{"id":34181,"date":"2019-08-28T17:17:45","date_gmt":"2019-08-28T11:47:45","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=34181"},"modified":"2019-08-28T17:17:45","modified_gmt":"2019-08-28T11:47:45","slug":"approximation-questions-for-ibps-po-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/approximation-questions-for-ibps-po-pdf\/","title":{"rendered":"Approximation Questions For IBPS PO PDF"},"content":{"rendered":"

Approximation Questions For IBPS PO PDF<\/span><\/h1>\n
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Download Approximation Questions For IBPS PO PDF. Practice Approximation\u00a0 Questions with Solutions for Banking exams based on asked questions in previous papers.<\/p>\n<\/div>\n<\/div>\n

Download Approximation Questions For IBPS PO PDF<\/a><\/p>\n

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Download IBPS PO Previous Papers PDF<\/a><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

Instructions<\/b><\/p>\n

What should come in place of the question mark (?) in the following questions ?<\/p>\n

Question 1:\u00a0<\/b>${2^{0.2}} \\times 64 \\times {8^{1.3}} \\times {4^{0.2}} = {8^?}$<\/p>\n

a)\u00a02.7<\/p>\n

b)\u00a02.5<\/p>\n

c)\u00a03.7<\/p>\n

d)\u00a03.2<\/p>\n

e)\u00a0None of these<\/p>\n

Question 2:\u00a0<\/b>83% of 6242 x 12% of 225 = ?<\/p>\n

a)\u00a0146286.42<\/p>\n

b)\u00a0134263.18<\/p>\n

c)\u00a0139883.22<\/p>\n

d)\u00a01562218.23<\/p>\n

e)\u00a0None of these<\/p>\n

Question 3:\u00a0<\/b>$1{1 \\over 8} + 1{6 \\over 7} + 3{3 \\over 5}$ = ?<\/p>\n

a)\u00a0$8{{121} \\over {140}}$<\/p>\n

b)\u00a0$6{{163} \\over {280}}$<\/p>\n

c)\u00a0$9{{197} \\over {280}}$<\/p>\n

d)\u00a0$7{{117} \\over {140}}$<\/p>\n

e)\u00a0None of these<\/p>\n

IBPS PO Quant Formulas & Shortcuts<\/a><\/p>\n

IBPS PO Previous papers<\/a><\/p>\n

Question 4:\u00a0<\/b>? \u00f7 25 \u00f7 12 = 248.76<\/p>\n

a)\u00a074628<\/p>\n

b)\u00a0497.52<\/p>\n

c)\u00a062452<\/p>\n

d)\u00a0870.66<\/p>\n

e)\u00a0None of these<\/p>\n

Question 5:\u00a0<\/b>${(73)^3}$ = ?<\/p>\n

a)\u00a0365127<\/p>\n

b)\u00a0298627<\/p>\n

c)\u00a0305867<\/p>\n

d)\u00a0389017<\/p>\n

e)\u00a0None of these<\/p>\n

Instructions<\/b><\/p>\n

What should come in place of the question mark (?) in the following questions?<\/p>\n

Question 6:\u00a0<\/b>$\\sqrt[3]{1331}$ =<\/p>\n

a)\u00a027<\/p>\n

b)\u00a021<\/p>\n

c)\u00a017<\/p>\n

d)\u00a09<\/p>\n

e)\u00a0None of these<\/p>\n

IBPS PO Free Mock Test<\/a><\/p>\n

Question 7:\u00a0<\/b>188.21 – 27.54 – 11.93 = ?<\/p>\n

a)\u00a0139.74<\/p>\n

b)\u00a0126.64<\/p>\n

c)\u00a0148.74<\/p>\n

d)\u00a0184.64<\/p>\n

e)\u00a0None of these<\/p>\n

Question 8:\u00a0<\/b>1268 \u00f7 8 \u00f7 2 = ?<\/p>\n

a)\u00a071.75<\/p>\n

b)\u00a0317<\/p>\n

c)\u00a0268<\/p>\n

d)\u00a079.25<\/p>\n

e)\u00a0None of these<\/p>\n

Question 9:\u00a0<\/b>${8^{1.1}} \\times {4^2}^{.7} \\times {2^{3.3}} = {2^?}$<\/p>\n

a)\u00a07.1<\/p>\n

b)\u00a014<\/p>\n

c)\u00a00.5<\/p>\n

d)\u00a09<\/p>\n

e)\u00a0None of these<\/p>\n

IBPS PO Previous Papers (Download Pdf)<\/a><\/p>\n

Instructions<\/b><\/p>\n

What approximate value will come in place of question mark (?) in the given questions? (You are not expected to calculate the exact value).<\/p>\n

Question 10:\u00a0<\/b>344 \u00f7 4.99 + 144.08 \u00f7 8.89 =?<\/p>\n

a)\u00a0119<\/p>\n

b)\u00a085<\/p>\n

c)\u00a043<\/p>\n

d)\u00a054<\/p>\n

e)\u00a0132<\/p>\n

Question 11:\u00a0<\/b>43.99 x 20.001 – 1439 \u00f7 6 = ?<\/p>\n

a)\u00a0500<\/p>\n

b)\u00a0640<\/p>\n

c)\u00a0540<\/p>\n

d)\u00a0600<\/p>\n

e)\u00a0680<\/p>\n

Question 12:\u00a0<\/b>459.85 + 519.82 = ?% of 1399.92<\/p>\n

a)\u00a090<\/p>\n

b)\u00a070<\/p>\n

c)\u00a075<\/p>\n

d)\u00a050<\/p>\n

e)\u00a080<\/p>\n

Question 13:\u00a0<\/b>40 % of 309 \u00f7 4 + ? = 6.9992<\/p>\n

a)\u00a024<\/p>\n

b)\u00a018<\/p>\n

c)\u00a042<\/p>\n

d)\u00a056<\/p>\n

e)\u00a034<\/p>\n

IBPS PO Important Questions PDF<\/a><\/p>\n

Free Banking Study Material (15,000 Solved Questions<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Expression : ${2^{0.2}} \\times 64 \\times {8^{1.3}} \\times {4^{0.2}} = {8^?}$<\/p>\n

