35 IBPS RRB Clerk Mocks @ Rs. 149<\/a><\/p>\n 70 IBPS RRB (PO + Clerk) Mocks @ Rs. 199<\/a><\/p>\n Take a free mock test for IBPS RRB Clerk<\/a><\/p>\n Download IBPS RRB Clerk Previous Papers PDF<\/a><\/p>\n Question 1:\u00a0<\/b>In a constituency there are 3 contestants A,B, C and a total of 2,00,000 votes are present in which the winning candidate \u2018A\u2019 scored the same number of votes equal to the other two candidates if 10% of votes are invalid and the ratio of votes received by C and B is 1:2. Total number of votes received by \u2018B\u2019 is ?<\/p>\n a)\u00a010000<\/p>\n b)\u00a015000<\/p>\n c)\u00a045000<\/p>\n d)\u00a060000<\/p>\n e)\u00a030000<\/p>\n Question 2:\u00a0<\/b>A person eats 60% of the apples he brought and throws away 15% of the apples and after a week he again eats 50% of the remaining apples and throws away 20% of the apples and the next week he eats the remaining apples.If the total apples thrown away is 500 then what is the number of apples that he had eaten ?<\/p>\n a)\u00a01600<\/p>\n b)\u00a01800<\/p>\n c)\u00a02000<\/p>\n d)\u00a01500<\/p>\n e)\u00a01700<\/p>\n Question 3:\u00a0<\/b>A pattern of numbers is in the form of 2,3,1,4,0,5,-1,6,-2,….. What is the average of first 20 terms of the given pattern ?<\/p>\n a)\u00a00<\/p>\n b)\u00a00.75<\/p>\n c)\u00a02.50<\/p>\n d)\u00a01.50<\/p>\n e)\u00a03<\/p>\n Instructions<\/b><\/p>\n Directions (16 – 20): Study the table below and answer the questions that follow:<\/p>\n Note: Some values are missing. You need to calculate them according to the given data.<\/p>\n Question 4:\u00a0<\/b>What is the average time taken(in seconds) by all the trains to cross the man if the time taken by B and D to cross the platforms is 5 seconds and 9 seconds respectively?<\/p>\n a)\u00a03<\/p>\n b)\u00a04<\/p>\n c)\u00a02<\/p>\n d)\u00a05<\/p>\n e)\u00a0None of these<\/p>\n Question 5:\u00a0<\/b>What is the time taken by Train A to cross the platform if the length of the platform which A crosses is 25 metres more than the length of the platform which E crosses?<\/p>\n a)\u00a09 seconds<\/p>\n b)\u00a012 seconds<\/p>\n c)\u00a011 seconds<\/p>\n d)\u00a013 seconds<\/p>\n e)\u00a0None of these<\/p>\n Question 6:\u00a0<\/b>What is the difference between the time taken by the trains B and D to cross the man if the time taken by B and D to cross their platforms are 5 seconds and 9 seconds respectively?<\/p>\n a)\u00a03 seconds<\/p>\n b)\u00a02 seconds<\/p>\n c)\u00a01 second<\/p>\n d)\u00a04 seconds<\/p>\n e)\u00a0None of these<\/p>\n Question 7:\u00a0<\/b>A man has 2 sons and the ages of them are 12 years and 15 years.He deposits total of Rs 3,60,000 in the bank for a time period that is until any one of them reaches 18 years and the money is deposited in the ratio of their present ages.What is the difference between the total amount they receive after the stipulated time if rate of interest is 5% simple interest ?<\/p>\n a)\u00a024000<\/p>\n b)\u00a028000<\/p>\n c)\u00a040000<\/p>\n d)\u00a032000<\/p>\n e)\u00a036000<\/p>\n Question 8:\u00a0<\/b>A person purchases 200 apples at Rs 300 per dozen.He sold 40% of the apples at Rs 30 per each apple and 25% of the remaining apples were spoiled and in the remaining apples half were sold at Rs 40 per each and the other half were sold at 35 per each. Find the profit\/loss percent<\/p>\n a)\u00a024.5%<\/p>\n b)\u00a024%<\/p>\n c)\u00a024.7%<\/p>\n d)\u00a024.8%<\/p>\n e)\u00a025%<\/p>\n Question 9:\u00a0<\/b>A trader got 10%,20% and 30% profit by selling three article A,B and C respectively.If the sum of cost price by A and B is twice that of C and the difference between the cost price of A and B(A>B) is 40% of the cost price of A. What is the overall profit of the trader ?