{"id":35323,"date":"2019-09-25T18:13:44","date_gmt":"2019-09-25T12:43:44","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=35323"},"modified":"2019-10-31T16:25:18","modified_gmt":"2019-10-31T10:55:18","slug":"quadratic-equation-questions-for-ibps-clerk-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/quadratic-equation-questions-for-ibps-clerk-pdf\/","title":{"rendered":"Quadratic Equation Questions For IBPS Clerk PDF"},"content":{"rendered":"

Quadratic Equation Questions For IBPS Clerk PDF<\/span><\/h1>\n

Download important Quadratic Equation Questions PDF based on previously asked questions in IBPS Clerk and other MBA Exams. Practice Quadratic Equation Question and Answers for IBPS Clerk Exam.<\/p>\n

Download Quadratic Equation Questions For IBPS Clerk PDF<\/a><\/p>\n

4 Free IBPS Clerk Online Mock Tests (with solutions)<\/a><\/p>\n

Download IBPS Clerk Previous papers PDF<\/a><\/p>\n

Go to Free Banking Study Material<\/a> (15,000 Solved Questions)<\/p>\n

Instructions<\/b><\/p>\n

In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a & b
\nMark answer if
\na) a<b
\n<\/b<\/p>\n

<b
\n<\/b
\n<b
\nb) $a\\leq b$
\nc) relationship between a & b cannot be established
\nd) a>b
\ne) $a\\geq b$<\/p>\n

Question 1:\u00a0<\/b>I.$2a^{2}+a-1=0$
\nII.$12b^{2}-17b+6=0$<\/p>\n

a)\u00a0$a<b$<\/b><\/p>\n

b)\u00a0$a\\leq b$<\/p>\n

c)\u00a0Relationship between $a$ & $b$ cannot be established<\/p>\n

d)\u00a0$a>b$<\/p>\n

e)\u00a0$a\\geq b$<\/p>\n

Question 2:\u00a0<\/b>I.$a^{2}-5a+6=0$
\nII. $2b^{2}-13b+21=0$<\/p>\n

a)\u00a0$a<b$<\/b><\/p>\n

b)\u00a0$a\\leq b$<\/p>\n

c)\u00a0Relationship between $a$ & $b$ cannot be established<\/p>\n

d)\u00a0$a>b$<\/p>\n

e)\u00a0$a\\geq b$<\/p>\n

Question 3:\u00a0<\/b>I.$a^{2}+5a+6=0$
\nII.$b^{2}+7b+12=0$<\/p>\n

a)\u00a0$a<b$<\/b><\/p>\n

b)\u00a0$a \\leq b$<\/p>\n

c)\u00a0Relationship between $a$ & $b$ cannot be established<\/p>\n

d)\u00a0$a>b$<\/p>\n

e)\u00a0$a \\geq b$<\/p>\n

105 IBPS Clerk for just Rs. 199<\/a><\/p>\n

IBPS Clerk Online Moct Test<\/a><\/p>\n

Question 4:\u00a0<\/b>I.$16a^{2}=1$
\nII.$3b^{2}+7b+2=0$<\/p>\n

a)\u00a0$a<b$<\/b><\/p>\n

b)\u00a0$a\\leq b$<\/p>\n

c)\u00a0Relationship between $a$ & $b$ cannot be established<\/p>\n

d)\u00a0$a>b$<\/p>\n

e)\u00a0$a\\geq b$<\/p>\n

Question 5:\u00a0<\/b>I.$a^{2}+2a+1=0$
\nII.$b^{2}=\\pm4$<\/p>\n

a)\u00a0$a<b$<\/b><\/p>\n

b)\u00a0$a \\leq b$<\/p>\n

c)\u00a0Relationship between $a$ & $b$ cannot be established<\/p>\n

d)\u00a0$a>b$<\/p>\n

e)\u00a0$a \\geq b$<\/p>\n

Instructions<\/b><\/p>\n

In each of the following question two equations are given you have to solve them and
\nGive answer (a)if p<q
\n<\/q
\nGive answer (b)if p>q
\nGive answer (c)if $p\\leq$q
\nGive answer(d)if $p\\geq$q
\nGive answer (e)if p=q<\/p>\n

