{"id":34447,"date":"2019-09-04T18:22:48","date_gmt":"2019-09-04T12:52:48","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=34447"},"modified":"2019-09-04T18:22:48","modified_gmt":"2019-09-04T12:52:48","slug":"time-distance-questions-for-rrb-group-d-set-2-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/time-distance-questions-for-rrb-group-d-set-2-pdf\/","title":{"rendered":"Time & Distance Questions for RRB Group-D Set-2 PDF"},"content":{"rendered":"

Time & Distance Questions for RRB Group-D Set-2 PDF<\/strong><\/span><\/h2>\n

Download Top-15 RRB Group-D Time & Distance Questions set-2 PDF.\u00a0RRB GROUP-D Maths questions based on asked questions in previous exam papers very important for the Railway Group-D exam.<\/p>\n

Download Time & Distance Questions for RRB Group-D Set-2 PDF<\/a><\/p>\n\n

Download RRB Group-D Previous Papers PDF<\/a><\/p>\n

Take a RRB Group-D free mock test<\/a><\/p>\n

Question 1:\u00a0<\/b>Walking at a speed of 10 km\/hr, Madhu reaches her university 15 minutes late. Next time she increases her speed by 2 km\/hr, but she is still late by 5 minutes. The distance of the university from her house is:<\/p>\n

a)\u00a015 km<\/p>\n

b)\u00a030 km<\/p>\n

c)\u00a020 km<\/p>\n

d)\u00a010 km<\/p>\n

Question 2:\u00a0<\/b>Driving @ 48 $\\frac{km}{hr}$ Barun reached the destination 2 minutes ahead of time. If he drove @ 42 $\\frac{km}{hr}$ he would have been 1 minute late. What is the distance that Barun drove?<\/p>\n

a)\u00a017.6 km<\/p>\n

b)\u00a017.2 km<\/p>\n

c)\u00a016.4 km<\/p>\n

d)\u00a016.8 km<\/p>\n

Question 3:\u00a0<\/b>Rahim started a journey 15 minutes late, and as a result, had to drive at a speed of 54 km\/h instead of 45 km\/h to reach his destination on time. What is the distance covered during the course of the journey?<\/p>\n

a)\u00a090 km<\/p>\n

b)\u00a067.5 km<\/p>\n

c)\u00a013.5 km<\/p>\n

d)\u00a075.5 km<\/p>\n

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Question 4:\u00a0<\/b>A car starting from rest, accelerates in a straight road at a constant rate of 3.0 $ms^{-2}$ for 8 s. Find the distance travelled by the car during this time.<\/p>\n

a)\u00a075 m<\/p>\n

b)\u00a086 m<\/p>\n

c)\u00a096 m<\/p>\n

d)\u00a0100 m<\/p>\n

Question 5:\u00a0<\/b>A car starts from city A and travels towards city B at a speed of 60 kmph. After one hour, a bike starts from city B and travels towards city A at a speed of 40 kmph. After the bike and the car cross each other, the time taken by the car to reach city B is 4 hours less than the time taken by the bike to reach city A. What is the distance between the 2 cities (in km)?<\/p>\n

Question 6:\u00a0<\/b>Raman and Rajeev leave their respective houses at the speed of 6 kmph and 4 kmph respectively to meet at a common point lying somewhere in the middle. Raman has a horse who is very excited about the meeting. He leaves Raman’s house, at the same time, and goes towards Rajeev, and after meeting him, comes back to Raman and then again goes to Rajeev. In this way, the horse continues his to and fro journey at the speed of 15 kmph till the three of them meet. If the total distance covered by the horse is $3k$ km, what is the distance between the houses of Raman and Rajeev (in km)?<\/p>\n

a)\u00a0$k$<\/p>\n

b)\u00a0$2k$<\/p>\n

c)\u00a0$3k$<\/p>\n

d)\u00a0$5k$<\/p>\n

Question 7:\u00a0<\/b>A and B are at a distance of 1.7 km apart and they start running towards each other at a speed of 8 m\/s and 9 m\/s respectively. Afier how much time, will they meet each other?<\/p>\n

a)\u00a01 minute 4 seconds<\/p>\n

b)\u00a014 seconds<\/p>\n

c)\u00a014 minutes<\/p>\n

d)\u00a01 minute 40 seconds<\/p>\n

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Question 8:\u00a0<\/b>A girl walks to school from her house at 5 km\/h speed for 24 minutes and cycles back the same distance at 8 km\/h. The time taken to cycle back is:<\/p>\n