=> $(2)^{0.2} \\times (2)^6 \\times (2)^{3 \\times 1.3} \\times (2)^{2 \\times 0.2} = (2)^{3 \\times x}$<\/p>\n

=> $(2)^{0.2 + 6 + 3.9 + 0.4} = (2)^{3 x}$<\/p>\n

=> $(2)^{10.5} = (2)^{3 x}$<\/p>\n

Comparing powers of 2, we get :<\/p>\n

=> $3x = 10.5$<\/p>\n

=> $x = \\frac{10.5}{3} = 3.5$<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Expression\u00a0:\u00a083% of 6242 x 12% of 225 = ?<\/p>\n

= $(\\frac{83}{100} \\times 6242) \\times (\\frac{12}{100} \\times 225)$<\/p>\n

= $5180.86 \\times 27$<\/p>\n

= $139883.22$<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression\u00a0:\u00a0$1{1 \\over 8} + 1{6 \\over 7} + 3{3 \\over 5}$ = ?<\/p>\n

= $(1 + 1 + 3) + (\\frac{1}{8} + \\frac{6}{7} + \\frac{3}{5})$<\/p>\n

= $5 + (\\frac{35 + 240 + 168}{280})$<\/p>\n

= $5 + \\frac{443}{280} = 5 + \\frac{280 + 163}{280}$<\/p>\n

= $5 + (1 + \\frac{163}{280}) = 6{{163} \\over {280}}$<\/p>\n

4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Expression\u00a0:\u00a0? \u00f7 25 \u00f7 12 = 248.76<\/p>\n

=> $\\frac{x}{25} \\times \\frac{1}{12} = 248.76$<\/p>\n

=> $x = 248.76 \\times 300$<\/p>\n

=> $x = 74628$<\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Expression\u00a0:\u00a0${(73)^3}$<\/p>\n

= $73 \\times 73 \\times 73$<\/p>\n

= $5329 \\times 73 = 389017$<\/p>\n

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Shortcut Method\u00a0: We can find the last two digits of $73^3$, which is ’17’<\/p>\n

Thus, ans – (D)<\/p>\n

6)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Expression : $\\sqrt[3]{1331}$<\/p>\n

= $\\sqrt[3]{11 \\times 11 \\times 11}$<\/p>\n

= $11$<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Expression\u00a0:\u00a0188.21 – 27.54 – 11.93 = ?<\/p>\n

= 188.21 – 39.47<\/p>\n

= 148.74<\/p>\n

8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Expression\u00a0:\u00a01268 \u00f7 8 \u00f7 2 = ?<\/p>\n

= $\\frac{1268}{8} \\div 2$<\/p>\n

= $\\frac{158.5}{2} = 79.25$<\/p>\n

9)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Expression : ${8^{1.1}} \\times {4^2}^{.7} \\times {2^{3.3}} = {2^?}$<\/p>\n

=> $(2)^{3 \\times 1.1} \\times (2)^{2 \\times 0.7} \\times (2)^{3.3} = (2)^x$<\/p>\n

=> $(2)^{3.3} \\times (2)^{1.4} \\times (2)^{3.3} = (2)^x$<\/p>\n

=> $(2)^{3.3 + 1.4 + 3.3} = (2)^x$<\/p>\n

Comparing both sides, we get :<\/p>\n

=> $x = 3.3 + 1.4 + 3.3 = 8$<\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression\u00a0:\u00a0344 \u00f7 4.99 + 144.08 \u00f7 8.89 =?<\/p>\n

= $(\\frac{345}{5}) + (\\frac{144}{9})$<\/p>\n

= $69 + 16 = 85$<\/p>\n

11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression\u00a0:\u00a043.99 x 20.001 – 1439 \u00f7 6 = ?<\/p>\n

= $(44 \\times 20) – (\\frac{1440}{6})$<\/p>\n

= $880 – 240 = 640$<\/p>\n

12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression\u00a0:\u00a0459.85 + 519.82 = ?% of 1399.92<\/p>\n

=> $460 + 520 = \\frac{x}{100} \\times 1400$<\/p>\n

=> $980 = 14x$<\/p>\n

=> $x = \\frac{980}{14} = 70$<\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

40 % of 249 \u00f7 4 + ? = 6.9992<\/p>\n

0.40*249\/4 –\u00a06.9992 = ?<\/p>\n

? = 18<\/p>\n

\u00a0<\/b><\/strong>

IBPS PO Previous Papers (Download PDF)<\/a><\/p><\/p>\n

Download IBPS PO Free Preparation App<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Approximation Questions For IBPS PO PDF Download Approximation Questions For IBPS PO PDF. Practice Approximation\u00a0 Questions with Solutions for Banking exams based on asked questions in previous papers. Take a free mock test for IBPS PO Download IBPS PO Previous Papers PDF Instructions What should come in place of the question mark (?) in the […]<\/p>\n","protected":false},"author":32,"featured_media":34189,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[228],"tags":[48],"class_list":{"0":"post-34181","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-ibpspo","8":"tag-ibps-po"},"better_featured_image":{"id":34189,"alt_text":"approximation questions for ibps po pdf","caption":"approximation questions for ibps po pdf\n","description":"approximation questions for ibps po 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