\n<p>b)\u00a0If x &gt; y<\/p>\n<p>c)\u00a0If x \u2264 y<\/p>\n<p>d)\u00a0If x \u2265 y<\/p>\n<p>e)\u00a0If relationship between x and y cannot be determined<\/p>\n<p><b>Instructions<\/b><\/p>\n<p>In the given questions, two quantities are given, one as Quantity I and another as Quantity II. You have to determine relationship between two quantities and choose the appropriate option.<\/p>\n<p>a: If quantity I \u2265 quantity II<br \/>\nb: If quantity I &gt; quantity II<br \/>\nc: If quantity I &lt; quantity II<br \/>\nd: If quantity I = quantity II or the relationship cannot be established from the information that is given<br \/>\ne: If quantity quantity II<\/p>\n<p><b>Question 6:\u00a0<\/b>Ram invested P in scheme A and 2P in scheme B, for two years each. Scheme A offers simple interest p.a. Scheme B offers compound interest (compounded annually) at the rate of 10% p.a. Respective ratio between the interest earned from scheme A and that earned from scheme B was 8 : 21.<br \/>\nQuantity :<br \/>\nI. Rate of interest offered by scheme A.<br \/>\nII. Rate of interest offered by scheme C (simple interest p.a.), when 1,600\/- is invested for 3 years earns an interest of 384\/-.<\/p>\n<p>a)\u00a0If quantity I \u2265 quantity II<\/p>\n<p>b)\u00a0If quantity I &gt; quantity II<\/p>\n<p>c)\u00a0If quantity I &lt; quantity II<\/p>\n<p>d)\u00a0If quantity I = quantity II or the relationship cannot be established from the information that is given<\/p>\n<p>e)\u00a0If quantity quantity II<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/blog\/ibps-clerk-questions-and-answers-pdf\/\" target=\"_blank\" class=\"btn btn-info \">IBPS Clerk Important Questions PDF<\/a><\/p>\n<p><b>Instructions<\/b><\/p>\n<p>&lt;p &#8220;=&#8221;&#8221;&gt;In these questions two equations numbered I and II are given. You have to solve both the equations and give answer<\/p>\n<p>a: if x &lt; y<br \/>\nb: if x &gt; y<br \/>\nc: if x = y<br \/>\nd: if x = y<br \/>\ne: if x= y or relationship between x and y cannot be established<\/p>\n<p><b>Question 7:\u00a0<\/b>I. $3x^{2}+ 29x + 56 = 0$<br \/>\nII. $2y^{2} + 15y + 25 = 0$<\/p>\n<p>a)\u00a0if x &lt; y<\/p>\n<p>b)\u00a0if x &gt; y<\/p>\n<p>c)\u00a0if x =&gt; y<\/p>\n<p>d)\u00a0if x &lt;= y<\/p>\n<p>e)\u00a0if x= y or relationship between x and y cannot be established<\/p>\n<p><b>Instructions<\/b><\/p>\n<p>In each of these questions an equation is given with a question mark (?) in place of the correct figure on the right hand side which satisfies the equality. Based on the values on the left hand side and the symbol of equality given, you have to decide which of the following figures will satisfy the equality and thus come in place of the question mark.<br \/>\nSymbols and Stand for<\/p>\n<p>&gt; \u00a0 greater than<\/p>\n<p>= \u00a0equal to<\/p>\n<p>&lt; \u00a0lesser than<\/p>\n<p>$\\geq$ either greater than or equal to<\/p>\n<p>$\\leq$ \u00a0either lesser than or equal to<\/p>\n<p><b>Question 8:\u00a0<\/b>$\\pm [(35 \\div 2) &#8211; (43.5 \\div 3)] \\leq ?$<\/p>\n<p>a)\u00a0&#8211; 3<\/p>\n<p>b)\u00a09<\/p>\n<p>c)\u00a0$\\sqrt{9}$<\/p>\n<p>d)\u00a03<\/p>\n<p>e)\u00a0\u00b1 3<\/p>\n<p><b>Question 9:\u00a0<\/b>$[175-(52 &#8211; 72)] \\geq ?$<\/p>\n<p>a)\u00a0+195<\/p>\n<p>b)\u00a0-195<\/p>\n<p>c)\u00a0195<\/p>\n<p>d)\u00a0196<\/p>\n<p>e)\u00a0$\\sqrt{195}$<\/p>\n<p><b>Question 10:\u00a0<\/b>$-((\\sqrt{225}-\\sqrt{144})\\times-(1.5))=?