{"id":35601,"date":"2019-10-03T11:33:17","date_gmt":"2019-10-03T06:03:17","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=35601"},"modified":"2019-10-03T11:33:17","modified_gmt":"2019-10-03T06:03:17","slug":"geometry-questions-for-ssc-cpo-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/geometry-questions-for-ssc-cpo-pdf\/","title":{"rendered":"Geometry Questions for SSC CPO PDF"},"content":{"rendered":"

Geometry Questions for SSC CPO PDF<\/strong><\/span><\/h1>\n

Download Top-15\u00a0SSC CPO Geometry Questions and Answers PDF, based on asked questions in previous CPO & other SSC exam papers.<\/p>\n

Download Geometry Questions for SSC CPO PDF<\/a><\/p>\n

FREE SSC EXAM YOUTUBE VIDEOS<\/a><\/p>\n

Download SSC General Knowledge PDF <\/a><\/p>\n

Question 1:\u00a0<\/b>What is the total number of circles passing through the two \ufb01xed points?<\/p>\n

a)\u00a01<\/p>\n

b)\u00a02<\/p>\n

c)\u00a04<\/p>\n

d)\u00a0In\ufb01nite<\/p>\n

Question 2:\u00a0<\/b>Find the volume $(in cm^3)$ of a cube of side 4.5 cm.<\/p>\n

a)\u00a055.467<\/p>\n

b)\u00a014.445<\/p>\n

c)\u00a091.125<\/p>\n

d)\u00a026.465<\/p>\n

Question 3:\u00a0<\/b>If the sum of the interior angles of a regular polygon is $720^\\circ$ then how many sides does it have?<\/p>\n

a)\u00a08<\/p>\n

b)\u00a09<\/p>\n

c)\u00a06<\/p>\n

d)\u00a010<\/p>\n

SSC CPO Free Mock Test<\/a> (Latest Pattern)<\/p>\n

SSC CPO Previous Papers<\/a>\u00a0(Download PDF)<\/p>\n

Free 18000 Solved Questions: SSC Study Material<\/a><\/p>\n

Question 4:\u00a0<\/b>The length of one side and the diagonal of a rectangle are 20 cm and 29 cm respectively. Find the length of its other side (in cm).<\/p>\n

a)\u00a042<\/p>\n

b)\u00a030<\/p>\n

c)\u00a021<\/p>\n

d)\u00a060<\/p>\n

Question 5:\u00a0<\/b>AB is the chord of circle of length 6 cm. From the center of the circle a perpendicular is drawn which intersects the chord at M and distance between centre and chord is 4 cm. \ufb01nd the area $(in cm^2)$ of the circle)<\/p>\n

a)\u00a055<\/p>\n

b)\u00a061.5<\/p>\n

c)\u00a070<\/p>\n

d)\u00a078.5<\/p>\n

Daily Free Online GK Tests<\/a><\/p>\n

Question 6:\u00a0<\/b>The two chords AB and CD of a circle intersect at point P, such that BP=4 cm, PD=5 cm, and CP=8 cm. \ufb01nd the length of chord AB.<\/p>\n

a)\u00a08<\/p>\n

b)\u00a010<\/p>\n

c)\u00a012<\/p>\n

d)\u00a014<\/p>\n

Question 7:\u00a0<\/b>Find the total surface area $(in cm^2)$ of a right circular cylinder of diameter 28 cm and height 12 cm.<\/p>\n

a)\u00a02200<\/p>\n

b)\u00a02080<\/p>\n

c)\u00a01920<\/p>\n

d)\u00a02288<\/p>\n

Question 8:\u00a0<\/b>The circumference of a circle is 110 cm. Find its radius (in cm).<\/p>\n

a)\u00a035<\/p>\n

b)\u00a019.5<\/p>\n

c)\u00a017.5<\/p>\n

d)\u00a039<\/p>\n

Question 9:\u00a0<\/b>The area of a square is $30.25 cm^2$. Find its perimeter (in cm).<\/p>\n

a)\u00a044<\/p>\n

b)\u00a023<\/p>\n

c)\u00a022<\/p>\n

d)\u00a046<\/p>\n

SSC CPO Previous Question Papers (download pdf)<\/a><\/p>\n

SSC CPO FREE MOCK TEST<\/a><\/p>\n

Question 10:\u00a0<\/b>The base and height of a right angled triangle is 12 cm and 5 cm respectively. Find the circum-radius (in cm) of the triangle.<\/p>\n

a)\u00a05<\/p>\n

b)\u00a06<\/p>\n

c)\u00a06.5<\/p>\n

d)\u00a07<\/p>\n

Question 11:\u00a0<\/b>For the circle shown below, find the length (in cm) of the largest cord of the circle.<\/p>\n

