{"id":34021,"date":"2019-08-26T17:57:10","date_gmt":"2019-08-26T12:27:10","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=34021"},"modified":"2019-08-26T17:57:10","modified_gmt":"2019-08-26T12:27:10","slug":"compound-interest-questions-for-ibps-po","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/compound-interest-questions-for-ibps-po\/","title":{"rendered":"Compound Interest Questions For IBPS PO"},"content":{"rendered":"

Compound Interest Questions For IBPS PO<\/span><\/h1>\n
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Download Compound Interest Questions For IBPS PO PDF. Practice Compound Interest Questions with Solutions for Banking exams based on asked questions in previous papers.<\/p>\n<\/div>\n

Download Compound Interest Questions For IBPS PO<\/a><\/p>\n

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Download IBPS PO Previous Papers PDF<\/a><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

Question 1:\u00a0<\/b>What is the compound interest obtained on a sum of 1200 after two years, if the rate of interest for the first year is 5% and for the second year is 10%?<\/p>\n

a)\u00a0Rs 186<\/p>\n

b)\u00a0Rs 210<\/p>\n

c)\u00a0Rs 194<\/p>\n

d)\u00a0Rs 152<\/p>\n

e)\u00a0None of these<\/p>\n

Question 2:\u00a0<\/b>If Rs 18000 is invested in both simple interest and compound interest, what is the difference in interest after 2 years? Note that the interest in both the cases is equal to 10%.<\/p>\n

a)\u00a0Rs.180<\/p>\n

b)\u00a0Rs.200<\/p>\n

c)\u00a0Rs.360<\/p>\n

d)\u00a0Rs.400<\/p>\n

e)\u00a0none of these<\/p>\n

Question 3:\u00a0<\/b>Amit and Mohit, both deposit Rs 67500 in a bank which offers 10% interest yearly for simple interest and 6% interest yearly for compound interest which is compounded half yearly. Amit opted for simple interest scheme while Mohit opted for compound interest scheme. After n years, Amit\u2019s balance doubles in value. What is the ratio of Mohit\u2019s balance after n years to the amount he deposited?<\/p>\n

a)\u00a0$(1+\\frac{6}{100})^{20}$<\/p>\n

b)\u00a0$(1+\\frac{3}{100})^{20}$<\/p>\n

c)\u00a0$(1+\\frac{6}{100})^{10}$<\/p>\n

d)\u00a0$(1+\\frac{3}{100})^{10}$<\/p>\n

e)\u00a0None of these<\/p>\n

IBPS PO Quant Formulas & Shortcuts<\/a><\/p>\n

IBPS PO Previous papers<\/a><\/p>\n

Question 4:\u00a0<\/b>Harilal is a money lender who borrows money from the bank at a simple interest rate of 20%. He then lends it to people at an interest rate of 25% compounded annually and returns the money to bank as soon as he gets it back from his borrower. He borrowed Rs 1,00,000 from the bank and gave half of it to Ram and rest of it to Shyam. Ram returned the money with interest after 1 year, while Shyam returned it after 2 years. How much money did Harilal made in the whole transaction?<\/p>\n

a)\u00a0Rs 6250<\/p>\n

b)\u00a0Rs 7250<\/p>\n

c)\u00a0Rs 10625<\/p>\n

d)\u00a0Rs 11250<\/p>\n

e)\u00a0None of these<\/p>\n

Question 5:\u00a0<\/b>Find the difference between the compound interest and simple interest offered by bank for the principle of Rs 100000 at 10% per annum after 3 years.<\/p>\n

a)\u00a03000<\/p>\n

b)\u00a03100<\/p>\n

c)\u00a03500<\/p>\n

d)\u00a02900<\/p>\n

e)\u00a02500<\/p>\n

Instructions<\/b><\/p>\n

Calculate the quantity I and the quantity II on the basis of the given information then compare them and answer the following questions accordingly.<\/p>\n

