Download Top-20 IBPS RRB Clerk Quadratic Equation Questions PDF. Quadratic Equation questions based on asked questions in previous year exam papers very important for the IBPS RRB Assistant exam<\/p>\n
Download Quadratic Equation Questions For IBPS RRB Clerk<\/a><\/p>\n 35 IBPS RRB Clerk Mocks @ Rs. 149<\/a><\/p>\n 70 IBPS RRB (PO + Clerk) Mocks @ Rs. 199<\/a><\/p>\n Take a free mock test for IBPS RRB Clerk<\/a><\/p>\n Download IBPS RRB Clerk Previous Papers PDF<\/a><\/p>\n Instructions<\/b><\/p>\n In each of these questions, two equations are given. You have to solve these equations and find out the values of x and y and give answer<\/p>\n Question 1:\u00a0<\/b>I: $x^2-2x-323=0$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established<\/p>\n Question 2:\u00a0<\/b>I: $\\sqrt{x-14}+\\sqrt{1444}=\\sqrt{2116}$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established<\/p>\n Question 3:\u00a0<\/b>I: $x^2-170x+7221=0$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established<\/p>\n Question 4:\u00a0<\/b>I: $x^2+12\\sqrt{11}+143=0$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Question 5:\u00a0<\/b>I: $x^3-128=1727872$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Instructions<\/b><\/p>\n In each of these questions, two equations are given. You have to solve these equations and find out the values of x and y and give answer<\/p>\n Question 6:\u00a0<\/b>I: $x^2-x-812=0$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Question 7:\u00a0<\/b>I: $x^2+0.25x-60=0$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Question 8:\u00a0<\/b>I: $\\sqrt{x+14}+\\sqrt{841} = \\sqrt{1369}$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Question 9:\u00a0<\/b>I: $x^2-16\\sqrt{5}x+300=0$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Question 10:\u00a0<\/b>I: $6\\sqrt{x}+\\dfrac{5}{\\sqrt{x}} = \\sqrt{x}$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Free Mock Test for IBPS RRB Clerk<\/a><\/p>\n IBPS RRB Clerk Previous Papers<\/a><\/p>\n Instructions<\/b><\/p>\n In each of these questions, two equations are given. You have to solve these equations and find out the values of x and y and give answer<\/p>\n Question 11:\u00a0<\/b>I: $x^2+15\\sqrt{3}x-378=0$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Question 12:\u00a0<\/b>I: $\\dfrac{19}{\\sqrt{x}}+\\dfrac{18}{\\sqrt{x}}=\\sqrt{x}$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Question 13:\u00a0<\/b>I: $3x^2-76x+481=0$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Question 14:\u00a0<\/b>I: $x^2+3x-270=0$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Question 15:\u00a0<\/b>I: $x = \\sqrt{9604}$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Instructions<\/b><\/p>\n In each of these questions, two equations are given. You have to solve these equations and find out the values of x and y and give answer<\/p>\n Question 16:\u00a0<\/b>I: $3x^2+5x-68=0$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Question 17:\u00a0<\/b>I: $x^2+6x-1147=0$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Question 