{"id":33512,"date":"2019-08-13T16:04:01","date_gmt":"2019-08-13T10:34:01","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=33512"},"modified":"2019-09-09T16:28:37","modified_gmt":"2019-09-09T10:58:37","slug":"boat-and-stream-questions-for-ibps-po","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/boat-and-stream-questions-for-ibps-po\/","title":{"rendered":"Boat and Stream Questions For IBPS PO"},"content":{"rendered":"

Boat and Stream Questions For IBPS PO<\/span><\/h1>\n
Download Boat and Stream Questions For IBPS PO PDF. Practice Boat and Stream Questions with Solutions for Banking exams based on asked questions in previous papers.<\/div>\n
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Question 1:\u00a0<\/b>A boat takes 12 hours to reach point B from point A. It takes 6 hours to reach point A from point B. The river flows from A to B. How much time will it take to travel from A to B if the river remains still?<\/p>\n

a)\u00a09 hours<\/p>\n

b)\u00a010 hours<\/p>\n

c)\u00a08 hours<\/p>\n

d)\u00a07.5 hours<\/p>\n

e)\u00a010.5 hours<\/p>\n

Question 2:\u00a0<\/b>A boat develops a leak 18 km from the shore. The ship is still able to move at 12 km\/hr and can move only for 25 minutes. A rescue boat which takes 5 minutes to evacuate the crew of the boat leaves the shore at the same time. What should be the minimum speed of the rescue boat to successfully evacuate the crew from the boat in time?<\/p>\n

a)\u00a036 kmph<\/p>\n

b)\u00a044 kmph<\/p>\n

c)\u00a038 kmph<\/p>\n

d)\u00a042 kmph<\/p>\n

e)\u00a040 kmph<\/p>\n

Question 3:\u00a0<\/b>There is a river which flows from west to east at a speed of 5 m\/s. Arjun, is standing at one bank of the river. He decides to use his motorboat to reach the other bank of the river. His boat travels at a constant speed of 10 m\/s. He wants to travel in such a manner that he reaches a point on the other side which is perpendicularly opposite to his starting point. Find the time he takes to reach other side of the bank if the width of the river is 60 meters.<\/p>\n

a)\u00a0$5\\sqrt{2}$ seconds<\/p>\n

b)\u00a0$6$ seconds<\/p>\n

c)\u00a0$12$ seconds<\/p>\n

d)\u00a0$4\\sqrt{3}$ seconds<\/p>\n

e)\u00a0$6\\sqrt{2}$ seconds<\/p>\n

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Question 4:\u00a0<\/b>A boat takes 2 hours to travel from point A to B in still water .To find out it\u2019s speed up-stream ,which of the following information is needed.
\ni. Distance between point A and B
\nIi.Time taken to travel down stream from B to A
\niii. Speed of the stream of the water
\niv. Effective speed of Boat while traveling Downstream from B to A<\/p>\n

a)\u00a0All are required<\/p>\n

b)\u00a0Even these we cannot found the answer<\/p>\n

c)\u00a0Only i,iii, and either ii or iv<\/p>\n

d)\u00a0Only i and iii<\/p>\n

e)\u00a0None of these<\/p>\n

Question 5:\u00a0<\/b>The speed of the boat in still water is 24 kmph and the speed of the stream is 41cm\/h. The time taken by the boat to travel from A to B downstream is 36 minutes less than the time taken by the same boat to travel from B to\u2019C upstream. If the distance between A and B is 4 km more than the distance between B and C, what is the distance between A and B?<\/p>\n

a)\u00a0112 km<\/p>\n

b)\u00a01401cm<\/p>\n

c)\u00a056 km<\/p>\n

d)\u00a0841cm<\/p>\n

e)\u00a0281cm<\/p>\n

Question 6:\u00a0<\/b>A man takes 2.2 times as long to row a distance upstream as to row the same distance downstream. If he can row 55 km downstream in 2 hours 30 minutes, what is the speed of the boat in still water? (in km\/h)<\/p>\n