a)\u00a015 minutes<\/p>\n

b)\u00a08 minutes<\/p>\n

c)\u00a010 minutes<\/p>\n

d)\u00a021 minutes<\/p>\n

Question 9:\u00a0<\/b>The distance between two cities is covered in $3\\frac{1}{4}$ hours at a speed of 52 km\/h. If the speed is increased to 65 km\/h. how much time would be saved ?<\/p>\n

a)\u00a039 minutes<\/p>\n

b)\u00a045 minutes<\/p>\n

c)\u00a040 minutes<\/p>\n

d)\u00a042 minutes<\/p>\n

Question 10:\u00a0<\/b>A train needs to travel 400 km. It travels half of the distance at 160 km\/hr and remaining half of the distance at 120 km\/hr. In how much time it can travel total distance?<\/p>\n

a)\u00a0180 min<\/p>\n

b)\u00a0175 min<\/p>\n

c)\u00a0160 min<\/p>\n

d)\u00a0150 min<\/p>\n

Question 11:\u00a0<\/b>Two players A and B runs from a same point with their speeds in the ratio 3:4$\\pi$. A runs to and fro\u00a0diagonally while B runs along the circumference. If the radius is 2m find the total distance traveled by A by the time they will meet again?<\/p>\n

a)\u00a024m<\/p>\n

b)\u00a012m<\/p>\n

c)\u00a048m<\/p>\n

d)\u00a036m<\/p>\n

RRB Group-D Important Questions (download PDF)<\/a><\/p>\n\n

Question 12:\u00a0<\/b>Raj takes $2\\dfrac{1}{3}$ hours to complete a certain distance at a speed of 51 km\/hr. What time would Kiran take to complete the same distance at a speed of 68km\/hr?<\/p>\n

a)\u00a0$1\\frac{2}{3}$ hours<\/p>\n

b)\u00a0$1\\frac{3}{4}$ hours<\/p>\n

c)\u00a0$2$ hours<\/p>\n

d)\u00a0$1\\frac{1}{2}$ hours<\/p>\n

Question 13:\u00a0<\/b>The distance between two places can be covered in 3\u00a0 $\\frac{1}{2}$ hours at a speed of 62 km\/hr.If the speed is increased by 8 km\/hr, how much time would be saved?<\/p>\n

a)\u00a020 minutes<\/p>\n

b)\u00a024 minutes<\/p>\n

c)\u00a015 minutes<\/p>\n

d)\u00a030 minutes<\/p>\n

Question 14:\u00a0<\/b>37 trees are planted in a straight line such that distance between any two consecutive trees is same. A car takes 20 seconds to reach the 13th tree. How much more time (in seconds) will it take to reach the last tree?<\/p>\n

a)\u00a036<\/p>\n

b)\u00a040<\/p>\n

c)\u00a057<\/p>\n

d)\u00a060<\/p>\n

Question 15:\u00a0<\/b>Two boats P and Q run between two cities A and B on a stream with flow of 5 km\/h. The cities are 300 km apart and P and Q have still water speeds of 25 km\/h and 15 km\/h respectively. P and Q start from cities A and B towards B and A respectively at the same time. When and where will they meet for the second time?<\/p>\n

a)\u00a0After 20 hours at 100 km from B<\/p>\n

b)\u00a0After 10 hours at 100 km from B<\/p>\n

c)\u00a0After 12 hours at 100 km from B<\/p>\n

d)\u00a0After 20 hours at 200 km from B<\/p>\n

General Science Notes for RRB Exams (PDF)<\/a><\/p>\n\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

5)\u00a0Answer:\u00a0360<\/b><\/p>\n

Let the distance between the 2 cities be ‘x’ km.
\nBy the time the bike starts, the car has already traveled for an hour (60 km).
\nDistance between the car and the bike when the bike starts = (x-60) km.<\/p>\n

Time taken by the car and bike to meet each other after the bike starts = (x-60)\/(40+60) = (x-60)\/100 hours.<\/p>\n

The car takes 4 hours less to reach city B than the time taken by the bike to reach city A.
\nLet ‘t’ be the time taken by the car to reach city B after crossing the bike.
\n=> t*60 = (x-60)\/100 * 40
\nt = (x-60)\/150\u00a0 ———(1)
\nTime taken by the bike after crossing the car to reach city A = t+4 hours.<\/p>\n

(t +4)*40 = (x-60)\/100*60 + 60
\nt+4 = 1.5(x+40)\/100
\nt+4 = (1.5x + 60)\/100
\nt = (1.5x-340)\/100 ————(2)<\/p>\n

