Download Top-20 IBPS RRB PO Most Expected Questions PDF. Most Expected questions based on asked questions in previous year exam papers very important for the IBPS RRB PO (Officer Scale-I, II & III) exam<\/p>\n
Download IBPS RRB PO Most Expected Questions PDF<\/a><\/p>\n 35 IBPS RRB PO Mocks @ Rs. 149. Enroll Now<\/a><\/p>\n 70 IBPS RRB (PO + Clerk) Mocks @ Rs. 199<\/a><\/p>\n Take a free mock test for IBPS RRB PO<\/a><\/p>\n Download IBPS RRB PO Previous Papers PDF<\/a><\/p>\n Question 1:\u00a0<\/b>The amount that the banking ombudsman charge when an individual files a complaint regarding any bank to it?<\/p>\n a)\u00a025<\/p>\n b)\u00a050<\/p>\n c)\u00a0100<\/p>\n d)\u00a0No fees involved<\/p>\n e)\u00a0100rs and fees will be reimbursed if the individual wins the case.<\/p>\n Question 2:\u00a0<\/b>\u2018Let\u2019s Make Money Simple\u2019 is the tagline of which bank?<\/p>\n a)\u00a0ICICI Bank<\/p>\n b)\u00a0Kotak Mahindra Bank<\/p>\n c)\u00a0RBL Bank<\/p>\n d)\u00a0Karnataka Bank<\/p>\n e)\u00a0Citi Bank<\/p>\n Question 3:\u00a0<\/b>Which of the following is the first bank to introduce internet banking?<\/p>\n a)\u00a0Punjab National Bank<\/p>\n b)\u00a0ICICI Bank<\/p>\n c)\u00a0Corporation Bank<\/p>\n d)\u00a0State Bank of India<\/p>\n e)\u00a0HDFC Bank<\/p>\n Question 4:\u00a0<\/b>An asset is classified as a substandard asset if it has remained as an NPA (Non Performing Asset) for a period ____________<\/p>\n a)\u00a0less than 12 months<\/p>\n b)\u00a0more than or equal to 12 months<\/p>\n c)\u00a0less than or equal to 12 months<\/p>\n d)\u00a0less than or equal to 6 months<\/p>\n e)\u00a0equal to 6 months<\/p>\n Question 5:\u00a0<\/b>What is the interest rate of Public Provident Fund (PPF) at present (July 2019 to September 2019)?<\/p>\n a)\u00a08.5%<\/p>\n b)\u00a07.8%<\/p>\n c)\u00a08.3%<\/p>\n d)\u00a08.0%<\/p>\n e)\u00a07.9%<\/p>\n Question 6:\u00a0<\/b>A person lent same amount of Rs 10000 at 30% Simple interest for time period of 2 years and 20% Compound interest for time period of 3 years then what is the difference between the interest received ?<\/p>\n a)\u00a01200<\/p>\n b)\u00a01250<\/p>\n c)\u00a01280<\/p>\n d)\u00a01240<\/p>\n e)\u00a01260<\/p>\n Free Mock Test for IBPS RRB PO<\/a><\/p>\n IBPS RRB Clerk Previous Papers<\/a><\/p>\n Question 7:\u00a0<\/b>Compound interest on a certain sum for 3 years is Rs 2880 and for 4 years it is Rs 3456. What is the value of sum taken ?<\/p>\n a)\u00a0Rs 5000<\/p>\n b)\u00a0Rs10000<\/p>\n c)\u00a0Rs 8000<\/p>\n d)\u00a0Rs 9000<\/p>\n e)\u00a0Rs 7000<\/p>\n Instructions<\/b><\/p>\n Calculate the quantity I and the quantity II on the basis of the given information then compare them and answer the following questions accordingly.