{"id":35205,"date":"2019-09-24T12:20:16","date_gmt":"2019-09-24T06:50:16","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=35205"},"modified":"2019-09-24T12:20:16","modified_gmt":"2019-09-24T06:50:16","slug":"algebra-questions-for-rrb-ntpc-set-3-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/algebra-questions-for-rrb-ntpc-set-3-pdf\/","title":{"rendered":"Algebra Questions for RRB NTPC Set-3 PDF"},"content":{"rendered":"

Algebra Questions for RRB NTPC Set-3 PDF<\/strong><\/span><\/h1>\n

Download RRB NTPC Algebra Questions Set-3 PDF. Top 10 RRB NTPC Maths questions based on asked questions in previous exam papers very important for the Railway NTPC exam.<\/p>\n

Download Algebra Questions for RRB NTPC Set-3 PDF<\/a><\/p>\n

Take a free mock test for RRB NTPC<\/a><\/p>\n

Download RRB NTPC Previous Papers PDF<\/a><\/p>\n\n

Question 1:\u00a0<\/b>$\\sqrt{8 + \\sqrt{57 + \\sqrt{38 + \\sqrt{108 + \\sqrt{169}}}}}$<\/p>\n

a)\u00a04<\/p>\n

b)\u00a06<\/p>\n

c)\u00a08<\/p>\n

d)\u00a010<\/p>\n

Question 2:\u00a0<\/b>If a * b = 2a + 3b – ab, then the value of (3 * 5 + 5 * 3) is<\/p>\n

a)\u00a010<\/p>\n

b)\u00a06<\/p>\n

c)\u00a04<\/p>\n

d)\u00a02<\/p>\n

Question 3:\u00a0<\/b>If a * b\u00a0= $a^{b}$, then the value of 5 * 3 is<\/p>\n

a)\u00a0125<\/p>\n

b)\u00a0243<\/p>\n

c)\u00a053<\/p>\n

d)\u00a015<\/p>\n

RRB NTPC Previous Papers [Download PDF]<\/a><\/p>\n

FREE RRB NTPC YOUTUBE VIDEOS<\/a><\/p>\n

Question 4:\u00a0<\/b>If $x = 1 + \\sqrt{2} + \\sqrt{3}$ , then the value of $(2x^4 – 8x^3 – 5x^2 + 26x- 28)$ is __?<\/p>\n

a)\u00a0$6\\sqrt{6}$<\/p>\n

b)\u00a0$0$<\/p>\n

c)\u00a0$3\\sqrt{6}$<\/p>\n

d)\u00a0$2\\sqrt{6}$<\/p>\n

Question 5:\u00a0<\/b>If $a^2+b^2+c^2=2(a-2b-c-3)$ then the value of a+b+c is<\/p>\n

a)\u00a03<\/p>\n

b)\u00a00<\/p>\n

c)\u00a02<\/p>\n

d)\u00a04<\/p>\n

 <\/p>\n

Question 6:\u00a0<\/b>Find the simplest value of $2\\sqrt{50} + \\sqrt{18} – \\sqrt{72}$ is __? $(\\sqrt{2} = 1.414)$.<\/p>\n

a)\u00a09.898<\/p>\n

b)\u00a010.312<\/p>\n

c)\u00a08.484<\/p>\n

d)\u00a04.242<\/p>\n

RRB NTPC Free Mock Test<\/a><\/p>\n\n

Question 7:\u00a0<\/b>If $a^{3}-b^{3}-c^{3}=0$ then the value of $a^{9}-b^{9}-c^{9}-3a^{3} b^{3} c^{3}$ is<\/p>\n

a)\u00a01<\/p>\n

b)\u00a02<\/p>\n

c)\u00a00<\/p>\n

d)\u00a0-1<\/p>\n

Question 8:\u00a0<\/b>If x + y + z = 6 and $x^{2}+y^{2}+z^{2}$=20 then the value of $x^{3}+y^{3}+z^{3}$-3xyz is<\/p>\n

a)\u00a064<\/p>\n

b)\u00a070<\/p>\n

c)\u00a072<\/p>\n

d)\u00a076<\/p>\n

Question 9:\u00a0<\/b>If a and b are the roots of the equation $x^2+4x-2=0$, find the equation, which will have the roots, $\\frac{a}{b}$ and $\\frac{b}{a}$.<\/p>\n

a)\u00a0$x^2 +5x +6 = 0$<\/p>\n

b)\u00a0$x^2 -10x +5 = 0$<\/p>\n

c)\u00a0$x^2 +10x +1 = 0$<\/p>\n

d)\u00a0$2x^2 +5x +1 = 0$<\/p>\n

Question 10:\u00a0<\/b>Find x in the equation $81^{0.75} * 6561^{0.25} = 3^x $<\/p>\n

a)\u00a06<\/p>\n

b)\u00a08<\/p>\n

c)\u00a02<\/p>\n

d)\u00a05<\/p>\n

Download General Science Notes PDF<\/a><\/p>\n\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Start from the root of 169 then second root will reduce to 11, thrid root will reduce to 7, fourth root will reduce to 8, and finally it reduce to value 4<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

For 3*5 put a=3 and b=5 in given equation
\nand for 5*3 put a=5 and b=3 in equation
\nnow add both values<\/p>\n

