Download important Coding Decoding Questions PDF based on previously asked questions in IBPS Clerk and other Banking Exams. Practice Coding Decoding Question and Answers for IBPS Clerk Exam.<\/p>\n
Download Coding Decoding Questions For IBPS Clerk Set-3 PDF<\/a><\/p>\n Get 25 IBPS Clerk mocks for Rs. 149. Enroll here<\/a><\/p>\n Take Free IBPS Clerk Mock Test<\/a><\/p>\n Download IBPS Clerk Previous papers PDF<\/a><\/p>\n Go to Free Banking Study Material<\/a> (15,000 Solved Questions)<\/p>\n Instructions<\/b><\/p>\n In each question below is given a group of digits followed by four combinations of letters or symbols (a),(b)(c) and (d). You have to find out which of the combinations correctly represent the group of digits based on the coding system and the conditions given below and mark the number of that combination as your answer. If none of the combinations correctly represents the group of digits mark (e) i.e \u2018None of these\u2019 as your answer Question 1:\u00a0<\/b>813469<\/p>\n a)\u00a0RAK%@D<\/p>\n b)\u00a0DAK%@R<\/p>\n c)\u00a0M%RD\u00a9A<\/p>\n d)\u00a0$\\bigstar$AK%@$\\bigstar$<\/p>\n e)\u00a0None of these<\/p>\n Question 2:\u00a0<\/b>794821<\/p>\n a)\u00a0MR%D\u00a9A<\/p>\n b)\u00a0AR%D\u00a9M<\/p>\n c)\u00a0M%RD\u00a9A<\/p>\n d)\u00a0$R%D\u00a9$<\/p>\n e)\u00a0None of these<\/p>\n Question 3:\u00a0<\/b>591426<\/p>\n a)\u00a0@RA%\u00a9P<\/p>\n b)\u00a0PRA%\u00a9@<\/p>\n c)\u00a0@AR%\u00a9P<\/p>\n d)\u00a0$RA%\u00a9$\\bigstar$<\/p>\n e)\u00a0None of these<\/p>\n IBPS Clerk Online Mock Test<\/a><\/p>\n Instructions<\/b><\/p>\n Study the following information to answer the given questions: Question 4:\u00a0<\/b>What is the code for \u2018ideas\u2019 ?<\/p>\n a)\u00a0sha<\/p>\n b)\u00a0ba<\/p>\n c)\u00a0gi<\/p>\n d)\u00a0ma<\/p>\n e)\u00a0Cannot be determined<\/p>\n Question 5:\u00a0<\/b>What does \u2018fa\u2019 stand for ?<\/p>\n a)\u00a0thoughts<\/p>\n b)\u00a0insights<\/p>\n c)\u00a0new<\/p>\n d)\u00a0and<\/p>\n e)\u00a0solutions<\/p>\n Question 6:\u00a0<\/b>\u2019fa lo ba\u2019 could be a code for which of the following ?<\/p>\n a)\u00a0thoughts and action<\/p>\n b)\u00a0create and innovate<\/p>\n c)\u00a0ideas and thoughts<\/p>\n d)\u00a0create new solutions<\/p>\n e)\u00a0always better ideas<\/p>\n IBPS Clerk Previous Papers<\/a><\/p>\n Question 7:\u00a0<\/b>What is the code for \u2018new\u2019 ?<\/p>\n a)\u00a0ki<\/p>\n b)\u00a0ri<\/p>\n c)\u00a0to<\/p>\n d)\u00a0fa<\/p>\n e)\u00a0ba<\/p>\n Question 8:\u00a0<\/b>Which of the following may represent \u2018insights always better\u2019 ?<\/p>\n a)\u00a0jo ki to<\/p>\n b)\u00a0ki to ri<\/p>\n c)\u00a0sha jo ri<\/p>\n d)\u00a0to sha jo<\/p>\n e)\u00a0sha to ba<\/p>\n Question 9:\u00a0<\/b>What is the code for \u2018thoughts\u2019 ?<\/p>\n a)\u00a0ma<\/p>\n b)\u00a0fa<\/p>\n c)\u00a0ba<\/p>\n d)\u00a0jo<\/p>\n e)\u00a0Either jo or fa<\/p>\n IBPS Clerk Important Questions PDF<\/a><\/p>\n Free Banking Study Material (15,000 Solved Questions)<\/a><\/p>\n Instructions<\/b><\/p>\n Study the information to answer the given questions ? Question 10:\u00a0<\/b>Which of the following represents \u2018risk also large\u2019 ?<\/p>\n a)\u00a0nu fu po<\/p>\n b)\u00a0nu gi ro<\/p>\n c)\u00a0ro po ta<\/p>\n d)\u00a0fu nu ro<\/p>\n e)\u00a0ro yu fu<\/p>\n Question 11:\u00a0<\/b>What is the code for \u2018very\u2019 ?<\/p>\n a)\u00a0ta<\/p>\n b)\u00a0fu<\/p>\n c)\u00a0ro<\/p>\n d)\u00a0nu<\/p>\n e)\u00a0gi<\/p>\n Question 12:\u00a0<\/b>What is the code for \u2018associated\u2019 ?<\/p>\n a)\u00a0mi<\/p>\n b)\u00a0ta<\/p>\n c)\u00a0ro<\/p>\n d)\u00a0gi<\/p>\n e)\u00a0nu<\/p>\n Question 13:\u00a0<\/b>What does the code \u2018di\u2019 stand for ?<\/p>\n a)\u00a0Either \u2018damaging\u2019 or \u2018inherent\u2019<\/p>\n b)\u00a0inherent<\/p>\n c)\u00a0also<\/p>\n d)\u00a0low<\/p>\n e)\u00a0risk<\/p>\n Question 14:\u00a0<\/b>Which of the following represents \u2018that is low\u2019 ?<\/p>\n a)\u00a0po mi du<\/p>\n b)\u00a0se po mi<\/p>\n c)\u00a0ta mi po<\/p>\n d)\u00a0se po nu<\/p>\n e)\u00a0ta mi se<\/p>\n Question 15:\u00a0<\/b>In a certain code language \u2018TERMINAL\u2019 is written as \u2018NSFUMBOJ\u2019 and \u2018TOWERS\u2019 is written as \u2018XPUTSF\u2019. How is \u2018MATE\u2019 written in that code?