{"id":35502,"date":"2019-09-28T18:47:42","date_gmt":"2019-09-28T13:17:42","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=35502"},"modified":"2019-09-28T18:47:42","modified_gmt":"2019-09-28T13:17:42","slug":"number-system-questions-for-iift-set-2-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/number-system-questions-for-iift-set-2-pdf\/","title":{"rendered":"Number System Questions For IIFT Set-2 PDF"},"content":{"rendered":"

Number System Questions For IIFT Set-2 PDF<\/strong><\/span><\/h1>\n

Download important IIFT Number System Questions PDF based on previously asked questions in IIFT and other MBA exams. Practice Number System questions and answers for IIFT exam.<\/p>\n

Download Number System Questions for IIFT Set-2 PDF<\/a><\/p>\n

Get 50% Off on IIFT & Other MBA Test Series\u00a0<\/a><\/p>\n

Download IIFT Previous Papers PDF<\/a><\/p>\n

Question 1:\u00a0<\/b>Arrange the following letters to form a meaningful word.<\/p>\n

<\/figure>\n

a)\u00a01 3 5 2 4 6 8 7<\/p>\n

b)\u00a08 6 7 1 4 2 3 5<\/p>\n

c)\u00a04 2 3 5 8 6 7 1<\/p>\n

d)\u00a05 3 7 1 8 4 2 6<\/p>\n

Question 2:\u00a0<\/b>A rod is cut into 3 equal parts. The resulting portions are then cut into 12, 18 and 32 equal parts, respectively. If each of the resulting portions have integer length, the minimum length of the rod is<\/p>\n

a)\u00a06912 units<\/p>\n

b)\u00a0864 units<\/p>\n

c)\u00a0288 units<\/p>\n

d)\u00a0240 units<\/p>\n

Question 3:\u00a0<\/b>If $a, b, c,$ and $d$ are integers such that $a+b+c+d=30$ then the minimum possible value of $(a – b)^{2} + (a – c)^{2} + (a – d)^{2}$\u00a0 is<\/p>\n

Question 4:\u00a0<\/b>A number is interesting if on adding the sum of the digits of the number and the product of the digits of the number, the result is equal to the number. What fraction of numbers between 10 and 100 (both 10 and 100 included) is interesting?<\/p>\n

a)\u00a00.1<\/p>\n

b)\u00a00.11<\/p>\n

c)\u00a00.16<\/p>\n

d)\u00a00.22<\/p>\n

e)\u00a0None of the above<\/p>\n

Question 5:\u00a0<\/b>Please read the following sentences carefully:
\nI \u2014 103 and 7 are the only prime factors of 1000027
\nII \u2014 $\\sqrt[6]{6!}>\\sqrt[7]{7!}$
\nIII \u2014 If I travel one half of my journey at an average speed of x km\/h, it will be impossible for me to attain an average speed of 2x km\/h for the entire journey.<\/p>\n

a)\u00a0All the statements are correct<\/p>\n

b)\u00a0Only Statement Il is correct<\/p>\n

c)\u00a0Only Statement Ill is correct<\/p>\n

d)\u00a0Both statements I and Il are correct<\/p>\n

e)\u00a0Both statements I and Ill are correct<\/p>\n

Practice IIFT Mock Tests<\/a><\/p>\n

IIFT Free Mock Test<\/a><\/p>\n

Question 6:\u00a0<\/b>An antique store has a collection of eight clocks. At a particular moment, the displayed times on seven of the eight clocks were as follows: 1:55 pm, 2:03 pm, 2:11 pm, 2:24 pm, 2:45 pm, 3:19 pm and 4:14 pm. If the displayed times of all eight clocks form a mathematical series, then what was the displayed time on the remaining clock?<\/p>\n

a)\u00a01:53 pm<\/p>\n

b)\u00a01:58 pm<\/p>\n

c)\u00a02:18 pm<\/p>\n

d)\u00a03:08 pm<\/p>\n

e)\u00a05:08 pm<\/p>\n

Question 7:\u00a0<\/b>If a, b and c are 3 consecutive integers between -10 to +10 (both inclusive), how many integer values are possible for the expression?
\n$\\frac{a^3+b^3+c^3+3abc}{(a+b+c)^2}$=?<\/p>\n

a)\u00a00<\/p>\n

b)\u00a01<\/p>\n

c)\u00a02<\/p>\n

d)\u00a03<\/p>\n

e)\u00a04<\/p>\n

Question 8:\u00a0<\/b>If x and y are real numbers, then the minimum value of $x^{2}+ 4xy+ 6y^{2}-4y+ 4$ is<\/p>\n