Question 6:\u00a0<\/b>I.$p^{2}-7p=-12$
\nII.$q^{2}-3q+2=0$<\/p>\n

a)\u00a0if p<q<\/q><\/p>\n

b)\u00a0if p>q<\/p>\n

c)\u00a0if $p\\leq$q<\/p>\n

d)\u00a0if $p\\geq$q<\/p>\n

e)\u00a0if p=q<\/p>\n

IBPS Clerk Previous Papers<\/a><\/p>\n

Question 7:\u00a0<\/b>I. $12p^{2}-7p=-1$
\nII. $6q^{2}-7q+2=0$<\/p>\n

a)\u00a0if $p < q$<\/q><\/p>\n

b)\u00a0if $p > q$<\/p>\n

c)\u00a0if $p\\leq q$<\/p>\n

d)\u00a0if $p\\geq q$<\/p>\n

e)\u00a0if $p = q$<\/p>\n

Question 8:\u00a0<\/b>I.$p^{2}+12p+35=0$
\nII.$2q^{2}+22q+56=0$<\/p>\n

a)\u00a0if p < q<\/q><\/p>\n

b)\u00a0if p>q<\/p>\n

c)\u00a0if $p \\leq q$<\/p>\n

d)\u00a0if $p\\geq q$<\/p>\n

e)\u00a0if p=q or no relationship can be established<\/p>\n

Question 9:\u00a0<\/b>I.$p^{2}-8p+15=0$
\nII.$q^{2}-5q=-6$<\/p>\n

a)\u00a0if p < q<\/q><\/p>\n

b)\u00a0if p>q<\/p>\n

c)\u00a0if $p\\leq q$<\/p>\n

d)\u00a0if $p\\geq q$<\/p>\n

e)\u00a0if p=q<\/p>\n

IBPS Clerk Important Questions PDF<\/a><\/p>\n

Question 10:\u00a0<\/b>I.$2p^{2}+20p+50=0$
\nII.$q^{2}=25$<\/p>\n

a)\u00a0if p<q <\/q><\/p>\n

b)\u00a0if p>q<\/p>\n

c)\u00a0if $p \\leq q$<\/p>\n

d)\u00a0if $p\\geq q $<\/p>\n

e)\u00a0if p = q<\/p>\n

Instructions<\/b><\/p>\n

For the two given equations I and II—-<\/p>\n

Question 11:\u00a0<\/b>I. $6p^{2}+5p+1=0$
\nII. $20q^{2}+9q=-1$<\/p>\n

a)\u00a0Give answer (A) if p is greater than q.<\/p>\n

b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n

c)\u00a0Give answer (C) if p is equal to q.<\/p>\n

d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n

e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n

Question 12:\u00a0<\/b>I. $3p^{2}+2p-1=0$ II. $2q^{2}+7q+6=0$<\/p>\n

a)\u00a0Give answer (A) if p is greater than q.<\/p>\n

b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n

c)\u00a0Give answer (C) if p is equal to q.<\/p>\n

d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n

e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n

Question 13:\u00a0<\/b>I. $3p^2+15p=-18$ II. $q^2+7q+12=0$<\/p>\n

a)\u00a0Give answer (A) if p is greater than q.<\/p>\n

b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n

c)\u00a0Give answer (C) if p is equal to q.<\/p>\n

d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n

e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n

Question 14:\u00a0<\/b>I. $p=\\frac{\\sqrt{4}}{\\sqrt{9}}$ II. $9q^{2}-12q+4=0$<\/p>\n

a)\u00a0Give answer (A) if p is greater than q.<\/p>\n

b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n

c)\u00a0Give answer (C) if p is equal to q.<\/p>\n

d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n

e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n

Question 15:\u00a0<\/b>I. $p^{2}+13p+42=0$ II. $q^{2}=36$<\/p>\n

a)\u00a0Give answer (A) if p is greater than q.<\/p>\n

b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n

c)\u00a0Give answer (C) if p is equal to q.<\/p>\n

d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n

e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n

Free Banking Study Material (15,000 Solved Questions)<\/a><\/p>\n

Instructions<\/b><\/p>\n

In these questions, two equations numbered I and II are given. You have to solve both the equations and select the appropriate option.<\/p>\n