Equating (1) and (2), we get,
\n(x-60)\/150 = (1.5x-340)\/100
\n2x – 120 = 4.5x – 1020
\n2.5x = 900
\nx = 360 km<\/p>\n

6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The horse will keep running at the speed of 15 kmph until Raman and Rajeev meet.<\/p>\n

Let us assume the distance between their houses is $x$ km.<\/p>\n

Since both are moving towards each other,<\/p>\n

their relative speed = (6 + 4) kmph = 10 kmph<\/p>\n

So, time required to meet = $\\dfrac{x}{10}$ hr<\/p>\n

Distance covered by the horse = $3k$ km<\/p>\n

Time taken by the horse = $\\dfrac{3k}{15}$ hr<\/p>\n

Both the times must be equal.<\/p>\n

So, $\\dfrac{x}{10}$ = $\\dfrac{3k}{15}$<\/p>\n

On solving, we get<\/p>\n

$x = 2k$<\/p>\n

Hence, option B is the correct answer.<\/p>\n

7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Given that the train travels first 200 km at 160 km\/hr
\nTime taken = $\\dfrac{200}{160} = \\dfrac{5}{4}$ hours
\nTrain travels remaining 200 km at 120 km\/hr
\nTime taken = $\\dfrac{200}{120} = \\dfrac{5}{3}$ hours
\nTotal time taken = $\\dfrac{5}{4} + \\dfrac{5}{3} = \\dfrac{15 + 20}{12} = \\dfrac{35}{12} \\times 60 = 175$ minutes<\/p>\n

11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Ratio of the speed of A and B =\u00a03:4$\\pi$. This implies that for every 3m traveled by A , B will travel 4$\\pi$m.<\/p>\n

Radius of the Circle =2m<\/p>\n

Circumference of the circle =4$\\pi$m.<\/p>\n

Hence for one complete round of B, A will travel 3m.<\/p>\n

A cannot meet B at a diametrically opposite point because for every meter A moves B covers a one-third of a circle.<\/p>\n

Thus they will meet at the same point.<\/p>\n

<\/figure>\n

For A to reach back at the starting point it will travel 8m.<\/p>\n

Thus for both the players to reach at the same point it has to be a multiple of 3 and 8 which is 24.<\/p>\n

Hence the answer is Option A.<\/p>\n

12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Speed of Raj = 51 km\/hr
\nTime taken by Raj to travel a certain distance = $2\\dfrac{1}{3} = \\dfrac{7}{3}$ hours
\nHence, Distance travelled by Raj = $\\dfrac{7}{3} \\times 51 = 119 km$
\nGiven, Speed of Kiran = 68 km\/hr
\nTime required for Kiran to travel 119 km at 68 km\/hr = $\\dfrac{119}{68} = \\dfrac{7}{4} = 1\\dfrac{3}{4}$ hours<\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let the\u00a0distance between any two consecutive trees\u00a0= $d$ metres<\/p>\n

=> Total distance between the 37 trees = $36d$ metres<\/p>\n

Time taken to reach the 13th tree = 20 seconds<\/p>\n

=> Speed of car = distance\/time<\/p>\n

= $\\frac{12d}{20}=\\frac{3d}{5}$ m\/s<\/p>\n

Thus, time taken to reach the last tree from the first tree = $\\frac{36d}{\\frac{3d}{5}}$<\/p>\n

= $36\\times\\frac{5}{3}=60$ seconds<\/p>\n

$\\therefore$ The car will take (60-20) = 40 seconds more\u00a0to reach the last tree<\/p>\n

=> Ans – (B)<\/p>\n

15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n\n

We hope this Time & Distance Questions set-2 PDF for RRB Group-D Exam will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Time & Distance Questions for RRB Group-D Set-2 PDF Download Top-15 RRB Group-D Time & Distance Questions set-2 PDF.\u00a0RRB GROUP-D Maths questions based on asked questions in previous exam papers very important for the Railway Group-D exam. Download RRB Group-D Previous Papers PDF Take a RRB Group-D free mock test Question 1:\u00a0Walking at a speed […]<\/p>\n","protected":false},"author":41,"featured_media":34449,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1679],"tags":[491,1637,1976,2052,1647],"class_list":{"0":"post-34447","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-group-d","11":"tag-rrb","12":"tag-rrb-exam","13":"tag-rrb-group-d-2019","14":"tag-rrb-maths","15":"tag-rrb-mocks"},"better_featured_image":{"id":34449,"alt_text":"Time & Distance Questions for RRB Group-D Set-2 PDF","caption":"Time & Distance Questions for RRB Group-D Set-2 PDF","description":"Time & Distance Questions for RRB Group-D Set-2 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DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n