<\/p>\n a)\u00a060.2%<\/p>\n b)\u00a060.8%<\/p>\n c)\u00a060.4%<\/p>\n d)\u00a060.6%<\/p>\n e)\u00a070%<\/p>\n Question 10:\u00a0<\/b>If the ratio of investments of Ram, Ravi and Ramesh are in the ratio of $\\frac{1}{5}$ : $\\frac{2}{3}$ : $\\frac{3}{2}$ and they invested for 100\/7%, $\\frac{3}{2}$%, $\\frac{5}{2}$% respectively of their investment, and the profit of C is 178 then what will be the profit of A?<\/p>\n a)\u00a0760<\/p>\n b)\u00a0775<\/p>\n c)\u00a0700<\/p>\n d)\u00a0288<\/p>\n e)\u00a0322<\/p>\n Free Mock Test for IBPS RRB Clerk<\/a><\/p>\n IBPS RRB Clerk Previous Papers<\/a><\/p>\n Question 11:\u00a0<\/b>A solution contains three different liquids X,Y and Z in the ratio 5:7:4. If liquids X and Y are added to it so that the resultant solution has X,Y and Z in the ratio 3:2:1 then in which ratio X and Y are added to the solution ?<\/p>\n a)\u00a07:1<\/p>\n b)\u00a07:2<\/p>\n c)\u00a05:1<\/p>\n d)\u00a05:2<\/p>\n e)\u00a06:1<\/p>\n Question 12:\u00a0<\/b>A solution contains 3 liquids A,B and C.The ratio of volumes of B and C is 7:2.It contains 15 litres of A.If 5 litres of B and 4 litres of C is replaced by equal volumes of A then the ratio of volumes of A and B becomes 4:5. What is the total volume of the solution?<\/p>\n a)\u00a060 litres<\/p>\n b)\u00a050 litres<\/p>\n c)\u00a045 litres<\/p>\n d)\u00a030 litres<\/p>\n e)\u00a070 litres<\/p>\n Question 13:\u00a0<\/b>The ratio of 3rd and 6th term of a GP is 27. If the first term of the GP is 10, then find out the sum of infinite terms of this convergent GP.<\/p>\n a)\u00a030<\/p>\n b)\u00a040<\/p>\n c)\u00a015<\/p>\n d)\u00a020<\/p>\n e)\u00a025<\/p>\n Question 14:\u00a0<\/b>Sum of the first 3 terms of an AP is 2\/9 times the sum of first 6 terms of the same AP. Find out the ratio of first term to the common difference of the same AP.<\/p>\n a)\u00a03 : 8<\/p>\n b)\u00a01 : 4<\/p>\n c)\u00a02 : 7<\/p>\n d)\u00a01 : 3<\/p>\n e)\u00a01 : 5<\/p>\n Question 15:\u00a0<\/b>N is a number that leaves the same remainder on dividing 2527, 2419, 2383, and 2599. The largest value of N that satisfies the condition is<\/p>\n a)\u00a054<\/p>\n b)\u00a018<\/p>\n c)\u00a072<\/p>\n d)\u00a036<\/p>\n e)\u00a090<\/p>\n Instructions<\/b><\/p>\n In each of the following questions a question is asked followed by three statements.You have to study the questions and all the given three statements and all the statements and decide whether any information provided in the statement are redundant and can be dispensed with while answering the questions ?<\/p>\n Question 16:\u00a0<\/b>What will be the cost of the painting the four walls of a room with length ,width and height is 5,3,8 meters respectively. The room has one window and one door. a)\u00a0I only<\/p>\n b)\u00a0II only<\/p>\n c)\u00a0III only<\/p>\n d)\u00a0II or III only<\/p>\n e)\u00a0All are required to answer the question<\/p>\n Question 17:\u00a0<\/b>How much time will the train X take to cross another train Y running in the opposite direction ? a)\u00a0I only<\/p>\n b)\u00a0II only<\/p>\n c)\u00a0III only<\/p>\n d)\u00a0I or II only<\/p>\n e)\u00a0Data inadequate<\/p>\n Question 18:\u00a0<\/b>Three friends X,Y,Z started a partnership business investing money in the ratio of the 5 :4:2 respectively for a period of 3 years.What is the amount received by X as share in the total profit ? a)\u00a0I only<\/p>\n b)\u00a0II only<\/p>\n c)\u00a0III Only<\/p>\n d)\u00a0I and II only<\/p>\n e)\u00a0I or II or III<\/p>\n Question 19:\u00a0<\/b>The sum of ages of father and his daughter is 45 years. If the product of their ages 8 years ago was 3 times the age of the father at that time. What will be the age of father after 4 years?