Question 16:\u00a0<\/b>I. $2x^{2}+19x+45=0$
\nII. $2y^{2}+11y+12=0$<\/p>\n

a)\u00a0x = y<\/p>\n

b)\u00a0x> y<\/p>\n

c)\u00a0x < y<\/p>\n

d)\u00a0relationship between xand y cannot be determined<\/p>\n

e)\u00a0x + y<\/p>\n

Question 17:\u00a0<\/b>I. $3x^{2}-13x+12=0$
\nII. $2y^{2}-15y+28=0$<\/p>\n

a)\u00a0x> y<\/p>\n

b)\u00a0x= y<\/p>\n

c)\u00a0x < y<\/p>\n

d)\u00a0relationship between x and y cannot be determined<\/p>\n

e)\u00a0x\u2264 y<\/p>\n

Question 18:\u00a0<\/b>I. $x^{2}=16$
\nII. $2y^{2}-17y+36=0$<\/p>\n

a)\u00a0x > y<\/p>\n

b)\u00a0x > y<\/p>\n

c)\u00a0x < y<\/p>\n

d)\u00a0relationship between x and y cannot be determined<\/p>\n

e)\u00a0$x \\leq y$<\/p>\n

Daily Free Banking Online Tests<\/a><\/p>\n

Question 19:\u00a0<\/b>I. $6x^{2}+19x+15=0$
\nII. $3y^{2}+11y+10=0$<\/p>\n

a)\u00a0x = y<\/p>\n

b)\u00a0x > y<\/p>\n

c)\u00a0x < y<\/p>\n

d)\u00a0$x \\geq y$<\/p>\n

e)\u00a0$x \\leq y$<\/p>\n

Question 20:\u00a0<\/b>I. $2x^{2}-11x+15=0$
\nII. $2y^{2}-11y+14=0$<\/p>\n

a)\u00a0x > y<\/p>\n

b)\u00a0x> y<\/p>\n

c)\u00a0x < y<\/p>\n

d)\u00a0relationship between x and y cannot be determined<\/p>\n

e)\u00a0x \u2264 y<\/p>\n

IBPS Clerk Free Online Coaching<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$2a^{2}+a-1=0$
\nWe get the factor as:
\na=-1, a=0.5<\/p>\n

$12b^{2}-17b+6=0$
\nSolving, we get the factor as,
\nb= 1.5, b= .75<\/p>\n

Hence, b>a
\nOption A is correct option.<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Soving the quadratic equations we get,
\n$a^{2}-5a+6=0$
\ni.e (a-2)(a-3)=0
\ni.e a=2, a=3<\/p>\n

$2b^{2}-13b+21=0$
\ni.e (b-3.5)(b-3)=0
\ni.e b= 3.5 and b=3<\/p>\n

Hence, we can deduce that $a\\leq b$
\nTherefore, option B is correct.<\/p>\n

3)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

$a^{2}+5a+6=0$
\ni.e (a+2)(a+3)=0
\ni.e a=-2, a=-3<\/p>\n

.$b^{2}+7b+12=0$
\ni.e (b+4)(b+3)=0
\ni.e b=-4, b=-3<\/p>\n

Hence, we can deduce that $a \\geq b$.
\nTherefore, option E is correct.<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$16a^{2}=1$
\nSolving we get, a=-.25, a=+.25<\/p>\n

$3b^{2}+7b+2=0$
\nSolving we get, b= -2. b = -1\/3<\/p>\n

Hence, a>b. Option D is correct.<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

We can easily solve equation I to get a = -1
\nBut we cannot solve $b^{2}=\\pm4$. Square root of negative number is not a real number.
\nHence, we cannot find a value of b. Therefore, we cannot establish a relationship between a and b.<\/p>\n

6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$p^2-7p+12 = 0$
\n$(p-3)(p-4) = 0$
\n$p = 3, 4$<\/p>\n

$q^2-3q+2 = 0$
\n$(q-1)(q-2) = 0$
\n$q = 1, 2$<\/p>\n

$\\therefore p > q$<\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$12p^2-7p+1 = 0$
\n$(4p-1)(3p-1) = 0$
\n$p = \\frac{1}{3}, \\frac{1}{4}$<\/p>\n

$6q^2-7q+2 = 0$
\n$(2q-1)(3q-2) = 0$
\n$q = \\frac{1}{2}, \\frac{2}{3}$<\/p>\n

$\\therefore p < q$<\/p>\n

8)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

$p^2+12p+35 = 0$
\n$(p+5)(p+7) = 0$
\n$p = -5, -7$<\/p>\n

$2q^2+22q+56 = 0$
\n$q^2+11q+28 = 0$
\n$(q+4)(q+7) = 0$
\n$q = -4, -7$<\/p>\n

As we can see $p$ can be greater than, less than or equal to $q$. No relationship can be established between $p$ and $q$ and hence, option E is the right answer.<\/p>\n

9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$p^2-8p+15 = 0$
\n$(p-3)(p-5) = 0$
\n$p = 3, 5$<\/p>\n