18:\u00a0<\/b>I: $x^2=13456$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Question 19:\u00a0<\/b>I: $2x^2-3x-629=0$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Question 20:\u00a0<\/b>I: $x^2+x-306 = 0$ a)\u00a0x is greater than y<\/p>\n b)\u00a0x is less than y<\/p>\n c)\u00a0x is greater than or equal to y<\/p>\n d)\u00a0x is less than or equal to y<\/p>\n e)\u00a0x is equal to y (or) The relationship between x and y cannot be established.<\/p>\n Quantitative Aptitude formulas PDF<\/a><\/p>\n 520 Banking Mocks – Just Rs. 499<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(D)<\/strong><\/p>\n I: $x^2-2x-323=0$ II: $y^2-40y+399=0$ Comparing x and y, 2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n I: $\\sqrt{x-14}+\\sqrt{1444}=\\sqrt{2116}$ II: $\\dfrac{\\sqrt{y}}{\\sqrt{3}{y}}=64^\\frac{1}{18}$<\/p>\n $\\dfrac{y^\\frac{1}{2}}{y^\\frac{1}{3}} = (64^\\frac{1}{3})^\\frac{1}{6}$<\/p>\n $y^\\frac{1}{6} = 4^\\frac{1}{6}$ Comparing x and y, 3)\u00a0Answer\u00a0(A)<\/strong><\/p>\n I: $x^2-170x+7221=0$ II: $3y^2+170y+2407=0$ Comparing x and y 4)\u00a0Answer\u00a0(B)<\/strong><\/p>\n I: $x^2+12\\sqrt{11}+143=0$ II: $y^2-22\\sqrt{3}y+360=0$ Comparing x and y, 5)\u00a0Answer\u00a0(B)<\/strong><\/p>\n I: $x^3-128=1727872$ II: $\\sqrt{3}{y^2} = \\dfrac{\\sqrt{2}{y^3}}{121^\\frac{5}{6}}$<\/p>\n $y^\\frac{2}{3} = \\dfrac{y^\\frac{3}{2}}{121^\\frac{5}{5}}$<\/p>\n $y^{\\frac{3}{2}-\\frac{2}{3}} = 121^\\frac{5}{6}$ Comparing x and y, 6)\u00a0Answer\u00a0(E)<\/strong><\/p>\n I: $x^2-x-812=0$ II: $y^2+y-1332=0$ Comparing x and y, Therefore, The relationship between x and y cannot be established.<\/p>\n 7)\u00a0Answer\u00a0(E)<\/strong><\/p>\n I: $x^2+0.25x-60=0$ $4x^2+x-240=0$ II: $y^2-0.33y-8=0$ $3y^2-y-24=0$ Comparing x and y $\\dfrac{15}{4}>\\dfrac{-8}{3}$<\/p>\n Therefore, The relationship between x and y cannot be established.<\/p>\n 8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n I: $\\sqrt{x+14}+\\sqrt{841} = \\sqrt{1369}$ II: $y^2+0.5y-60=0$ Comparing x and y 9)\u00a0Answer\u00a0(E)<\/strong><\/p>\n I: $x^2-16\\sqrt{5}x+300=0$ II: $y^2-31\\sqrt{5}y+750=0$ Comparing x and y, Therefore, The relationship between x and y cannot be determined.<\/p>\n 10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n I: $6\\sqrt{x}+\\dfrac{5}{\\sqrt{x}} = \\sqrt{x}$<\/p>\n $\\dfrac{6x+5}{\\sqrt{x}} = \\sqrt{x}$<\/p>\n $6x+5=x$ II: $\\dfrac{2^\\frac{5}{9}}{\\sqrt[3]{y}} = y^\\frac{2}{9}$<\/p>\n $2^\\frac{5}{9} = y^\\frac{2}{9} \\times y^\\frac{1}{3}$ By comparing x and y, Therefore, x is less than y.<\/p>\n 11)\u00a0Answer\u00a0(E)<\/strong><\/p>\n I: $x^2+15\\sqrt{3}x-378=0$ II: $y^2-6\\sqrt{2}y-224=0$ By comparing x and y, Therefore, The relationship between x and y cannot be determined.