Download important IIFT Percentages Questions PDF based on previously asked questions in IIFT and other MBA exams. Practice Percentages\u00a0 questions and answers for IIFT exam.<\/p>\n
Download Percentages Questions for IIFT PDF<\/a><\/p>\n Get 50% Off on IIFT & Other MBA Test Series\u00a0<\/a><\/p>\n Download IIFT Previous Papers PDF<\/a><\/p>\n Practice IIFT Mock Tests<\/a><\/p>\n Question 1:\u00a0<\/b>If equal numbers of people are born on each day, find the approximate percentage of the people whose birthday will fall on 29th February. If we are to consider people born in 20th century (1901-2000) and assuming no deaths.<\/p>\n a)\u00a00.374<\/p>\n b)\u00a00.5732<\/p>\n c)\u00a00.0664<\/p>\n d)\u00a0None of these<\/p>\n Question 2:\u00a0<\/b>Arun’s present age in years is 40% of Barun’s. In another few years, Arun’s age will be half of Barun’s. By what percentage will Barun’s age increase during this period?<\/p>\n Question 3:\u00a0<\/b>The number of girls appearing for an admission test is twice the number of boys. If 30% of the girls and 45% of the boys get admission, the percentage of candidates who do not get admission is<\/p>\n a)\u00a035<\/p>\n b)\u00a050<\/p>\n c)\u00a060<\/p>\n d)\u00a065<\/p>\n Question 4:\u00a0<\/b>Tina, Mina, Gina, Lina and Bina are 5 sisters, aged in that order, with Tina being the eldest. Each of them had to carry a bucket of water from a well to their house. Their buckets\u2019 capacities were proportional to their ages. While returning, equal amount of water got splashed out of their buckets. Who lost maximum amount of water as a percentage of the bucket capacity?<\/p>\n a)\u00a0Tina<\/p>\n b)\u00a0Mina<\/p>\n c)\u00a0Gina<\/p>\n d)\u00a0Lina<\/p>\n e)\u00a0Bina<\/p>\n Question 5:\u00a0<\/b>In 2006, Raveendra was allotted 650 shares of Sun Systems Ltd in the initial public offer, at the face value of Rs. 10 per share. In 2007, Sun Systems declared the bonus at the rate of 3 : 13. In 2008, the company again declared the bonus at the rate of 2 : 4. In 2009, the company declared a dividend of 12.5%. How much dividend does Raveendra get in 2009 as a percentage of his initial investment?<\/p>\n a)\u00a024.5%<\/p>\n b)\u00a023.9%<\/p>\n c)\u00a024.1%<\/p>\n d)\u00a023%<\/p>\n IIFT Free Mock Test<\/a><\/p>\n Enroll for CAT\/MBA Courses<\/a><\/p>\n Question 6:\u00a0<\/b>The ratio of number of male and female journalists in a newspaper office is 5:4. The newspaper has two sections, political and sports. If 30 percent of the male journalists and 40 percent of the female journalists are covering political news, what percentage of the journalists (approx.) in the newspaper is currently involved in sports reporting?<\/p>\n a)\u00a065 percent<\/p>\n b)\u00a060 percent<\/p>\n c)\u00a070 percent<\/p>\n d)\u00a0None of the above<\/p>\n Question 7:\u00a0<\/b>There are two alloys P and Q made up of silver, copper and aluminium. Alloy P contains 45% silver and rest aluminum. Alloy Q contains 30% silver, 35% copper and rest aluminium. Alloys P and Q are mixed in the ratio of 1 : 4 . 5. The approximate percentages of silver and copper in the newly formed alloy is:<\/p>\n a)\u00a033% and 29%<\/p>\n b)\u00a029% and 26%<\/p>\n c)\u00a035% and 30%<\/p>\n d)\u00a0None of the above<\/p>\n Question 8:\u00a0<\/b>Arun’s present age in years is 40% of Barun’s. In another few years, Arun’s age will be half of Barun’s. By what percentage will Barun’s age increase during this period?<\/p>\n Question 9:\u00a0<\/b>The number of girls appearing for an admission test is twice the number of boys. If 30% of the girls and 45% of the boys get admission, the percentage of candidates who do not get admission is<\/p>\n a)\u00a035<\/p>\n b)\u00a050<\/p>\n c)\u00a060<\/p>\n d)\u00a065<\/p>\n Question 10:\u00a0<\/b>In a village, the production of food grains increased by 40% and the per capita production of food grains increased by 27% during a certain period. The percentage by which the population of the village increased during the same period is nearest to<\/p>\n a)\u00a016<\/p>\n b)\u00a013<\/p>\n c)\u00a010<\/p>\n d)\u00a07<\/p>\n Top 500+ Free Questions for IIFT<\/a><\/p>\n IIFT Previous year question\u00a0 answer PDF<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Assume one person is born every day. In 100 years, there will be 25 leap years. So 25*1 additional people will be born on these days.<\/p>\n So, total people born will be = $365 \\times 100 \\times 1 + 25 \\times 1$ 2)\u00a0Answer:\u00a020<\/b><\/p>\n Let Arun’s current age be A. Hence, Barun’s current age is 2.5A 3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the number of girls be 2x and number of boys be x.