<\/p>\n a)\u00a0FUBN<\/p>\n b)\u00a0UFNB<\/p>\n c)\u00a0BNFU<\/p>\n d)\u00a0BNDS<\/p>\n e)\u00a0None of these<\/p>\n Question 16:\u00a0<\/b>\u2018ERID\u2019 is related to \u2018DIRE\u2019 in the same way as \u2018RIPE\u2019 is related to\u2026\u2026\u2026..?<\/p>\n a)\u00a0EPIR<\/p>\n b)\u00a0PERI<\/p>\n c)\u00a0EPRI<\/p>\n d)\u00a0PEIR<\/p>\n e)\u00a0IPRE<\/p>\n Instructions<\/b><\/p>\n In each question below, a group of digits\/symbols is given, followed by four combinations of letters numbered (1), (2), (3), and (4). You have to find out which of the combinations (1), (2), (3) and (4) correctly represents the group of digits\/symbols based on the following coding system and the conditions those follow and mark the number of that combination as your answer. If none of the four combinations correctly represents the group of digits\/symbols, mark (5) i.e.,\u2019None of these\u2019 as the answer Question 17:\u00a0<\/b>@91$26<\/p>\n a)\u00a0JEFHRP<\/p>\n b)\u00a0PEFHRP<\/p>\n c)\u00a0XEFHRX<\/p>\n d)\u00a0PEFHRJ<\/p>\n e)\u00a0None of these<\/p>\n Question 18:\u00a0<\/b>387#\u00a99<\/p>\n a)\u00a0KMDTAE<\/p>\n b)\u00a0KDMATE<\/p>\n c)\u00a0EDMTAK<\/p>\n d)\u00a0KDMTAK<\/p>\n e)\u00a0None of these<\/p>\n Question 19:\u00a0<\/b>4@312$\\delta$<\/p>\n a)\u00a0VPKFRV<\/p>\n b)\u00a0VPKFRI<\/p>\n c)\u00a0XPKFRX<\/p>\n d)\u00a0IPKFRV<\/p>\n e)\u00a0None of these<\/p>\n Question 20:\u00a0<\/b>%4187*<\/p>\n a)\u00a0QIFDMU<\/p>\n b)\u00a0UIFDMQ<\/p>\n c)\u00a0XIFDMX<\/p>\n d)\u00a0UIFDMU<\/p>\n e)\u00a0None of these<\/p>\n Daily Free Banking Online Tests<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n The data given to us is:<\/p>\n Digits 5 1 3 4 9 6 8 2 7 Here, by choosing proper symbols, we get code as: DAK%@R.<\/p>\n 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The data given to us is:<\/p>\n Digits 5 1 3 4 9 6 8 2 7 As both the digits are odd, they can be coded as $.<\/p>\n Only option D has $ at the end. Hence, the correct option is D.<\/p>\n 3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n The data given to us is:<\/p>\n Digits 5 1 3 4 9 6 8 2 7 Here, 5 is odd and 6 is even, there symbols would be reversed. Hence, option A is correct.<\/p>\n 4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n By analysing the relation between the given sentences and the codes we can deduce following codes and their words. Hence, the correct option is C.<\/p>\n 5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n By analysing the relation between the given sentences and the codes we can deduce following codes and their words. Hence, and stands for fa. Option D is correct.<\/p>\n 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n By analysing the relation between the given sentences and the codes we can deduce following codes and their words. Here, fa= and and ba= create. Only ‘innovate (lo)’ is new word.<\/p>\n Hence, option B is correct.<\/p>\n 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n By analysing the relation between the given sentences and the codes we can deduce following codes and their words. Hence, option B is correct.<\/p>\n 8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n By analysing the relation between the given sentences and the codes we can deduce following codes and their words. By analysing the relation between the given sentences and the codes we can deduce following codes and their words. Hence, option A is correct.<\/p>\n 10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n From the intersection of the first two information, we can conclude that “nu” and “gi” will either “Risk” or “very”.<\/p>\n From the intersection of the first and third information, we can conclude that “ta” will mean “associated”.<\/p>\n From the intersection of first and fourth information, “nu” will mean “risk” and hence, “gi” will mean “Very”<\/p>\n “ro” will be “large” and “fu” means also<\/p>\n Hence, answer will be D<\/p>\n 11)\u00a0Answer\u00a0(E)<\/strong><\/p>\n From the intersection of the first two information, we can conclude that “nu” and “gi” will either “Risk” or “very”.<\/p>\n From the intersection of the first and third information, we can conclude that “ta” will mean “associated”.