<\/p>\n 12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n I: $\\dfrac{19}{\\sqrt{x}}+\\dfrac{18}{\\sqrt{x}}=\\sqrt{x}$<\/p>\n $\\dfrac{19+18}{\\sqrt{x}} = \\sqrt{x}$<\/p>\n $x=37$<\/p>\n II: $\\dfrac{1369}{\\sqrt{y^{-1}}} = y^\\frac{5}{2}$<\/p>\n $\\dfrac{1369}{y^\\frac{-1}{2}} = y^\\frac{5}{2}$<\/p>\n $y^\\frac{5-1}{2} = 1369$ By comparing x and y, 13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n I: $3x^2-76x+481=0$ II: $y^2+6y-187=0$ 14)\u00a0Answer\u00a0(E)<\/strong><\/p>\n I: $x^2+3x-270=0$ II: $y^2+4y-285=0$ By comparing x and y, 15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n I: $x = \\sqrt{9604}$ By comparing x and y, 16)\u00a0Answer\u00a0(B)<\/strong><\/p>\n I: $3x^2+5x-68=0$ II: $y^2-33y+272=0$ By comparing x and y values, 17)\u00a0Answer\u00a0(E)<\/strong><\/p>\n I: $x^2+6x-1147=0$ II: $y^2-6x-667=0$ By comparing x and y, 18)\u00a0Answer\u00a0(B)<\/strong><\/p>\n I: $x^2 = 13456$ II: $y = \\sqrt{15129}$ By comparing x and y values, 19)\u00a0Answer\u00a0(E)<\/strong><\/p>\n I: $2x^2-3x-629=0$ II: $y^2-4y-252=0$ By comparing x and y values, $\\dfrac{37}{2}>-14$<\/p>\n Therefore, The relationship between x and y cannot be determined.<\/p>\n 20)\u00a0Answer\u00a0(E)<\/strong><\/p>\n I: $x^2+x-306 = 0$ II: $y^2+5y-696=0$ By comparing x and y values,
\nII: $y^2-40y+399=0$<\/p>\n
\nII: $\\dfrac{\\sqrt{y}}{\\sqrt{3}{y}}=64^\\frac{1}{18}$<\/p>\n
\nII: $3y^2+170y+2407=0$<\/p>\n
\nII: $y^2-22\\sqrt{3}y+360=0$<\/p>\n
\nII: $\\sqrt{3}{y^2} = \\dfrac{\\sqrt{2}{y^3}}{121^\\frac{5}{6}}$<\/p>\n
\nII: $y^2+y-1332=0$<\/p>\n
\nII: $y^2-0.33y-8=0$<\/p>\n
\nII: $y^2+0.5y-60=0$<\/p>\n
\nII: $y^2-31\\sqrt{5}y+750=0$<\/p>\n
\nII: $\\dfrac{2^\\frac{5}{9}}{\\sqrt[3]{y}} = y^\\frac{2}{9}$<\/p>\n
\nII: $y^2-6\\sqrt{2}y-224=0$<\/p>\n
\nII: $\\dfrac{1369}{\\sqrt{y^{-1}}} = y^\\frac{5}{2}$<\/p>\n
\nII: $y^2+6y-187=0$<\/p>\n
\nII: $y^2+4y-285=0$<\/p>\n
\nII: $y^2 = 7569$<\/p>\n
\nII: $y^2-33y+272=0$<\/p>\n
\nII: $y^2-6x-667=0$<\/p>\n
\nII: $y=\\sqrt{15129}$<\/p>\n
\nII: $y^2-4y-252=0$<\/p>\n
\nII: $y^2+5y-696=0$<\/p>\n
\n$x^2-19x+17x-323=0$
\n$x(x-19)+17(x-19)=0$
\n$(x-19)(x+17)=0$
\n$x=19$ or $x=-17$<\/p>\n
\n$y^2-19y-21y+399=0$
\n$y(y-19)-21(y-19)=0$
\n$(y-19)(y-21)=0$
\n$y=19$ or $y=21$<\/p>\n
\n$19 = 19$
\n$19 < 21$
\n$-17 < 19$
\n$-17 < 21$
\nTherefore, x is less than or equal to y.<\/p>\n
\n$\\sqrt{x-14}+38=46$
\n$\\sqrt{x-14}=8$
\n$x-14=64$
\n$x=78$<\/p>\n
\n$y=4$<\/p>\n
\n$78>4$
\nTherefore,x is greater than y.<\/p>\n
\n$x^2-87x-83x+7221=0$
\n$x(x-87)-83(x-87)=0$
\n$(x-87)(x-83)=0$
\n$x=87$ or $x=83$<\/p>\n
\n$3y^2+87y+83y+2407=0$
\n$3y(y+29)+83(y+29)=0$
\n$(y+29)(3y+83)=0$
\n$y=-29$ or $y=-\\dfrac{83}{3}$<\/p>\n
\n$87>-29$
\n$87>-\\dfrac{83}{3}$
\n$83>-29$
\n$83>-\\dfrac{83}{3}$
\nTherefore, x is greater than y.<\/p>\n
\n$x^2+13\\sqrt{11}x+\\sqrt{11}x+143=0$
\n$x(x+13\\sqrt{11})+\\sqrt{11}(x+13\\sqrt{11})=0$
\n$(x+13\\sqrt{11})(x+\\sqrt{11})=0$
\n$x=-13\\sqrt{11}$ or $x=-\\sqrt{11}$
\nThe approximate value of $\\sqrt{11} = 3$
\nThen, $x=-39$ or $x=-3$<\/p>\n
\n$y^2-20\\sqrt{3}y-12\\sqrt{3}y+360=0$
\n$y(y-20\\sqrt{3})-12\\sqrt{3}(y-20\\sqrt{3})=0$
\n$(y-20\\sqrt{3})(y-12\\sqrt{3})=0$
\n$y=20\\sqrt{3}$ or $y=12\\sqrt{3}$
\nThe approximate value of $\\sqrt{3}=1$
\nThen, $x=20$ or $x=12$<\/p>\n
\nBoth the x values are negative and both the y values are positive.
