Download important IIFT Clocks Questions PDF based on previously asked questions in IIFT and other MBA exams. Practice Clocks questions and answers for IIFT exam.<\/p>\n
Download Clocks Questions for IIFT PDF<\/a><\/p>\n Get 50% Off on IIFT & Other MBA Test Series\u00a0<\/a><\/p>\n Download IIFT Previous Papers PDF<\/a><\/p>\n Practice IIFT Mock Tests<\/a><\/p>\n Question 1:\u00a0<\/b>An antique store has a collection of eight clocks. At a particular moment, the displayed times on seven of the eight clocks were as follows: 1:55 pm, 2:03 pm, 2:11 pm, 2:24 pm, 2:45 pm, 3:19 pm and 4:14 pm. If the displayed times of all eight clocks form a mathematical series, then what was the displayed time on the remaining clock?<\/p>\n a)\u00a01:53 pm<\/p>\n b)\u00a01:58 pm<\/p>\n c)\u00a02:18 pm<\/p>\n d)\u00a03:08 pm<\/p>\n e)\u00a05:08 pm<\/p>\n Question 2:\u00a0<\/b>Alarms from 3 different clocks sound after every 2, 4 and 6 hours, respectively. If the clocks are started at the same time, how many times do the alarms ring together in 3 days?<\/p>\n a)\u00a06<\/p>\n b)\u00a03<\/p>\n c)\u00a09<\/p>\n d)\u00a02<\/p>\n Question 3:\u00a0<\/b>What would be the smaller of the two angles formed by the hour hand and the minute hand at 4 : 52 p.m.?<\/p>\n a)\u00a0$\u00a0162^\\circ $<\/p>\n b)\u00a0$\u00a0164.5^\\circ $<\/p>\n c)\u00a0$\u00a0165^\\circ $<\/p>\n d)\u00a0$\u00a0166^\\circ $<\/p>\n Question 4:\u00a0<\/b>What is the obtuse angle formed by the hands of a clock when the time in the clock is 2:30?<\/p>\n a)\u00a0$95^\\circ$<\/p>\n b)\u00a0$120^\\circ$<\/p>\n c)\u00a0$105^\\circ$<\/p>\n d)\u00a0$165^\\circ$<\/p>\n Question 5:\u00a0<\/b>In Ravi\u2019s clock shop, two clocks were brought for repairs. One clock has the cuckoo coming out every sixteen minutes, while the other one has the cuckoo coming out every eighteen minutes. Both cuckoos come out at 12.00 noon. When will they both come out together again?<\/p>\n a)\u00a02.06 PM<\/p>\n b)\u00a02.08 PM<\/p>\n c)\u00a02.24 PM<\/p>\n d)\u00a02.32 PM<\/p>\n IIFT Free Mock Test<\/a><\/p>\n Enroll for CAT\/MBA Courses<\/a><\/p>\n Question 6:\u00a0<\/b>The time in a clock is 20 minutes past 2. Find the angle between the hands of the clock.<\/p>\n a)\u00a045 degrees<\/p>\n b)\u00a050 degrees<\/p>\n c)\u00a060 degrees<\/p>\n d)\u00a0120 degrees<\/p>\n Question 7:\u00a0<\/b>A clock gains five minutes every hour. What will be the angle traversed by the second hand in one minute?<\/p>\n a)\u00a0360o<\/sup><\/p>\n b)\u00a0360.5o<\/sup><\/p>\n c)\u00a0390o<\/sup><\/p>\n d)\u00a0380o<\/sup><\/p>\n Question 8:\u00a0<\/b>After 9’O clock at what time between 9 p.m. and 10 p.m. will the hour and minute hands of a clock point in opposite direction?<\/p>\n a)\u00a015 minutes past 9<\/p>\n b)\u00a016 minutes past 9<\/p>\n c)\u00a0$(\\frac{180}{11})$ minutes past 9<\/p>\n d)\u00a0$(\\frac{190}{11})$ minutes past 9<\/p>\n Question 9:\u00a0<\/b>The angle between the minute hand and hour hand of a clock when the time is 7:20 is equal to<\/p>\n a)\u00a0$45^\\circ$<\/p>\n b)\u00a0$90^\\circ$<\/p>\n c)\u00a0$100^\\circ$<\/p>\n d)\u00a0$120^\\circ$<\/p>\n Question 10:\u00a0<\/b>If a clock is kept on the table in such a way that at 3:10 pm the hour hand points south, after how much time will the minute hand point east?<\/p>\n a)\u00a020 minutes<\/p>\n b)\u00a035 minutes<\/p>\n c)\u00a050 minutes<\/p>\n d)\u00a090 minutes<\/p>\n Top 500+ Free Questions for IIFT<\/a><\/p>\n IIFT Previous year question\u00a0 answer PDF<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let us find out the difference between the times given to figure out the pattern. The Fibonacci series is as follows: 2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n If we take the LCM of\u00a02, 4 and 6 hours then got 12 hours.