<\/p>\n a)\u00a027 years<\/p>\n b)\u00a038 years<\/p>\n c)\u00a011 years<\/p>\n d)\u00a034 years<\/p>\n e)\u00a031 years<\/p>\n Question 20:\u00a0<\/b>Srinivas is four times as old as his daughter. Five years ago, Srinivas was nine times as old as his daughter was at that time. His daughter’s present age is:<\/p>\n a)\u00a010 years<\/p>\n b)\u00a08 years<\/p>\n c)\u00a06 years<\/p>\n d)\u00a05 years<\/p>\n Quantitative Aptitude formulas PDF<\/a><\/p>\n 520 Banking Mocks – Just Rs. 499<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Total number of valid votes=200000*(0.9) 2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n let the total number of apples be \u2018p\u2019 3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Here the pattern consists of 2 different series in AP 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the length of the train B be $T_B$ metres $\\dfrac{T_B + 210}{5} = 70$<\/p>\n => $T_B + 210 = 350$ Let the length of the train D be $T_D$ metres $\\dfrac{T_D + 200}{9} = 40$<\/p>\n => $T_D + 200 = 360$ Therefore, Length of the train D = 160 metres Therefore, Average time taken by all the trains to cross the man = $\\dfrac{6+2+3+4+5}{5} = \\dfrac{20}{5} = 4$ seconds<\/p>\n 5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Speed of train A = 198 km\/hr = $198\\times\\dfrac{5}{18} = 55$ m\/sec 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the length of the train B be $T_B$ metres $\\dfrac{T_B + 210}{5} = 70$<\/p>\n => $T_B + 210 = 350$ Let the length of the train D be $T_D$ metres $\\dfrac{T_D + 200}{9} = 40$<\/p>\n => $T_D + 200 = 360$ Therefore, Length of the train D = 160 metres Therefore, Required difference = 4-2 = 2 seconds.<\/p>\n 7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n From the given information the time period is 18-15=3 years 8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Given CP per dozen=300 9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the cost price of A,B and C be a,b and c 10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n The ratio of profit is given by,<\/p>\n = $(\\frac{1}{5} \\times \\frac{1}{5} \\times \\frac{1}{7}) : (\\frac{2}{3} \\times \\frac{2}{3} \\times \\frac{3}{200}) : (\\frac{3}{2} \\times \\frac{3}{2} \\times \\frac{5}{200})$<\/p>\n =\u00a0$\\frac{1}{175} : \\frac{1}{50} : \\frac{9}{160}$<\/p>\n The profit of A =<\/p>\n 11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the initial volumes of X,Y and Z be 5x,7x and 4x respectively 12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the initial volumes be A,B and C 13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let \u2018r\u2019 be the common ratio of the given GP. 14)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let \u2018a\u2019 and \u2018d\u2019 be the first term and common difference of the given AP. 15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n N leaves the same remainder on dividing 2527, 2419, 2383, and 2599, the difference between any pair of these numbers should be divisible by the number. The smallest difference will be the limiting factor. 16)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Length = 5 m , Breadth = 3 m and Height = 8 m<\/p>\n To find the cost of painting the walls of the room, we should know the cost of painting and the area of door and window.