\nTherefore, x is less than y.<\/p>\n
\n$x^3 = 1728000$
\n$x=120$<\/p>\n
\n$y^\\frac{5}{6}=121^\\frac{5}{6}$
\n$y = 121$<\/p>\n
\n$120 < 121$.
\nTherefore, x is less than y.<\/p>\n
\n$x^2-29x+28x-812=0$
\n$x(x-29)+28(x-29)=0$
\n$(x-29)(x+28)=0$
\n$x=29$ or $x=-28$<\/p>\n
\n$y^2+37y-36y-1332=0$
\n$y(y+37)-36(y+37)=0$
\n$(y+37)(y-36)=0$
\n$y=-37$ or $y=36$<\/p>\n
\n$29>-37$
\n$29<36$
\n$-28>-37$
\n$-29<36$<\/p>\n
\n$x^2+\\dfrac{x}{4}-60=0$<\/p>\n
\n$4x^2+16x-15x-240=0$
\n$4x(x+16)-15(x+16)=0$
\n$(x+16)(4x-15)=0$
\n$x=-16$ or $x=\\dfrac{15}{4}$<\/p>\n
\n$y^2-\\dfrac{y}{3}-8=0$<\/p>\n
\n$3y^2-9y+8y-24=0$
\n$3y(y-3)+8(y-3)=0$
\n$(y-3)(3y+8)=0$
\n$y=3$ or $y=\\dfrac{-8}{3}$<\/p>\n
\n$-16<3$
\n$-16$\\dfrac{15}{4}>3$<\/p>\n
\n$\\sqrt{x+14}+29=37$
\n$\\sqrt{x+14}=8$
\n$x+14=64$
\n$x=40$<\/p>\n
\n$2y^2+y-120=0$
\n$2y^2+16y-15y-120=0$
\n$2y(y+8)-15(y+8)=0$
\n$(y+8)(2y-15)=0$
\n$y=-8$ or $y=\\dfrac{15}{2}=7.5$<\/p>\n
\n$40 > -8$
\n$40 > 7.5$
\nTherefore, x is greater than y.<\/p>\n
\n$x^2-10\\sqrt{5}x-6\\sqrt{5}x+300=0$
\n$x(x-10\\sqrt{5})-6\\sqrt{5}(x-10\\sqrt{5})=0$
\n$(x-10\\sqrt{5})(x-6\\sqrt{5})=0$
\n$x=10\\sqrt{5}$ or $x=6\\sqrt{5}$<\/p>\n
\n$y^2-25\\sqrt{5}y-6\\sqrt{5}y+750=0$
\n$y(y-25\\sqrt{5})-6\\sqrt{5}(y-25\\sqrt{5})=0$
\n$(y-25\\sqrt{5})(y-6\\sqrt{5})=0$
\n$y=25\\sqrt{5}$ or $y=6\\sqrt{5}$<\/p>\n
\n$10\\sqrt{5} < 25\\sqrt{5}$
\n$10\\sqrt{5} > 6\\sqrt{5}$
\n$6\\sqrt{5} < 25\\sqrt{5}$
\n$6\\sqrt{5}=6\\sqrt{5}$<\/p>\n
\n$5x=-5$
\n$x=-1$<\/p>\n
\n$2^\\frac{5}{9} = y^\\frac{5}{9}$
\n$y=2$<\/p>\n
\n$-1<2$<\/p>\n
\n$x^2+21\\sqrt{3}x-6\\sqrt{3}x-378=0$
\n$x(x+21\\sqrt{3})-6\\sqrt{3}(x+21\\sqrt{3})=0$
\n$(x+21\\sqrt{3})(x-6\\sqrt{3})=0$
\n$x=-21\\sqrt{3}$ or $x=6\\sqrt{3}$
\nApproximate value of $\\sqrt{3}=2$.
