{"id":37435,"date":"2019-11-12T16:55:10","date_gmt":"2019-11-12T11:25:10","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=37435"},"modified":"2019-11-13T14:45:46","modified_gmt":"2019-11-13T09:15:46","slug":"approximation-questions-for-rrb-ntpc-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/approximation-questions-for-rrb-ntpc-pdf\/","title":{"rendered":"Approximation Questions for RRB NTPC PDF"},"content":{"rendered":"

Approximation Questions for RRB NTPC PDF<\/strong><\/span><\/h2>\n

Download RRB NTPC Approximations Questions PDF. Top 10 RRB NTPC questions based on asked questions in previous exam papers very important for the Railway NTPC exam.<\/p>\n

Download Approximation Questions for RRB NTPC PDF<\/a><\/p>\n

Take a free mock test for RRB NTPC<\/a><\/p>\n

Download RRB NTPC Previous Papers PDF<\/a><\/p>\n\n

Question 1:\u00a0<\/b>If 0.001 + x = 0.01, then find the approximate value of ‘x’.<\/p>\n

a)\u00a00.5<\/p>\n

b)\u00a01<\/p>\n

c)\u00a00.1<\/p>\n

d)\u00a00.01<\/p>\n

Question 2:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following questions?
\n$21 + 68 \\div 17 = ? $<\/p>\n

a)\u00a025<\/p>\n

b)\u00a035<\/p>\n

c)\u00a040<\/p>\n

d)\u00a010<\/p>\n

Question 3:\u00a0<\/b>What approximate value should comein place of the question mark (?) in the following equation?
\n($\\frac{1}{9}\\div\\frac{1}{9}$ of $\\frac{1}{3}$) of $\\frac{1}{6}=?$<\/p>\n

a)\u00a0$\\frac{1}{6}$<\/p>\n

b)\u00a0$\\frac{1}{2}$<\/p>\n

c)\u00a0$\\frac{1}{9}$<\/p>\n

d)\u00a0$\\frac{1}{3}$<\/p>\n

Question 4:\u00a0<\/b>What approximate value should come in place of (?) in the following equation ?
\n9876 $\\div$ \u00a024.96 + 215.005 – ? = 309.99<\/p>\n

a)\u00a0395<\/p>\n

b)\u00a0295<\/p>\n

c)\u00a0300<\/p>\n

d)\u00a0315<\/p>\n

e)\u00a0310<\/p>\n

Question 5:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following question ?
\n$45.709 \\div 11.342 \\times 6.667 = ?$<\/p>\n

a)\u00a088<\/p>\n

b)\u00a046<\/p>\n

c)\u00a0112<\/p>\n

d)\u00a056<\/p>\n

e)\u00a027<\/p>\n

RRB NTPC Previous Papers [Download PDF]<\/a><\/p>\n\n

Question 6:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following question?
\n$54.786 \\div 10.121 \\times 4.454 = ?$<\/p>\n

a)\u00a084<\/p>\n

b)\u00a048<\/p>\n

c)\u00a0118<\/p>\n

d)\u00a058<\/p>\n

e)\u00a024<\/p>\n

Question 7:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following questions?
\n$59.786 \\div 14.444 \\times 8.321 = ?$<\/p>\n

a)\u00a049<\/p>\n

b)\u00a058<\/p>\n

c)\u00a022<\/p>\n

d)\u00a066<\/p>\n

e)\u00a034<\/p>\n

Question 8:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following question?
\n$4275 \\div 496 \\times (21)^{2} = ?$<\/p>\n

a)\u00a03795<\/p>\n

b)\u00a03800<\/p>\n

c)\u00a03810<\/p>\n

d)\u00a03875<\/p>\n

e)\u00a03995<\/p>\n

Question 9:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value)
\n$9980 \\div 49 \\times (4.9)^{2} – 1130 = ?$<\/p>\n

a)\u00a03800<\/p>\n

b)\u00a04500<\/p>\n

c)\u00a02600<\/p>\n

d)\u00a03000<\/p>\n

e)\u00a04080<\/p>\n

Question 10:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following equation ?
\n$695.95\\div 29.07 \\times ? + 40.25 = 399.99$<\/p>\n

a)\u00a014<\/p>\n

b)\u00a017<\/p>\n

c)\u00a012<\/p>\n

d)\u00a016<\/p>\n

e)\u00a015<\/p>\n

Download General Science Notes PDF<\/a><\/p>\n

FREE RRB NTPC YOUTUBE VIDEOS<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$0.001 + x = 0.01$<\/p>\n