<\/figure>\n

a)\u00a08<\/p>\n

b)\u00a012<\/p>\n

c)\u00a016<\/p>\n

d)\u00a018<\/p>\n

Question 12:\u00a0<\/b>The volume of a cube is $274.625 cm^3$. Find its side (in cm).<\/p>\n

a)\u00a07.5<\/p>\n

b)\u00a06.5<\/p>\n

c)\u00a05.5<\/p>\n

d)\u00a03.5<\/p>\n

Question 13:\u00a0<\/b>If the perimeter of a semicircle is 72 cm, then \ufb01nd its area $(in\u00a0 cm^2)$.<\/p>\n

a)\u00a0308<\/p>\n

b)\u00a0616<\/p>\n

c)\u00a0160<\/p>\n

d)\u00a0320<\/p>\n

Question 14:\u00a0<\/b>The area of a square is $42.25 cm^2$. Find its perimeter (in cm).<\/p>\n

a)\u00a052<\/p>\n

b)\u00a026<\/p>\n

c)\u00a028<\/p>\n

d)\u00a056<\/p>\n

Question 15:\u00a0<\/b>The area of a right angled triangle ABC, right angled at B, is 46 sq units. A median is drawn from A to BC which intersects at D. Find the area (in sq. units) of triangle ABD.<\/p>\n

a)\u00a012<\/p>\n

b)\u00a023<\/p>\n

c)\u00a046<\/p>\n

d)\u00a088<\/p>\n

Free SSC Study Material (18,000 Solved Questions)<\/a><\/p>\n

Download SSC CPO Previous Papers (Download PDF)<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let there be 2 fixed points, as we can see from the figure that there can be infinite circles that passes through these 2 fixed points.<\/p>\n

<\/figure>\n

=> Ans – (D)<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Side of cube =\u00a0$a=4.5$ cm<\/p>\n

=> Volume of cube = $a^3$<\/p>\n

= $(4.5)^3=91.125$ $cm^3$<\/p>\n

=> Ans – (C)<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Sum of all interior angles of a polygon with $’n’$ sides = $(n-2)\\times180^\\circ$<\/p>\n

Let the number of sides be $n$<\/p>\n

=> Sum of interior angles =\u00a0$(n-2)\\times180^\\circ=720^\\circ$<\/p>\n

=\u00a0$(n-2)=\\frac{720^\\circ}{180^\\circ}=4$<\/p>\n

=> $n=4+2=6$<\/p>\n

=> Ans – (C)<\/p>\n

4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the length of rectangle = $l$ cm and breadth, $b=20$ cm<\/p>\n

=> Diagonal, $d^2=l^2+b^2$<\/p>\n

=> $l^2=(29)^2-(20)^2$<\/p>\n

=> $l^2=841-400=441$<\/p>\n

=> $l=\\sqrt{441}=21$<\/p>\n

$\\therefore$ Length of its other side\u00a0=\u00a021 cm<\/strong><\/p>\n

=> Ans – (C)<\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

<\/figure>\n

Given\u00a0: AB = 6 cm and OM = 4 cm<\/p>\n

To find\u00a0: Area of circle = ?<\/p>\n

Solution\u00a0: Let $r$ be the radius of circle<\/p>\n

Also, MB = $\\frac{6}{2}=3$ cm<\/p>\n

In right $\\triangle$ MOB,<\/p>\n

=> $(OB)^2=(OM)^2+(MB)^2$<\/p>\n

=> $(OB)^2=(4)^2+(3)^2$<\/p>\n

=> $r^2=16+9=25$<\/p>\n

=> $r=\\sqrt{25}=5$ cm<\/p>\n

$\\therefore$ Area of circle = $\\pi r^2$<\/p>\n

= $3.14 \\times(5)^2=78.5$ $cm^2$<\/p>\n

=> Ans – (D)<\/p>\n

6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

<\/figure>\n

Given\u00a0: AB and CD are chords of the circle which intersect at point P. BP = 4 cm, CP = 8 cm and PD = 5 cm<\/p>\n

To find\u00a0: AB = ?<\/p>\n

Solution\u00a0: Let AP = $x$ cm<\/p>\n

Now, when two chords intersect\u00a0each other inside a circle, the products of their segments are equal.<\/p>\n

=> $(AP)\\times(BP)=(CP)\\times(DP)$<\/p>\n

=> $x\\times4=8\\times5$<\/p>\n

=> $x=\\frac{40}{4}=10$<\/p>\n

$\\therefore$ AB = AP + PB = $10+4=14$ cm<\/p>\n

=> Ans – (D)<\/p>\n

7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Height of cylinder, $h=12$ cm and radius, $r=\\frac{28}{2}=14$ cm<\/p>\n

Total surface area of cylinder = $2\\pi r(r+h)$<\/p>\n

= $2\\times\\frac{22}{7}\\times14\\times(14+12)$<\/p>\n

= $88\\times26=2288$ $cm^2$<\/p>\n

=> Ans – (D)<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let radius of circle = $r$ cm<\/p>\n

=> Circumference = $2\\pi r=110$<\/p>\n

=> $2\\times\\frac{22}{7}\\times r=110$<\/p>\n

=> $r=110\\times\\frac{7}{44}$<\/p>\n

=> $r=2.5\\times7=17.5$ cm<\/p>\n

=> Ans – (C)<\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let side of square = $s$ cm<\/p>\n