<\/p>\n Area of 4 walls (Curved Surface Area of cuboid) = $2h(l+b)$<\/p>\n = $(2 \\times 8)(5+3) = 16 \\times 8 = 128$ $m^2$<\/p>\n From I & II : Cost = Rs 25 per square meter<\/p>\n Area of window = $2.25$ $m^2$<\/p>\n and Area of door = $2 \\times 2.25 = 4.5$ $m^2$<\/p>\n Thus, area to be painted = $128 – 2.25 – 4.5 = 121.25$ $m^2$<\/p>\n $\\therefore$ Cost of painting 4 walls = $25 \\times 121.25 = Rs$ $3031.25$<\/p>\n Thus, statement III is redundant.<\/p>\n => Ans – (C)<\/p>\n 17)\u00a0Answer\u00a0(E)<\/strong><\/p>\n To find the time taken by train X to cross train Y, we should know the sum of speed of the trains\u00a0(as they are moving in opposite directions) and the sum of lengths of the train<\/p>\n In statement II, ratio of speed of train\u00a0X : Y = 3\u00a0: 2<\/p>\n Thus, we cannot find the speeds of the two trains.<\/p>\n $\\therefore$ Data is inadequate<\/p>\n => Ans – (E)<\/p>\n 18)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Ratio of investment of\u00a0X : Y : Z = 5\u00a0: 4\u00a0: 2<\/p>\n To find the share of profit earned by X (or anyone), we need to find the total profit earned.<\/p>\n From statement III : Average profit for 3 years = Rs. 2750<\/p>\n => Total profit = $2750 \\times 3$ = Rs. 8250<\/p>\n Amount received by X = $\\frac{5}{(5+4+2)} \\times 8250$ = Rs. 3750<\/p>\n Thus, statements I and II are redundant.<\/p>\n => Ans – (D)<\/p>\n 19)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the present age of father be \u2018f\u2019 and the daughter be \u2018d\u2019 20)\u00a0Answer\u00a0(B)<\/strong><\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/DI9.JPG\")
<\/figure>\n
\nI.Cost of painting per square meter is Rs 25
\nII.Area of window is 2.25 sq m which is half of the area of the door
\nIII.Area of the room is 15 sq meter<\/p>\n
\nI.Train X crosses a signal pole in 6 secs
\nII.Ratio of the speeds of trains X and Y is 3:2
\nIII.Length of the two trains together is 500 meters<\/p>\n
\nI.Total amount invested in the business is Rs.22,000
\nII.Profit was distributed after a period of 2 years
\nIII.The average amount of profit earned per year is Rs 2,750<\/p>\n
\n=180000
\nGiven A=B+C
\nTherefore A+B+C=180000
\nA+A=180000
\n2A=180000
\nA=90000
\nGiven B\/C=2\/1
\nB=2C
\nB+C=90000
\nB+(B\/2)=90000
\n3B\/2 =90000
\nB=30000*2
\nB=60000<\/p>\n
\nIn the 1st week he ate 0.6p and thrown away 0.15p
\nTherefore after 1st week apples left=p-(0.6p+0.15p)
\n=0.25p
\nIn the second week he ate 0.125p and thrown away (0.25)*(0.2)*p=0.05p
\nTherefore after 2nd week apples left=0.25p-(0.125p+0.05p)
\n=0.25p-0.175p
\n=0.075
\nTotal apples eaten =0.6p+0.125p+0.075p
\n=0.8p
\nTotal apples thrown away=0.2p
\nTherefore 0.2p=500
\np=2500
\nTotal apples eaten =0.8*2500
\n=2000<\/p>\n
\ni.e 2,1,0,-1,… and the other 3,4,5\u2026..
\n10th term in 2,1,0,-1,… is -7
\n10th term in 3,4,5\u2026.. is 12
\nSum of 1st series is 3-((7*8)\/2)=3-28=-25
\nSum of 2nd series is (12(13)\/2)-3=78-3=75
\nSum=50
\nAverage=50\/20
\n=2.5<\/p>\n
\nLength of the platform which B crosses = 210 metres
\nTime taken to cross the platform = 5 seconds
\nSpeed of train B = 252 km\/hr = $252\\times\\dfrac{5}{18} = 70$ m\/sec<\/p>\n
\n=> $T_B = 140$
\nTherefore, Length of the train B = 140 m
\nThen, Time taken by train B to cross the man = $\\dfrac{140}{70} = 2$ seconds<\/p>\n
\nLength of the platform which D crosses = 200 metres
\nTime taken to cross the platform = 9 seconds
\nSpeed of Train D = 144 km\/hr = $144\\times\\dfrac{5}{18} = 40$ m\/sec<\/p>\n
\n=> $T_D = 160$<\/p>\n
\nTime taken by the train D to cross the man = $\\dfrac{160}{40} = 4$ seconds<\/p>\n
\nLength of train A = 55*6 = 330 m
\nLength of platform which A crosses = 360+25 = 385 metres