<\/p>\n Girls getting admission = 0.6x<\/p>\n Boys getting admission = 0.45x<\/p>\n Number of students not getting admission = 3x – 0.6x -0.45x = 1.95x<\/p>\n Percentage = (1.95x\/3x) * 100 = 65%<\/p>\n 4)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the capacities of bucket of water carried by Tina, Mina, Gina, Lina and Bina respectively be $W_T, W_M, W_G, W_L, W_B$<\/p>\n It is given that : $W_T > W_M > W_G > W_L > W_B$<\/p>\n Let they spill $x$ litres of water from the bucket.<\/p>\n Thus, %age of water spilled by them respectively be<\/p>\n = $\\frac{x}{W_T} \\times 100 $, $\\frac{x}{W_M} \\times 100$, $\\frac{x}{W_G} \\times 100$, $\\frac{x}{W_L} \\times 100$, $\\frac{x}{W_B} \\times 100$<\/p>\n $\\because W_T > W_M > W_G > W_L > W_B$<\/p>\n $\\therefore \\frac{x}{W_T} \\times 100$ < $ \\frac{x}{W_M} \\times 100$ < $\\frac{x}{W_G} \\times 100$ < $\\frac{x}{W_L} \\times 100$ < $\\frac{x}{W_B} \\times 100$<\/p>\n Thus, Bina lost maximum amount of water as a percentage of the bucket capacity.<\/p>\n 5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Bonus share received in 2007 = 650 * (3\/13) = 150 Hence, option D is the correct answer.<\/p>\n Quant Formula For IIFT PDF<\/a><\/p>\n IIFT Free Mock Test<\/a><\/p>\n 6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n The ratio of number of male and female journalists in a newspaper office is 5:4. The newspaper has two sections, political and sports. If 30 percent of the male journalists and 40 percent of the female journalists are covering political news, what percentage of the journalists (approx.) in the newspaper is currently involved in sports reporting?<\/p>\n Let ‘9x’ be the number of total journalists in the office. Then, we can say that the number of male and female journalists are ‘5x’ and ‘4x’ respectively.<\/p>\n It is given that 30 percent of the male journalists and 40 percent of the female journalists are covering political news. Hence, total number of journalists who are covering political news = 0.3*5x + 0.4*4x = 3.1x<\/p>\n Therefore, the total number\u00a0journalists who are covering sports news = 9x – 3.1x = 5.9x.<\/p>\n Hence, the\u00a0percentage of the journalists in the newspaper is currently involved in sports reporting = $\\dfrac{5.9x}{9x}\\times 100$ $\\approx$ 65 percent. Therefore, option A is the correct answer.<\/p>\n 7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Composition of alloy P<\/p>\n Silver:Copper:Aluminium = 45:0:55<\/p>\n Composition of alloy Q<\/p>\n Silver:Copper:Aluminium = 30:35:35<\/p>\n They are mixed in ratio of 1: 4.5<\/p>\n Let us consider alloy P is taken 200 grams and alloy Q is taken 900 grams.<\/p>\n Then for alloy P :-<\/p>\n Silver:Copper:Aluminium = 90:0:110<\/p>\n For alloy Q:<\/p>\n Silver:Copper:Aluminium = 270:315:315<\/p>\n Total weight of P and Q combined is 1100 grams.<\/p>\n When P and Q are mixed, the new combined ratio of<\/p>\n Silver:Copper:Aluminium = 360:315:425<\/p>\n Percentage of Silver in mixture = $\\frac{360}{1100}$ x 100 $\\cong$ 33%<\/p>\n Percentage of Copper in mixture = $\\frac{315}{1100}$ x 100 $\\cong$ 29%<\/p>\n 8)\u00a0Answer:\u00a020<\/b><\/p>\n Let Arun’s current age be A. Hence, Barun’s current age is 2.5A 9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the number of girls be 2x and number of boys be x.<\/p>\n Girls getting admission = 0.6x<\/p>\n Boys getting admission = 0.45x<\/p>\n Number of students not getting admission = 3x – 0.6x -0.45x = 1.95x<\/p>\n Percentage = (1.95x\/3x) * 100 = 65%<\/p>\n 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let initial population and production be x,y and final population be z
\nAnd people born on 29th february = $25 \\times 1$
\nHence percentage will be = $\\frac{25 \\times 1}{365 \\times 100 \\times 1 + 25 \\times 1} \\times 100$ = 0.0684<\/p>\n
\nLet Arun’s age be half of Barun’s age after X years.
\nTherefore, 2*(X+A) = 2.5A + X
\nOr, X = 0.5A
\nHence, Barun’s age increased by 0.5A\/2.5A = 20%<\/p>\n
\nBonus share received in 2008 = 800 * (1\/2) = 400
\nSo, has has (150 + 400) = 550 extra shares
\nDividend he will get = $\\dfrac{1200 * 12.5}{650} * 100$% = $23$%<\/p>\n
\nLet Arun’s age be half of Barun’s age after X years.
\nTherefore, 2*(X+A) = 2.5A + X
\nOr, X = 0.5A
\nHence, Barun’s age increased by 0.5A\/2.5A = 20%<\/p>\n
\nFinal production = 1.4y, final percapita = 1.27 times initial percapita
\n=> $\\frac{1.4y}{z} $ = $ 1.27 \\times \\frac{y}{x}$
\n=> $\\frac{z}{x} = \\frac{1.4}{1.27} \\approx 1.10$
\nHence the percentage increase in population = 10%<\/p>\n