Download Top-20 IBPS RRB PO Approximation Questions PDF. Approximation questions based on asked questions in previous year exam papers very important for the IBPS RRB PO (Officer Scale-I, II & III) exam.<\/p>\n
Download Approximation Questions For IBPS RRB PO Set-2 PDF<\/a><\/p>\n 35 IBPS RRB PO Mocks @ Rs. 149. Enroll Now<\/a><\/p>\n 70 IBPS RRB (PO + Clerk) Mocks @ Rs. 199<\/a><\/p>\n Take a free mock test for IBPS RRB PO<\/a><\/p>\n Download IBPS RRB PO Previous Papers PDF<\/a><\/p>\n Question 1:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following questions? a)\u00a025<\/p>\n b)\u00a035<\/p>\n c)\u00a040<\/p>\n d)\u00a010<\/p>\n Question 2:\u00a0<\/b>What value should come in place of the question mark (?) in the following questions? a)\u00a0180<\/p>\n b)\u00a0140<\/p>\n c)\u00a0165<\/p>\n d)\u00a0155<\/p>\n Question 3:\u00a0<\/b>What approximate value should comein place of the question mark (?) in the following equation? a)\u00a0$\\frac{1}{6}$<\/p>\n b)\u00a0$\\frac{1}{2}$<\/p>\n c)\u00a0$\\frac{1}{9}$<\/p>\n d)\u00a0$\\frac{1}{3}$<\/p>\n Question 4:\u00a0<\/b>What value should come in place of question mark(?) in the following equation? a)\u00a0395<\/p>\n b)\u00a0295<\/p>\n c)\u00a0225<\/p>\n d)\u00a0215<\/p>\n Question 5:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following question ? a)\u00a088<\/p>\n b)\u00a046<\/p>\n c)\u00a0112<\/p>\n d)\u00a056<\/p>\n e)\u00a027<\/p>\n Question 6:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following question? a)\u00a084<\/p>\n b)\u00a048<\/p>\n c)\u00a0118<\/p>\n d)\u00a058<\/p>\n e)\u00a024<\/p>\n Free Mock Test for IBPS RRB PO<\/a><\/p>\n IBPS RRB Clerk Previous Papers<\/a><\/p>\n Question 7:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following questions? a)\u00a049<\/p>\n b)\u00a058<\/p>\n c)\u00a022<\/p>\n d)\u00a066<\/p>\n e)\u00a034<\/p>\n Question 8:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following question? a)\u00a03795<\/p>\n b)\u00a03800<\/p>\n c)\u00a03810<\/p>\n d)\u00a03875<\/p>\n e)\u00a03995<\/p>\n Question 9:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value) a)\u00a03800<\/p>\n b)\u00a04500<\/p>\n c)\u00a02600<\/p>\n d)\u00a03000<\/p>\n e)\u00a04080<\/p>\n Question 10:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following equation ? a)\u00a014<\/p>\n b)\u00a017<\/p>\n c)\u00a012<\/p>\n d)\u00a016<\/p>\n e)\u00a015<\/p>\n Quantitative Aptitude formulas PDF<\/a><\/p>\n 520 Banking Mocks – Just Rs. 499<\/a><\/p>\n Question 11:\u00a0<\/b>What approximate value should come in place of the question mark (?) in the following equation ? a)\u00a010<\/p>\n b)\u00a013<\/p>\n c)\u00a014.5<\/p>\n d)\u00a01.35<\/p>\n e)\u00a012<\/p>\n Question 12:\u00a0<\/b>What approximate value should come in place of question mark(?) in the following equation ? a)\u00a0395<\/p>\n b)\u00a0295<\/p>\n c)\u00a0300<\/p>\n d)\u00a0315<\/p>\n e)\u00a0310<\/p>\n 18000 Free Solved Questions – Banking Study Material<\/a><\/p>\n 35 IBPS RRB PO Mocks @ Rs. 149. Enroll Now<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n By applying BODMAS we have 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n By applying BODMAS we have 3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n ($\\dfrac{1}{9}\\div\\dfrac{1}{9}$\u00a0 of\u00a0 $\\dfrac{1}{3}$) of $\\dfrac{1}{6} = (\\dfrac{1}{9} \\div \\dfrac{1}{27}$)\u00a0 of\u00a0 $\\dfrac{1}{6}$<\/p>\n $= \\dfrac{1}{9} \\times 27$\u00a0 of\u00a0 $\\dfrac{1}{6}$<\/p>\n $= 3 \\times \\dfrac{1}{6} = \\dfrac{1}{2}$<\/p>\n 4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $360\\sqrt?