Last Day – 10 SSC MTS Mocks for just Rs. 117<\/a><\/p>\n Take a free mock test for SSC MTS<\/a><\/p>\n SSC MTS Previous Papers<\/a> (Download PDF)<\/p>\n Instructions<\/b><\/p>\n Question 1:\u00a0<\/b>A person moves 20m north and turns 180 degrees clockwise and moves 15m and again turns 135 degrees anti clockwise and moves 5m. In which direction is he facing finally ?<\/p>\n a)\u00a0Northeast<\/p>\n b)\u00a0Northwest<\/p>\n c)\u00a0Southeast<\/p>\n d)\u00a0Southwest<\/p>\n Question 2:\u00a0<\/b>A person walks 15m east and turns 90 degrees clockwise and moves 14m and again turns 270 degrees anti clockwise and moves 20m.Which direction is he facing finally ?<\/p>\n a)\u00a0West<\/p>\n b)\u00a0North<\/p>\n c)\u00a0South<\/p>\n d)\u00a0East<\/p>\n Question 3:\u00a0<\/b>If a person starts from his office and moves 40m south. He takes right and moves 25m.He takes right and moves 30m. He takes right and moves 20m. In which direction is he with respect to the house ?<\/p>\n a)\u00a0Southwest<\/p>\n b)\u00a0Southeast<\/p>\n c)\u00a0Northeast<\/p>\n d)\u00a0Northwest<\/p>\n Question 4:\u00a0<\/b>If South becomes Northwest then Northeast becomes ?<\/p>\n a)\u00a0North<\/p>\n b)\u00a0South<\/p>\n c)\u00a0Southeast<\/p>\n d)\u00a0West<\/p>\n Question 5:\u00a0<\/b>Rahul travels 25m east from his house and takes a right and moves 15m. He again takes a right and moves 10m.He finally takes a left and moves 25m. What is the shortest distance between his house and final point ?<\/p>\n a)\u00a015$\\sqrt{10}$m<\/p>\n b)\u00a0$\\sqrt{1825}$m<\/p>\n c)\u00a03$\\sqrt{325}$m<\/p>\n d)\u00a015$\\sqrt{3}$m<\/p>\n SSC MTS Previous Papers PDF<\/a><\/p>\n Take a free mock test for SSC MTS<\/a><\/p>\n Question 6:\u00a0<\/b>A person moves 12m west and takes a right and moves 13m.He again takes left and moves 14m. He takes right and moves 15m. If he again takes a right and left moving 4m and 5m respectively then in which direction is he with respect to his initial position ?<\/p>\n a)\u00a0Northwest<\/p>\n b)\u00a0Northeast<\/p>\n c)\u00a0Southeast<\/p>\n d)\u00a0Southwest<\/p>\n Question 7:\u00a0<\/b>A person moves 20m west. He takes right and moves 15m. He takes left and moves 25m and again takes a left and moves 40m and finally he takes a right and moves 40m. What is the direction of his final point with respect to the starting point ?<\/p>\n a)\u00a0Southeast<\/p>\n b)\u00a0Northeast<\/p>\n c)\u00a0Southwest<\/p>\n d)\u00a0Northwest<\/p>\n Question 8:\u00a0<\/b>Two persons start from the same point one travels 50m north and then takes left and travels 15m and again takes a left and moves 20m and the other moves 40m south and takes right and moves 20m and again takes a right and moves 30m.What is the shortest distance between both of them ?<\/p>\n a)\u00a0$\\sqrt{1650}$m<\/p>\n b)\u00a025$\\sqrt{3}$m<\/p>\n c)\u00a030$\\sqrt{2}$m<\/p>\n d)\u00a0$\\sqrt{1625}$m<\/p>\n Question 9:\u00a0<\/b>Sita travels 20m east from her office. She turns left and walks 30m. She takes left and travels 15m and finally she takes right and travels 5m. What is the shortest distance between her final point and office ?<\/p>\n a)\u00a035m<\/p>\n b)\u00a025$\\sqrt{2}$m<\/p>\n c)\u00a020$\\sqrt{2}$m<\/p>\n d)\u00a015$\\sqrt{5}$m<\/p>\n Question 10:\u00a0<\/b>A person travels 50m north from his house. He turns right and travels 25 m.He turns right and travels 50m and finally he takes right and travels 75m then what is the shortest distance between his house and final point ?<\/p>\n a)\u00a025 m<\/p>\n b)\u00a050 m<\/p>\n c)\u00a025$\\sqrt{5}$m<\/p>\n d)\u00a0100m<\/p>\n SSC Study Material (18000 Solved Questions)<\/a><\/p>\n General Science Notes for SSC Exams<\/a><\/p>\n Question 11:\u00a0<\/b>A train took 3 hours to travel a certain distance at 20 m\/sec. At how much speed it should go to travel the same distance in 2 hours?<\/p>\n a)\u00a030 km\/hr<\/p>\n b)\u00a060 km\/hr<\/p>\n c)\u00a0108 km\/hr<\/p>\n d)\u00a096 km\/hr<\/p>\n Question 12:\u00a0<\/b>If a bus travels at 60 km\/hr instead of 40 km\/hr, it would have travelled 40 km more in same time. Find the actual distance it travelled.