<\/strong><\/p>\n Question 8:\u00a0<\/b>Quantity 1: Simple interest charged by a bank on a sum of Rs. 1000 at the rate of 22% annum for 2 years. a)\u00a0Quantity 1 > Quantity 2<\/p>\n b)\u00a0Quantity 1 $\\geq$ Quantity 2<\/p>\n c)\u00a0Quantity 1 < Quantity 2<\/p>\n d)\u00a0Quantity 1 $\\leq$ Quantity 2<\/p>\n e)\u00a0Quantity 1 = Quantity 2<\/p>\n Question 9:\u00a0<\/b>The coordinates of the vertices of a right-angled triangle are A (6, 2), B(8, 0) and C (2, -2). The coordinates of the orthocentre of triangle PQR are<\/p>\n a)\u00a0(2, -2)<\/p>\n b)\u00a0(2, 1)<\/p>\n c)\u00a0(6, 2)<\/p>\n d)\u00a0(8, 0)<\/p>\n Question 10:\u00a0<\/b>find the area of an equilateral triangle if the height of the triangle is 24 cm.<\/p>\n a)\u00a0$192\\sqrt{3} cm^2$<\/p>\n b)\u00a0$175\\sqrt{3} cm^2$<\/p>\n c)\u00a0$178\\sqrt{3} cm^2$<\/p>\n d)\u00a0$164\\sqrt{3} cm^2$<\/p>\n Quantitative Aptitude formulas PDF<\/a><\/p>\n 35 IBPS RRB PO Mocks @ Rs. 149. Enroll Now<\/a><\/p>\n Question 11:\u00a0<\/b>If P, Q and R are the three points on a circle such that the angle subtended by the chords PQ and PR at the centre O are 80\u00b0 and 130\u00b0 respectively then LQPR is equal to<\/p>\n a)\u00a080\u00b0<\/p>\n b)\u00a075\u00b0<\/p>\n c)\u00a090\u00b0<\/p>\n d)\u00a070\u00b0<\/p>\n Question 12:\u00a0<\/b>\u200bIf a metallic cone of radius 30 cm and height 40 cm is melted and recast into metallic spheres of radius 10 cm, find the number of spheres formed.<\/p>\n a)\u00a05<\/p>\n b)\u00a09<\/p>\n c)\u00a06<\/p>\n d)\u00a012<\/p>\n Instructions<\/b><\/p>\n Find the missing number (?) in the given series from the options provided.<\/p>\n Question 13:\u00a0<\/b>2, 4, 7, 11, 16, ?<\/p>\n a)\u00a022<\/p>\n b)\u00a021<\/p>\n c)\u00a020<\/p>\n d)\u00a023<\/p>\n e)\u00a024<\/p>\n Question 14:\u00a0<\/b>9, 27, 45, 63, ?<\/p>\n a)\u00a079<\/p>\n b)\u00a080<\/p>\n c)\u00a081<\/p>\n d)\u00a082<\/p>\n e)\u00a083<\/p>\n Question 15:\u00a0<\/b>3, 8, 15, 24, 35, ?<\/p>\n a)\u00a063<\/p>\n b)\u00a049<\/p>\n c)\u00a080<\/p>\n d)\u00a048<\/p>\n e)\u00a056<\/p>\n Question 16:\u00a0<\/b>If two sides of a triangle are 6 cm and 4 cm then how many integral values are possible for the third side ?<\/p>\n a)\u00a06<\/p>\n b)\u00a07<\/p>\n c)\u00a08<\/p>\n d)\u00a09<\/p>\n e)\u00a010<\/p>\n Question 17:\u00a0<\/b>A person standing on the top of a building of height 20m observes the angle of elevation of the top of other building as 60 degrees and angle of depression of the bottom the same building as 30 degrees. What is the difference between the heights of two building ?<\/p>\n a)\u00a010m<\/p>\n b)\u00a040m<\/p>\n c)\u00a050m<\/p>\n d)\u00a030m<\/p>\n e)\u00a060m<\/p>\n Question 18:\u00a0<\/b>A cuboid has its length, breadth and height in the ratio of 4:5:6 If the length is decreased b 25% ,breadth is increased by 20% and height is increased by 33.33 % then what is the percentage change in total surface area of the cuboid ?<\/p>\n a)\u00a021.1%<\/p>\n b)\u00a023.8%<\/p>\n c)\u00a022.3%<\/p>\n d)\u00a021.6%<\/p>\n e)\u00a022.6%<\/p>\n Question 19:\u00a0<\/b>Three sides of a triangle are 12 cm,14 cm and 16 cm. What is the value of inradius of the triangle ?