a)\u00a040<\/p>\n

b)\u00a08<\/p>\n

c)\u00a016<\/p>\n

d)\u00a024<\/p>\n

e)\u00a032<\/p>\n

IBPS PO Free Mock Test<\/a><\/p>\n

Question 7:\u00a0<\/b>A boat takes a total time of twelve hours to travel 105 kms upstream and the same distance downstream. The speed of the boat in still water is six times of the speed of the current. What is the speed of the boat in still water? (in km\/hr)<\/p>\n

a)\u00a012<\/p>\n

b)\u00a030<\/p>\n

c)\u00a018<\/p>\n

d)\u00a024<\/p>\n

e)\u00a036<\/p>\n

Question 8:\u00a0<\/b>A boat takes a total time of eight hours to travel 63 kms upstream and the same distance downstream. The speed of the current is ${1 \\over 8}$th of the speed of the boat in still water. What is the speed of the boat in still water? (in km\/hr)<\/p>\n

a)\u00a032<\/p>\n

b)\u00a024<\/p>\n

c)\u00a016<\/p>\n

d)\u00a08<\/p>\n

e)\u00a038<\/p>\n

Question 9:\u00a0<\/b>A boat takes six hours to travel a certain distance downstream and five hours to travel a certain distance upstream. The distance travelled upstream is half of the travelled downstream. If the speed of the current is 4 km\/hr, what is the speed of the boat in still water? (in km\/hr)<\/p>\n

a)\u00a016<\/p>\n

b)\u00a020<\/p>\n

c)\u00a024<\/p>\n

d)\u00a010<\/p>\n

e)\u00a018<\/p>\n

IBPS PO Previous Papers (Download Pdf)<\/a><\/p>\n

Question 10:\u00a0<\/b>A boatman can row a boat downstream at 13 kmph and upstream at 9 kmph. What will be the speed of boat in still water ? (in kmph).<\/p>\n

a)\u00a012<\/p>\n

b)\u00a010.5<\/p>\n

c)\u00a011<\/p>\n

d)\u00a010<\/p>\n

e)\u00a011.5<\/p>\n

Question 11:\u00a0<\/b>Mukesh swims in a flowing river and takes total 32 minutes to swim from point 1 to point 2 and then again back to point 1. If the distance between point 1 and point 2 is 240 m and Mukesh covers 360 m upstream distance in 30 minutes. What is the speed of the river stream?<\/p>\n

a)\u00a05.5 m\/min<\/p>\n

b)\u00a03.5 m\/min<\/p>\n

c)\u00a03 m\/min<\/p>\n

d)\u00a05 m\/min<\/p>\n

e)\u00a04 m\/min<\/p>\n

Question 12:\u00a0<\/b>Sumit rows downstream from Allahabad to Varanasi in 10 hours. The distance between Allahabad and Varanasi is 180 km and Sumit\u2019s speed in still water is eight times the speed of the stream. Sumit decides to go back to Allahabad along the same route. However, due to strong winds the speed of the stream has increased by 100 percent. If Sumit rows at his earlier speed, then how much time will it take for him to reach Allahabad?<\/p>\n

a)\u00a012 hours<\/p>\n

b)\u00a020 hours<\/p>\n

c)\u00a018 hours<\/p>\n

d)\u00a015 hours<\/p>\n

e)\u00a024 hours<\/p>\n

IBPS PO Important Questions PDF<\/a><\/p>\n

Question 13:\u00a0<\/b>A boat takes 2 hours to travel from point A to B in still water .To find out it\u2019s speed up-stream ,which of the following information is needed.
\ni. Distance between point A and B
\nIi.Time taken to travel down stream from B to A
\niii. Speed of the stream of the water
\niv. Effective speed of Boat while traveling Downstream from B to A<\/p>\n