<\/p>\n From the intersection of first and fourth information, “nu” will mean “risk” and hence, “gi” will mean “Very”<\/p>\n 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n From the intersection of the first two information, we can conclude that “nu” and “gi” will either “Risk” or “very”.<\/p>\n From the intersection of the first and third information, we can conclude that “ta” will mean “associated”.<\/p>\n Hence, answer will be “B”<\/p>\n 13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n From the intersection of the first two information, we can conclude that “nu” and “gi” will either “Risk” or “very”.<\/p>\n From the intersection of the first and third information, we can conclude that “ta” will mean “associated”.<\/p>\n From the intersection of first and fourth information, “nu” will mean “risk” and hence, “gi” will mean “Very”<\/p>\n “ro” will be “large” and “fu” means also<\/p>\n Now for the fourth information, there will be no intersection for the word damaging and inherent. Hence, code “di” either will be “damaging” or “inherent”.<\/p>\n 14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n From the intersection of the first two information, we can conclude that “nu” and “gi” will either “Risk” or “very”.<\/p>\n From the intersection of the first and third information, we can conclude that “ta” will mean “associated”.<\/p>\n From the intersection of first and fourth information, “nu” will mean “risk” and hence, “gi” will mean “Very”<\/p>\n “ro” will be “large” and “fu” means “also”<\/p>\n “se” will be “low” and “po” will be “that”<\/p>\n Hence, answer will be B<\/p>\n 15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n while coding \u2018TERMINAL’, for first four letters, every letter will change to its next letter in alphabetical series and 1st and the fourth letter will exchange their positions and 2nd, 3rd will exchange their positions. Similarly, next four letters will also follow the same pattern. Hence, code will be \u2018NSFUMBOJ\u2019<\/p>\n Now for “MATE”, we will change the letters according to above-stated pattern only. M will be N, A will be B and they will exchange their positions. T will be U and E will be F and they will also exchange their positions.<\/p>\n Hence, answer will be C<\/p>\n 16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n ERID is DIRE written in reverse form. Here, the first digit is symbol and the last digit is a number and therefore no conditions apply. Here, the first digit is odd and last one is even, their is no change in the code.<\/p>\n Now, 387#\u00a99 will be coded as KDMTAE.<\/p>\n But, none of the option match<\/p>\n Hence, the correct option is E i.e none of these. The code starts with even digit and ends with symbol. Hence, the code for symbol will be used for both digit and symbol. The first and last in the groups are symbols and hence, both will be coded as ‘X’. Highly Rated Free Preparation App for Banking Exams<\/a><\/p>\n
\nDigits 5 1 3 4 9 6 8 2 7
\ncode P A K % R @ D \u00a9 M
\nConditions:
\n(i) If the first digit is odd and the last digit is even the codes for the first and last digits are to be interchanged
\n(ii) If both the first and the last digits are even both are to be coded as $\\bigstar$
\n(iii) If both the first and the last digits are odd both are to be coded as $.<\/p>\n
\nIn a certain code, \u2018always create new ideas \u2018 is written as \u2018ba ri sha gi\u2019 ideas and new thoughts\u2019 is written as \u2018fa gi ma ri\u2019 \u2018create thoughts and insight\u2019 is written as \u2018ma jo ba fa\u2019, and \u2018new and better solutions\u2019 is written as \u2018ki ri to fa\u2019.<\/p>\n
\nIn a certain code
\n\u2018very large risk associated\u2019 is written as \u2018nu ta ro gi\u2019\u2019
\n\u2018risk is very low\u2019 is written as \u2018gi se nu mi\u2019,
\n\u2018is that also associated\u2019 is written as \u2018ta mi po fu\u2019,
\n\u2018inherent risk also damaging\u2019 is written as \u2018fu nu di yu\u2019,
\n(All codes are two letter codes only)<\/p>\n
\nDigit\/Symbol 5 9 @ \u00a9 3 8 1 $ % 4 2 6 * 7 $\\delta$ #
\nLetter Code B E P A K D F H Q I R J U M V T
\nConditions
\n(a) If the first unit in the group is an even digit and the last unit is a symbol, both these are to be coded as the code for the symbol.