<\/p>\n a)\u00a0$\\frac{32}{\\sqrt{15}}$<\/p>\n b)\u00a0$\\frac{12}{\\sqrt{15}}$<\/p>\n c)\u00a0$\\frac{8}{\\sqrt{15}}$<\/p>\n d)\u00a0$\\frac{24}{\\sqrt{15}}$<\/p>\n e)\u00a0$\\frac{16}{\\sqrt{15}}$<\/p>\n Question 20:\u00a0<\/b>Area of a rectangle is 9600 square meters. Length of the rectangle is twice the length of the diagonal of a square having area as 1800 square meters.If a lady travels whole perimeter of the rectangle in 8 seconds then what is the speed of the lady ?<\/p>\n a)\u00a020 m\/s<\/p>\n b)\u00a030 m\/s<\/p>\n c)\u00a050 m\/s<\/p>\n d)\u00a025 m\/s<\/p>\n e)\u00a045 m\/s<\/p>\n 18000 Free Solved Questions – Banking Study Material<\/a><\/p>\n 35 IBPS RRB PO Mocks @ Rs. 149. Enroll Now<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n 2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n 3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n 4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n 5)\u00a0Answer\u00a0(E)<\/strong><\/p>\n 6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Given P=10000 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let R%=r 8)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Simple interest paid to bank = 1000*.22*2 = Rs. 440 9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n 10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Given, 11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Centre of the circle is O<\/p>\n 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Given, a metallic cone of radius 30 cm and height 40 cm 13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n $\\Rightarrow$ $T_{2} – T _{1} = 4 – 2 = 2$ 14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n $\\Rightarrow$ $T_{1} = 9 = 5^2 – 4^2$ 15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n $\\Rightarrow$ $T_{1} = 3 = 2^2 – 1$ 16)\u00a0Answer\u00a0(B)<\/strong><\/p>\n For a triangle to form the sum of two sides should be greater than the third side and the difference of two sides should be less than the third side 17)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let the height of other building be \u2018h\u2019 18)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the length,breadth and height of the cuboid be 4x,5x and 6x respectively 19)\u00a0Answer\u00a0(A)<\/strong><\/p>\n We know that Area of a triangle=abc\/(4R) 20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Given that l*b=9600 sq mtrs
\nQuantity 2: Compound interest charged by another bank on a sum of Rs. 1000 at the rate of 20% annum for 2 years compounded annually.<\/p>\n
\nR=30%
\nT=2 years
\nI=(10000*2*30)\/100
\n=Rs 6000
\nR%=r
\nCI=$P(1+(r\/100))^{3}-P$
\nCI=10000(216\/125) -10000
\nCI=10000(91\/125)
\nCI=7280
\nDifference=7280-6000
\n=Rs 1280<\/p>\n
\nGiven $ Pr(1+r)^{2}$=2880
\n$ Pr(1+r)^{3}$=3456
\nDividing both the equations we have
