{"id":33346,"date":"2019-08-09T18:20:15","date_gmt":"2019-08-09T12:50:15","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=33346"},"modified":"2019-08-09T18:24:49","modified_gmt":"2019-08-09T12:54:49","slug":"arithmetic-questions-for-ibps-po-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/arithmetic-questions-for-ibps-po-pdf\/","title":{"rendered":"Arithmetic Questions for IBPS PO PDF"},"content":{"rendered":"

Arithmetic Questions for IBPS PO PDF<\/strong><\/span><\/h1>\n
Download Arithmetic\u00a0 Questions For IBPS PO PDF. Practice Arithmetic Questions with Solutions for Banking exams based on asked questions in previous papers.<\/div>\n
<\/div>\n

Download Arithmetic Questions for IBPS PO PDF <\/a><\/p>\n

280 IBPS Mocks for Rs. 299 – Enroll Now<\/a><\/p><\/div>\n

<\/div>\n

Take a free mock test for IBPS PO<\/a><\/p>\n

Download IBPS PO Previous Papers PDF<\/a><\/p>\n

Instructions<\/b><\/p>\n

What approximate value will come at the place of question mark \u2018?\u2019 in the following question?<\/p>\n

Question 1:\u00a0<\/b>?% of $4.97^4 = 8.002*18.75$<\/p>\n

a)\u00a017<\/p>\n

b)\u00a028<\/p>\n

c)\u00a031<\/p>\n

d)\u00a019<\/p>\n

e)\u00a024<\/p>\n

Question 2:\u00a0<\/b>33.333% of (19.99% of (14.48% of 300.97) = ?<\/p>\n

a)\u00a04<\/p>\n

b)\u00a03<\/p>\n

c)\u00a01.9<\/p>\n

d)\u00a02.5<\/p>\n

e)\u00a04.5<\/p>\n

Question 3:\u00a0<\/b>42.98% of 571 – 84.08% of 219.997 = ?<\/p>\n

a)\u00a054.5<\/p>\n

b)\u00a064.2<\/p>\n

c)\u00a060.7<\/p>\n

d)\u00a071.1<\/p>\n

e)\u00a057.8<\/p>\n

IBPS PO Quant Formulas & Shortcuts<\/a><\/p>\n

IBPS PO Previous papers<\/a><\/p>\n

Question 4:\u00a0<\/b>$\\frac{\\sqrt{436+292} + ?^2}{18.001}$ = 54.88<\/p>\n

a)\u00a027<\/p>\n

b)\u00a039<\/p>\n

c)\u00a033<\/p>\n

d)\u00a031<\/p>\n

e)\u00a029<\/p>\n

Question 5:\u00a0<\/b>$16.042^2 + ? = 27.994 * 15.012 + 324.98\/5$<\/p>\n

a)\u00a0193<\/p>\n

b)\u00a0229<\/p>\n

c)\u00a0214<\/p>\n

d)\u00a0246<\/p>\n

e)\u00a0198<\/p>\n

Question 6:\u00a0<\/b>The denominator of a fraction is 2 more than thrice it\u2019s numerator.If the numerator as well as denominator are increased by one,the fraction becomes \u2153 .what was that the original fraction?<\/p>\n

a)\u00a02\/8<\/p>\n

b)\u00a03\/11<\/p>\n

c)\u00a04\/14<\/p>\n

d)\u00a05\/17<\/p>\n

e)\u00a0Cannot be determined<\/p>\n

IBPS PO Free Mock Test<\/a><\/p>\n

Question 7:\u00a0<\/b>What should come in place of the question marks in the following equations?
\n$\\frac{?}{24}=\\frac{72}{\\sqrt{?}}$<\/p>\n

a)\u00a012<\/p>\n

b)\u00a016<\/p>\n

c)\u00a0114<\/p>\n

d)\u00a0144<\/p>\n

e)\u00a0None of these<\/p>\n

Question 8:\u00a0<\/b>A number gets reduced to its one third when 48 is subtracted from it.What is two third of that Number?<\/p>\n

a)\u00a024<\/p>\n

b)\u00a072<\/p>\n

c)\u00a036<\/p>\n

d)\u00a048<\/p>\n

e)\u00a0None of these<\/p>\n

Instructions<\/b><\/p>\n

Find the what approximate value which should be come in place of the following questions .(You are not expected to \u00a0calculate exact value).<\/p>\n