Question 6:\u00a0<\/b>Quantity I: A person invested certain amount in Scheme A which offers 5% Simple Interest. Had he invested in Scheme B which offers 5% Compound Interest, he would have earned Rs.100 more. Find the sum.
\nQuantity II: A lent Rs.25000 to B at 12% per annum Simple Interest for 2 years. B lent it to C at 8% per annum Simple Interest for 2 years. Find the profit of B.<\/p>\n

a)\u00a0Quantity I > Quantity II<\/p>\n

b)\u00a0Quantity I < Quantity II<\/p>\n

c)\u00a0Quantity I $\\geq$ Quantity II<\/p>\n

d)\u00a0Quantity I $\\leq$ Quantity II<\/p>\n

e)\u00a0Quantity I = Quantity II or The relationship between Quantity I and Quantity II cannot be established.<\/p>\n

IBPS PO Free Mock Test<\/a><\/p>\n

Instructions<\/b><\/p>\n

Calculate the quantity I and the quantity II on the basis of the given information then compare them and answer the following questions accordingly.<\/p>\n

Question 7:\u00a0<\/b>Quantity I: What is the compound interest of a sum of Rs.9720 when compounded annually at $11\\frac{1}{9}$% for a period of 2 years?
\nQuantity II: Rs.1400<\/p>\n

a)\u00a0Quantity I > Quantity II<\/p>\n

b)\u00a0Quantity I < Quantity II<\/p>\n

c)\u00a0Quantity I $\\leq$ Quantity II<\/p>\n

d)\u00a0Quantity I $\\geq$ Quantity II<\/p>\n

e)\u00a0Quantity I = Quantity II or The relationship between Quantity I and Quantity II can\u2019t be determined<\/p>\n

Instructions<\/b><\/p>\n

Calculate the quantity I and the quantity II on the basis of the given information then compare them and answer the following questions accordingly.<\/p>\n

Question 8:\u00a0<\/b>Quantity I: What is the compound interest of a sum of Rs.6776 when compounded annually at $9\\frac{1}{11}$% for a period of 2 years?
\nQuantity II: Rs.1288<\/p>\n

a)\u00a0Quantity I > Quantity II<\/p>\n

b)\u00a0Quantity I < Quantity II<\/p>\n

c)\u00a0Quantity I $\\leq$ Quantity II<\/p>\n

d)\u00a0Quantity I $\\geq$ Quantity II<\/p>\n

e)\u00a0Quantity I = Quantity II or The relationship between Quantity I and Quantity II can\u2019t be determined<\/p>\n

Instructions<\/b><\/p>\n

Calculate the quantity I and the quantity II on the basis of the given information then compare them and answer the following questions accordingly.<\/p>\n

Question 9:\u00a0<\/b>Quantity I: The difference between simple interest and compound interest on a certain sum of money at 5% interest in 2 years is Rs.3. Then find the principal.
\nQuantity II: Rs.1500<\/p>\n

a)\u00a0Quantity I > Quantity II<\/p>\n

b)\u00a0Quantity I < Quantity II<\/p>\n

c)\u00a0Quantity I $\\leq$ Quantity II<\/p>\n

d)\u00a0Quantity I $\\geq$ Quantity II<\/p>\n

e)\u00a0Quantity I = Quantity II or The relationship between Quantity I and Quantity II can\u2019t be determined<\/p>\n

IBPS PO Previous Papers (Download Pdf)<\/a><\/p>\n

Instructions<\/b><\/p>\n

Calculate the quantity I and the quantity II on the basis of the given information then compare them and answer the following questions accordingly.<\/p>\n

Question 10:\u00a0<\/b>Quantity I: What is the principal if Rs.16800 of compound interest is accrued at an interest of 10% for 2 years compounded annually?
\nQuantity II: Rs.82000<\/p>\n

a)\u00a0Quantity I > Quantity II<\/p>\n

b)\u00a0Quantity I < Quantity II<\/p>\n

c)\u00a0Quantity I $\\leq$ Quantity II<\/p>\n

d)\u00a0Quantity I $\\geq$ Quantity II<\/p>\n

e)\u00a0Quantity I = Quantity II or The relationship between Quantity I and Quantity II can\u2019t be determined<\/p>\n