\nThen, $x = -21\\times2 = -42$ or $x = 6\\times2 = 12$<\/p>\n
\n$y^2-14\\sqrt{2}y+8\\sqrt{2}y-224=0$
\n$y(y-14\\sqrt{2})+8\\sqrt{2}(y-14\\sqrt{2})=0$
\n$(y-14\\sqrt{2})(y+8\\sqrt{2})=0$
\n$y=14\\sqrt{2}$ or $y=-8\\sqrt{2}$
\nApproximate value of $\\sqrt{2} = 1$
\nThen, $y = 14$ or $y = -8$<\/p>\n
\n$-42 < 14$
\n$-42 < -8$
\n$12 < 14$
\n$12 > -8$<\/p>\n
\n$y^2 = 1369$
\n$y = -37$ or $y = +37$<\/p>\n
\n$37 > -37$
\n$37 = 37$
\nTherefore, x is greater than or equal to y.<\/p>\n
\n$3x^2-39x-37x+481=0$
\n$3x(x-13)-37(x-13)=0$
\n$(x-13)(3x-37)=0$
\n$x=13$ or $x=\\dfrac{37}{3}$<\/p>\n
\n$y^2+17y-11y-187=0$
\n$y(y+17)-11(y+17)=0$
\n$(y+17)(y-11)=0$
\n$y=-17$ or $y=11$
\nBy comparing x and y,
\n$13>-17$
\n$13>11$
\n$\\dfrac{37}{3}>-17$
\n$\\dfrac{37}{3}>11$
\nTherefore, x is greater than y.<\/p>\n
\n$x^2+18x-15x-270=0$
\n$x(x+18)-15(x+18)=0$
\n$(x-15)(x+18)=0$
\n$x=15$ or $x=-18$<\/p>\n
\n$y^2+19y-15y-285=0$
\n$y(y+19)-15(y+19)=0$
\n$(y-15)(y+19)=0$
\n$y=15$ or $y=-19$<\/p>\n
\n$15=15$
\n$15>-19$
\n$-18<15$
\n$-18>-19$
\nTherefore, The relationship between x and y cannot be established.<\/p>\n
\n$x = 98$
\nII: $y^2 = 7569$
\n$y = \\pm 87$
\n$y = -87$ or $y=87$<\/p>\n
\n$98 > -87$
\n$98 > 87$
\nTherefore, x is greater than y.<\/p>\n
\n$3x^2-12x+17x-68=0$
\n$3x(x-4)+17(x-4)=0$
\n$(x-4)(3x+17)=0$
\n$x=4$ or $x=\\dfrac{-17}{3}$<\/p>\n
\n$y^2-16y-17y+272=0$
\n$y(y-16)-17(y-16)=0$
\n$(y-16)(y-17)=0$
\n$y=16$ or $y=17$<\/p>\n
\n$4 < 16$
\n$4 <17$
\n$\\dfrac{-17}{3}<16$
\n$\\dfrac{-17}{3}<17$
\nTherefore, x is less than y.<\/p>\n
\n$x^2+37x-31x-1147=0$
\n$x(x+37)-31(x+37)=0$
\n$(x+37)(x-31)=0$
\n$x=-37$ or $x=31$<\/p>\n
\n$y^2-29y+23y-667=0$
\n$y(y-29)+23(y-29)=0$
\n$(y-29)(y+23)=0$
\n$y=29$ or $y=-23$<\/p>\n
\n$-37 < 29$
\n$-37 < -23$
\n$31 > 29$
\n$31 > -23$
\nTherefore, The relationship between x and y cannot be established.<\/p>\n
\n$x = \\pm 116$
\n$x = -116$ or $x=116$<\/p>\n
\n$y = 123$<\/p>\n
\n$-116 < 123$
\n$116 < 123$
\nTherefore, x is less than y.<\/p>\n
\n$2x^2+34x-37x-629=0$
\n$2x(x+17)-37(x+17)=0$
\n$(x+17)(2x-37)=0$
\n$x=-17$ or $x=\\dfrac{37}{2}$<\/p>\n
\n$y^2-18y+14y-252=0$
\n$y(y-18)+14(y-18)=0$
\n$(y-18)(y+14)=0$
\n$y=18$ or $y=-14$<\/p>\n
\n$-17 < 18$
\n$-17 < -14$
\n$\\dfrac{37}{2}>18$<\/p>\n
\n$x^2+18x-17x-306=0$
\n$x(x+18)-17(x+18)=0$
\n$(x+18)(x-17)=0$
\n$x=-18$ or $x=17$<\/p>\n
\n$y^2+29y-24y-696=0$
\n$y(y+29)-24(y+29)=0$
\n$(y+29)(y-24)=0$
\n$y = -29$ or $y = 24$<\/p>\n
\n-18 > -29
\n18 < 24
\n17 > -29
\n17 < 24
\nTherefore, The relationship between x and y cannot be established.<\/p>\n