Question 9:\u00a0<\/b>$\\sqrt{45689}=?$<\/p>\n

a)\u00a0180<\/p>\n

b)\u00a0415<\/p>\n

c)\u00a0150<\/p>\n

d)\u00a0214<\/p>\n

e)\u00a0300<\/p>\n

IBPS PO Previous Papers (Download Pdf)<\/a><\/p>\n

Question 10:\u00a0<\/b>$(10008.99)^{2}\/(10009.001)\\times\\sqrt{3589}\\times0.4987=?$<\/p>\n

a)\u00a030,000<\/p>\n

b)\u00a03,00,000<\/p>\n

c)\u00a05,000<\/p>\n

d)\u00a09,000,000<\/p>\n

e)\u00a0None of these<\/p>\n

Question 11:\u00a0<\/b>399.9+ 206 x 11.009=?<\/p>\n

a)\u00a02800<\/p>\n

b)\u00a06666<\/p>\n

c)\u00a04666<\/p>\n

d)\u00a02400<\/p>\n

e)\u00a02688<\/p>\n

Question 12:\u00a0<\/b>$\\frac{2}{5}+\\frac{7}{8}\\times\\frac{17}{19}\\div\\frac{6}{5}=?$<\/p>\n

a)\u00a01<\/p>\n

b)\u00a0$\\frac{1}{2}$<\/p>\n

c)\u00a02$\\frac{1}{2}$<\/p>\n

d)\u00a0$\\frac{3}{4}$<\/p>\n

e)\u00a0$\\frac{9}{11}$<\/p>\n

IBPS PO Important Questions PDF<\/a><\/p>\n

Free Banking Study Material (15,000 Solved Questions<\/a><\/p>\n

Question 13:\u00a0<\/b>The sum of three consecutive number is given .What is difference between first and third number?<\/p>\n

a)\u00a01<\/p>\n

b)\u00a03<\/p>\n

c)\u00a0Either 1 or 2<\/p>\n

d)\u00a02<\/p>\n

e)\u00a0None of these<\/p>\n

Question 14:\u00a0<\/b>What will be come in the place of question mark?
\n$0.001+9.909\\times1.01\\div0.1$<\/p>\n

a)\u00a099.0819<\/p>\n

b)\u00a0100.0819<\/p>\n

c)\u00a0100.091<\/p>\n

d)\u00a0100.0919<\/p>\n

e)\u00a0None of these<\/p>\n

Question 15:\u00a0<\/b>What value should come in the question mark
\n$4275\\div496\\times(21^{2})$=?<\/p>\n

a)\u00a03795<\/p>\n

b)\u00a03800<\/p>\n

c)\u00a03810<\/p>\n

d)\u00a03875<\/p>\n

e)\u00a03995<\/p>\n

Daily Free Banking Online Test<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

?% of $4.97^4 = 8.002*18.75$ can be written as
\n?% of $5^4 = 8*18.75$
\n?% of 625 = 150
\n? = 150*100\/625 = 24
\nHence, option E is the correct choice.<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

33.333% of (19.99% of (14.48% of 300.97) can be approximately written as
\n0.15*301 \/ 3 \/ 5 = 45\/15 = 3 approx.
\nHence, option B is the correct choice.<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

42.98% of 571 – 84.08% of 219.997 can be approximately written as
\n0.43*571 – 0.84*220 = 245.5 – 184.8 = 60.7 approx.
\nHence, option c is the correct choice.<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$\\frac{\\sqrt{436+292} + ?^2}{18.001}$ = 54.88 can be written as
\n$\\frac{\\sqrt{728} + ?^2}{18}$ = 54.88
\n27 + $?^2$ = 987.84
\n$?^2$ = 30.99 = 31 approx.
\nHence, option D is the correct option.<\/p>\n

5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$16.042^2 + ? = 27.994 * 15.012 + 324.98\/5$ can be approximately written as
\n$16^2 + ? = 28 * 15 + 325\/5$
\n256 + ? = 420 + 65
\n? = 229
\nHence, option B is the correct choice.<\/p>\n

6)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Let the numerator = $x$<\/p>\n

=> Denominator = $(3x+2)$<\/p>\n

Fraction = $\\frac{x}{3x+2}$<\/p>\n

If the numerator as well as denominator are increased by one<\/p>\n

=> $\\frac{x+1}{3x+2+1}=\\frac{1}{3}$<\/p>\n

=> $\\frac{x+1}{3x+3}=\\frac{1}{3}$<\/p>\n

=> $3x+3=3x+3$<\/p>\n

It cannot be solved, thus $x$ can take any value and the fraction can be 2\/8 , 3\/11 , 4\/14 ,….<\/p>\n

=> Ans – (E)<\/p>\n

7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Expression\u00a0:\u00a0$\\frac{?}{24}=\\frac{72}{\\sqrt{?}}$<\/p>\n