3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Put a=5 and b=3 in given equation
\nhence it will be $5^{3}$ = 125<\/p>\n

4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

x = 1+ $\\sqrt {2} + \\sqrt {3} $
\n$(x-1)^{2}$ = $(\\sqrt {2} + \\sqrt {3}) ^ {2} $
\n$x^{2} +1 – 2x = 5 + 2 \\sqrt {6}$
\n$x^{2} – 2x = 4 + 2 \\sqrt {6}$ ( eq. (1) )
\n$(x^{2} – 2x)^{2} = x^{4} + 4x^{2} – 4x^{3} = 40 + 16\\sqrt{6} $ eq (2)
\nNow in $2x^{4} – 8x^{3} – 5x^{2} + 26x – 28 $
\nor $2(x^{4} – 4x^{3}) – 5x^{2} + 26x – 28 $ ( putting values from eq (1) and eq (2) )
\nAfter solving we will get it reduced to $6\\sqrt{6}$<\/p>\n

5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Given\u00a0$a^2+b^2+ c^2=2(a-2b-c-3)$,<\/p>\n

So, $(a-1)^2+(b+2)^2+(c-1)^2=0$<\/p>\n

Hence, a=1, b=-2 and c=1<\/p>\n

So, the sum of the equation is<\/p>\n

6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Given equation can be reduced in the form of $10\\sqrt2 + 3\\sqrt2 – 6\\sqrt2 = 7\\sqrt2$
\nHence\u00a0\u00a0$7\\sqrt2$ will be around 9.898<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

shortcut :<\/p>\n

put c = 0 in\u00a0\u00a0$a^{3}-b^{3}-c^{3}=0$ $\\Rightarrow$\u00a0$a^{3}=b^{3}$<\/p>\n

$a^{9}-b^{9}-(0)^{9}-3a^{3} b^{3} (0)^{3}$ =\u00a0$a^{9}-b^{9}$ =\u00a0$(a^{3})^{3}-(b^{3})^{3}$ =\u00a0\u00a0$(a)^{3}-(a)^{3}$ = 0\u00a0 ( $\\because$ $a^{3}=b^{3}$ )<\/p>\n

so the answer is option C.<\/p>\n

normal method :<\/strong><\/p>\n

$a^{3}-b^{3}-c^{3}=0$<\/p>\n

$a^{3}=b^{3}+c^{3}$<\/p>\n

cubing on both sides,<\/p>\n

$(a^{3})^{3}=(b^{3}+c^{3})^{3}$<\/p>\n

$a^{9}=b^{9}+c^{9}+3b^{3} c^{3}(b^{3}+c^{3})$<\/p>\n

$a^{9}=b^{9}+c^{9}+3b^{3} c^{3}(a^{3})$<\/p>\n

$a^{9}-b^{9}-c^{9}-3a^{3}b^{3} c^{3}=0$<\/p>\n

so the answer is option C.<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

We know that $x^{3}+y^{3}+z^{3}-3xyz = (x + y + z)(x^2 +y^2 + z^2 -xy-yz-xz)$
\n$x^{3}+y^{3}+z^{3}-3xyz = (6)(20 -xy-yz-xz)$
\nHence the solution must be a multiple of 6.
\nOut of the given options only Option C is a multiple of 6.
\nHence Option C is the correct answer.<\/span><\/span><\/span>
\n<\/span><\/span><\/span><\/span><\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Sum of the roots of new equation = $\\frac{a}{b} + \\frac{b}{a}$ = $\\frac{a^2 + b^2}{ab}$ = $\\frac{(a+b)^2 – 2ab}{ab}$ = $\\frac{(-4)^2 – 2*(-2)}{(-2)}$ =-10
\nProduct of the roots = $\\frac{a}{b} * \\frac{b}{a}$ = 1
\nTherefore, the required equation is $x^2 +10x +1 = 0$.<\/p>\n

10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$81^{0.75} = 27$
\n$6561^{0.25} = 9$
\n==> $81^{0.75} * 6561^{0.25} = 3^5 $
\n==> x = 5.<\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

We hope this\u00a0Algebra Questions Set-3 pdf\u00a0 for RRB NTPC Exam will be highly useful for your Preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Algebra Questions for RRB NTPC Set-3 PDF Download RRB NTPC Algebra Questions Set-3 PDF. Top 10 RRB NTPC Maths questions based on asked questions in previous exam papers very important for the Railway NTPC exam. Take a free mock test for RRB NTPC Download RRB NTPC Previous Papers PDF Question 1:\u00a0$\\sqrt{8 + \\sqrt{57 + \\sqrt{38 […]<\/p>\n","protected":false},"author":41,"featured_media":35207,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1603],"tags":[491,1623,2659],"class_list":{"0":"post-35205","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-ntpc","11":"tag-rrb","12":"tag-rrb-ntpc-maths","13":"tag-rrb-ntpc-mocks"},"better_featured_image":{"id":35207,"alt_text":"Algebra Questions for RRB NTPC Set-3 PDF","caption":"Algebra Questions for RRB NTPC Set-3 PDF","description":"Algebra Questions for RRB NTPC Set-3 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