$q^2-5q+6 = 0$
\n$(q-2)(q-3) = 0$
\n$q = 2, 3$<\/p>\n

$p\\geq q$<\/p>\n

10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$2p^2+20p+50 = 0$
\n$p^2+10p+25 = 0$
\n$(p+5)^2 = 0$
\n$p = -5$<\/p>\n

$q^2 = 25$
\n$q = 5, -5$<\/p>\n

$p\\leq q$<\/p>\n

11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$6p^2+5p+1 = 0$
\n$(2p+1)(3p+1) = 0$
\n$p = -\\frac{1}{2}, -\\frac{1}{3}$<\/p>\n

$20q^2+9q+1 = 0$
\n$(4q+1)(5q+1) = 0$
\n$q = -\\frac{1}{4}, -\\frac{1}{5}$<\/p>\n

$p < q$<\/p>\n

12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$3p^2+2p-1 = 0$
\n$(3p-1)(p+1) = 0$
\n$p = -1, \\frac{1}{3}$<\/p>\n

$2q^2+7q+6 = 0$
\n$(2q+3)(q+2) = 0$
\n$q = -2, -\\frac{3}{2}$<\/p>\n

p > q<\/p>\n

13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$3p^2+15p+18 = 0$
\n$p^2+5p+6 = 0$
\n$(p+2)(p+3) = 0$
\n$p = -3, -2$<\/p>\n

$q^2+7q+12 = 0$
\n$(q+4)(q+3) = 0$
\n$q = -4, -3$<\/p>\n

$p\\geq q$<\/p>\n

14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$p = \\frac{\\sqrt{4}}{\\sqrt{9}}$
\n$p = \\frac{2}{3}$<\/p>\n

$9q^2-12q+4 = 0$
\n${(3q-2)}^2 = 0$
\n$q = \\frac{2}{3}$<\/p>\n

p = q<\/p>\n

15)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

$p^2+13p+42 = 0$
\n$(p+6)(p+7) = 0$
\n$p = -6, -7$<\/p>\n

$q^2 = 36$
\n$q = -6, 6$<\/p>\n

$p\\leq q$<\/p>\n

16)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$2x^2+19x+45 = 0$
\n$(2x+9)(x+5) = 0$
\n$x = -5, -\\frac{9}{2}$<\/p>\n

$2y^2+11y+12 = 0$
\n$(2y+3)(y+4) = 0$
\n$y = -4, -\\frac{3}{2}$<\/p>\n

x < y<\/p>\n

17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$3x^2-13x+12 = 0$
\n$(3x-4)(x-3) = 0$
\n$x = \\frac{4}{3}, 3$<\/p>\n

$2y^2-15y+28 = 0$
\n$(2y-7)(y-4) = 0$
\n$y = \\frac{7}{2}, 4$<\/p>\n

x < y<\/p>\n

18)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

$x^2 = 16$
\n$x = 4, -4$<\/p>\n

$2y^2-17y+36 = 0$
\n$(2y-9)(y-4) = 0$
\n$y = \\frac{9}{2}, 4$<\/p>\n

$x \\leq y$<\/p>\n

19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$6x^2+19x+15 = 0$
\n$(3x+5)(2x+3) = 0$
\n$x = -\\frac{5}{3}, -\\frac{3}{2}$<\/p>\n

$3y^2+11y+10 = 0$
\n$(3y+5)(y+2) = 0$
\n$y = -\\frac{5}{3}, -2$<\/p>\n

$x\\geq y$<\/p>\n

20)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$2x^2-11x+15 = 0$
\n$(2x-5)(x-3) = 0$
\n$x = 3, \\frac{5}{2}$<\/p>\n

$2y^2-11y+14 = 0$
\n$(2y-7)(y-2) = 0$
\n$y = 2, \\frac{7}{2}$<\/p>\n

relationship between x and y cannot be established<\/p>\n

Download Free IBPS Clerk Preparation App<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Quadratic Equation Questions For IBPS Clerk PDF Download important Quadratic Equation Questions PDF based on previously asked questions in IBPS Clerk and other MBA Exams. Practice Quadratic Equation Question and Answers for IBPS Clerk Exam. Download IBPS Clerk Previous papers PDF Go to Free Banking Study Material (15,000 Solved Questions) Instructions In each of these […]<\/p>\n","protected":false},"author":32,"featured_media":35329,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[229],"tags":[50],"class_list":{"0":"post-35323","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-ibpsclerk","8":"tag-ibps-clerk"},"better_featured_image":{"id":35329,"alt_text":"quadratic equation questions for ibps clerk pdf","caption":"quadratic equation questions for ibps clerk pdf\n","description":"quadratic equation questions for ibps clerk 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