{"id":33836,"date":"2019-08-22T13:04:08","date_gmt":"2019-08-22T07:34:08","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=33836"},"modified":"2019-08-22T13:04:08","modified_gmt":"2019-08-22T07:34:08","slug":"number-series-questions-for-rrb-ntpc-set-2-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/number-series-questions-for-rrb-ntpc-set-2-pdf\/","title":{"rendered":"Number Series Questions for RRB NTPC Set-2 PDF"},"content":{"rendered":"

Number Series Questions for RRB NTPC Set-2 PDF<\/strong><\/span><\/h2>\n

Download RRB NTPC Number Series Questions and Answers set – 2 PDF. Top 15 RRB NTPC Number series questions based on asked questions in previous exam papers very important for the Railway NTPC exam.<\/p>\n

Download Number Series Questions for RRB NTPC Set-2 PDF<\/a><\/p>\n\n

Take a free mock test for RRB NTPC<\/a><\/p>\n

Download RRB NTPC Previous Papers PDF<\/a><\/p>\n

Question 1:\u00a0<\/b>Find the next number in the series:
\n12, 36, 108, 324, 972, ___<\/p>\n

a)\u00a02712<\/p>\n

b)\u00a02916<\/p>\n

c)\u00a03016<\/p>\n

d)\u00a03200<\/p>\n

Question 2:\u00a0<\/b>Find the missing number in the series:
\n4, 5, 9, ?, 23, 37, 60, 97<\/p>\n

a)\u00a011<\/p>\n

b)\u00a013<\/p>\n

c)\u00a019<\/p>\n

d)\u00a014<\/p>\n

Question 3:\u00a0<\/b>Find the next number in the series:
\n5, 16, 27, 38, 49, 60, ____<\/p>\n

a)\u00a070<\/p>\n

b)\u00a071<\/p>\n

c)\u00a085<\/p>\n

d)\u00a082<\/p>\n

RRB NTPC Previous Papers [Download PDF]<\/a><\/p>\n

FREE RRB NTPC YOUTUBE VIDEOS<\/a><\/p>\n

Question 4:\u00a0<\/b>What comes next in the given series:2,3,5,7,11,13,17<\/p>\n

a)\u00a020<\/p>\n

b)\u00a019<\/p>\n

c)\u00a021<\/p>\n

d)\u00a022<\/p>\n

Question 5:\u00a0<\/b>What comes next in the given series:3,8,15,24,35,48,<\/p>\n

a)\u00a063<\/p>\n

b)\u00a080<\/p>\n

c)\u00a056<\/p>\n

d)\u00a060<\/p>\n

Question 6:\u00a0<\/b>What comes next in the given series:3,8,15,24,35,48,63,80<\/p>\n

a)\u00a090<\/p>\n

b)\u00a091<\/p>\n

c)\u00a099<\/p>\n

d)\u00a097<\/p>\n

Question 7:\u00a0<\/b>What comes next in the given series:1,2,4,7,11,16,22,29,37,46,<\/p>\n

a)\u00a055<\/p>\n

b)\u00a056<\/p>\n

c)\u00a052<\/p>\n

d)\u00a059<\/p>\n

RRB NTPC Free Mock Test<\/a><\/p>\n\n

Question 8:\u00a0<\/b>Complete the following series: 11, 15, 20, 26, 33, ?<\/p>\n

a)\u00a045<\/p>\n

b)\u00a043<\/p>\n

c)\u00a041<\/p>\n

d)\u00a040<\/p>\n

Question 9:\u00a0<\/b>Complete the following series: 10, 17, 25, 34, 44, ?<\/p>\n

a)\u00a054<\/p>\n

b)\u00a055<\/p>\n

c)\u00a064<\/p>\n

d)\u00a061<\/p>\n

Question 10:\u00a0<\/b>Find the missing term in the series:
\n981, 1089, 1225, 1369, ?<\/p>\n

a)\u00a01461<\/p>\n

b)\u00a01521<\/p>\n

c)\u00a01681<\/p>\n

d)\u00a01491<\/p>\n

Question 11:\u00a0<\/b>Find the missing term in the series:
\n3, 7, 13, 21, ?<\/p>\n

a)\u00a031<\/p>\n

b)\u00a030<\/p>\n

c)\u00a029<\/p>\n

d)\u00a028<\/p>\n

Download General Science Notes PDF<\/a><\/p>\n\n

Question 12:\u00a0<\/b>Complete the following series:
\n19, 79, 319, 1279, ?<\/p>\n

a)\u00a05009<\/p>\n

b)\u00a05109<\/p>\n

c)\u00a05111<\/p>\n

d)\u00a05119<\/p>\n

Question 13:\u00a0<\/b>Complete the following series:
\n5, 11, 8, 13, 11, ?<\/p>\n

a)\u00a015<\/p>\n

b)\u00a05<\/p>\n

c)\u00a010<\/p>\n

d)\u00a08<\/p>\n

Question 14:\u00a0<\/b>Complete the following series:
\n50, 255, 1280, 6405, ?<\/p>\n

