{"id":36441,"date":"2019-10-22T19:01:17","date_gmt":"2019-10-22T13:31:17","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=36441"},"modified":"2019-10-22T19:01:17","modified_gmt":"2019-10-22T13:31:17","slug":"quadratic-equation-questions-for-rrb-ntpc-set-2-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/quadratic-equation-questions-for-rrb-ntpc-set-2-pdf\/","title":{"rendered":"Quadratic Equation Questions for RRB NTPC set-2 PDF"},"content":{"rendered":"

Quadratic Equation Questions for RRB NTPC set-2 PDF<\/strong><\/span><\/h2>\n

Download RRB NTPC Quadratic Equation Questions set-2 PDF. Top 10 RRB NTPC questions based on asked questions in previous exam papers very important for the Railway NTPC exam.<\/p>\n

Download Quadratic Equation Questions for RRB NTPC set-2 PDF<\/a><\/p>\n

Take a free mock test for RRB NTPC<\/a><\/p>\n

Download RRB NTPC Previous Papers PDF<\/a><\/p>\n\n

Question 1:\u00a0<\/b>Sum of the roots of a quadratic equation Q1 is -1 and product is -156 then what is the quadratic equation having roots that are 2 less than the roots of the quadratic equation Q1 ?<\/p>\n

a)\u00a0$x^{2}+10x-150$=0<\/p>\n

b)\u00a0$x^{2}-5x-150$=0<\/p>\n

c)\u00a0$x^{2}+5x-200$=0<\/p>\n

d)\u00a0$x^{2}-5x-200$=0<\/p>\n

e)\u00a0$x^{2}+5x-150$=0<\/p>\n

Question 2:\u00a0<\/b>In each question two equations numbered (I) and (II) are given. Student should solve both the equations and solve the question.
\nI. x$^{2}$ – 25x – 54 = 0
\nII. y$^{2}$ + 104 = 30y<\/p>\n

a)\u00a0x $\\leq$ y<\/p>\n

b)\u00a0x = y or relation cannot be established between x and y<\/p>\n

c)\u00a0x $\\geq$ y<\/p>\n

d)\u00a0x > y<\/p>\n

e)\u00a0x < y<\/p>\n

Question 3:\u00a0<\/b>In the following questions two equations numbered I and II are given. Solve both the equations and choose the correct answer.
\nI. $X^{2} – 10X + 21 = 0$
\nII.$Y^{2} + 6Y – 27= 0$<\/p>\n

a)\u00a0X < Y<\/p>\n

b)\u00a0X $\\geq$ Y<\/p>\n

c)\u00a0X $\\leq$ Y<\/p>\n

d)\u00a0X > Y<\/p>\n

e)\u00a0X = Y or the relationship cannot be determined.<\/p>\n

RRB NTPC Previous Papers [Download PDF]<\/a><\/p>\n

FREE RRB NTPC YOUTUBE VIDEOS<\/a><\/p>\n

Question 4:\u00a0<\/b>In the following questions two equations numbered I and II are given. Solve both the equations and choose the correct answer.
\nI. $7X^{2} – 2X – 9 = 0$
\nII.$Y^{2} – Y – 72= 0$<\/p>\n

a)\u00a0X < Y<\/p>\n

b)\u00a0X $\\geq$ Y<\/p>\n

c)\u00a0X $\\leq$ Y<\/p>\n

d)\u00a0X > Y<\/p>\n

e)\u00a0X = Y or the relationship cannot be determined.<\/p>\n

Question 5:\u00a0<\/b>In the following questions two equations numbered I and II are given. Solve both the equations and choose the correct answer.
\nI. $2X^{2} – 4X – 16 = 0$
\nII.$Y^{2} + 8Y + 15 = 0$<\/p>\n