\n1\/(1+r)=5\/6
\n6=5+5r
\nr=1\/5
\nR=(1\/5)*100
\nR=20%
\nTherefore $P(1\/5)(1+(1\/5))^{2}$=2880
\nP(36\/125)=2880
\nP=2880*125\/36
\nP=Rs 10000<\/p>\n
\nCompound interest paid to bank = $1000(1 + \\dfrac{20}{100})^2 – 1000$ = Rs. 440
\nHence, we can say that Quantity 1 = Quantity 2. Option E is the correct answer.<\/p>\n
\nAD = 15 cm and ABC is an equilateral triangle<\/p>\n
\nVolume of metallic cone = $\\frac{1}{3} \\pi r^2 h$<\/p>\n
\n$\\Rightarrow$ $T_{3} – T _{2} = 7 – 4 = 3$
\n$\\Rightarrow$ $T_{4} – T _{3} = 11 – 7 = 4$
\n$\\Rightarrow$ $T_{5} – T _{4} = 16 – 11 = 5$
\nHere we can see the pattern that difference between consecutive terms are in A.P. and it is increasing by 1. Therefore,
\n$\\Rightarrow$ $T_{6} = 6 + T _{5} = 6+16 = 22$
\nHence, option A is the correct answer.<\/p>\n
\n$\\Rightarrow$ $T_{2} = 27 = 6^2 – 3^2$
\n$\\Rightarrow$ $T_{3} = 45 = 7^2 – 2^2$
\n$\\Rightarrow$ $T_{4} = 63 = 8^2 – 1^2$
\nHence, we can say that $\\Rightarrow$ $T_{n} = (n+4)^2 – (5-n)^2$
\n$\\Rightarrow$ $T_{5} = (5+4)^2 – (5-4)^2 = 81$
\nHence, option C is the correct answer.<\/p>\n
\n$\\Rightarrow$ $T_{2} = 8 = 3^2 – 1$
\n$\\Rightarrow$ $T_{3} = 15 = 4^2 – 1$
\n$\\Rightarrow$ $T_{4} = 24 = 5^2 – 1$
\n$\\Rightarrow$ $T_{5} = 35 = 6^2 – 1$
\nHence, we can say that $\\Rightarrow$ $T_{n} = (n+1)^2 – 1$
\n$\\Rightarrow$ $T_{6} = (6+1)^2 – 1 = 48$
\nHence, option D is the correct answer.<\/p>\n
\nTherefore (6+4)>s>(6-4)
\n10>s>2
\nSo all the values between 2 and 10 are possible as third side
\ni.e 3,4,5,6,7,8 and 9
\nTherefore 7 values are possible<\/p>\n
\nDistance between the buildings be \u2018d\u2019
\nFrom the figure we have $\\tan60$=d\/20
\nd=$\\sqrt{3}20$
\nFrom the figure we have in the upper triangle $\\tan60$=x\/d
\n$\\sqrt{3}$=x\/$\\sqrt{3}20$
\nx=60 cm
\nTherefore h=60+20
\nh=80 cm
\nDifference=80-20
\n=60 cm<\/p>\n
\nTotal surface area of the cube=2lb+2bh+2lh
\n=$2*(20*x^{2})+2*(24*x^{2})+2*(30*x^{2})$
\n=$(40+48+60)x^{2}$
\n=$148x^{2}$
\nNew length of cuboid=4x*3\/4
\n=3x
\nNew breadth of cuboid=5x*(120\/100)
\n=6x
\nNew height of cuboid=6x*(4\/3)
\n=8x
\nTotal surface area of cuboid with new dimensions=$2*(18*x^{2})+2*(48*x^{2})+2*(24*x^{2})$
\n=$(36+96+48)x^{2}$
\n=$180x^{2}$
\nPercentage change in the total surface area=((180-148)\/148)*100
\n=800\/37
\n=21.6%<\/p>\n
\nS=(a+b+c)\/2
\n=(12+14+16)\/2
\n=42\/2
\n=21
\nArea of a triangle=$\\sqrt{s(s-a)(s-b)(s-c)}$
\n=$\\sqrt{21(21-12)(21-14)(21-16)}$
\n=$\\sqrt{21(9)(7)(5)}$
\n=$21\\sqrt{15}$
\nR=abc\/(4*area)
\nR=(12*14*16)\/(4*$21\\sqrt{15}$)
\nR=$\\frac{32}{\\sqrt{15}}$<\/p>\n
\nArea of a square $s^{2}$=1800
\n$s^{2}$=30*30*2
\ns=30$\\sqrt{2}$
\nGiven that l=2d
\nd=$\\sqrt{2}$s
\nl=2d
\nl=2$\\sqrt{2}$s
\nl=$2\\sqrt{2}*30\\sqrt{2}$
\nl=120 meters
\nAslo 120*b=9600
\nl=80 meters
\nPerimeter of the rectangle=2(l+b)
\n=2*(120+80)
\n=2*200
\n=400 meters
\nGiven time=8 sec
\nSpeed=400\/8
\n=50 m\/s<\/p>\n