a)\u00a0All are required<\/p>\n

b)\u00a0Even these we cannot found the answer<\/p>\n

c)\u00a0Only i,iii, and either ii or iv<\/p>\n

d)\u00a0Only i and iii<\/p>\n

e)\u00a0None of these<\/p>\n

Question 14:\u00a0<\/b>The speed of the boat in still water is 24 kmph and the speed of the stream is 41cm\/h. The time taken by the boat to travel from A to B downstream is 36 minutes less than the time taken by the same boat to travel from B to\u2019C upstream. If the distance between A and B is 4 km more than the distance between B and C, what is the distance between A and B?<\/p>\n

a)\u00a0112 km<\/p>\n

b)\u00a01401cm<\/p>\n

c)\u00a056 km<\/p>\n

d)\u00a0841cm<\/p>\n

e)\u00a0281cm<\/p>\n

Question 15:\u00a0<\/b>A man takes 2.2 times as long to row a distance upstream as to row the same distance downstream. If he can row 55 km downstream in 2 hours 30 minutes, what is the speed of the boat in still water? (in km\/h)<\/p>\n

a)\u00a040<\/p>\n

b)\u00a08<\/p>\n

c)\u00a016<\/p>\n

d)\u00a024<\/p>\n

e)\u00a032<\/p>\n

Question 16:\u00a0<\/b>A boat takes a total time of twelve hours to travel 105 kms upstream and the same distance downstream. The speed of the boat in still water is six times of the speed of the current. What is the speed of the boat in still water? (in km\/hr)<\/p>\n

a)\u00a012<\/p>\n

b)\u00a030<\/p>\n

c)\u00a018<\/p>\n

d)\u00a024<\/p>\n

e)\u00a036<\/p>\n

Question 17:\u00a0<\/b>A boat takes a total time of eight hours to travel 63 kms upstream and the same distance downstream. The speed of the current is ${1 \\over 8}$th of the speed of the boat in still water. What is the speed of the boat in still water? (in km\/hr)<\/p>\n

a)\u00a032<\/p>\n

b)\u00a024<\/p>\n

c)\u00a016<\/p>\n

d)\u00a08<\/p>\n

e)\u00a038<\/p>\n

Question 18:\u00a0<\/b>A boat takes six hours to travel a certain distance downstream and five hours to travel a certain distance upstream. The distance travelled upstream is half of the travelled downstream. If the speed of the current is 4 km\/hr, what is the speed of the boat in still water? (in km\/hr)<\/p>\n

a)\u00a016<\/p>\n

b)\u00a020<\/p>\n

c)\u00a024<\/p>\n

d)\u00a010<\/p>\n

e)\u00a018<\/p>\n

Question 19:\u00a0<\/b>A boatman can row a boat downstream at 13 kmph and upstream at 9 kmph. What will be the speed of boat in still water ? (in kmph).<\/p>\n

a)\u00a012<\/p>\n

b)\u00a010.5<\/p>\n

c)\u00a011<\/p>\n

d)\u00a010<\/p>\n

e)\u00a011.5<\/p>\n

Question 20:\u00a0<\/b>A boat goes downstream at the rate of 9 kmph and upstream at the rate of 6 kmph. Find the speed of current.<\/p>\n

a)\u00a01.5 kmph<\/p>\n

b)\u00a02 kmph<\/p>\n

c)\u00a07.5 kmph<\/p>\n

d)\u00a04.5 kmph<\/p>\n

e)\u00a0None of these<\/p>\n

Free Banking Study Material (15,000 Solved Questions<\/a><\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the speed of the boat be \u2018b\u2019 and the speed of the stream be \u2018s\u2019.
\nLet the distance between A and B be \u2018D\u2019.<\/p>\n

