{"id":37609,"date":"2019-11-15T12:26:29","date_gmt":"2019-11-15T06:56:29","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=37609"},"modified":"2019-11-18T11:08:41","modified_gmt":"2019-11-18T05:38:41","slug":"algebra-questions-for-ibps-clerk-set-2-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/algebra-questions-for-ibps-clerk-set-2-pdf\/","title":{"rendered":"Algebra Questions for IBPS Clerk set-2 PDF"},"content":{"rendered":"

Algebra Questions for IBPS Clerk set-2 PDF<\/strong><\/span><\/h1>\n

Download important\u00a0 Algebra Questions set-2 PDF based on previously asked questions in IBPS Clerk and other Banking Exams. Practice Scheduling Questions and Answers for IBPS Clerk Exam.<\/p>\n

Download Algebra Questions for IBPS Clerk set-2 PDF<\/a><\/p>\n

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Take Free IBPS Clerk Mock Test<\/a><\/p>\n

Download IBPS Clerk Previous papers PDF<\/a><\/p>\n

Go to Free Banking Study Material<\/a> (15,000 Solved Questions)<\/p>\n

Question 1:\u00a0<\/b>The value of x for which the expressions 19 -\u00ad 5x and 19x + 5 become equal is …………..<\/p>\n

a)\u00a07\/12<\/p>\n

b)\u00a0-7\/12<\/p>\n

c)\u00a0-12\/7<\/p>\n

d)\u00a0\u00ad12\/7<\/p>\n

Question 2:\u00a0<\/b>If 7 + 4x > 3 + 3x and 3x – 2 < 5 – x; then x can take which of the following values?<\/p>\n

a)\u00a02<\/p>\n

b)\u00a03<\/p>\n

c)\u00a01<\/p>\n

d)\u00a0-5<\/p>\n

Question 3:\u00a0<\/b>If $3x^{2} = 10^{2} – 5^{2}$, find the value of x?<\/p>\n

a)\u00a07<\/p>\n

b)\u00a05<\/p>\n

c)\u00a09<\/p>\n

d)\u00a011<\/p>\n

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Question 4:\u00a0<\/b>If (7x – 13) – (12x + 3) = 14, then the value of x is ______ .<\/p>\n

a)\u00a0-6<\/p>\n

b)\u00a06<\/p>\n

c)\u00a02\/5<\/p>\n

d)\u00a0-2\/5<\/p>\n

Question 5:\u00a0<\/b>If 2 + 2x < 5 – x\/2 and 5x + 3 > 5 – 5x; then x can take which of the following values?<\/p>\n

a)\u00a02<\/p>\n

b)\u00a00<\/p>\n

c)\u00a0-2<\/p>\n

d)\u00a01<\/p>\n

Question 6:\u00a0<\/b>If (x + y):(x – y) = 5:2, find value of (4x + 5y) \/ (x – 4y)<\/p>\n

a)\u00a043\/5<\/p>\n

b)\u00a0-5\/43<\/p>\n

c)\u00a0-43\/5<\/p>\n

d)\u00a05\/43<\/p>\n

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Question 7:\u00a0<\/b>The value of x for which the expressions 11x + 7 and 17x – 1 become equal is ______.<\/p>\n

a)\u00a0-4\/3<\/p>\n

b)\u00a03\/4<\/p>\n

c)\u00a04\/3<\/p>\n

d)\u00a0-3\/4<\/p>\n

Question 8:\u00a0<\/b>If 2x + 3y = 0 and 3x -\u00ad 4y = 34, then x -\u00ad y =<\/p>\n

a)\u00a010<\/p>\n

b)\u00a0-10<\/p>\n

c)\u00a02<\/p>\n

d)\u00a0-2<\/p>\n

IBPS Clerk Important Questions PDF<\/a><\/p>\n

Question 9:\u00a0<\/b>If 5 \u00ad- 3x < 4 \u00ad- x and 5(2 -\u00ad x) > 2 -\u00ad 2x, then x can take which of the following values?<\/p>\n

a)\u00a00<\/p>\n

b)\u00a0-1<\/p>\n

c)\u00a01<\/p>\n

d)\u00a03<\/p>\n

Question 10:\u00a0<\/b>If a:b = 3:8, find the value of (5a – \u00ad3b)\/(2a + b).<\/p>\n

a)\u00a09\/14<\/p>\n

b)\u00a014\/9<\/p>\n

c)\u00a0-9\/14<\/p>\n

d)\u00a0-14\/9<\/p>\n

Free Banking Study Material (15,000 Solved Questions)<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Expressions :\u00a019 -\u00ad 5x and 19x + 5<\/p>\n