a)\u00a0X < Y<\/p>\n

b)\u00a0X $\\geq$ Y<\/p>\n

c)\u00a0X $\\leq$ Y<\/p>\n

d)\u00a0X > Y<\/p>\n

e)\u00a0X=Y or the relationship cannot be determined.<\/p>\n

Question 6:\u00a0<\/b>I.\u00a0$x^{2}+3x-28=0$
\nII.\u00a0$y^{2} -y-20=0$<\/p>\n

a)\u00a0x > y<\/p>\n

b)\u00a0x \u2265 y<\/p>\n

c)\u00a0x < y<\/p>\n

d)\u00a0x \u2264 y<\/p>\n

e)\u00a0x = y or the relation cannot be established.<\/p>\n

RRB NTPC Free Mock Test<\/a><\/p>\n\n

Question 7:\u00a0<\/b>$2x^2 + 3x + 1 = 0$
\n$4y^2 + 16y + 15 = 0$<\/p>\n

a)\u00a0$x > y$<\/p>\n

b)\u00a0$x < y$<\/p>\n

c)\u00a0$x \\geq y$<\/p>\n

d)\u00a0$x \\leq y$<\/p>\n

e)\u00a0$x = y$ or no relation<\/p>\n

Question 8:\u00a0<\/b>Two quadratic equations are given below. Solve these equations and select the appropriate option.$x^{2} – 2x – 63 = 0$
\n$y^{2} – 8y + 15= 0$<\/p>\n

a)\u00a0If x is greater than or equal to y<\/p>\n

b)\u00a0If x is greater than y<\/p>\n

c)\u00a0If x is less than or equal to y<\/p>\n

d)\u00a0If x is less than y<\/p>\n

e)\u00a0If x = y or no relation can be established between x and y<\/p>\n

Question 9:\u00a0<\/b>Two quadratic equations are given below. Solve these equations and select the appropriate option$x^{2} – 15x +26 = 0$
\n$y^{2} + 9y – 22= 0$<\/p>\n

a)\u00a0If x is greater than or equal to y<\/p>\n

b)\u00a0If x is greater than y<\/p>\n

c)\u00a0If x is less than or equal to y<\/p>\n

d)\u00a0If x is less than y<\/p>\n

e)\u00a0If x = y or no relation can be established between x and y<\/p>\n

Question 10:\u00a0<\/b>Two quadratic equations are given below. Solve these equations and select the appropriate option.$x^{2} + 8x – 48 = 0$
\n$y^{2} + 9y – 10= 0$<\/p>\n

a)\u00a0If x is greater than or equal to y<\/p>\n

b)\u00a0If x is greater than y<\/p>\n

c)\u00a0If x is less than or equal to y<\/p>\n

d)\u00a0If x is less than y<\/p>\n

e)\u00a0If x = y or no relation can be established between x and y<\/p>\n

Download General Science Notes PDF<\/a><\/p>\n\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

As given sum of the roots=-1
\nProduct of the roots=-156
\nSo the quadratic equation Q1 is $x^{2}+x-156$=0
\n$x^{2}-12x+13x-156$=0
\nx(x-12)+13(x-12)=0
\n(x+13)(x-12)=0
\nx=-13 and x=12
\nSo the required new roots are -15 and 10
\nTherefore required quadratic equation is (x+15)(x-10)=0
\n$x^{2}+5x-150$=0<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

I.\u00a0x$^{2}$ – 25x – 54 = 0<\/p>\n

x$^{2}$ – 27x + 2x – 54 = 0<\/p>\n

x(x – 27) + 2(x – 27) = 0<\/p>\n

x = -2 or x = 27<\/p>\n

II. \u00a0y$^{2}$ + 104 = 30y<\/p>\n

y$^{2}$ -30y + 104 = 0<\/p>\n

y$^{2}$ – 26y – 4y + 104 = 0<\/p>\n

y(y-26) – 4(y-26) = 0<\/p>\n

y=26 or y=4<\/p>\n

The relation between x and y cannot be established as one value of x is greater than and other value of x is less than y.<\/p>\n

Hence, option B is the correct answer.<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

On solving the equation I,
\n(X – 3)(X – 7) = 0,
\nX = 3, X = 7.<\/p>\n

On solving the equation II,
\n(Y + 9)(Y – 3) = 0,
\nY = -9, Y = 3.<\/p>\n

One value of X=3 is equals to Y while the other value is higher than both the values of Y hence we can say that X $\\geq$ Y.<\/p>\n

