Download important IIFT Time and Work Questions PDF based on previously asked questions in IIFT and other MBA exams. Practice Time and Work questions and answers for IIFT exam.<\/p>\n
Download IIFT Time and Work Questions PDF<\/a><\/p>\n Get 50% Off on IIFT & Other MBA Test Series\u00a0<\/a><\/p>\n Download IIFT Previous Papers PDF<\/a><\/p>\n Practice IIFT Mock Tests<\/a><\/p>\n Question 1:\u00a0<\/b>A can complete a piece of work in 4 days. B takes double the time taken by A, C takes double that of B, and D takes double that of C to complete the same task. They are paired in groups of two each. One pair takes two-thirds the time needed by the second pair to complete the work. Which is the first pair?<\/p>\n a)\u00a0A and B<\/p>\n b)\u00a0A and C<\/p>\n c)\u00a0B and C<\/p>\n d)\u00a0A and D<\/p>\n Question 2:\u00a0<\/b>There\u2019s a lot of work in preparing a birthday dinner. Even after the turkey is in the oven, there\u2019s still the potatoes and gravy, yams, salad, and cranberries, not to mention setting the table. a)\u00a020 min<\/p>\n b)\u00a030 min<\/p>\n c)\u00a040 min<\/p>\n d)\u00a050 min<\/p>\n Question 3:\u00a0<\/b>In a watch, the minute hand crosses the hour hand for the third time exactly after every 3 hr 18 min and 15s of normal time. What is the time gained or lost by this watch in one day?<\/p>\n a)\u00a014 min 10 s lost<\/p>\n b)\u00a013 min 48 s lost<\/p>\n c)\u00a013 min 20 s gained<\/p>\n d)\u00a014 min 40 s gained<\/p>\n Instructions<\/b>Boston is 4 hr ahead of Frankfurt and 2 hr behind India. X leaves Frankfurt at 6 p.m. on Friday and reaches Boston the next day. After waiting there for 2 hr, he leaves exactly at noon and reaches India at 1 a.m. On his return journey, he takes the same route as before, but halts at Boston for 1hr less than his previous halt there. He then proceeds to Frankfurt.<\/p>\n Question 4:\u00a0<\/b>If X had started the return journey from India at 2.55 a.m. on the same day that he reached there, after how much time would he reach Frankfurt?<\/p>\n a)\u00a024 hr<\/p>\n b)\u00a025 hr<\/p>\n c)\u00a026 hr<\/p>\n d)\u00a0Data insufficient<\/p>\n Question 5:\u00a0<\/b>Three wheels can complete 60, 36 and 24 revolutions per minute. There is a red spot on each wheel that touches the ground at time zero. After how much time, all these spots will simultaneously touch the ground again?<\/p>\n a)\u00a0$\\frac{5}{2}$ s<\/p>\n b)\u00a0$\\frac{5}{3}$ s<\/p>\n c)\u00a0$5$ s<\/p>\n d)\u00a0$7.5$ s<\/p>\n IIFT Free Mock Test<\/a><\/p>\n Enroll for CAT\/MBA Courses<\/a><\/p>\n Question 6:\u00a0<\/b>It takes six technicians a total of 10 hr to build a new server from Direct Computer, with each working at the same rate. If six technicians start to build the server at 11 am, and one technician per hour is added beginning at 5 pm, at what time will the server be completed? a)\u00a06.40 pm<\/p>\n b)\u00a07 pm<\/p>\n c)\u00a07.20 pm<\/p>\n d)\u00a08 pm<\/p>\n Question 7:\u00a0<\/b>Three small pumps and a large pump are filling a tank. Each of the three small pump works at 2\/3 the rate of the large pump. If all four pumps work at the same time, they should fill the tank in what fraction of the time that it would have taken the large pump alone? a)\u00a04\/7<\/p>\n b)\u00a01\/3<\/p>\n c)\u00a02\/3<\/p>\n d)\u00a03\/4<\/p>\n Question 8:\u00a0<\/b>A, B and C individually can finish a work in 6, 8 and 15 hours respectively. They started the work together and after completing the work got Rs.94.60 in all. When they divide the money among themselves, A, B and C will respectively get (in Rs.)<\/p>\n a)\u00a044, 33, 17.60<\/p>\n b)\u00a043, 27, 20, 24.40<\/p>\n c)\u00a045, 30, 19.60<\/p>\n d)\u00a042, 28, 24.60<\/p>\n Instructions<\/b>The Weirdo Holiday Resort follows a particular system of holidays for its employees. People are given holidays on the days where the first letter of the day of the week is the same as the first letter of their names. All employees work at the same rate.