{"id":35713,"date":"2019-10-04T11:20:33","date_gmt":"2019-10-04T05:50:33","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=35713"},"modified":"2019-10-04T11:20:54","modified_gmt":"2019-10-04T05:50:54","slug":"time-and-work-questions-for-ssc-cpo-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/time-and-work-questions-for-ssc-cpo-pdf\/","title":{"rendered":"Time and Work Questions for SSC CPO PDF"},"content":{"rendered":"

Time and Work Questions for SSC CPO PDF<\/strong><\/span><\/h1>\n

Download Top-15\u00a0SSC CPO Time and Work Questions and Answers PDF, based on asked questions in previous CPO & other SSC exam papers.<\/p>\n

Download Time and Work Questions for SSC CPO PDF<\/a><\/p>\n

FREE SSC EXAM YOUTUBE VIDEOS<\/a><\/p>\n

Download SSC General Knowledge PDF <\/a><\/p>\n

Question 1:\u00a0<\/b>A can do a work in 15 days and B in 20 days. If they work on it together for 5 days, then what fraction of work is left?<\/p>\n

a)\u00a02\/9<\/p>\n

b)\u00a03\/10<\/p>\n

c)\u00a05\/12<\/p>\n

d)\u00a01\/4<\/p>\n

Question 2:\u00a0<\/b>Manoj can do a piece of work in 42 hours. If he is joined by Jayashree who is 100% more efficient, in what time they will finish the work together?<\/p>\n

a)\u00a07 hours<\/p>\n

b)\u00a03.5 hours<\/p>\n

c)\u00a014 hours<\/p>\n

d)\u00a02.5 hours<\/p>\n

Question 3:\u00a0<\/b>Prahlad has done 1\/3rd of a job in 30 days, Sarfaraz completes the rest of the job in 90 days. In how many days can they together do the job?<\/p>\n

a)\u00a027 days<\/p>\n

b)\u00a018 days<\/p>\n

c)\u00a054 days<\/p>\n

d)\u00a036 days<\/p>\n

SSC CPO Free Mock Test<\/a> (Latest Pattern)<\/p>\n

SSC CPO Previous Papers<\/a>\u00a0(Download PDF)<\/p>\n

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Question 4:\u00a0<\/b>Mahmood can do a piece of work in 40 hours. If he is joined by Janaki who is 50% more efficient, in what time will they together finish the work?<\/p>\n

a)\u00a02 hours<\/p>\n

b)\u00a06 hours<\/p>\n

c)\u00a016 hours<\/p>\n

d)\u00a03 hours<\/p>\n

Daily Free Online GK Tests<\/a><\/p>\n

Question 5:\u00a0<\/b>Painter ‘A’ can paint a house in 10 days and ‘B’ can do it in 20 days. With help of ‘C’, they did the job in 5 days only. Then, ‘C’ alone can do the job in:<\/p>\n

a)\u00a020 days<\/p>\n

b)\u00a010 days<\/p>\n

c)\u00a040 days<\/p>\n

d)\u00a050 days<\/p>\n

Question 6:\u00a0<\/b>Munni can bake 70 cakes in 7 hours, Munni and Guddi together can bake 90 cakes in 6 hours. How many cakes Guddi can bake in 10 hours?<\/p>\n

a)\u00a0100<\/p>\n

b)\u00a050<\/p>\n

c)\u00a0125<\/p>\n

d)\u00a025<\/p>\n

Question 7:\u00a0<\/b>Amal is 5 times as good a workman as Bhairav and therefore is able to finish a job in 48 days less than Bhairav. Working together, they can do it in<\/p>\n

a)\u00a020 days<\/p>\n

b)\u00a05 days<\/p>\n

c)\u00a025 days<\/p>\n

d)\u00a010 days<\/p>\n

Question 8:\u00a0<\/b>A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?<\/p>\n

a)\u00a075 days<\/p>\n

b)\u00a037.5 days<\/p>\n

c)\u00a017.5 days<\/p>\n

d)\u00a035 days<\/p>\n

Question 9:\u00a0<\/b>A can do a work in 15 days and B in 20 days. If they work on it together for 6 days, then what fraction of work is left?<\/p>\n

a)\u00a01\/4<\/p>\n

b)\u00a02\/9<\/p>\n

c)\u00a01\/5<\/p>\n

d)\u00a03\/10<\/p>\n

SSC CPO Previous Question Papers (download pdf)<\/a><\/p>\n

SSC CPO FREE MOCK TEST<\/a><\/p>\n

Question 10:\u00a0<\/b>Meghnad can do a piece of work in 45 hours. If he is joined by Jayshri, who is 50% more efficient, in what time will they together finish the work?<\/p>\n