Instructions<\/b><\/p>\n

In the following question, Quantity 1 and Quantity 2 are given. Calculate the values and compare them and then choose the option accordingly:<\/p>\n

Question 11:\u00a0<\/b>Kabir has borrowed Rs. 5000 at the rate of 12% per annum compound interest from Guru. Kabir has lent the entire amount to Bhuvan at 15% per annum simple interest.
\nQuantity 1:The amount Kabir owes by the end of 2 years.
\nQuantity 2:The amount Kabir is owed by the end of 2 years.<\/p>\n

a)\u00a0Quantity 1 $>$ Quantity 2<\/p>\n

b)\u00a0Quantity 1 $<$ Quantity 2<\/p>\n

c)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n

d)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n

e)\u00a0Quantity 1 $=$ Quantity 2 or no relation can be established<\/p>\n

Instructions<\/b><\/p>\n

In the following question, Quantity 1 and Quantity 2 are given. Calculate the values and compare them and then choose the option accordingly<\/p>\n

Question 12:\u00a0<\/b>Quantity 1: Interest earned on Rs.1000 invested at 10% p.a compound interest for 4 years (compounded annually)
\nQuantity 2:Interest earned on Rs.1000 invested at 20% p.a. compound interest for 2 years (compounded annually)<\/p>\n

a)\u00a0Quantity 1 $>$ Quantity 2<\/p>\n

b)\u00a0Quantity 1 $<$ Quantity 2<\/p>\n

c)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n

d)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n

e)\u00a0Quantity 1 $=$ Quantity 2 or no relation can be established<\/p>\n

Instructions<\/b><\/p>\n

In the following question, Quantity 1 and Quantity 2 are given. Calculate the values and compare them and then choose the option accordingly.<\/strong><\/p>\n

Question 13:\u00a0<\/b>Quantity 1: Simple interest earned on Rs.5125 at 6.75% p.a in three years.
\nQuantity 2: Compound interest earned on Rs.5125 at 9% in two years when compounded annually.<\/p>\n

a)\u00a0Quantity 1 $>$ Quantity 2<\/p>\n

b)\u00a0Quantity\u00a01\u00a0$<$\u00a0Quantity\u00a02<\/p>\n

c)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n

d)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n

e)\u00a0Quantity 1 $=$ Quantity 2 or no relation can be established<\/p>\n

Instructions<\/b><\/p>\n

In the following question, Quantity 1 and Quantity 2 are given. Calculate the values and compare them and then choose the option accordingly<\/p>\n

 <\/p>\n

Question 14:\u00a0<\/b>Quantity I: Interest earned by Shaktikanta by lending Rs. 10000 at 20% per year for 2 years compounding on a yearly basis.
\nQuantity II: Simple interest paid by Subhash on borrowing Rs. 6000 at 30% per year for 2 years.<\/p>\n

a)\u00a0Quantity 1 $>$ Quantity 2<\/p>\n

b)\u00a0Quantity 1 $<$ Quantity 2<\/p>\n

c)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n

d)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n

e)\u00a0Quantity 1 $=$ Quantity 2 or no relation can be established<\/p>\n

Instructions<\/b><\/p>\n

Calculate the Quantity I and the Quantity II on the basis of the given information then compare them and answer the following questions accordingly.<\/p>\n

 <\/p>\n

Question 15:\u00a0<\/b>Quantity I: Interest earned by Ratan by lending Rs. 8000 at 40% per year for 1.5 years compounding on a half-yearly basis.
\nQuantity II: Profit made by Russell by selling a laptop at 10% less than the marked price which he bought for Rs 15000 and marked up price by 38%.<\/p>\n

a)\u00a0Quantity 1 = Quantity 2<\/p>\n

b)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n

c)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n

d)\u00a0Quantity 1 > Quantity 2<\/p>\n

e)\u00a0Quantity 1 < Quantity 2<\/p>\n

Instructions<\/b><\/p>\n

In the following question, Quantity 1 and Quantity 2 are given. Calculate the values and compare them and then choose the option accordingly.<\/strong><\/p>\n