<\/p>\n Question 9:\u00a0<\/b>Raja starts working on February 25(Sunday), 1996, and finishes the job on March 2, 1996. How much time would T and J take to finish the same job if both start on the same day as Raja?<\/p>\n a)\u00a04 days<\/p>\n b)\u00a05 days<\/p>\n c)\u00a0Either a or b<\/p>\n d)\u00a0Cannot be determined<\/p>\n Question 10:\u00a0<\/b>A contract is to be completed in 56 days and 104 men are set to work. Each working 8 hours a day, after 30 days, 2\/5th of the work is finished. How many additional men may be employed so that work may be completed on time, each man now working 9 hours per day?<\/p>\n a)\u00a056 men<\/p>\n b)\u00a065 men<\/p>\n c)\u00a046 men<\/p>\n d)\u00a0None of the above<\/p>\n Top 500+ Free Questions for IIFT<\/a><\/p>\n IIFT Previous year question\u00a0 answer PDF<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n A takes 4 days to complete the work. In order to measure, let the total work be of 64 units. Hence, the speed of working of each of the four persons is given below.<\/p>\n A – 16 units\/hr From the given options, we need to find two pairs in such a way that their speeds are in the ratio 3:2. Note that A+D=18 while B+C=12 and the ratio is 3:2<\/p>\n Hence, the first pair is A and D and the second pair is B and C<\/p>\n 2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the time taken working together be t. From the options, if time = 40 min, that is, t = 2\/3 3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n In a normal watch, the minute hand crosses the hour’s hand after every 1 hour 5 minutes and 27 seconds. In this watch, the time taken for this to happen is 3 hours 18 minutes and 15 seconds. 4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n X leaves Frankfurt at 6 PM and reaches Boston at 10 AM, which is 6 AM in Frankfurt => 12-hour journey<\/p>\n Leaves Boston at 12 PM ad reaches India at 1 AM, which is 11 PM\u00a0in Boston => 11-hour journey<\/p>\n => Total time = 12 + 2 + 11\u00a0= 25\u00a0hours<\/p>\n Return journey is 1 hour lesser => 25 – 1 = 24 hours.<\/p>\n 5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n The first wheel completes a revolution in $\\frac{60}{60}=1$ second The three wheels touch the ground simultaneously at time which are multiples of the above three times. So, the correct option is option (c)<\/p>\n Quant Formula For IIFT PDF<\/a><\/p>\n IIFT Free Mock Test<\/a><\/p>\n 6)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the work done by each technician in one hour be 1 unit. 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the work done by the big pump in one hour be 3 units. 8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Money will be distributed in the ratio of work done in an hour. 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Raja takes 7 days to complete the job.<\/p>\n Feb 25, 1996 is a Sunday.<\/p>\n If T and J start working on Sunday, they can complete the work by wednesday because T would have worked for 3 days and J would worked for 4 days, thereby matching the number of days worked by Raja.<\/p>\n Hence, they can complete the job in 4 days.<\/p>\n 10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let ‘W’ be the amount of work. It is given that,<\/p>\n $\\dfrac{2}{5}*W = 104*8*30$ … (1)<\/p>\n Let ‘X’ be the number of\u00a0additional men required to finish the work on time.<\/p>\n $W – \\dfrac{2}{5}*W = (104+x)*9*(56-30)$ … (2)<\/p>\n By equation (1) and (2) we can say that,<\/p>\n $\\dfrac{2}{3} = \\dfrac{104*8*30}{(104+x)*9*(56-30)}$<\/p>\n $\\Rightarrow$\u00a0$(104+x)*9*26 = 12*104*30$<\/p>\n $\\Rightarrow$\u00a0$(104+x)=160$<\/p>\n $\\Rightarrow$\u00a0$x=56$.<\/p>\n Hence, option A is the correct answer.<\/p>\n
\nThree friends \u2014 Asit, Arnold and Afzal \u2014 work together to get all of these chores done. The time it takes them to do the work together is 6 hr less than Asit would have taken working alone, 1 hr less than Arnold would have taken alone, and half the time Afzal would have taken working alone. How long did it take them to do these chores working together?<\/p>\n
\n[CAT 2002]<\/p>\n
\n[CAT 2002]<\/p>\n
\nSo, B takes 8 days to complete the same work.