a)\u00a09 hours<\/p>\n

b)\u00a06 hours<\/p>\n

c)\u00a012 hours<\/p>\n

d)\u00a018 hours<\/p>\n

Question 11:\u00a0<\/b>Mother can bake 20 cakes in 4 hours, Mother and Dadima together can bake 60 cakes in 10 hours. How many cakes Dadima can bake in 30 hours?<\/p>\n

a)\u00a030<\/p>\n

b)\u00a075<\/p>\n

c)\u00a060<\/p>\n

d)\u00a025<\/p>\n

Question 12:\u00a0<\/b>A mason can build a wall in 18 hours. After 9 hours he takes a break. What fraction of the wall is yet to be built?<\/p>\n

a)\u00a00.9<\/p>\n

b)\u00a00.25<\/p>\n

c)\u00a00.5<\/p>\n

d)\u00a00.2<\/p>\n

Question 13:\u00a0<\/b>Praful has done 1\/2 of a job in 30 days, Sarabjit completes the rest of the job in 10 days. In how many days can they together do the job?<\/p>\n

a)\u00a030 days<\/p>\n

b)\u00a045 days<\/p>\n

c)\u00a015 days<\/p>\n

d)\u00a060 days<\/p>\n

Question 14:\u00a0<\/b>Pradeep has done 1\/4th of a job in 14 days, Saquib completes the rest of the job in 56 days. In how many days can they together complete the job?<\/p>\n

a)\u00a064 days<\/p>\n

b)\u00a032 days<\/p>\n

c)\u00a016 days<\/p>\n

d)\u00a08 days<\/p>\n

Question 15:\u00a0<\/b>Jaikishen can do a piece of work in 15 hours. If he is joined by Jhanvi who is 50% more efficient, in what time will they together finish the work?<\/p>\n

a)\u00a06 hours<\/p>\n

b)\u00a012 hours<\/p>\n

c)\u00a03 hours<\/p>\n

d)\u00a09 hours<\/p>\n

Question 16:\u00a0<\/b>Which planet has the maximum number of satellites?<\/p>\n

a)\u00a0Jupiter<\/p>\n

b)\u00a0Earth<\/p>\n

c)\u00a0Neptune<\/p>\n

d)\u00a0Saturn<\/p>\n

Free SSC Study Material (18,000 Solved Questions)<\/a><\/p>\n

Download SSC CPO Previous Papers (Download PDF)<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let total work to be done = 60 units<\/p>\n

A’s efficiency = $\\frac{60}{15} = 4$ units\/day<\/p>\n

B’s efficiency = $\\frac{60}{20} = 3$ units\/day<\/p>\n

(A + B)’s 1 day’s work together = 4 + 3 = 7 units\/day<\/p>\n

Now, work done by them together in 5 days = $5 \\times 7 = 35$ units<\/p>\n

=> Work left = 60 – 35 = 25 units<\/p>\n

$\\therefore$ Fraction of work that is left = $\\frac{25}{60} = \\frac{5}{12}$<\/p>\n

=> Ans – (C)<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let total work to be done = 42 units<\/p>\n

Manoj’s efficiency = $\\frac{42}{42} = 1$ unit\/hr<\/p>\n

Jayashree is 100% more efficient, => Jayashree’s efficiency = $1 + \\frac{100}{100} \\times 1 = 2$ units\/hr<\/p>\n

(Manoj + Jayashree)’s 1 day’s work together = 1 + 2 = 3 units\/hr<\/p>\n

$\\therefore$ Time taken by Manoj and Jayashree together to finish the work = $\\frac{42}{3} = 14$ hours<\/p>\n

=> Ans – (C)<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let total work to be done = 90 units<\/p>\n

Work done by Prahlad in 30 days = $\\frac{1}{3} \\times 90 = 30$ units<\/p>\n

Prahlad’s efficiency = $\\frac{30}{30} = 1$ unit\/day<\/p>\n

Remaining work = 90 – 30 = 60 units<\/p>\n

Sarfaraz completes 60 units in 90 days<\/p>\n

=> Sarfaraz’s efficiency = $\\frac{60}{90} = \\frac{2}{3}$ units\/day<\/p>\n

(Prahlad + Sarfaraz)’s 1 day’s work = $1 + \\frac{2}{3} = \\frac{5}{3}$ units\/day<\/p>\n