a)\u00a0\u20124<\/p>\n

b)\u00a00<\/p>\n

c)\u00a02<\/p>\n

d)\u00a04<\/p>\n

e)\u00a0None of the above<\/p>\n

Question 9:\u00a0<\/b>If $n^2 = 123456787654321$, what is $n$?<\/p>\n

a)\u00a012344321<\/p>\n

b)\u00a01235789<\/p>\n

c)\u00a011111111<\/p>\n

d)\u00a01111111<\/p>\n

Question 10:\u00a0<\/b>A is the set of positive integers such that when divided by 2, 3, 4, 5, 6 leaves the remainders 1, 2, 3, 4, 5 respectively. How many integers between 0 and 100 belong to set A?<\/p>\n

a)\u00a00<\/p>\n

b)\u00a01<\/p>\n

c)\u00a02<\/p>\n

d)\u00a0None of these<\/p>\n

Enroll for CAT\/MBA Courses<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

OVERHEAD is the word that can be formed from the given letters.
\nHence, option C is the correct answer.<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The rod is cut into 3 equal parts thus the length of the rod will be a multiple of 3.
\nEach part is then cut into $12 = 2^2*3$
\n$18 = 2*3^2$ and $32 = 2^5$ parts and thus, each part of rod has to be a multiple of $2^5*3^2 = 288$
\nThus, the rod will be a multiple of $288*3 = 864$
\nThus, the minimum length of the rod is 864 units.
\nHence, option B is the correct answer.<\/p>\n

3)\u00a0Answer:\u00a02<\/b><\/p>\n

For the value of given expression to be minimum, the values of $a, b, c$ and $d$ should be as close as possible. 30\/4 = 7.5. Since each one of these are integers so values must be 8, 8, 7, 7. On putting these values in the given expression, we get
\n$(8 – 8)^{2} + (8 – 7)^{2} + (8 – 7)^{2}$
\n=> 1 + 1 = 2<\/p>\n

4)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

As the number is between 10 and 100 and 100 cannot be the number we are looking for, we can assume the number to be of two-digits.
\nLet the number be xy.
\nAccording to the question, for the number to be interesting
\nx + y + xy = 10x + y
\nOn solving, we get
\nxy = 9x
\nor, x (9 – y) = 0
\nx cannot be 0, because we need a number greater than or equal to 10.
\nSo, 9 – y = 0
\n=> y = 9
\nFor all the numbers whose unit digit is 9 will be an interesting number.
\nSo, the numbers are 19, 29, 39, 49, …..99
\nThere are 9 such numbers out of 91 total numbers between 10 and 100 including both.
\nRequired fraction = $\\dfrac{9}{91}$ = 0.0989
\nAs this is not given in any of the options, the answer will be “none of the above”.
\nHence, option E is the correct answer.<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let us evaluate the statements one by one:
\nI:\u00a0103 and 7 are the only prime factors of 1000027
\nOn successively dividing 1000027 by 103 and 7, we get 1387 as the answer.
\n1387 is divisible by 19.
\nTherefore, statement I is false.
\nII:\u00a0$\\sqrt[6]{6!}>\\sqrt[7]{7!}$
\nRaising the power to 42 on both sides, we get,
\n$[6!]^7>[7!]^6$
\n$6!*[6!]^6 > 7^6*[6!]^6$
\n$7^6$ is greater than $6!$.
\nTherefore, statement II is false.
\nIII:It has been given that the person travels one-half of the journey at x kmph.
\nLet us assume the distance to be ‘2d’.
\nLet us assume the average speed to be 2d and check for the feasibility.
\nLet the speed at which the person travels the other half of the journey be y.
\nd\/x + d\/y = 2d\/2x
\nd\/x + d\/y = d\/x
\n=> d\/y = 0 or y tends to infinity.
\nTherefore, such a scenario is not possible and hence, statement III is true.
\nOnly statement III is true. Therefore, option C is the right answer.<\/p>\n

Practice IIFT Mock Tests<\/a><\/p>\n

IIFT Free Mock Test<\/a><\/p>\n

6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let us find out the difference between the times given to figure out the pattern.
\nThe times given are\u00a01:55 pm, 2:03 pm, 2:11 pm, 2:24 pm, 2:45 pm, 3:19 pm and 4:14 pm.
\nThe difference between 2 consecutive times given are\u00a0 8 minutes, 8 minutes, 13 minutes, 21 minutes, 34 minutes, and 55 minutes.
\nWe can observe that the difference between the times are in the Fibonacci series.
\n8 +\u00a013 = 21
\n21 +\u00a013 = 34
\n34 +\u00a021 = 55<\/p>\n

