{"id":35832,"date":"2019-10-05T18:39:30","date_gmt":"2019-10-05T13:09:30","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=35832"},"modified":"2019-10-05T18:39:30","modified_gmt":"2019-10-05T13:09:30","slug":"simplification-questions-for-bank-clerk-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/simplification-questions-for-bank-clerk-pdf\/","title":{"rendered":"Simplification Questions for Bank CLERK PDF"},"content":{"rendered":"

Simplification Questions for Bank CLERK PDF<\/strong><\/span><\/h2>\n

Download Simplification banking important questions and answers PDF. Practice solved problems provided with detailed explanations for bank clerk exam.<\/p>\n

Download Simplification Questions for Bank CLERK PDF<\/a><\/p>\n

75 SBI Clerk Mocks & Sectionals – Rs. 360<\/a><\/p>\n

Download all SBI Clerk questions and Answers PDF\u00a0<\/a><\/p>\n

For more questions visit SBI Clerk Previous question papers (solved)<\/a><\/p>\n

Instructions<\/b><\/p>\n

What should come in place of question mark (?) in the following question ?<\/p>\n

Question 1:\u00a0<\/b>$[(144)^{2}\\div48\\times18]\\div36=\\sqrt{?}$<\/p>\n

a)\u00a023328<\/p>\n

b)\u00a036<\/p>\n

c)\u00a0216<\/p>\n

d)\u00a046656<\/p>\n

e)\u00a0None of these<\/p>\n

Question 2:\u00a0<\/b>$(27)^{18}\\div(27)^{3}=?$<\/p>\n

a)\u00a0$(27)^{54}$<\/p>\n

b)\u00a0$(27)^{21}$<\/p>\n

c)\u00a0$(27)^{15}$<\/p>\n

d)\u00a0$(27)^{6}$<\/p>\n

e)\u00a0None of these<\/p>\n

Question 3:\u00a0<\/b>$5\\frac{1}{4}+6\\frac{2}{3}+7\\frac{1}{6}=?$<\/p>\n

a)\u00a019.5<\/p>\n

b)\u00a0$19\\frac{11}{12}$<\/p>\n

c)\u00a0$19\\frac{1}{12}$<\/p>\n

d)\u00a019<\/p>\n

e)\u00a0None of these<\/p>\n

Question 4:\u00a0<\/b>$4895+364\\times0.75-49=?$<\/p>\n

a)\u00a05119<\/p>\n

b)\u00a03895<\/p>\n

c)\u00a03907<\/p>\n

d)\u00a05210<\/p>\n

e)\u00a0None of these<\/p>\n

Instructions<\/b><\/p>\n

What should come in place of the question mark (?) in the following number series?<\/p>\n

Question 5:\u00a0<\/b>$\\frac{1}{4}, \\frac{1}{2}, \\frac{3}{4}, 1, 1\\frac{1}{4}, 1\\frac{1}{2}, 1\\frac{3}{4}, ?$<\/p>\n

a)\u00a02<\/p>\n

b)\u00a04<\/p>\n

c)\u00a061<\/p>\n

d) 41<\/p>\n

e) 21<\/p>\n

SBI Clerk Previous question Papers<\/a><\/p>\n

SBI Clerk expected Cutoff 2018<\/a><\/p>\n

Question 6:\u00a0<\/b>What will come in place of both the question marks (?) in the following question ?$\\frac{(?)^{0.6}}{104}=\\frac{26}{(?)^{1.4}}$<\/p>\n

a)\u00a058<\/p>\n

b)\u00a0-48<\/p>\n

c)\u00a0-56<\/p>\n

d)\u00a042<\/p>\n

e)\u00a0-52<\/p>\n

Question 7:\u00a0<\/b>Out of the fractions $\\frac{1}{2}, \\frac{7}{8}, \\frac{3}{4}, \\frac{5}{6}$, and $\\frac{6}{7}$ what is the difference between the largest and smallest fractions ?<\/p>\n

a)\u00a0$\\frac{7}{13}$<\/p>\n

b)\u00a0$\\frac{3}{8}$<\/p>\n

c)\u00a0$\\frac{4}{7}$<\/p>\n

d)\u00a0$\\frac{1}{6}$<\/p>\n

e)\u00a0None of these<\/p>\n

Question 8:\u00a0<\/b>If $(11)^{3}$ is subtracted from $(46)^{2}$ . what will be the remainder ?<\/p>\n

a)\u00a0787<\/p>\n

b)\u00a0785<\/p>\n

c)\u00a0781<\/p>\n

d)\u00a0783<\/p>\n

e)\u00a0None of these<\/p>\n

Question 9:\u00a0<\/b>90.05 + 281 \u00f7 4 -151.06 = $\\sqrt[3]{?}$<\/p>\n

a)\u00a027<\/p>\n

b)\u00a0343<\/p>\n

c)\u00a0216<\/p>\n

d)\u00a0729<\/p>\n

e)\u00a0176<\/p>\n

Question 10:\u00a0<\/b>$17.98^{2} + 4.05 \\times 90.11 \\div 4.98 = ?$<\/p>\n

a)\u00a0396<\/p>\n

b)\u00a0336<\/p>\n

c)\u00a0242<\/p>\n

d)\u00a0423<\/p>\n

e)\u00a0816<\/p>\n

Take a Free SBI Clerk Mock test<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Lets assume the unknown number to be x.
\nNow, we will solve in a stepwise manner going by BODMAS rule.
\n144^2=20736,
\n20736\/48=432
\n432*18=7776
\n7776\/36=216
\nNow x=216^2 = 46656 which is option D.<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