=> $19 – 5x = 19x + 5$<\/p>\n

=> $19x + 5x = 19 – 5$<\/p>\n

=> $24x = 14$<\/p>\n

=> $x = \\frac{14}{24} = \\frac{7}{12}$<\/p>\n

=> Ans – (A)<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Expression 1\u00a0:\u00a07 + 4x > 3 + 3x<\/p>\n

=> $4x – 3x$ > $3 – 7$<\/p>\n

=> $x$\u00a0> $-4$ ————–(i)<\/p>\n

Expression 2\u00a0:\u00a03x – 2 < 5 – x<\/p>\n

=> $3x + x$ < $5 + 2$<\/p>\n

=> $4x$ < $7$<\/p>\n

=> $x$\u00a0< $\\frac{7}{4}$ —————–(ii)<\/p>\n

Combining inequalities (i) and (ii), we get\u00a0: $-4$ < $x$ < $\\frac{7}{4}$<\/p>\n

Thus, $x$ can take values = -3 , -2 , -1 , 0 , 1<\/strong><\/p>\n

=> Ans – (C)<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression\u00a0:\u00a0$3x^{2} = 10^{2} – 5^{2}$<\/p>\n

=> $3x^2 = 100 – 25$<\/p>\n

=> $3x^2 = 75$<\/p>\n

=> $x^2 = \\frac{75}{3} = 25$<\/p>\n

=> $x = \\sqrt{25} = 5$<\/p>\n

=> Ans – (B)<\/p>\n

4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

 <\/p>\n

Expression\u00a0: $(7x – 13) – (12x + 3) = 14$<\/p>\n

=> $7x – 13 – 12x – 3 = 14$<\/p>\n

=> $-5x – 16 = 14$<\/p>\n

=> $-5x = 16 + 14 = 30$<\/p>\n

=> $x = \\frac{30}{-5} = -6$<\/p>\n

=> Ans – (A)<\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Expression\u00a01\u00a0:\u00a02 + 2x < 5 – x\/2<\/p>\n

=> $2x + \\frac{x}{2}$\u00a0< $5 – 2$<\/p>\n

=> $\\frac{5x}{2}$ < $3$<\/p>\n

=> $x$\u00a0< $\\frac{6}{5}$ ———-(i)<\/p>\n

Expression\u00a02\u00a0:\u00a05x + 3 > 5 – 5x<\/p>\n

=> $5x + 5x$\u00a0> $5 – 3$<\/p>\n

=> $10x$\u00a0> $2$<\/p>\n

=> $x$\u00a0> $\\frac{1}{5}$ ———-(ii)<\/p>\n

Combining inequalities (i) and (ii), we get\u00a0: $\\frac{1}{5}$ < $x$ < $\\frac{6}{5}$<\/p>\n

Thus, the only value that $x$ can take = 1<\/p>\n

=> Ans – (D)<\/p>\n

6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Given\u00a0: $\\frac{x + y}{x – y} = \\frac{5}{2}$<\/p>\n

=> $2x + 2y = 5x – 5y$<\/p>\n

=> $2y + 5y = 5x – 2x$ => $7y = 3x$<\/p>\n

=> $y = \\frac{3x}{7}$<\/p>\n

To find\u00a0: $\\frac{4x + 5y}{x – 4y}$<\/p>\n

= $[4x + 5(\\frac{3x}{7})] \\div [x – 4(\\frac{3x}{7})]$<\/p>\n

= $(4x + \\frac{15x}{7}) \\div (x – \\frac{12x}{7})$<\/p>\n

= $(\\frac{43x}{7}) \\div (\\frac{-5x}{7})$<\/p>\n

=\u00a0$\\frac{43x}{7} \\times \\frac{-7}{5x} = \\frac{-43}{5}$<\/p>\n

=> Ans – (C)<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Expressions\u00a0:\u00a011x + 7 and 17x – 1<\/p>\n