$ + 4500 = 19700 – 9800<\/p>\n $\\Rightarrow\u00a0360\\sqrt? + 4500 = 9900$<\/p>\n $\\Rightarrow\u00a0360\\sqrt? = 5400$<\/p>\n $\\Rightarrow\u00a0\\sqrt? = 15$<\/p>\n $\\Rightarrow ? = 15^2$<\/p>\n $\\Rightarrow ? = 225$<\/p>\n 5)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Expression\u00a0:\u00a0$45.709 \\div 11.342 \\times 6.667 = ?$<\/p>\n = $\\frac{44}{11} \\times 7$<\/p>\n = $4 \\times 7 = 28$<\/p>\n $\\approx$ 27<\/p>\n 6)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Expression\u00a0: $54.786 \\div 10.121 \\times 4.454 = ?$<\/p>\n = $\\frac{55}{10} \\times 4.5$<\/p>\n = $24.75 \\approx 24$<\/p>\n 7)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Expression\u00a0:\u00a0$59.786 \\div 14.444 \\times 8.321 = ?$<\/p>\n = $\\frac{60}{15} \\times 8$<\/p>\n = $4 \\times 8$<\/p>\n = $32 \\approx 34$<\/p>\n 8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Expression\u00a0:\u00a0$4275 \\div 496 \\times (21)^{2} = ?$<\/p>\n = $\\frac{4275 \\times 441}{495}$<\/p>\n = 3808.63 $\\approx$ 3810<\/p>\n 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Since an approximate answer is sufficient, you can rewrite the question as $10000 \\div 50 \\times 5^{2} – 1130$<\/p>\n Following BDMAS rule the result is 3870.<\/p>\n The nearest value is 3800.<\/p>\n Hence Option A is the correct answer.<\/p>\n 10)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the number to replace the question mark be equal to $X$<\/p>\n Hence, $695.95\\div 29.07 \\times X + 40.25 = 399.99$<\/p>\n $399.99 \\approx 400$ and $695.95 \\approx 696$ and $29.07 \\approx 29$<\/p>\n So, the expression looks like $696 \\div 29 \\times X + 40 = 400$ 11)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the number to come in place of the question mark be equal to $X$<\/p>\n So, $29.38 \\times 37.05 \\div X + 7.45 = 100.5$ 12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let x be the value of the unknown number.<\/p>\n x= $\\frac{9876}{24.96}$ + 215.005 – 309.99<\/p>\n = 395.67 – 94.985 $ = \\approx$ 300<\/p>\n
\n$21 + 68 \\div 17 = ? $<\/p>\n
\n$31 \\div 3 \\times 15 = ?$<\/p>\n
\n($\\frac{1}{9}\\div\\frac{1}{9}$ of $\\frac{1}{3}$) of $\\frac{1}{6}=?$<\/p>\n
\n$360\\sqrt?$ + 4500 = 19700 – 9800<\/p>\n
\n$45.709 \\div 11.342 \\times 6.667 = ?$<\/p>\n
\n$54.786 \\div 10.121 \\times 4.454 = ?$<\/p>\n
\n$59.786 \\div 14.444 \\times 8.321 = ?$<\/p>\n
\n$4275 \\div 496 \\times (21)^{2} = ?$<\/p>\n
\n$9980 \\div 49 \\times (4.9)^{2} – 1130 = ?$<\/p>\n
\n$695.95\\div 29.07 \\times ? + 40.25 = 399.99$<\/p>\n
\n$29.38 \\times 37.05 \\div ? + 7.45 = 100.5$<\/p>\n
\n$9876\\div 24.96+215.005-?=309.99$<\/p>\n
\n=$21+(68\\div17)$
\n=21+4
\n=25<\/p>\n
\n$(31\/3)\\times 15$
\n=$31\\times 5$
\n=155<\/p>\n
\nHence, $24 \\times X = 360$ or $X = 15$<\/p>\n
\nOr, $29.38 \\times 37.05 \\div X = 93.05$
\nSo, $X = \\frac{29.38 \\times 37.05}{93.05} = 11.69 \\approx 12$<\/p>\n