We know that, by the rule of indices,<\/p>\n

ab <\/sup>$\\div$ ac<\/sup> = a(b-c) <\/sup><\/p>\n

Hence, $(27)^{18}\\div(27)^{3}=(27)^{(18-3)}$ = $(27)^{15}$<\/p>\n

Hence, Option C is correct option.<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

First, we convert mixed fractions into proper fractions:
\n$5\\frac{1}{4}=\\frac{21}{4}$
\n$6\\frac{2}{3}=\\frac{20}{3}$
\n$7\\frac{1}{6}=\\frac{43}{6}$
\nNow, $5\\frac{1}{4}+6\\frac{2}{3}+7\\frac{1}{6}=\\frac{21}{4}+\\frac{20}{3}+\\frac{43}{6}$<\/p>\n

= $\\frac{229}{12}$<\/p>\n

In mixed fraction form 229\/12 = $19\\frac{1}{12}$
\nOption C is correct.<\/p>\n

4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The problem can be solved by applying BODMAS rule in a stepwise manner.
\n$364\\times0.75$ = 273
\nNow, 4895+273= 5168
\n5168 – 49 = 5119 which is option A.<\/p>\n

5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$\\frac{1}{4}$ is added to each number<\/p>\n

$\\frac{1}{4}$ + $\\frac{1}{4}$ = $\\frac{1}{2}$<\/p>\n

$\\frac{1}{2}$\u00a0+ $\\frac{1}{4}$ = $\\frac{3}{4}$<\/p>\n

$\\frac{3}{4}$\u00a0+ $\\frac{1}{4}$ = 1<\/p>\n

1\u00a0+ $\\frac{1}{4}$ = $1\\frac{1}{4}$<\/p>\n

$1\\frac{1}{4}$\u00a0+ $\\frac{1}{4}$ = $1\\frac{1}{2}$<\/p>\n

$1\\frac{1}{2}$\u00a0+ $\\frac{1}{4}$ = $1\\frac{3}{4}$<\/p>\n

$1\\frac{3}{4}$\u00a0+ $\\frac{1}{4}$ =\u00a02<\/strong><\/p>\n

SBI Clerk Free Practice Questions<\/a><\/p>\n

6)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

$\\frac{(x)^{0.6}}{104}=\\frac{26}{(x)^{1.4}}$<\/p>\n

${(x)^{0.6}} * {(x)^{01.4}}$ = 104*26<\/p>\n

${(x)^{2}}$ = 104*26<\/p>\n

x = \u00b1<\/span><\/span>52<\/span><\/p>\n

7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Given values are ,
\n$\\frac{1}{2}$ = 0.5<\/p>\n

$\\frac{7}{8}$ = 0.87<\/p>\n

$\\frac{3}{4}$ = 0.75<\/p>\n

$\\frac{5}{6}$ = 0.83<\/p>\n

$\\frac{6}{7}$ = 0.86<\/p>\n

\u2234 Required difference = $\\frac{7}{8}$ – $\\frac{1}{2}$ = (7-4)\/8 = 3\/8<\/p>\n

8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Here<\/p>\n

$(46)^2$ = 2116<\/p>\n

$(11)^3$ = 1331<\/p>\n

So, 2116 – 1331 = 785<\/p>\n

9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

The given statement can be written as $90 + 60 – 151 = \\sqrt[3]{?}$<\/p>\n

$9 =\\sqrt[3]{?}$<\/p>\n

=> ? = 729<\/span><\/p>\n

Option D is the answer.<\/span><\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The given equation can be written as $18^{2} + \\frac{4*90}{5}$<\/p>\n

= $324 + 4*18$<\/p>\n

= $396$<\/p>\n

Option A is the right answer.<\/p>\n

SBI Clerk Daily practice tests<\/a><\/p>\n

SBI Clerk Free Mock Test<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Simplification Questions for Bank CLERK PDF Download Simplification banking important questions and answers PDF. Practice solved problems provided with detailed explanations for bank clerk exam. Download all SBI Clerk questions and Answers PDF\u00a0 For more questions visit SBI Clerk Previous question papers (solved) Instructions What should come in place of question mark (?) in the […]<\/p>\n","protected":false},"author":42,"featured_media":35835,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[8,169,125,2067,2071,232],"tags":[2815,2817],"class_list":{"0":"post-35832","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-banking","8":"category-downloads","9":"category-featured","10":"category-ibps-rrb-clerk","11":"category-ibps-rrb-clerk-en","12":"category-sbiclerk","13":"tag-bank-clerk-2019","14":"tag-simplification-questions-for-bank-clerk"},"better_featured_image":{"id":35835,"alt_text":"Simplification Questions for Bank CLERK PDF","caption":"Simplification Questions for Bank 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