We know that D\/(b-s) = 12.
\nD = 12b – 12s ——–(1).<\/p>\n

We also know that D\/(b+s) = 6.
\nD = 6b + 6s ———-(2)<\/p>\n

Equating (1) and (2), we get,
\n12b – 12s = 6b + 6s
\n=> 6b = 18s
\nb = 3s.
\nD = 12*3s – 12*s
\nD = 24s.
\nTime taken to travel from A to B in still water = D\/b = 24s\/3s = 8 hours.
\nTherefore, option C is the right answer.<\/p>\n

2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Distance between Boat and shore = 18 km
\nThe rescue boat must reach the leaking boat in 20 minutes as 5 minutes is needed for evacuation.
\nLet the relative velocity of the 2 boats be \u2018v\u2019
\nSo, v = $\\frac{18}{20}$ km per min = 18*60\/20 kmph = 54 kmph
\nSo minimum speed of the rescue boat = 54 – 12 = 42 kmph
\nHence, option D is correct option.<\/p>\n

3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Since he wants to reach a point which is perpendicularly opposite, he should ensure that the horizontal displacement is zero.<\/p>\n

Hence, his horizontal component of the speed should be 5 m\/s east to west.<\/p>\n

Let’s represent it in a diagram,<\/p>\n

<\/figure>\n

His speed in the horizontal direction = $10 \\sin \\theta$<\/p>\n

His speed in the vertical direction = $10 \\cos \\theta$<\/p>\n

$10 \\sin \\theta = 5$<\/p>\n

Hence, $\\theta$ = 30\u00b0<\/p>\n

His speed in vertical direction = $10 \\cos 30$ = $5 \\sqrt{3}$<\/p>\n

Time taken to cover a vertical distance of 60m = $\\frac{60}{5\\sqrt{3}}$ = $4\\sqrt{3}$ seconds.<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Time taken by boat\u00a0to travel from point A to B in still water\u00a0= 2 hours<\/p>\n

To find the upstream speed, we definitely need the speed of stream, thus statement (iii) is mandatory.<\/p>\n

Also, the distance between points A and B or the speed of boat in still water is needed.<\/p>\n

Thus, statements (i) and (iii) are required to find the upstream speed of the boat.<\/p>\n

=> Ans – (D)<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let speed of boat in still water = $x$ km\/hr<\/p>\n

=> Speed of current = $y$ km\/hr<\/p>\n

Let distance travelled = $d$ km<\/p>\n

Acc. to ques, => $2.2 (\\frac{d}{x + y}) = \\frac{d}{x – y}$<\/p>\n

=> $2.2x – 2.2y = x + y$<\/p>\n

=> $2.2x – x = y + 2.2y$<\/p>\n

=> $3x = 8y$ ————-(i)<\/p>\n

Also, the man takes 2 hrs 30 mins in travelling 55 km downstream.<\/p>\n

=> $\\frac{55}{x + y} = 2 + \\frac{1}{2}$<\/p>\n

=> $\\frac{55}{x + y} = \\frac{5}{2}$<\/p>\n

=> $x + y = 22$<\/p>\n

Multiplying both sides by 8, and using eqn(i), we get\u00a0:<\/p>\n

=> $8x + 3x = 22 \\times 8$<\/p>\n

=> $x = \\frac{22 \\times 8}{11} = 16$ km\/hr<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let speed of current = $x$ km\/hr<\/p>\n

=> Speed of boat in still water = $6x$ km\/hr<\/p>\n

Acc. to ques, => $\\frac{105}{7x} + \\frac{105}{5x} = 12$<\/p>\n

=> $\\frac{15}{x} + \\frac{21}{x} = 12$<\/p>\n

=> $\\frac{36}{x} = 12$<\/p>\n

=> $x = \\frac{36}{12} = 3$<\/p>\n

$\\therefore$ Speed of boat in still water = $6 \\times 3 = 18$ km\/hr<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let speed of current = $x$ km\/hr<\/p>\n