4)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

On solving the equation I,
\n$7X^{2} – 2X – 9 = 0$
\n$7X^{2} – 9X + 7X – 9 = 0$
\n(X + 1)(7X – 9) = 0,
\nX = -1, X = 9\/7.<\/p>\n

On solving the equation II,
\n(Y – 9)(Y + 8) = 0,
\nY = 9, Y = -8.<\/p>\n

Since X = -1 is greater than Y = -8 while at the same time X = -1 is smaller than Y = 9. Hence we can say that no relationship exists.<\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

On solving the equation I,
\n$2X^{2} – 4X – 16 = 0$
\n$X^{2} – 2X – 8 = 0$
\n(X – 4)(X + 2) = 0,
\nX = 4, X = -2.<\/p>\n

On solving the equation II,
\n(Y + 5)(Y + 3) = 0,
\nY = -5, Y = -3.<\/p>\n

For both the roots X > Y. Hence answer d.<\/p>\n

6)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

I.$x^{2} + 3x – 28 = 0$<\/p>\n

=> $x^2 + 7x – 4x – 28 = 0$<\/p>\n

=> $x (x + 7) – 4 (x + 7) = 0$<\/p>\n

=> $(x – 4) (x + 7) = 0$<\/p>\n

=> $x = 4 , -7$<\/p>\n

II.$y^{2} – y – 20 = 0$<\/p>\n

=> $y^2 – 5y + 4y – 20 = 0$<\/p>\n

=> $y (y – 5) + 4 (y – 5) = 0$<\/p>\n

=> $(y + 4) (y – 5) = 0$<\/p>\n

=> $y = -4 , 5$<\/p>\n

$\\therefore$ No relation can be established.<\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$2x^2 + 3x + 1 = 0$
\n(2x + 1) (x + 1) = 0
\nx = -0.5 or -1
\n$4y^2 + 16y + 15 = 0$
\n$(2y + 3) (2y + 5) = 0$
\ny = -1.5 or -2.5<\/p>\n

Hence, x > y.<\/p>\n

8)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

The first equation can be factorized as
\n(x + 7)(x- 9) = 0
\nSo the roots of the first equation are x = -7 and x = 9
\nThe second equation can be factorized as
\n(y- 5)(y-3) = 0
\nThus, the roots of the second equation are y = 5 and y = 3
\nThus, the possible combinations of x,y are
\n(-7,5), (-7,3), (9,5) and (9,3)
\nSo we can see that no relation can be established between x and y.<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$x^{2} – 15x +26 = 0$
\n$(x-2)(x-13)=0$
\nX = 2 or 13<\/p>\n

$y^{2} + 9y – 22= 0$
\n$(y+11)(y-2) = 0$
\nY= 2 or -11<\/p>\n

Therefore, x is greater than or equal to y. option A.<\/p>\n

10)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

The first equation can be factorized as
\n(x + 12)(x- 4) = 0
\nSo the roots of the first equation are x = -12 and x = 4
\nThe second equation can be factorized as
\n(y+10)(y-1) = 0
\nThus, the roots of the second equation are y = 10 and y = 1
\nThus, the possible combinations of x,y are
\n(-12,-10), (-12,1), (4,-10) and (4,1)
\nSo we can see that no relation can be established between x and y.<\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