 <\/p>\n

Question 16:\u00a0<\/b>Quantity 1: Simple interest earned on Rs.4962 at 6.75% p.a in three years.
\nQuantity 2: Compound interest earned on Rs.4962 at 10% in two years when compounded annually.<\/p>\n

a)\u00a0Quantity 1 $>$ Quantity 2<\/p>\n

b)\u00a0Quantity\u00a01\u00a0$<$\u00a0Quantity\u00a02<\/p>\n

c)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n

d)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n

e)\u00a0Quantity 1 $=$ Quantity 2 or no relation can be established<\/p>\n

Instructions<\/b><\/p>\n

Calculate the Quantity I and the Quantity II on the basis of the given information then compare them and answer the following questions accordingly.<\/p>\n

 <\/p>\n

Question 17:\u00a0<\/b>Quantity I: Interest paid by Kabir on borrowing Rs. 8000 at 20% per year for 2 years compounding on yearly basis.
\nQuantity II: Loss incurred by Amir if the cost price of a mobile is Rs. 6000 on which he marked up the price by 25% and offered a discount of 60%.<\/p>\n

a)\u00a0Quantity 1 = Quantity 2<\/p>\n

b)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n

c)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n

d)\u00a0Quantity 1 > Quantity 2<\/p>\n

e)\u00a0Quantity 1 < Quantity 2<\/p>\n

Instructions<\/b><\/p>\n

In the following question, Quantity 1 and Quantity 2 are given. Calculate the values and compare them and then choose the option accordingly.<\/strong><\/p>\n

 <\/p>\n

Question 18:\u00a0<\/b>Quantity 1: Simple interest earned on Rs.3576 at 8% p.a in three years.
\nQuantity 2: Compound interest earned on Rs.3576 at 10% in two years when compounded annually.<\/p>\n

a)\u00a0Quantity 1 $>$ Quantity 2<\/p>\n

b)\u00a0Quantity\u00a01\u00a0$<$\u00a0Quantity\u00a02<\/p>\n

c)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n

d)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n

e)\u00a0Quantity 1 $=$ Quantity 2 or no relation can be established<\/p>\n

Instructions<\/b><\/p>\n

Calculate the Quantity I and the Quantity II on the basis of the given information then compare them and answer the following questions accordingly.<\/p>\n

 <\/p>\n

Question 19:\u00a0<\/b>Quantity I: Interest earned by Ram by lending Rs. 6000 at 15% per year for 2 years compounding on yearly basis.
\nQuantity II: Profit earned by Kishan by selling a toy in Rs. 8000 on which he marked up the price by 25%.<\/p>\n

a)\u00a0Quantity 1 = Quantity 2<\/p>\n

b)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n

c)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n

d)\u00a0Quantity 1 > Quantity 2<\/p>\n

e)\u00a0Quantity 1 < Quantity 2<\/p>\n

Instructions<\/b><\/p>\n

In the following question, Quantity 1 and Quantity 2 are given. Calculate the values and compare them and then choose the option accordingly.<\/strong><\/p>\n

 <\/p>\n

Question 20:\u00a0<\/b>Quantity 1: Rate at which simple interest earned on Rs.5000 in two years is Rs.800.
\nQuantity 2: Rate at which compound interest earned on Rs.1000 in three years is Rs.331.<\/p>\n

a)\u00a0Quantity 1 $>$ Quantity 2<\/p>\n

b)\u00a0Quantity\u00a01\u00a0$<$\u00a0Quantity\u00a02<\/p>\n

c)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n

d)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n

e)\u00a0Quantity 1 $=$ Quantity 2 or no relation can be established<\/p>\n

IBPS PO Important Questions PDF<\/a><\/p>\n

Free Banking Study Material (15,000 Solved Questions<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The value of the sum at the end of two years = 1200(1.05)*(1.1) = 1386
\nTherefore compound interest obtained = 1386-1200 = Rs 186
\nSo the correct option to choose is A – Rs 186.<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