$<\/p>\n<p>a)\u00a04.5<\/p>\n<p>b)\u00a0&#8211; 4.5<\/p>\n<p>c)\u00a05.4<\/p>\n<p>d)\u00a0&#8211; 5.4<\/p>\n<p>e)\u00a04.8<\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/banking-study-material\" target=\"_blank\" class=\"btn btn-danger \">Free Banking Study Material (15,000 Solved Questions)<\/a><\/p>\n<p>Download <a href=\"https:\/\/cracku.in\/ibps-clerk-previous-papers\" target=\"_blank\" rel=\"noopener\">IBPS Clerk Previous papers PDF<\/a><\/p>\n<p><span style=\"text-decoration: underline;\"><strong>Answers &amp; Solutions:<\/strong><\/span><\/p>\n<p><strong>1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>$3x^{2} + 23x + 44 = 0$.<br \/>\n$x=\\frac{-23\\pm\\sqrt{23^{2}-4\\times44\\times3}}{2\\times3}$<br \/>\n$x=\\frac{-23\\pm1}{6}$.<br \/>\n$x=\\frac{-11}{3},-4$.<br \/>\n$3y^{2} + 20y + 33 =0$<span class=\"redactor-invisible-space\" style=\"background-color: initial;\">.<br \/>\n<\/span>$y=\\frac{-20\\pm\\sqrt{20^{2}-4\\times33\\times3}}{2\\times3}$.<br \/>\n$y=\\frac{-20\\pm2}{6}$.<br \/>\n$y=-3,\\frac{(-11)}{3}$.<br \/>\nClearly,<br \/>\nx &lt;= y<br \/>\nHence, Option D is correct.<\/p>\n<p><strong>2)\u00a0Answer\u00a0(E)<\/strong><\/p>\n<p>$4x^{2} &#8211; 29x + 45 = 0$.<br \/>\n$x=\\frac{29\\pm\\sqrt{29^{2}-4\\times45\\times4}}{2\\times4}$<br \/>\n$x=\\frac{29\\pm3}{8}$.<br \/>\n$x=\\frac{13}{4},4$.<br \/>\n$3y^{2} &#8211; 19y + 28 =0$<span class=\"redactor-invisible-space\" style=\"background-color: initial;\">.<br \/>\n<\/span>$y=\\frac{19\\pm\\sqrt{19^{2}-4\\times28\\times3}}{2\\times3}$.<br \/>\n$y=\\frac{19\\pm5}{6}$.<br \/>\n$y=4,\\frac{7}{3}$.<br \/>\nClearly,<br \/>\nif x= y or relationship between x and y cannot be established<br \/>\nHence, Option E is correct.<\/p>\n<p><strong>3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>$2x^{2} &#8211; 13x + 21 = 0$.<br \/>\n<span class=\"redactor-invisible-space\">$x=\\frac{13\\pm\\sqrt{13^{2}-4\\times21\\times2}}{2\\times2}$<br \/>\n$x=\\frac{13\\pm1}{4}$.<br \/>\n$x=\\frac{7}{2},3$.<br \/>\n$5y^{2} &#8211; 22y + 21 =0$<span class=\"redactor-invisible-space\">.<br \/>\n<\/span><\/span><span class=\"redactor-invisible-space\" style=\"background-color: initial;\">$y=\\frac{22\\pm\\sqrt{22^{2}-4\\times21\\times5}}{2\\times5}$<br \/>\n$y=\\frac{22\\pm8}{10}$.<br \/>\n$y=3,\\frac{7}{5}$.<br \/>\nClearly,<br \/>\nx =&gt; y<br \/>\nHence, Option C is correct.<br \/>\n<\/span><\/p>\n<p><strong>4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>I. $15x^{2} + 26x + 8 = 0$<\/p>\n<p>=&gt; $15x^2 + 6x + 20x + 8 = 0$<\/p>\n<p>=&gt; $(3x + 4) (5x + 2) = 0$<\/p>\n<p>=&gt; $x = \\frac{-4}{3} , \\frac{-2}{5}$<\/p>\n<p>II. $25y^{2} + 15y + 2 = 0$<\/p>\n<p>=&gt; $25y^2 + 5y + 10y + 2 = 0$<\/p>\n<p>=&gt; $(5y + 2) (5y + 1) = 0$<\/p>\n<p>=&gt; $y = \\frac{-2}{5} , \\frac{-1}{5}$<\/p>\n<p>$\\therefore x \\leq y$<\/p>\n<p><strong>5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n<p>I. $10x^{2} + 21x + 8 = 0$<\/p>\n<p>=&gt; $10x^2 + 5x + 16x + 8 = 0$<\/p>\n<p>=&gt; $(5x + 8) (2x + 1) = 0$<\/p>\n<p>=&gt; $x = \\frac{-8}{5} , \\frac{-1}{2}$<\/p>\n<p>II. $5y^{2} + 19y + 18 = 0$<\/p>\n<p>=&gt; $5y^2 + 10y + 9y + 18 = 0$<\/p>\n<p>=&gt; $(5y + 9) (y + 2) = 0$<\/p>\n<p>=&gt; $y = \\frac{-9}{5} , -2$<\/p>\n<p>$\\therefore x &gt; y$<\/p>\n<p><strong>6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n<p>$S.I. = \\frac{P \\times