\n(b) If the first unit in the group is an odd digit and the last unit is an even digit, their codes are to the unchanged.
\n(c) If both the first and the last units in the group are symbols, both these are to be coded as \u2018X\u2019.<\/p>\n
\ncode P A K % R @ D \u00a9 M
\nConditions:
\n(i) If the first digit is odd and the last digit is even the codes for the first and last digits are to be interchanged
\n(ii) If both the first and the last digits are even both are to be coded as $\\bigstar$
\n(iii) If both the first and the last digits are odd both are to be coded as $.<\/p>\n
\ncode P A K % R @ D \u00a9 M
\nConditions:
\n(i) If the first digit is odd and the last digit is even the codes for the first and last digits are to be interchanged
\n(ii) If both the first and the last digits are even both are to be coded as $\\bigstar$
\n(iii) If both the first and the last digits are odd both are to be coded as $.<\/p>\n
\ncode P A K % R @ D \u00a9 M
\nConditions:
\n(i) If the first digit is odd and the last digit is even the codes for the first and last digits are to be interchanged
\n(ii) If both the first and the last digits are even both are to be coded as $\\bigstar$
\n(iii) If both the first and the last digits are odd both are to be coded as $.<\/p>\n
\n591426 would be coded as @RA%\u00a9P<\/p>\n
\nideas=gi,
\nand=fa,
\nnew=ri,
\ncreate=ba,
\nthoughts=ma,
\ninsights=jo,
\nalways= sha,
\nbetter solution= ki so.<\/p>\n
\nideas=gi,
\nand=fa,
\nnew=ri,
\ncreate=ba,
\nthoughts=ma,
\ninsights=jo,
\nalways= sha,
\nbetter solution= ki so.<\/p>\n
\nideas=gi,
\nand=fa,
\nnew=ri,
\ncreate=ba,
\nthoughts=ma,
\ninsights=jo,
\nalways= sha,
\nbetter solution= ki so.<\/p>\n
\nideas=gi,
\nand=fa,
\nnew=ri,
\ncreate=ba,
\nthoughts=ma,
\ninsights=jo,
\nalways= sha,
\nbetter solution= ki so.<\/p>\n
\nideas=gi,
\nand=fa,
\nnew=ri,
\ncreate=ba,
\nthoughts=ma,
\ninsights=jo,
\nalways= sha,
\nsolution= so,
\nbetter = to.
\nHence, option D is correct.
\n9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n
\nideas=gi,
\nand=fa,
\nnew=ri,
\ncreate=ba,
\nthoughts=ma,
\ninsights=jo,
\nalways= sha,
\nsolution=\u00a0 so.<\/p>\n
\nHence, we can obtain EPIR by writing RIPE in reverse form.
\nOption A is correct.
\n17)\u00a0Answer\u00a0(D)<\/strong><\/p>\n
\nThis @91$26 can be coded as PEFHRJ.
\nThe correct option is D.
\n18)\u00a0Answer\u00a0(E)<\/strong><\/p>\n
\n19)\u00a0Answer\u00a0(A)<\/strong><\/p>\n
\nHence, the correct coding of 4@312$\\delta$ will be VPKFRV.
\nThe correct option is A.
\n20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n
\nTherefore, %4187* will be coded as XIFDMX.
\nThe correct option is C.<\/p>\n