\nThen, Time taken by A to cross the platform = $\\dfrac{330+385}{55} = \\dfrac{715}{55} = 13$ seconds.<\/p>\n
\nLength of the platform which B crosses = 210 metres
\nTime taken to cross the platform = 5 seconds
\nSpeed of train B = 252 km\/hr = $252\\times\\dfrac{5}{18} = 70$ m\/sec<\/p>\n
\n=> $T_B = 140$
\nTherefore, Length of the train B = 140 m
\nThen, Time taken by train B to cross the man = $\\dfrac{140}{70} = 2$ seconds<\/p>\n
\nLength of the platform which D crosses = 200 metres
\nTime taken to cross the platform = 9 seconds
\nSpeed of Train D = 144 km\/hr = $144\\times\\dfrac{5}{18} = 40$ m\/sec<\/p>\n
\n=> $T_D = 160$<\/p>\n
\nTime taken by the train D to cross the man = $\\dfrac{160}{40} = 4$ seconds<\/p>\n
\nSo the money is distributed in the ratio 4:5 i.e On 1st son it is (4\/9)*360000=160000
\nOn the second son it is (5\/9)*360000=200000
\nInterest for 1st son=160000*3*5\/100
\n=24000
\nInterest for 2n son=200000*3*5\/100
\n=12000
\nAmount received by 1st son=160000+24000
\n=184000
\nAmount received by 2nd son=200000+12000
\n=212000
\nDifference=212000-184000
\n=28000<\/p>\n
\nFor each apple cost=300\/12
\n=Rs 25
\nTotal cost price of apples=200*25
\n=5000
\nHe sold 40% of apples at Rs 30 per each
\nSo (40\/100)*200 =80 apples
\n80*30=Rs 2400
\n25% of remaining apples are spoiled i.e (3\/5)*(1\/4)*120=18 apples
\nSo total leftover apples=120-18
\n=102
\nSo 51 apples are sold at 40 per each and the other 51 apples at 35 per each
\nTherefore total CP=51*40+51*35
\n=2040+1785
\n=Rs 3825
\nTotal CP=3825+2400
\n=6225
\nProfit percent=((6225-5000)\/(5000))*100
\n=1225\/50
\n=24.5 %<\/p>\n
\nSP of A=1.1a
\nSP of B=1.2b
\nSP of C=1.3c
\nTotal SP=1.1a+1.2b+1.3c
\nTotal CP=a+b+c
\nAso given a+b=2c
\na-b=0.4a
\nb=0.6a
\na+b=2c
\n1.6a=2c
\nc=0.8a
\nTotal SP=1.1a+1.2(0.6a)+1.3(0.8a)
\n=1.1a+0.72a+1.04a
\n=3.86a
\nTotal CP=a+0.6a+0.8a
\n=2.4 a
\nTotal profit percent=((3.86a-2.4a)\/(2.4a))*100
\n=60.8%<\/p>\n
\nNow let \u2018a\u2019 amount of X is added to the solution
\nLet \u2018b\u2019 amount of Y is added to solution
\nLet the final volume of each liquid X,Y and Z be 3y,2y and y respectively
\nAs the volume of Z is not changed we have 4x=y
\nNew volume of X=5x+a
\nNew volume of Y=7x+b
\nTherefore we have 5x+a=3y
\n5x+a=12x
\na=7x
\n7x+b=2(4x)
\nb=8x-7x
\nb=x
\nRatio of a:b=7:1<\/p>\n
\nA=15 litres
\nB=7x and C=2x
\nA=15+5+4=24 litres
\nB=7x-5
\nC=2x-4
\nGiven 24\/(7x-5)=4:5
\n120=28x-20
\n28x=1440
\nx=5 litres
\nB=7(5)-5=30 litres
\nC=2(5)-4=6 litres
\nTotal volume=24+30+6=60 litres<\/p>\n
\nThe ratio of 3rd and 6th term of a GP is 27.
\n$\\dfrac{ar^2}{ar^5}$ = 27
\n$\\Rightarrow$ $\\dfrac{1}{r^3}$ = 27
\n$\\Rightarrow$ $r = \\dfrac{1}{3}$
\nSum of infinite GP = $\\dfrac{a}{1-r}$ = $\\dfrac{10}{1-1\/3}$ = 15
\nHence, option C is the correct answer.<\/p>\n
\n$\\Rightarrow$ $\\dfrac{3}{2}(2a + 2d) = \\dfrac{2}{9}[\\dfrac{6}{2}(2a + 5d)]$
\n$\\Rightarrow$ $3a+3d = \\dfrac{2}{3}(2a + 5d)$
\n$\\Rightarrow$ $9a+9d = 4a + 10d$
\n$\\Rightarrow$ $5a = d$
\n$\\Rightarrow$ $\\dfrac{a}{d} = \\dfrac{1}{5}$
\nTherefore, option E is the correct answer.<\/p>\n
\n2599 – 2527 = 72
\n2599- 2419= 180
\n2599-2383= 216
\n2527- 2419= 108
\n2527- 2383= 144
\n2419- 2383= 36
\nAs we can see, 36 is the smallest difference and hence, the largest number that satisfies the given condition is 36.
\nTherefore, option D is the right answer.<\/p>\n
\nAs per the given question,
\nf + d = 45 \u2026.(1) and
\n(f – 8)(d – 8) = 3(f – 8)
\nSubstitute equation (1) in the above equation
\n(f – 8)(37 – f) = 3(f – 8)
\n37 – f = 3 (or) f = 34
\nThe age of the father after 4 years will be 34 + 4 = 38 years.
\nHence, option B is the correct answer.<\/p>\n