=> Speed of boat in still water = $8x$ km\/hr<\/p>\n

Acc. to ques, => $\\frac{63}{9x} + \\frac{63}{7x} = 8$<\/p>\n

=> $\\frac{7}{x} + \\frac{9}{x} = 8$<\/p>\n

=> $\\frac{16}{x} = 8$<\/p>\n

=> $x = \\frac{16}{8} = 2$<\/p>\n

$\\therefore$ Speed of boat in still water = $8 \\times 2 = 16$ km\/hr<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let speed of boat in still water = $x$ km\/hr<\/p>\n

Let distance travelled downstream = $2d$ km<\/p>\n

=> Distance travelled upstream = $d$ km<\/p>\n

Using, $time = \\frac{distance}{speed}$<\/p>\n

=> $6 = \\frac{2d}{x + 4}$ ———(i)<\/p>\n

and $5 = \\frac{d}{x – 4}$ ———(ii)<\/p>\n

Dividing eqn(i) from (ii), we get :<\/p>\n

=> $\\frac{6}{5} = \\frac{\\frac{2d}{x + 4}}{\\frac{d}{x – 4}}$<\/p>\n

=> $\\frac{6}{5} = \\frac{2 (x – 4)}{x + 4}$<\/p>\n

=> $6x + 24 = 10x – 40$<\/p>\n

=> $10x – 6x = 24 + 40 = 64$<\/p>\n

=> $x = \\frac{64}{4} = 16$ km\/hr<\/p>\n

10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Speed of boat in still water<\/p>\n

= $\\frac{1}{2}$ (downstream + upstream)<\/p>\n

= $\\frac{1}{2} (13 + 9) = \\frac{22}{2}$<\/p>\n

= $11$ kmph<\/p>\n

11)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Let the speed of Mukesh and river be \u2018m\u2019 and \u2018r\u2019 respectively.
\nWe have, $\\frac{240}{m+r} + \\frac{240}{m-r} = 32$
\nAlso, $\\frac{360}{m-r} = 30$
\nm – r = 12 m\/min
\nThus we get, $\\frac{240}{m+r} + \\frac{240}{12} = 32$
\nm + r = 20 m\/min
\nSolving both the equations we get,
\nm = 16 m\/min
\nr = 4 m\/min
\nHence, option E is the right choice.<\/p>\n

12)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

It took total of 10 hours to travel 180 km. Hence the effective speed was 18 km\/hr. Let the speed of the stream was \u2018x\u2019. So the speed of the Sumit will be 8x.
\nHence, 9x = 18
\n=> x = 2
\nNow while coming back the speed of the stream has doubled. So it has become 4. He will now be rowing upstream. So effective speed will be 16 – 4 = 12
\nHence, required time = 180\/12 = 15 hours<\/p>\n

13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Time taken by boat\u00a0to travel from point A to B in still water\u00a0= 2 hours<\/p>\n

To find the upstream speed, we definitely need the speed of stream, thus statement (iii) is mandatory.<\/p>\n

Also, the distance between points A and B or the speed of boat in still water is needed.<\/p>\n

Thus, statements (i) and (iii) are required to find the upstream speed of the boat.<\/p>\n

=> Ans – (D)<\/p>\n

14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let speed of boat in still water = $x$ km\/hr<\/p>\n

=> Speed of current = $y$ km\/hr<\/p>\n

Let distance travelled = $d$ km<\/p>\n

Acc. to ques, => $2.2 (\\frac{d}{x + y}) = \\frac{d}{x – y}$<\/p>\n

=> $2.2x – 2.2y = x + y$<\/p>\n

=> $2.2x – x = y + 2.2y$<\/p>\n

=> $3x = 8y$ ————-(i)<\/p>\n

Also, the man takes 2 hrs 30 mins in travelling 55 km downstream.<\/p>\n

=> $\\frac{55}{x + y} = 2 + \\frac{1}{2}$<\/p>\n

=> $\\frac{55}{x + y} = \\frac{5}{2}$<\/p>\n

=> $x + y = 22$<\/p>\n

Multiplying both sides by 8, and using eqn(i), we get\u00a0:<\/p>\n

=> $8x + 3x = 22 \\times 8$<\/p>\n

=> $x = \\frac{22 \\times 8}{11} = 16$ km\/hr<\/p>\n

16)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let speed of current = $x$ km\/hr<\/p>\n