<\/p>\n a)\u00a0160 km<\/p>\n b)\u00a080 km<\/p>\n c)\u00a0120 km<\/p>\n d)\u00a0100 km<\/p>\n Question 13:\u00a0<\/b>A train covers a certain distance in 3 hours at 40 km\/hr. If it has to cover the same distance in 2 hours, then the speed at which it is required to travel is?<\/p>\n a)\u00a080 km\/hr<\/p>\n b)\u00a060 km\/hr<\/p>\n c)\u00a040 km\/hr<\/p>\n d)\u00a0100 km\/hr<\/p>\n Question 14:\u00a0<\/b>A boat travels 30 km upstream in 10 hours and travels 52 km downstream in 4 hours. What is the time taken to cover 121 km downstream if the speeds of both stream and boat are decreased by 1 km\/hr ?<\/p>\n a)\u00a012 hrs<\/p>\n b)\u00a011 hrs<\/p>\n c)\u00a010 hrs<\/p>\n d)\u00a09 hrs<\/p>\n Question 15:\u00a0<\/b>A boat travels 120 km upstream in 6 hours and travels 90 km downstream with double the speed of upstream. What is the time taken to cover the 90km downstream ?<\/p>\n a)\u00a02 hr 10 min<\/p>\n b)\u00a02 hr 15 min<\/p>\n c)\u00a02 hr 20 min<\/p>\n d)\u00a02 hr 30 min<\/p>\n Question 16:\u00a0<\/b>A train of length 200 meters crosses another train of length 100 meters\u2019 in 60 seconds which are separated by initial distance of \u2018l\u2019 meters.If they both are moving in the opposite direction with speeds 72 km\/hr and 18 km\/hr then find the value of l.<\/p>\n a)\u00a01100 meters<\/p>\n b)\u00a01150 meters<\/p>\n c)\u00a01200 meters<\/p>\n d)\u00a01250 meters<\/p>\n Question 17:\u00a0<\/b>A train of length 300 meters crosses another train of length \u2018l\u2019 in 30 seconds.If they both are moving in the same direction with speeds 108 km\/hr and 54 km\/hr then find the value of l.<\/p>\n a)\u00a0100 meters<\/p>\n b)\u00a0150 meters<\/p>\n c)\u00a0200 meters<\/p>\n d)\u00a0250 meters<\/p>\n Instructions<\/b><\/p>\n Question 18:\u00a0<\/b>Two trains of length 180 meters with velocity 30 m\/s and 60 m\/s travel in opposite direction and if the initial distance between them is 0.54 kilometres then what is the time taken for their tails to cross each other ?<\/p>\n a)\u00a05 sec<\/p>\n b)\u00a07 sec<\/p>\n c)\u00a08 sec<\/p>\n d)\u00a010 sec<\/p>\n Question 19:\u00a0<\/b>A man travels with a speed of 15 m\/s to reach the destination 5 seconds late and travels with 20 m\/s to reach the destination 5 seconds early.What is the original distance to be travelled ?<\/p>\n a)\u00a05.85 km<\/p>\n b)\u00a05.15 km<\/p>\n c)\u00a05.25 km<\/p>\n d)\u00a05.35 km<\/p>\n Question 20:\u00a0<\/b>A man travels half of the distance with speed \u2018v\/2\u2019 and one fourth of the distance with \u2018v\u2019 and remaining distance with \u20182v\u2019.What is the average speed of the journey ?<\/p>\n a)\u00a08v\/13<\/p>\n b)\u00a08v\/15<\/p>\n c)\u00a08v\/17<\/p>\n d)\u00a08v\/19<\/p>\n 200+ SSC Important Practice Sets<\/a><\/p>\n GK Q&A for Competitive Exams (Download PDF)<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n 2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n 3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n From the figure the required direction is Southwest.<\/p>\n 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n If south becomes northwest i.e 135 degrees clockwise then northeast becomes south.<\/p>\n 5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n =$\\sqrt{1825}$<\/p>\n 6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n <\/p>\n From the figure we have the required direction as North.<\/p>\n 7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n From the figure we have the required direction as Southwest.