When an amount is invested in both S.I and C.I, the interest will be the same in the first year. In the second year, money invested in C.I will also charge interest on the interest accrued in the first year. Thus, the interest on the interest of the 1st year is the difference between S.I and C.I for two years.
\nThe interest obtained in the 1st year = Rs. 1800 x 10% = Rs. 1800
\nThe interest charged on Rs. 1800 = 1800 x 10% = Rs. 180
\nThus, the required difference = Rs.180<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let P=Rs 67500
\nNow, for Amit, P(1+nr\/100)=2P
\n= nr\/100=1
\nr=10
\n=> n=10
\nMohit\u2019s balance after n years will be $P(1+\\frac{3}{100})^{20}$ since the interest is 6% which is compounded half yearly. So the time period that we will take is 20.
\nSo the ratio will be $(1+\\frac{3}{100})^{20}$<\/p>\n

4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Total money that Ram returned to Harilal is:$50000\\times(1+\\frac{25}{100})^{1}$
\nTotal money that Harilal returned to bank is simple interest on principle for 1 year + principle =$50000\\times(1+\\frac{20*1}{100})$
\nProfit on Ram\u2019s transaction is: $50000\\times(\\frac{25-20}{100})=Rs 2500$
\nMoney that Shyam returned to Harilal is $50000\\times(1+\\frac{25}{100})^{2}=50000\\times(\\frac{25}{16})=50000\\times(1+\\frac{9}{16})$
\nTotal money that Harilal returned to bank is simple interest on principle for 2 year + principle =$50000\\times(1+\\frac{20*2}{100})=50000\\times(1+\\frac{4}{10})$
\nProfit on Shyam\u2019s transaction is: $50000\\times(\\frac{9}{16}-\\frac{4}{10})=50000\\times(\\frac{13}{80})=Rs 8125 $
\nTotal Money made is Rs 8125 + Rs 2500= Rs 10625<\/p>\n

5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

SI = P*R*T\/100 = 100000*10*3\/100 = 30000
\nCI = P$(1+r\/100)^n$-P =$100000(1.1)^3-100000$ = 133100-100000 = 33100
\nDifference = 33100-30000 = 3100<\/p>\n

6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Quantity I:
\nLet the principal be Rs.10000
\nSimple Interest at 5% SI for 2 years = $\\dfrac{10000\\times5\\times2}{100} = Rs.1000$
\nAmount for 1 year at 5% CI = 105% of Rs.10000 = Rs.10500
\nAmount for 2 years at 5% CI = 105% of Rs.10500 = Rs.11025
\nTotal Compound Interest = Rs.11025 – Rs.10000 = Rs.1025
\nDifference between SI and CI = Rs.1025 – Rs.1000 = Rs.25
\nGiven that the difference = Rs.100
\nRs.25 \u2192 Rs.100
\nRs.10000 \u2192 ?
\n= $\\dfrac{10000\\times100}{25} = Rs.40000$
\nHence, Principal = Rs.40000
\nQuantity II:
\nProfit of B = $\\dfrac{25000\\times12\\times2}{100} – \\dfrac{25000\\times8\\times2}{100} = Rs.6000 – Rs.4000 = Rs.2000$<\/p>\n

Therefore, Quantity I > Quantity II<\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Quantity I: Given Principal = Rs.9720
\nTime Period = 2 years
\nRate of interest = $11\\frac{1}{9}$%.
\n$11\\frac{1}{9}$ = $\\frac{100}{9}$%
\nCompound Interest at the end of 1 year $= 9720\\times\\dfrac{100}{9}\\times\\dfrac{1}{100} = Rs.1080$
\nAmount at the end of 1st year $= 9720+1080 = Rs.10800$
\nCompound Interest at the end of 2nd year $= 10800\\times\\dfrac{100}{9}\\times\\dfrac{1}{100} = Rs.1200$
\nAmount at the end of 2nd year $= 10800+1200 = Rs.12000$
\nCompound Interest for 2 years $= Rs.12000-Rs.9720 = Rs.2280$
\nQuantity II: $Rs.1400$<\/p>\n