a)\u00a030100<\/p>\n

b)\u00a024590<\/p>\n

c)\u00a030300<\/p>\n

d)\u00a032030<\/p>\n

Question 15:\u00a0<\/b>Complete the following series:
\n11, 18, 28, 41, 57, ?<\/p>\n

a)\u00a076<\/p>\n

b)\u00a074<\/p>\n

c)\u00a086<\/p>\n

d)\u00a084<\/p>\n

RRB NTPC Free Mock Test<\/a><\/p>\n

RRB NTPC Previous Papers (Download PDF)<\/a><\/p>\n\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The differences between consecutive terms are 24, 72, 216, 648. Hence, the differences are increasing in an exponential manner. Thus, the series must be a Geometric Progression. a=12 and r=36\/12 = 3.<\/p>\n

Thus, the terms of the series are 12, 12*3, $12*3^2$, $12*3^3$, $12*3^4$. Thus, the next term of the series = 972 * 3 = 2916.<\/p>\n

2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

The differences between consecutive terms are 1, 4 and 14, 23 and 37. We see that terms of the series are appearing in the list of differences. Hence, the series is formed by adding previous terms of the series.
\ni.e. 4+5=9, 5+9=14, 9+14=23, 14+23=37, 23+37=60 and 37+60=97.<\/p>\n

Hence, the missing number is 14.<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The differences between consecutive terms is 16-5=11, 27-16=11, 38-27-11, 49-38=11 and 60-49=11. Hence, the difference is a constant. Thus, the series is an Arithmetic Progression.<\/p>\n

The next number in the series would be 60+11=71.<\/p>\n

4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The given series is the list of prime numbers. The next prime number after 17 is 19.<\/p>\n

5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The given series is of the form n(n+2) = 1*3, 2*4, 3*5, 4*6 and so on.
\nThe next term would be 7*9 = 63<\/p>\n

6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

The given terms are of the format $n^2-1$.
\n3 =$2^2-1$
\n8 =$3^2-1$
\n15 =$4^2-1$
\n24 =$5^2-1$
\n35 =$6^2-1$
\nand so on
\nThe next term would be $10^2-1 = 99$<\/p>\n

7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

The difference of two consecutive terms are in AP.
\n2-1 = 1, 4-2 = 2, 7-4 = 3, 11-7 = 4, 16-11 = 5, 22-16 = 6, 29-22 = 7, 37-29 = 8, 46-37 = 9
\nx-46 = 10
\nx = 56<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

11+4 = 15 ; 15+5 = 20 ; 20+6 = 26 ; 26+7 = 33; 33+8 = 41<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

10+7 = 17; 17+8 = 25 ; 25+9 = 34 ; 34+10 = 44 ; 44+11 = 55<\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

981 = $31^2$
\n1089 = $33^2$
\n1225 = $35^2$
\n1369 = $37^2$
\n1521 = $39^2$<\/p>\n

11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

7 – 3 = 4
\n13 – 7 = 6
\n21 – 13 = 8
\nx – 21 = 10
\n=> x = 31<\/p>\n

12)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

19*4+3 = 79 ; 79*4+3 = 319; 319*4+4 = 1279 ; 1279*4+3 = 5119<\/p>\n

13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

First, third and 5th letter are forming an A.P. with the common difference of 3
\nSecond, third and sixth letter are also forming an A.P. with the common difference of 2
\nHence, answer will be \u201ca\u201d<\/p>\n

14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

9*5+5 = 50 ; 50*5+5= 255 ; 255*5+5 = 1280 ; 1280*5+5 = 6405, 6405*5+5=32030<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

11+7=18 ; 18+10=28 ; 28+13=41 ;41+16 = 57, 57+19=76<\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

We hope this Number Series Questions set-2\u00a0 pdf\u00a0 for RRB NTPC Exam will be highly useful for your Preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Number Series Questions for RRB NTPC Set-2 PDF Download RRB NTPC Number Series Questions and Answers set – 2 PDF. Top 15 RRB NTPC Number series questions based on asked questions in previous exam papers very important for the Railway NTPC exam. Take a free mock test for RRB NTPC Download RRB NTPC Previous Papers […]<\/p>\n","protected":false},"author":41,"featured_media":33838,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,31,1603,1601],"tags":[489,491,1637,1619],"class_list":{"0":"post-33836","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-railways","10":"category-rrb-ntpc","11":"category-rrb-ntpc-je","12":"tag-railway-exam","13":"tag-rrb","14":"tag-rrb-exam","15":"tag-rrb-ntpc-2019"},"better_featured_image":{"id":33838,"alt_text":"Number Series Questions for RRB NTPC Set-2 PDF","caption":"Number Series Questions for RRB NTPC Set-2 PDF","description":"Number Series Questions for RRB NTPC Set-2 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