=> $11x + 7 = 17x – 1$<\/p>\n

=> $17x – 11x = 7 + 1$<\/p>\n

=> $6x = 8$<\/p>\n

=> $x = \\frac{8}{6} = \\frac{4}{3}$<\/p>\n

=> Ans – (C)<\/p>\n

8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Equation 1\u00a0:\u00a02x + 3y = 0<\/p>\n

Multiplying by 3 on both sides, we get\u00a0:\u00a0$6x + 9y = 0$ ———–(iii)<\/p>\n

Equation 2\u00a0: 3x -\u00ad 4y = 34<\/p>\n

Multiplying by 2 on both sides, => $6x – 8y = 68$ ———–(iv)<\/p>\n

Subtracting equation(iv) from (iii),<\/p>\n

=> $(6x – 6x) + (9y + 8y) = (0 – 68)$<\/p>\n

=> $17y = -68$<\/p>\n

=> $y = \\frac{-68}{17} = -4$<\/p>\n

Substituting it in equation (i), we get\u00a0: $2x + 3(-4) = 0$<\/p>\n

=> $2x = 12$<\/p>\n

=> $x = \\frac{12}{2} = 6$<\/p>\n

$\\therefore (x – y) = 6 – (-4) = 6 + 4 = 10$<\/p>\n

=> Ans – (A)<\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Expression 1\u00a0:\u00a05 \u00ad- 3x < 4 \u00ad- x<\/p>\n

=> $3x-x$ > $5-4$<\/p>\n

=> $2x$ > $1$<\/p>\n

=> $x$ > $\\frac{1}{2}$ ————(i)<\/p>\n

Expression 2\u00a0:\u00a05(2 -\u00ad x) > 2 -\u00ad 2x<\/p>\n

=> $10-5x$ > $2-2x$<\/p>\n

=> $5x-2x$ < $10-2$<\/p>\n

=> $3x$ < $8$<\/p>\n

=> $x$ < $\\frac{8}{3}$ ————–(ii)<\/p>\n

Combining inequalities (i) and (ii), we get : $\\frac{1}{2}$ < $x$ < $\\frac{8}{3}$<\/p>\n

The only value that $x$ can take among the given options = 1<\/p>\n

=> Ans – (C)<\/p>\n

10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

It is given that $a$ : $b$ = 3\u00a0: 8<\/p>\n

Let $a = 3$ and $b = 8$<\/p>\n

To find\u00a0: $\\frac{5a – 3b}{2a + b}$<\/p>\n

= $\\frac{(5 \\times 3) – (3 \\times 8)}{(2 \\times 3) + (8)}$<\/p>\n

= $\\frac{(15 – 24)}{(6 + 8)} = \\frac{-9}{14}$<\/p>\n

=> Ans – (C)<\/p>\n

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We hope this Algebra Questions and answers for IBPS Clerk preparation will be helpful to you.<\/p>\n","protected":false},"excerpt":{"rendered":"

Algebra Questions for IBPS Clerk set-2 PDF Download important\u00a0 Algebra Questions set-2 PDF based on previously asked questions in IBPS Clerk and other Banking Exams. Practice Scheduling Questions and Answers for IBPS Clerk Exam. Take Free IBPS Clerk Mock Test Download IBPS Clerk Previous papers PDF Go to Free Banking Study Material (15,000 Solved Questions) […]<\/p>\n","protected":false},"author":41,"featured_media":37612,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,2999,229],"tags":[1773,3020,2385],"class_list":{"0":"post-37609","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-ibps-en","10":"category-ibpsclerk","11":"tag-ibps-clerk-2019","12":"tag-ibps-maths","13":"tag-ibps-mocks"},"better_featured_image":{"id":37612,"alt_text":"Algebra Questions for IBPS Clerk set-2 PDF","caption":"Algebra Questions for IBPS Clerk set-2 PDF","description":"Algebra Questions for IBPS Clerk set-2 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