=> Area = $s^2=30.25$<\/p>\n

=> $s=\\sqrt{30.25}=5.5$ cm<\/p>\n

$\\therefore$ Perimeter = $4\\times5.5=22$ cm<\/p>\n

=> Ans – (C)<\/p>\n

10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Length of base and height of triangle = 12 and 5 cm<\/p>\n

=> Let length of hypotenuse = $x$ cm<\/p>\n

=> $(x)^2=(12)^2+(5)^2$<\/p>\n

=> $(x)^2=144+25=169$<\/p>\n

=> $x=\\sqrt{169}=13$ cm<\/p>\n

Also, the circumcentre of a right angled triangle lies on its hypotenuse, thus circumradius = $\\frac{1}{2}\\times$ (hypotenuse)<\/p>\n

= $\\frac{1}{2}\\times13=6.5$ cm<\/p>\n

=> Ans – (C)<\/p>\n

11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

<\/p>\n

Given\u00a0: AT is tangent on the circle. AT = 6 cm and AB = 10 cm<\/p>\n

To find\u00a0: Largest chord = Diameter =\u00a0?<\/p>\n

Solution : In right $\\triangle$ ABT<\/p>\n

=> $(BT)^2=(AB)^2-(AT)^2$<\/p>\n

=> $(BT)^2=(10)^2-(6)^2$<\/p>\n

=> $(BT)^2=100-36=64$<\/p>\n

=> $BT=\\sqrt{64}=8$ cm<\/p>\n

$\\therefore$ Diameter = $2\\times8=16$ cm<\/p>\n

=> Ans – (C)<\/p>\n

12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let side of cube = $a$ cm<\/p>\n

Volume of cube = $a^3=274.625$<\/p>\n

=> $a=\\sqrt[3]{6.5\\times42.25}$<\/p>\n

=> $a=6.5$ cm<\/p>\n

=> Ans – (B)<\/p>\n

13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let radius of semi circle = $r$ cm<\/p>\n

=> Perimeter of semi circle = $\\pi r+2r=72$<\/p>\n

=> $r(\\frac{22}{7}+2)=72$<\/p>\n

=> $r(\\frac{22+14}{7})=72$<\/p>\n

=> $r=72\\times\\frac{7}{36}=14$ cm<\/p>\n

$\\therefore$ Area of semi-circle = $\\frac{1}{2} \\pi r^2$<\/p>\n

= $\\frac{1}{2}\\times\\frac{22}{7}\\times(14)^2$<\/p>\n

= $22\\times14=308$ $cm^2$<\/p>\n

=> Ans – (A)<\/p>\n

14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let side of square = $s$ cm<\/p>\n

=> Area = $s^2=42.25$<\/p>\n

=> $s=\\sqrt{42.25}=6.5$ cm<\/p>\n

$\\therefore$ Perimeter of square = $4s=4\\times6.5=26$ cm<\/p>\n

=> Ans – (B)<\/p>\n

15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Note\u00a0:- A median divides a triangle into two parts of equal areas.<\/p>\n

Proof\u00a0:<\/p>\n

<\/figure>\n

It is given that $ar(\\triangle ABC)=46$ sq.units<\/p>\n

Also, AD bisects BC, let\u00a0BC = $2x$ units => BD = $\\frac{2x}{2}=x$ units<\/p>\n

$\\therefore$\u00a0$\\frac{ar(\\triangle ABD)}{ar(\\triangle ABC)}=\\frac{\\frac{1}{2}\\times(AB)\\times(BD)}{\\frac{1}{2}\\times(AB)\\times(BC)}$<\/p>\n

=> $\\frac{\\triangle}{46}=\\frac{x}{2x}$<\/p>\n

=> $\\triangle=\\frac{46}{2}=23$ sq.units<\/p>\n

=> Ans – (B)<\/p>\n

Take a SSC CPO Free Mock Test<\/a><\/p>\n

HIGHLY RATED PREPARATION APP<\/a><\/p>\n

We hope this Geometry Questions PDF for SSC CPO Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Geometry Questions for SSC CPO PDF Download Top-15\u00a0SSC CPO Geometry Questions and Answers PDF, based on asked questions in previous CPO & other SSC exam papers. Question 1:\u00a0What is the total number of circles passing through the two \ufb01xed points? a)\u00a01 b)\u00a02 c)\u00a04 d)\u00a0In\ufb01nite Question 2:\u00a0Find the volume $(in cm^3)$ of a cube of side […]<\/p>\n","protected":false},"author":41,"featured_media":35603,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,9,1493,1441],"tags":[165,1727,2787,2000],"class_list":{"0":"post-35601","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-ssc","10":"category-ssc-cpo","11":"category-stenographer","12":"tag-ssc","13":"tag-ssc-cpo-2019","14":"tag-ssc-cpo-maths","15":"tag-ssc-mocks"},"better_featured_image":{"id":35603,"alt_text":"Geometry Questions for SSC CPO PDF","caption":"Geometry Questions for SSC CPO 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