$\\therefore$ Time taken by them together to do the job = $\\frac{90}{\\frac{5}{3}}$<\/p>\n

= $90 \\times \\frac{3}{5} = 54$ days<\/p>\n

=> Ans – (C)<\/p>\n

4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let total work to be done = 80 units<\/p>\n

Mahmood’s efficiency = $\\frac{80}{40} = 2$ units\/hr<\/p>\n

Janaki is 50% more efficient than Mahmood, => Janaki’s efficiency = $\\frac{150}{100} \\times 2 = 3$ units\/hr<\/p>\n

=> Mahmood and Janaki 1 day’s work = 2 + 3 = 5 units\/hr<\/p>\n

$\\therefore$ Time taken by them to finish the work together = $\\frac{80}{5} = 16$ hours<\/p>\n

=> Ans – (C)<\/p>\n

5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let total work to be done = 100 units<\/p>\n

Painter ‘A’ can paint a house in 10 days and ‘B’ can do it in 20 days<\/p>\n

=> A’s efficiency = $\\frac{100}{10} = 10$ units\/day<\/p>\n

B’s efficiency = $\\frac{100}{20} = 5$ units\/day<\/p>\n

Let C’s efficiency = $x$ units\/day<\/p>\n

According to ques,\u00a0all of them complete the job in 5 days<\/p>\n

=> $(10+5+x) \\times 5 = 100$<\/p>\n

=> $x+15=\\frac{100}{5}=20$<\/p>\n

=> $x=20-15=5$<\/p>\n

$\\therefore$ Time taken by C alone to do the job = $\\frac{100}{5}=20$ days<\/p>\n

=> Ans – (A)<\/p>\n

6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Cakes baked by Munni in 1 hour = $\\frac{70}{7} = 10$<\/p>\n

Cakes baked by Munni and Guddi together in 1 hour = $\\frac{90}{6} = 15$<\/p>\n

=> Cakes baked by Guddi in 1 hour = 15 – 10 = 5<\/p>\n

$\\therefore$ Cakes baked by Guddi in 10 hours = 10 $\\times$ 5 = 50<\/p>\n

=> Ans – (B)<\/p>\n

7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Ratio of times taken by Amal and Bhairav = 1 : 5<\/p>\n

The time difference is (5 – 1) = 4 days while Bhairav takes 5 days and Amal takes 1 day.<\/p>\n

If difference of time is 4 days, Bhairav takes 5 days.<\/p>\n

If difference of time is 48 days, Bhairav takes = $\\frac{5}{4} \\times 48 = 60$ days<\/p>\n

=> Amal takes 12 days<\/p>\n

Amal’s 1 day’s work = $\\frac{1}{12}$<\/p>\n

Bhairav’s 1 day’s work = $\\frac{1}{60}$<\/p>\n

=> (Amal + Bhairav)’s 1 day’s work = $\\frac{1}{12} + \\frac{1}{60} = \\frac{6}{60} = \\frac{1}{10}$<\/p>\n

$\\therefore$ Amal and Bhairav together can do the work in 10 days.<\/p>\n

8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Work done by A in 20 days = $\\frac{80}{100} = \\frac{4}{5}$<\/p>\n

Work done by A in 1 day = $\\frac{\\frac{4}{5}}{20} = \\frac{4}{100} = \\frac{1}{25}$<\/p>\n

Work done by A and B in 3 days = $\\frac{20}{100} = \\frac{1}{5}$ (Because remaining 20% is done in 3 days by A and B)<\/p>\n

Work done by A and B in 1 day = $\\frac{1}{15}$<\/p>\n

Work done by B in 1 day = $\\frac{1}{15} – \\frac{1}{25} = \\frac{2}{75}$<\/p>\n

=> B can complete the work in $\\frac{75}{2}$ days = 37.5 days<\/p>\n

9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let total work to be done = 60 units<\/p>\n

A’s efficiency = $\\frac{60}{15} = 4$ units\/day<\/p>\n

B’s efficiency = $\\frac{60}{20} = 3$ units\/day<\/p>\n

=> (A + B)’s 1 day’s work = 4 + 3 = 7 units\/day<\/p>\n

Work done by A and B together in 6 days = $6 \\times 7 = 42$ units<\/p>\n

=> Work left = 60 – 42 = 18 units<\/p>\n

$\\therefore$ Fraction of work that is left = $\\frac{18}{60} = \\frac{3}{10}$<\/p>\n