<\/p>\n In\u00a012 hours alarms ring\u00a0simultaneously once.<\/p>\n It means\u00a012 hours = 1.<\/p>\n Hence 3 days = 72\u00a0hours = 6.<\/p>\n 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n 4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Angle between the hands of a clock is given by the formula $\\dfrac{11}{2}H – 30M$ or $30M – \\dfrac{11}{2}H$ where H is hours and M is minutes. 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Time after cuckoo comes in first clock = 16 min<\/p>\n Time after cuckoo comes in second clock = 18 min<\/p>\n => Time after cuckoo will come together in both = L.C.M. (16,18)<\/p>\n = 144 min = 2 : 24 min<\/p>\n => They will both come out together again = 12 + 2:24 = 2:24 PM<\/p>\n <\/p>\n 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Hour hand will cover 360 degrees in 12 hours. Thus, 1 hour = 30 degrees. 7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n This clock moves 65 minutes for every 60 minutes.<\/p>\n => Each hand moves = $\\frac{65}{60}$ as far as it should.<\/p>\n A correct second hand moves $360^\\circ$ in one minute.<\/p>\n => This second hand moves = $\\frac{65}{60}\\times360^\\circ=390^\\circ$ in one minute.<\/p>\n => Ans – (C)<\/p>\n 8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Hour hand’s speed is $\\frac{1}{2} ^o$ per min. 9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Angle between hour hand and minute hand = |30*H – $\\frac{11}{2}$*M|<\/p>\n where, H -> hour and M -> minutes<\/p>\n So, at 7:20 => H = 7 & M = 20<\/p>\n => Angle = 30*7 – $\\frac{11}{2}$*20<\/p>\n = 210-110 = 100\u00b0<\/p>\n 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n If at 3:10 the hour hand is pointing south then 3 points South, 6 points West, 9 points North and 12 points East.
\nThe times given are\u00a01:55 pm, 2:03 pm, 2:11 pm, 2:24 pm, 2:45 pm, 3:19 pm and 4:14 pm.
\nThe difference between 2 consecutive times given are\u00a0 8 minutes, 8 minutes, 13 minutes, 21 minutes, 34 minutes, and 55 minutes.
\nWe can observe that the difference between the times are in the Fibonacci series.
\n8 +\u00a013 = 21
\n21 +\u00a013 = 34
\n34 +\u00a021 = 55<\/p>\n
\n1,1,2,3,5,8,13,21,34,55.
\nBut the first difference in the times given is 8.
\nTherefore, the missing time must be such that it divides the interval of 8 minutes into 3 minutes and 5 minutes.
\nThe missing time should be 1:58 pm and hence, option B is the right answer.<\/p>\n
\nHere, Given time = 02 : 30, H = 2 and M = 30.
\nAngle = $\\dfrac{11}{2} \\times 30 – 30 \\times 2 = 165 – 60 – 105^\\circ$<\/p>\n
\nIn 2 hour 20 minutes i.e. in 2.33 hours it will cover 2.33*30 = 70 degrees.
\nMinute hand will cover 360 degrees in 1 hours. Thus, in 20 minutes it will cover 120 degrees.
\nThus, the angle between the hour hand and the minute hand at 2 hour twenty minutes = 120-70 = 50 degrees.
\nHence, option B is the correct answer.<\/p>\n
\nAnd minute hand’s speed is $6^o$\u00a0per minute
\nSo relative speed of minute hand will be $6^o$ –\u00a0$\\frac{1}{2} ^o$ = $\\frac{11}{2}$ per minute
\nHence time taken to make an angle of $180^o$ in between will be = $\\frac{90}{\\frac{11}{2}}$ (As at 9:00 o’clock angle between them is already $90^o$ )
\nSo time will be\u00a0$\\frac{180}{11}$ minutes passed 9<\/p>\n
\nThus, after 50 minutes the minute hand will point 12 and thus East.
\nHence, option C is the correct answer.<\/p>\n