$ x = 0.01-0.001$<\/p>\n

$x=0.009$<\/p>\n

Hence d<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

By applying BODMAS we have
\n=$21+(68\\div17)$
\n=21+4
\n=25<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

($\\dfrac{1}{9}\\div\\dfrac{1}{9}$\u00a0 of\u00a0 $\\dfrac{1}{3}$) of $\\dfrac{1}{6} = (\\dfrac{1}{9} \\div \\dfrac{1}{27}$)\u00a0 of\u00a0 $\\dfrac{1}{6}$<\/p>\n

$= \\dfrac{1}{9} \\times 27$\u00a0 of\u00a0 $\\dfrac{1}{6}$<\/p>\n

$= 3 \\times \\dfrac{1}{6} = \\dfrac{1}{2}$<\/p>\n

4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Expression\u00a0:\u00a09876 $\\div$ \u00a024.96 + 215.005 – ? = 309.99<\/p>\n

=> $\\frac{9875}{25} + 215 – ? = 310$<\/p>\n

=> $395 + 215 – 310 = ?$<\/p>\n

=> $? = 610 – 310 = 300$<\/p>\n

5)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Expression\u00a0:\u00a0$45.709 \\div 11.342 \\times 6.667 = ?$<\/p>\n

= $\\frac{44}{11} \\times 7$<\/p>\n

= $4 \\times 7 = 28$<\/p>\n

$\\approx$ 27<\/p>\n

6)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Expression\u00a0: $54.786 \\div 10.121 \\times 4.454 = ?$<\/p>\n

= $\\frac{55}{10} \\times 4.5$<\/p>\n

= $24.75 \\approx 24$<\/p>\n

7)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Expression\u00a0:\u00a0$59.786 \\div 14.444 \\times 8.321 = ?$<\/p>\n

= $\\frac{60}{15} \\times 8$<\/p>\n

= $4 \\times 8$<\/p>\n

= $32 \\approx 34$<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Expression\u00a0:\u00a0$4275 \\div 496 \\times (21)^{2} = ?$<\/p>\n

= $\\frac{4275 \\times 441}{495}$<\/p>\n

= 3808.63 $\\approx$ 3810<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Since an approximate answer is sufficient, you can rewrite the question as $10000 \\div 50 \\times 5^{2} – 1130$<\/p>\n

Following BDMAS rule the result is 3870.<\/p>\n

The nearest value is 3800.<\/p>\n

Hence Option A is the correct answer.<\/p>\n

10)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Let the number to replace the question mark be equal to $X$<\/p>\n

Hence, $695.95\\div 29.07 \\times X + 40.25 = 399.99$<\/p>\n

$399.99 \\approx 400$ and $695.95 \\approx 696$ and $29.07 \\approx 29$<\/p>\n

So, the expression looks like $696 \\div 29 \\times X + 40 = 400$
\nHence, $24 \\times X = 360$ or $X = 15$<\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

We hope this Approximations Questions pdf for RRB NTPC exam will be highly useful for your Preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Approximation Questions for RRB NTPC PDF Download RRB NTPC Approximations Questions PDF. Top 10 RRB NTPC questions based on asked questions in previous exam papers very important for the Railway NTPC exam. Download RRB NTPC Previous Papers PDF Question 1:\u00a0If 0.001 + x = 0.01, then find the approximate value of ‘x’. a)\u00a00.5 b)\u00a01 c)\u00a00.1 […]<\/p>\n","protected":false},"author":41,"featured_media":37438,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1603],"tags":[1637,2052,1619,2659],"class_list":{"0":"post-37435","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-ntpc","11":"tag-rrb-exam","12":"tag-rrb-maths","13":"tag-rrb-ntpc-2019","14":"tag-rrb-ntpc-mocks"},"better_featured_image":{"id":37438,"alt_text":"Approximation Questions for RRB NTPC Set-2 PDF","caption":"Approximation Questions for RRB NTPC Set-2 PDF","description":"Approximation Questions for RRB NTPC Set-2 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