The Fibonacci series is as follows:
\n1,1,2,3,5,8,13,21,34,55.
\nBut the first difference in the times given is 8.
\nTherefore, the missing time must be such that it divides the interval of 8 minutes into 3 minutes and 5 minutes.
\nThe missing time should be 1:58 pm and hence, option B is the right answer.<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Since a,b,c are consecutive integers<\/p>\n

=> $a = b-1$ and $c = b+1$<\/p>\n

Expression\u00a0:\u00a0$\\frac{a^3+b^3+c^3+3abc}{(a+b+c)^2}$<\/p>\n

= $\\frac{(b – 1)^3 + b^3 + (b + 1)^3 + 3 (b – 1) b (b + 1)}{(b – 1 + b + b + 1)^2}$<\/p>\n

= $\\frac{b^3 + 3b + b^3 + b^3 + 3b + 3b^3 – 3b}{9 b^2}$<\/p>\n

= $\\frac{6 b^3 + 3 b}{9 b^2} = \\frac{2 b^2 + 1}{3 b}$<\/p>\n

Putting different values of b from – 10 to 10, we can verify that only – 1 and 1 satisfies to get integer values for the expression.<\/p>\n

Ans – (C)<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Expression\u00a0:\u00a0$x^{2}+ 4xy+ 6y^{2}-4y+ 4$<\/p>\n

= $(x^2 + 4xy + 4y^2) + (2y^2 – 4y + 4)$<\/p>\n

= $(x + 2y)^2 + \\frac{1}{2} (4y^2 – 8y + 8)$<\/p>\n

= $(x + 2y)^2 + \\frac{1}{2} [(2y)^2 – 2 (2y) (2) + (2)^2 + 4]$<\/p>\n

= $(x + 2y)^2 + \\frac{1}{2} [(2y – 2)^2 + 4]$<\/p>\n

= $(x + 2y)^2 + \\frac{1}{2} (2y – 2)^2 + 2$<\/p>\n

Since, $x$ and $y$ are real, => Min value of $(x + 2y)^2 = 0$<\/p>\n

Minimum value of $(2y – 2)^2 = 0$<\/p>\n

$\\therefore$ Minimum value of expression = $0 + 0 + 2 = 2$<\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Observe the pattern given below.
\n$11^2 = 121$
\n$111^2 = 12321$
\n$1111^2 = 1234321$ and so on.<\/p>\n

So, $11111111^2 = 123456787654321$<\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the number ‘n’ belong to the set A.
\nHence, the remainder when n is divided by 2 is 1
\nThe remainder when n is divided by 3 is 2
\nThe remainder when n is divided by 4\u00a0is 3
\nThe remainder when n is divided by 5\u00a0is 4 and
\nThe remainder when n is divided by 6\u00a0is 5<\/p>\n

So, when (n+1) is divisible by 2,3,4,5 and 6.
\nHence, (n+1) is of the form 60k for some natural number k.
\nAnd n is of the form 60k-1<\/p>\n

Between numbers 0 and 100, only 59 is of the form above and hence the correct answer is 1<\/p>\n

IIFT Previous year question\u00a0 answer PDF<\/a><\/p>\n

IIFT Free Mock Test<\/a><\/p>\n

We hope this Number System questions and answers for IIFT PDF will be helpful to you.<\/p>\n","protected":false},"excerpt":{"rendered":"

Number System Questions For IIFT Set-2 PDF Download important IIFT Number System Questions PDF based on previously asked questions in IIFT and other MBA exams. Practice Number System questions and answers for IIFT exam. Download IIFT Previous Papers PDF Question 1:\u00a0Arrange the following letters to form a meaningful word. a)\u00a01 3 5 2 4 6 […]<\/p>\n","protected":false},"author":42,"featured_media":35506,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3,169,125,350,362,366],"tags":[1195,2446],"class_list":{"0":"post-35502","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-cat","8":"category-downloads","9":"category-featured","10":"category-iift","11":"category-snap","12":"category-xat","13":"tag-iift-2019","14":"tag-number-system-questions-for-iift"},"better_featured_image":{"id":35506,"alt_text":"Number System Questions for IIFT Set-2 PDF","caption":"Number System Questions for IIFT Set-2 PDF\n","description":"Number System Questions for IIFT Set-2 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