10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let total work to be done = 90 units<\/p>\n

Meghnad’s efficiency = $\\frac{90}{45} = 2$ units\/hr<\/p>\n

Jayshri is 50% more efficient than Meghnad, => Jayshri’s efficiency = $\\frac{150}{100} \\times 2 = 3$ units\/hr<\/p>\n

=> Meghnad and Jayshri 1 day’s work = 2 + 3 = 5 units\/hr<\/p>\n

$\\therefore$ Time taken by them to finish the work together = $\\frac{90}{5} = 18$ hours<\/p>\n

11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Cakes baked by Mother in 1 hour = $\\frac{20}{4} = 5$<\/p>\n

Cakes baked by Mother and Dadima together in 1 hour = $\\frac{60}{10} = 6$<\/p>\n

=> Cakes baked by Dadima in 1 hour = 6 – 5 = 1<\/p>\n

$\\therefore$ Cakes baked by Dadima in 30 hours = 30 $\\times$ 1 = 30<\/p>\n

12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let total work to be done = 18 units<\/p>\n

Mason’s efficiency = $\\frac{18}{18} = 1$ unit\/hr<\/p>\n

Work done by the mason in 9 hours = $9 \\times 1 = 9$ units<\/p>\n

=> Work left = 18 – 9 = 9 units<\/p>\n

$\\therefore$ Fraction of work that is left = $\\frac{9}{18} = \\frac{1}{2}$<\/p>\n

= 0.5<\/p>\n

13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let total work to be done = 60 units<\/p>\n

Praful has done 1\/2 of a job i.e. $\\frac{60}{2} = 30$ units in 30 days<\/p>\n

=> Praful’s efficiency = $\\frac{30}{30} = 1$ unit\/day<\/p>\n

Work left = 60 – 30 = 30 units which is done by Sarabjit in 10 days<\/p>\n

=> Sarabjit’s efficiency = $\\frac{30}{10} = 3$ units\/day<\/p>\n

Praful and Sarabjit 1 day’s work = 1 + 3 = 4 units\/day<\/p>\n

$\\therefore$ Time taken by them together to complete the work = $\\frac{60}{4} = 15$ days<\/p>\n

14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let total work to be done = 56 units<\/p>\n

Pradeep has done 1\/4 of a job i.e. $\\frac{56}{4} = 14$ units in 14 days<\/p>\n

=> Pradeep’s efficiency = $\\frac{14}{14} = 1$ unit\/day<\/p>\n

Work left = 56 – 14 = 42 units which is done by Saquib in 56 days<\/p>\n

=> Saqub’s efficiency = $\\frac{42}{56} = 0.75$ units\/day<\/p>\n

Pradeep and Saquib 1 day’s work = 1 + 0.75 = 1.75 units\/day<\/p>\n

$\\therefore$ Time taken by them together to complete the work = $\\frac{56}{1.75} = 32$ days<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let total work to be done = 30 units<\/p>\n

Jaikishen’s efficiency = $\\frac{30}{15} = 2$ units\/hr<\/p>\n

Jhanvi is 50% more efficient, => Jhanvi’s efficiency = $\\frac{150}{100} \\times 2 = 3$ units\/hr<\/p>\n

Jaikishen and Jhanvi 1 hour’s work = 2 + 3 = 5 units\/hr<\/p>\n

=> Time taken by them to finish the work together = $\\frac{30}{5} = 6$ hours<\/p>\n

16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

shortlink to=”https:\/\/cracku.in\/ssc-cpo-mock-test” color=”red” css_class=””]Take a SSC CPO Free Mock Test[\/shortlink]<\/p>\n

HIGHLY RATED PREPARATION APP<\/a><\/p>\n

We hope this Time and Work Questions PDF for SSC CPO Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Time and Work Questions for SSC CPO PDF Download Top-15\u00a0SSC CPO Time and Work Questions and Answers PDF, based on asked questions in previous CPO & other SSC exam papers. Question 1:\u00a0A can do a work in 15 days and B in 20 days. If they work on it together for 5 days, then what […]<\/p>\n","protected":false},"author":49,"featured_media":35717,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,9,1493],"tags":[500],"class_list":{"0":"post-35713","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-ssc","10":"category-ssc-cpo","11":"tag-ssc-cpo"},"better_featured_image":{"id":35717,"alt_text":"Time and Work Questions for SSC CPO PDF","caption":"Time and Work Questions for SSC CPO PDF","description":"Time and Work Questions for SSC CPO 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