Hence, Quantity I > Quantity II<\/p>\n

8)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Quantity I:
\nGiven Principal = Rs.6776
\nRate of Interest = $9\\frac{1}{11}$% = $\\frac{1}{11}$
\nTime period = 2 years
\nCompound Interest at the end of 1 year $= 6776\\times\\frac{1}{11} = Rs.616$
\nAmount at the end of 1 year = 6776+616 = Rs.7392
\nCompound Interest at the end of 2 years $= 7392\\times\\frac{1}{11} = Rs.672$
\nAmount at the end of 2 years = 7392+672 = Rs.8064
\nTherefore, Compound Interest = 8064-6776 = Rs.1288<\/p>\n

Quantity II: Rs.1288
\nHence, Quantity I = Quantity II<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Quantity I: Let the principal amount be Rs.10000
\nThen, Simple Interest $= \\frac{10000\\times2\\times5}{100} = 1000$
\nAmount at the end of 1st year at 5% compound interest = Rs.$10500$
\nAmount for $2$ years $=$ Rs.$11025$
\nCompound Interest $= 11025 – 10000 =$ Rs.$1025$
\nDifference between SI and CI $= 1025 – 1000 =$ Rs.$25$
\nGiven that the difference $=$ Rs.$3$
\n$25\\rightarrow3$
\n$10000\\rightarrow?$
\n=> $\\frac{10000\\times3}{25} = 1200$
\nTherefore, principal = Rs.$1200$
\nQuantity II: Rs.1500<\/p>\n

Hence, Quantity I < Quantity II<\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Quantity I: Let the principal amount be Rs.100
\nAmount at the end of 1 year at 10% compound interest = Rs.110
\nAmount at the end of 2 years = Rs.121
\nCompound interest = 121-100 = Rs.21
\nGiven Compound Interest = Rs.16800
\n21 \u2192 16800
\n100 \u2192 ?
\n= $\\frac{100\\times16800}{21} = 80000$
\nHence, Principal = Rs.80000
\nQuantity II: Rs.82000<\/p>\n

Hence, Quantity I < Quantity II<\/p>\n

11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Since Kabir lends the entire amount, the principal is immaterial. Let us assume the principal to be \u2018p\u2019.<\/p>\n

The money that Kabir has borrowed will amount to p*1.12*1.12 = 1.2544*p
\nKabir has lent the entire amount at 15% SI. Kabir will get back p + 2*0.15*p = 1.3p<\/p>\n

As we can see, the amount that Kabir is owed is greater than the amount that Kabir owes. Therefore, quantity 2 is greater than quantity 1 and hence, option B is the right answer.<\/p>\n

12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Since the principal is the same in both the cases, we will compare the amounts by the end of the given periods.
\nQuantity 1:
\nRs.1000 invested at 10% p.a compound interest for 4 years will amount to $1000*(1.1)^4$ = $1.4641*1000$<\/p>\n

Quantity 2:
\nRs.1000 invested at 20% p.a. compound interest for 2 years will amount to $1000*(1.2)^2$ = $1.44*1000$<\/p>\n

As we can see, quantity 1 is greater than quantity 2 and hence, option A is the right answer.<\/p>\n

13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Quantity 1 = Rs.$\\dfrac{5125 * 6.75 * 3}{100}$ = Rs.1037.80.
\nQuantity 2 = Rs.(5125 * 1.09 * 1.09 – 5125) = Rs.964
\nThus, Quantity 1 is greater than Quantity 2.
\nHence, option A is the correct answer.<\/p>\n