\nC takes 16 days to complete the work.
\nD takes 32 days to complete the same work.<\/p>\n
\nB – 8 units\/hr
\nC – 4 units\/hr
\nD – 2 units\/hr<\/p>\n
\nTime taken by Arnold = t+1
\nTime taken by Asit = t+6
\nTime taken by Afzal = 2t
\n1\/(t+1) + 1\/(t+6) + 1\/2t = 1\/t<\/p>\n
\n3\/5 + 3\/20 + 3\/4 = (12+3+15)\/20 = 30\/20 = 3\/2 = 1\/t<\/p>\n
\nSo, the third time the hour’s hand crosses the minute’s hand is after 3 hours 16 minutes and 21 seconds.<\/p>\n
\nHence, the watch loses 1 minute and 54 seconds after every 3 hours 18 minutes and 15 seconds.
\n18 minutes and 15 seconds = 1095 seconds = 1095\/3600 $\\approx$ .304 hours.
\n=> 3 hours 18 minutes and 15 seconds = 3.304 hours
\nSo, time lost in a day is $1\\frac{54}{60}*\\frac{24}{3.304} = \\frac{114}{60}*\\frac{24}{3.304} \\approx 13.8$
\nSo, the time lost by the watch in a day is approximately equal to 13 minutes and 48 seconds.<\/p>\n
\nThe second wheel completes a revolution in $\\frac{60}{36}=1\\frac{2}{3}$ second
\nThe third wheel completes a revolution in $\\frac{60}{24}=2\\frac{1}{2}$ second<\/p>\n
\nHence, the required number is $LCM(1,\\frac{5}{3},\\frac{5}{2}) = 5$ seconds.<\/p>\n
\nTherefore, total work to be done = 60 units.
\nFrom 11 AM to 5 PM, work done = 6*6 = 36 units.
\nWork remaining = 60 – 36 = 24 units.
\nWork done in the next 3 hours = 7 units + 8 units + 9 units = 24 units.
\nTherefore, the work gets done by 8 PM.<\/p>\n
\nTherefore, work done by each of the small pumps in one hour = 2 units.
\nLet the total work to be done in filling the tank be 9 units.
\nTherefore, time taken by the big pump if it operates alone = 9\/3 = 3 hours.
\nIf all the pumps operate together, the work done in one hour = 3 + 2*3 = 9 units.
\nTogether, all of them can fill the tank in 1 hour.
\nRequired ratio = 1\/3<\/p>\n
\ni.e. $\\frac{1}{6} : \\frac{1}{8} : \\frac{1}{15}$
\nor 20:15:8
\nHence part of A will be = $\\frac{20}{43} \\times 94.6 = 44$
\npart of B will be = $\\frac{15}{43} \\times 94.6 = 33$
\npart of C will be = $\\frac{8}{43} \\times 94.6 = 17.60$<\/p>\n