We hope this Quadratic Equation Questions set-2 pdf for RRB NTPC exam will be highly useful for your Preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Quadratic Equation Questions for RRB NTPC set-2 PDF Download RRB NTPC Quadratic Equation Questions set-2 PDF. Top 10 RRB NTPC questions based on asked questions in previous exam papers very important for the Railway NTPC exam. Take a free mock test for RRB NTPC Download RRB NTPC Previous Papers PDF Question 1:\u00a0Sum of the roots […]<\/p>\n","protected":false},"author":41,"featured_media":36444,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1603],"tags":[1637,1593,1623],"class_list":{"0":"post-36441","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-ntpc","11":"tag-rrb-exam","12":"tag-rrb-ntpc","13":"tag-rrb-ntpc-maths"},"better_featured_image":{"id":36444,"alt_text":"Quadratic Equation Questions for RRB NTPC set-2 PDF","caption":"Quadratic Equation Questions for RRB NTPC set-2 PDF","description":"Quadratic Equation Questions for RRB NTPC set-2 PDF","media_type":"image","media_details":{"width":1200,"height":630,"file":"2019\/10\/fig-22-10-2019_10-52-39.jpg","sizes":{"thumbnail":{"file":"fig-22-10-2019_10-52-39-150x150.jpg","width":150,"height":150,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-150x150.jpg"},"medium":{"file":"fig-22-10-2019_10-52-39-300x158.jpg","width":300,"height":158,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-300x158.jpg"},"medium_large":{"file":"fig-22-10-2019_10-52-39-768x403.jpg","width":768,"height":403,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-768x403.jpg"},"large":{"file":"fig-22-10-2019_10-52-39-1024x538.jpg","width":1024,"height":538,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-1024x538.jpg"},"tiny-lazy":{"file":"fig-22-10-2019_10-52-39-30x16.jpg","width":30,"height":16,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-30x16.jpg"},"td_80x60":{"file":"fig-22-10-2019_10-52-39-80x60.jpg","width":80,"height":60,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-80x60.jpg"},"td_100x70":{"file":"fig-22-10-2019_10-52-39-100x70.jpg","width":100,"height":70,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-100x70.jpg"},"td_218x150":{"file":"fig-22-10-2019_10-52-39-218x150.jpg","width":218,"height":150,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-218x150.jpg"},"td_265x198":{"file":"fig-22-10-2019_10-52-39-265x198.jpg","width":265,"height":198,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-265x198.jpg"},"td_324x160":{"file":"fig-22-10-2019_10-52-39-324x160.jpg","width":324,"height":160,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-324x160.jpg"},"td_324x235":{"file":"fig-22-10-2019_10-52-39-324x235.jpg","width":324,"height":235,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-324x235.jpg"},"td_324x400":{"file":"fig-22-10-2019_10-52-39-324x400.jpg","width":324,"height":400,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-324x400.jpg"},"td_356x220":{"file":"fig-22-10-2019_10-52-39-356x220.jpg","width":356,"height":220,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-356x220.jpg"},"td_356x364":{"file":"fig-22-10-2019_10-52-39-356x364.jpg","width":356,"height":364,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-356x364.jpg"},"td_533x261":{"file":"fig-22-10-2019_10-52-39-533x261.jpg","width":533,"height":261,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-533x261.jpg"},"td_534x462":{"file":"fig-22-10-2019_10-52-39-534x462.jpg","width":534,"height":462,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-534x462.jpg"},"td_696x0":{"file":"fig-22-10-2019_10-52-39-696x365.jpg","width":696,"height":365,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-696x365.jpg"},"td_696x385":{"file":"fig-22-10-2019_10-52-39-696x385.jpg","width":696,"height":385,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-696x385.jpg"},"td_741x486":{"file":"fig-22-10-2019_10-52-39-741x486.jpg","width":741,"height":486,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-741x486.jpg"},"td_1068x580":{"file":"fig-22-10-2019_10-52-39-1068x580.jpg","width":1068,"height":580,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-1068x580.jpg"},"td_1068x0":{"file":"fig-22-10-2019_10-52-39-1068x561.jpg","width":1068,"height":561,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-1068x561.jpg"},"td_0x420":{"file":"fig-22-10-2019_10-52-39-800x420.jpg","width":800,"height":420,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39-800x420.jpg"}},"image_meta":{"aperture":"0","credit":"","camera":"","caption":"","created_timestamp":"0","copyright":"","focal_length":"0","iso":"0","shutter_speed":"0","title":"","orientation":"0"}},"post":null,"source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2019\/10\/fig-22-10-2019_10-52-39.jpg"},"yoast_head":"\n\n\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\n\n\n