=> $(?)^{(1+\\frac{1}{2})}= 72 \\times 24$<\/p>\n

=> $(?)^{\\frac{3}{2}} = 1728 = 12^3$<\/p>\n

Multiplying exponents by $(\\frac{2}{3})$ on both sides<\/p>\n

=> $(?)^{(\\frac{3}{2} \\times \\frac{2}{3})}= (12)^{(3 \\times \\frac{2}{3})}$<\/p>\n

=> $(?)=12^2=144$<\/p>\n

=> Ans – (D)<\/p>\n

8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let the number be $x$<\/p>\n

According to ques, => $x-48=\\frac{x}{3}$<\/p>\n

=> $3x-144=x$<\/p>\n

=> $3x-x=2x=144$<\/p>\n

=> $x=\\frac{144}{2}=72$<\/p>\n

$\\therefore$ $(\\frac{2}{3})^{rd}$ of number = $\\frac{2}{3} \\times 72$<\/p>\n

= $2 \\times 24 = 48$<\/p>\n

=> Ans – (D)<\/p>\n

9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Expression\u00a0:\u00a0$\\sqrt{45689}=?$<\/p>\n

= $\\sqrt{7 \\times 61 \\times 107}$<\/p>\n

= $213.75 \\approx 214$<\/p>\n

=> Ans – (D)<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

<\/u>Expression\u00a0:\u00a0$(10008.99)^{2}\/(10009.001)\\times\\sqrt{3589}\\times0.4987=?$<\/p>\n

$\\approx \\frac{(10009)^2}{10009} \\times \\sqrt{3600} \\times 0.5$<\/p>\n

= $1009 \\times 60 \\times 0.5$<\/p>\n

= $1009 \\times 30 = 30270$<\/p>\n

$\\approx 30,000$<\/p>\n

=> Ans – (A)<\/p>\n

11)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Expression\u00a0:\u00a0399.9+ 206 x 11.009=?<\/p>\n

$\\approx 400 + (206 \\times 11)$<\/p>\n

= $400+2266 = 2666$<\/p>\n

$\\approx 2688$<\/p>\n

=> Ans – (E)<\/p>\n

12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Expression\u00a0:\u00a0$\\frac{2}{5}+\\frac{7}{8}\\times\\frac{17}{19}\\div\\frac{6}{5}=?$<\/p>\n

= $\\frac{2}{5} + (\\frac{7}{8} \\times \\frac{17}{19} \\times \\frac{5}{6})$<\/p>\n

= $\\frac{2}{5} + \\frac{595}{912}$<\/p>\n

$\\approx 0.4+0.6=1$<\/p>\n

=> Ans – (A)<\/p>\n

13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let the 3 consecutive numbers be $(x-1),(x),(x+1)$<\/p>\n

Difference between first and third number = $(x+1)-(x-1)$<\/p>\n

= $(x-x)+(1+1)=2$<\/p>\n

=> Ans – (D)<\/p>\n

14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression\u00a0:\u00a0$0.001+9.909\\times1.01\\div0.1$<\/p>\n

= $0.001 + \\frac{9.909 \\times 1.01}{0.1}$<\/p>\n

= $0.001 + (10.00809 \\times 10)$<\/p>\n

= $0.001 + 100.0809 = 100.0819$<\/p>\n

15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression =\u00a0$4275\\div496\\times(21^{2})$=?<\/p>\n

= $\\frac{4275}{496} \\times 441$<\/p>\n

= $8.62 \\times 441 = 3801.42$<\/p>\n

$\\approx 3800$<\/p>\n

\u00a0<\/b><\/strong>

IBPS PO Previous Papers (Download PDF)<\/a><\/p><\/p>\n

Download IBPS PO Free Preparation App<\/a><\/p>\n

We hope this Arithmetic Questions pdf\u00a0 for RRB NTPC Exam will be highly useful for your Preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Arithmetic Questions for IBPS PO PDF Download Arithmetic\u00a0 Questions For IBPS PO PDF. Practice Arithmetic Questions with Solutions for Banking exams based on asked questions in previous papers. Take a free mock test for IBPS PO Download IBPS PO Previous Papers PDF Instructions What approximate value will come at the place of question mark \u2018?\u2019 […]<\/p>\n","protected":false},"author":41,"featured_media":33348,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[169,125,228],"tags":[66,223,2385,1781],"class_list":{"0":"post-33346","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads","8":"category-featured","9":"category-ibpspo","10":"tag-ibps","11":"tag-ibps-exam","12":"tag-ibps-mocks","13":"tag-ibps-po-2019"},"better_featured_image":{"id":33348,"alt_text":"Arithmetic Questions for IBPS PO PDF","caption":"Arithmetic Questions for IBPS PO PDF","description":"Arithmetic Questions for IBPS PO 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