14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Quantity I: Compounded interest earned by Shaktikanta = $10000*(1+\\dfrac{20}{100})^{2} – 10000$ = Rs. 4400
\nQuantity II: Simple interest paid by Subhash on Rs. 6000 at 30% per year for 2 years = 6000*0.30*2\/100 = Rs. 3600
\nHence, we can say that Quantity 1 > Quantity 2.<\/p>\n

15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Quantity I: Compounded interest earned by Ratan = $8000*(1+\\dfrac{40\/2}{100})^{2*1.5} – 8000$ = Rs. 5824
\nQuantity II: cost price = Rs. 15000, Mark-up percentage = 38%
\nTherefore, the marked price of the product = 1.38*15000 = Rs. 20700
\nHence, the selling price of the product = (1-0.1)*20700 = Rs. 18630
\nHence, the profit made by Russell = 18630 – 15000 = Rs. 3630
\nHence, we can say that Quantity 1 > Quantity 2.<\/p>\n

16)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Quantity 1 = $\\dfrac{4962 * 6.75 * 3}{100} = 4962 \\times \\dfrac{20.25}{100} = 4062 \\times (0.2025) $
\nQuantity 2 = $ 4962 \\times [(1.1)^{2} – 1] = 4962 \\times (0.21) $<\/p>\n

Since 4962 is same, we just need to compare the term on the right to compare the value of the expression.
\nThus, Quantity 2 is greater than Quantity 1.
\nHence, option B is the correct answer.<\/p>\n

17)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Quantity I: Compounded interest paid by Kabir = $8000*(1+\\dfrac{20}{100})^2 – 8000$ = Rs. 3520
\nQuantity II: cost price = Rs. 6000, Mark-up percentage = 25%
\nTherefore, the marked price of the product = 1.25*6000 = Rs. 7500
\nHence, the selling price of the product = (1-0.6)*7500 = Rs. 3000
\nHence, the loss incurred by Amir = 6000 – 3000 = Rs. 3000
\nHence, we can say that Quantity 1 > Quantity 2.<\/p>\n

18)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Quantity 1 = $\\dfrac{3576 \\times 8 \\times 3}{100} = 3576 \\times \\dfrac{24}{100} = 3576 \\times (0.24)$<\/p>\n

Quantity 2 = $3576 \\times [(1.1)^{2} – 1] = 3576 \\times (0.21) $<\/p>\n

Since 3576 is common, we just compare the second terms in the expression.<\/p>\n

Thus, Quantity 1 is greater than Quantity 2.
\nHence, option A is the correct answer.<\/p>\n

19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Quantity I: Compounded interest earned by Ram = $6000*(1+\\dfrac{15}{100})^2 – 6000$ = Rs. 1935
\nQuantity II: Marked price = Rs. 8000, Mark-up percentage = 25%
\nTherefore, the cost price of the product = $\\dfrac{100}{100+25}\\times 8000$ = Rs. 6400
\nHence, the profit amount made by Kishan = 8000 – 6400 = Rs. 1600
\nHence, we can say that Quantity 1 > Quantity 2.<\/p>\n

20)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Quantity 1 = Rs.$\\dfrac{800 * 100}{5000 * 2}$ = 8%
\nQuantity 2 cannot be calculated because the frequency of compounding is not given.
\nHence, option E is the correct answer.<\/p>\n

\u00a0<\/b><\/strong>

IBPS PO Previous Papers (Download PDF)<\/a><\/p><\/p>\n

Download IBPS PO Free Preparation App<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Compound Interest Questions For IBPS PO Download Compound Interest Questions For IBPS PO PDF. Practice Compound Interest Questions with Solutions for Banking exams based on asked questions in previous papers. Take a free mock test for IBPS PO Download IBPS PO Previous Papers PDF Question 1:\u00a0What is the compound interest obtained on a sum of […]<\/p>\n","protected":false},"author":32,"featured_media":34024,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[228],"tags":[48],"class_list":{"0":"post-34021","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-ibpspo","8":"tag-ibps-po"},"better_featured_image":{"id":34024,"alt_text":"compound interest questions for ibps po","caption":"compound interest questions for ibps po\n","description":"compound interest questions for ibps 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