=> Speed of boat in still water = $6x$ km\/hr<\/p>\n

Acc. to ques, => $\\frac{105}{7x} + \\frac{105}{5x} = 12$<\/p>\n

=> $\\frac{15}{x} + \\frac{21}{x} = 12$<\/p>\n

=> $\\frac{36}{x} = 12$<\/p>\n

=> $x = \\frac{36}{12} = 3$<\/p>\n

$\\therefore$ Speed of boat in still water = $6 \\times 3 = 18$ km\/hr<\/p>\n

17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let speed of current = $x$ km\/hr<\/p>\n

=> Speed of boat in still water = $8x$ km\/hr<\/p>\n

Acc. to ques, => $\\frac{63}{9x} + \\frac{63}{7x} = 8$<\/p>\n

=> $\\frac{7}{x} + \\frac{9}{x} = 8$<\/p>\n

=> $\\frac{16}{x} = 8$<\/p>\n

=> $x = \\frac{16}{8} = 2$<\/p>\n

$\\therefore$ Speed of boat in still water = $8 \\times 2 = 16$ km\/hr<\/p>\n

18)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let speed of boat in still water = $x$ km\/hr<\/p>\n

Let distance travelled downstream = $2d$ km<\/p>\n

=> Distance travelled upstream = $d$ km<\/p>\n

Using, $time = \\frac{distance}{speed}$<\/p>\n

=> $6 = \\frac{2d}{x + 4}$ ———(i)<\/p>\n

and $5 = \\frac{d}{x – 4}$ ———(ii)<\/p>\n

Dividing eqn(i) from (ii), we get :<\/p>\n

=> $\\frac{6}{5} = \\frac{\\frac{2d}{x + 4}}{\\frac{d}{x – 4}}$<\/p>\n

=> $\\frac{6}{5} = \\frac{2 (x – 4)}{x + 4}$<\/p>\n

=> $6x + 24 = 10x – 40$<\/p>\n

=> $10x – 6x = 24 + 40 = 64$<\/p>\n

=> $x = \\frac{64}{4} = 16$ km\/hr<\/p>\n

19)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Speed of boat in still water<\/p>\n

= $\\frac{1}{2}$ (downstream + upstream)<\/p>\n

= $\\frac{1}{2} (13 + 9) = \\frac{22}{2}$<\/p>\n

= $11$ kmph<\/p>\n

20)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Speed of current = $\\frac{1}{2}$ (downstream – upstream)<\/p>\n

= $\\frac{1}{2} (9 – 6)$<\/p>\n

= $\\frac{3}{2} = 1.5$ kmph<\/p>\n

\u00a0<\/b><\/strong>

IBPS PO Previous Papers (Download PDF)<\/a><\/p><\/p>\n

Download IBPS PO Free Preparation App<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Boat and Stream Questions For IBPS PO Download Boat and Stream Questions For IBPS PO PDF. Practice Boat and Stream Questions with Solutions for Banking exams based on asked questions in previous papers. \u00a0 Take a free mock test for IBPS PO Download IBPS PO Previous Papers PDF Question 1:\u00a0A boat takes 12 hours to […]<\/p>\n","protected":false},"author":32,"featured_media":33516,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[8,228],"tags":[2427,48,214],"class_list":{"0":"post-33512","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-banking","8":"category-ibpspo","9":"tag-boats-and-streams","10":"tag-ibps-po","11":"tag-quant"},"better_featured_image":{"id":33516,"alt_text":"boat and stream questions for ibps po","caption":"boat and stream questions for ibps po\n","description":"boat and stream questions for ibps 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