R \\times T}{100}$<\/p>\n<p>$C.I. = P [(1 + \\frac{R}{100})^T &#8211; 1]$<\/p>\n<p>Rate of interest for scheme B = 10 %<\/p>\n<p>Time period in each scheme = 2 years<\/p>\n<p>Acc to ques,<\/p>\n<p>=&gt; $\\frac{\\frac{P \\times R \\times 2}{100}}{2P [(1 + \\frac{10}{100})^2 &#8211; 1]} = \\frac{8}{21}$<\/p>\n<p>=&gt; $\\frac{\\frac{R}{50}}{\\frac{21}{50}} = \\frac{8}{21}$<\/p>\n<p>=&gt; $\\frac{R}{21} = \\frac{8}{21}$<\/p>\n<p>=&gt; $R = 8 \\%$<\/p>\n<p>Quantity I = 8\u00a0%<\/p>\n<p>Quantity\u00a0II\u00a0: $384 = \\frac{1600 \\times R \\times 3}{100}$<\/p>\n<p>=&gt; $R = \\frac{384}{48} = 8 \\%$<\/p>\n<p>$\\therefore$ Quantity I = Quantity II<\/p>\n<p><strong>7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<p>$3x^{2} + 29x + 56 = 0$.<br \/>\n$x=\\frac{-29\\pm\\sqrt{29^{2}-4\\times56\\times3}}{2\\times3}$<br \/>\n$x=\\frac{-29\\pm13}{6}$.<br \/>\n$x=\\frac{-8}{3},-7$.<br \/>\n$2y^{2} + 15y + 25 =0$<span class=\"redactor-invisible-space\" style=\"background-color: initial;\">.<br \/>\n<\/span>$y=\\frac{-15\\pm\\sqrt{15^{2}-4\\times25\\times2}}{2\\times2}$.<br \/>\n$y=\\frac{-15\\pm5}{4}$.<br \/>\n$y=-5,\\frac{(-5)}{2}$.<br \/>\nClearly,<br \/>\nx &lt; y<br \/>\nHence, Option A is correct.<\/p>\n<p><strong>8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n<p>$\\pm [(35 \\div 2) &#8211; (43.5 \\div 3)] $<br \/>\n= \u00b1 [17.5-14.5]<br \/>\n= \u00b1 3<br \/>\nSince \u00b1 3 $\\leq $ 3<\/p>\n<p><strong>9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<p>[175-(52 &#8211; 72)]<\/p>\n<p>= 175 +20<br \/>\n= 195<\/p>\n<p><strong>10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n<p>$-((\\sqrt{225}-\\sqrt{144})\\times-(1.5))=?$<br \/>\n= &#8211; (15-12) $ \\times $<span class=\"redactor-invisible-space\"> (-1.5)<br \/>\n= (-3)$ \\times $(-1.5) =4.5<br \/>\n<\/span><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.cracku.app&amp;hl=en_IN\" target=\"_blank\" class=\"btn btn-primary \">Highly Rated Free Preparation App for Banking Exams<\/a><\/p>\n<p class=\"text-center\"><a href=\"https:\/\/cracku.in\/ibps-clerk-online-mock-tests\" target=\"_blank\" class=\"btn btn-danger \">4 Free IBPS Clerk Mock Tests<\/a><\/p>\n<p>We hope this Quadratic Equation Questions and answers for IBPS Clerk preparation will be helpful to you.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Quadratic Equation Questions for IBPS Clerk Set-3 PDF Download important\u00a0 Quadratic Equation Questions set-3 PDF based on previously asked questions in IBPS Clerk and other Banking Exams. Practice Scheduling Questions and Answers for IBPS Clerk Exam. Take Free IBPS Clerk Mock Test Download IBPS Clerk Previous papers PDF Instructions &lt;p &#8220;=&#8221;&#8221;&gt;In these questions two equations [&hellip;]<\/p>\n","protected":false},"author":41,"featured_media":37698,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,2999,229],"tags":[1773,2783,3020],"class_list":{"0":"post-37695","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-ibps-en","10":"category-ibpsclerk","11":"tag-ibps-clerk-2019","12":"tag-ibps-clerk-mocks","13":"tag-ibps-maths"},"better_featured_image":{"id":37698,"alt_text":"Quadratic Equation Questions for IBPS Clerk Set-3 PDF","caption":"Quadratic Equation Questions for IBPS Clerk Set-3 PDF","description":"Quadratic Equation Questions for IBPS Clerk Set-3 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