<\/p>\n 8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n From the figure we have shortest distance =$\\sqrt{1600+25}$ 9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n From the figure we have shortest distance =$\\sqrt{1225+25}$ 10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n <\/p>\n From the figure we have shortest distance=50m<\/p>\n 11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Speed of the train = 20 m\/sec = 20*18\/5 = 72 kmph 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the distance travelled by the bus = x km 13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Given that the speed of the train = 40 km\/hr 14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n let the speed of the boat be \u2018b\u2019 and stream be \u2018s\u2019. 15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n let the speed of the boat be \u2018b\u2019 and stream be \u2018s\u2019. 16)\u00a0Answer\u00a0(C)<\/strong><\/p>\n As they both are travelling in the opposite direction,relative velocity becomes the sum between them i.e 72+18=90 km\/hr 17)\u00a0Answer\u00a0(B)<\/strong><\/p>\n As they both are travelling in the same direction,relative velocity becomes the difference between them i.e 108-54=54 km\/hr 18)\u00a0Answer\u00a0(D)<\/strong><\/p>\n As the both are travelling in opposite direction the relative velocity will be sum of the velocities i.e 30+60=90 m\/s 19)\u00a0Answer\u00a0(C)<\/strong><\/p>\n let the original time be t seconds 20)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the total distance be x![](\"https:\/\/cracku.in\/media\/uploads\/d10_3Lfrw8S.png\")
\nFinally he is facing Northeast direction<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/d9_yjVf0A1.png\")
\nFinally he is facing west direction<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/d8_MP6kMTj.png\")
<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/d7_j0R6f1e.png\")
<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/d6_LUvEpxk.png\")
\nFrom the figure we have shortest distance =$\\sqrt{1600+225}$<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/d5_Ke73m07.png\")
<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/d4_1Zm6YaF.png\")
<\/figure>\n![](\"https:\/\/cracku.in\/media\/uploads\/d3_P84Tnde.png\")
<\/figure>\n
\n=$\\sqrt{1625}$<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/d2_v8j95kF.png\")
<\/figure>\n
\n=$\\sqrt{1250}$
\n=$25\\sqrt{2}$<\/p>\n![](\"https:\/\/cracku.in\/media\/uploads\/d1_2syo26p.png\")
<\/figure>\n
\nDistance it can travel at 72 kmph in 3 hours = 72*3 = 216 km
\nRequired speed of the train to travel 216 km in 2 hours = 216\/2 = 108 km\/hr<\/p>\n
\nTime required to travel x km at 40 km\/hr = $\\dfrac{x}{40}$ hr
\nTime required to travel x+40 km at 60 km\/hr = $\\dfrac{x+40}{60}$ hr
\nTime is equal in both the conditions
\n$\\dfrac{x}{40}$ = $\\dfrac{x+40}{60}$
\n\u21d2 60x = 40x+1600
\n\u21d2 20x = 1600 \u21d2 x = 80
\nTherefore, Distance travelled by the bus = 80 km<\/p>\n
\nTime = 3 hours
\nThen, Distance travelled by the train = 40*3 = 120 km
\nGiven that the train needs to travel 120 km in 2 hours.
\nTherefore, Required speed = 120\/2 = 60 km\/hr<\/p>\n
\n30\/(b-s) =10
\nb-s=3
\n52\/(b+s) =4
\nb+s=13
\nb-s=3
\n2b=16
\nb=8 km\/hr
\ns=5 km\/hr
\nEach is decreased by 1 km\/hr so
\nb=7 km\/hr
\ns=4 km\/hr
\nTime taken for 121 km downstream=121\/11
\n=11 hrs<\/p>\n
\n120\/(b-s) =6
\nb-s=20
\nGiven b+s=2(b-s)
\nb+s=2b-2s
\n3s=b
\n3s-s=20
\n2s=20
\ns=10
\nb=30
\nTime taken for 90 km downstream=90\/40
\n=2.25 hrs<\/p>\n
\nConverting 90 km\/hr into m\/s we have 90*5\/18=25 m\/s
\nSum of the lengths of the train=200+100=300 meters
\nTherefore (300+l)\/25 =60
\n300+l=1500
\nl=1200 meters<\/p>\n
\nConverting 36 km\/hr into m\/s we have 54*5\/18=15 m\/s
\nSum of the lengths of the train=300+l
\nTherefore (300+l)\/15 =30
\n300+l=450
\nl=150 meters<\/p>\n
\nTotal distance to be travelled is length of the trains i.e 180+180=360 m and also the distance between them i.e 0.54 km=540 m
\nTotal=540+360=900 m
\nTime =900\/90
\n=10 seconds<\/p>\n
\nSo we have 15(t+5)=20(t-5)
\n15t+75=20t-100
\n5t=175 sec
\nt=35 sec
\nTotal distance=15*35
\n=5250 m
\n=5.25 km<\/p>\n
\nTotal time=(x\/(v\/2))+(x\/(4v))+(x\/(4*2v)
\n=19x\/8v
\nAverage speed=Total distance\/Total time
\n=x\/(19x\/8v)
\n=8v\/19<\/p>\n