Download Top-20 SSC MTS Alphabetical Series Questions PDF. Alphabetical Series questions based on asked questions in previous year exam papers very important for the SSC MTS exam.<\/p>\n
Download Alphabetical Series Questions For SSC MTS<\/a><\/p>\n Take a free mock test for SSC MTS<\/a><\/p>\n SSC MTS Previous Papers<\/a> (Download PDF)<\/p>\n Instructions<\/b><\/p>\n Which of the following comes in the place of ?<\/p>\n Question 1:\u00a0<\/b>ikm,jln,kmo,lnp,?<\/p>\n a)\u00a0moq<\/p>\n b)\u00a0mop<\/p>\n c)\u00a0mqo<\/p>\n d)\u00a0mqp<\/p>\n Question 2:\u00a0<\/b>LM,WV,PQ,SR,TU,?<\/p>\n a)\u00a0QP<\/p>\n b)\u00a0SR<\/p>\n c)\u00a0RQ<\/p>\n d)\u00a0ON<\/p>\n Question 3:\u00a0<\/b>aei,eio,iou,oua,?<\/p>\n a)\u00a0uai<\/p>\n b)\u00a0uae<\/p>\n c)\u00a0uei<\/p>\n d)\u00a0uoi<\/p>\n Question 4:\u00a0<\/b>A,D,I,P,?<\/p>\n a)\u00a0Y<\/p>\n b)\u00a0Z<\/p>\n c)\u00a0X<\/p>\n d)\u00a0V<\/p>\n Question 5:\u00a0<\/b>ace,bdf,ceg,dfh,?<\/p>\n a)\u00a0egf<\/p>\n b)\u00a0efg<\/p>\n c)\u00a0eig<\/p>\n d)\u00a0egi<\/p>\n SSC MTS Previous Papers PDF<\/a><\/p>\n Take a free mock test for SSC MTS<\/a><\/p>\n Question 6:\u00a0<\/b>AB,ZY,EF,VU,IJ,?<\/p>\n a)\u00a0PO<\/p>\n b)\u00a0SR<\/p>\n c)\u00a0RQ<\/p>\n d)\u00a0QP<\/p>\n Question 7:\u00a0<\/b>M,K,H,D,?<\/p>\n a)\u00a0A<\/p>\n b)\u00a0Z<\/p>\n c)\u00a0Y<\/p>\n d)\u00a0X<\/p>\n Question 8:\u00a0<\/b>X,Z,C,G,?<\/p>\n a)\u00a0M<\/p>\n b)\u00a0L<\/p>\n c)\u00a0J<\/p>\n d)\u00a0I<\/p>\n Question 9:\u00a0<\/b>D,W,F,U,H,?<\/p>\n a)\u00a0S<\/p>\n b)\u00a0T<\/p>\n c)\u00a0U<\/p>\n d)\u00a0R<\/p>\n Question 10:\u00a0<\/b>A,Y,C,W,E,?<\/p>\n a)\u00a0V<\/p>\n b)\u00a0D<\/p>\n c)\u00a0U<\/p>\n d)\u00a0E<\/p>\n SSC Study Material (18000 Solved Questions)<\/a><\/p>\n General Science Notes for SSC Exams<\/a><\/p>\n Instructions<\/b><\/p>\n In following alphabet series , one term missing as shown by question mark (?). Choose missing term from options<\/p>\n Question 11:\u00a0<\/b>ML, LO, QL, LS, ?<\/p>\n a)\u00a0UK<\/p>\n b)\u00a0KL<\/p>\n c)\u00a0UL<\/p>\n d)\u00a0UJ<\/p>\n Question 12:\u00a0<\/b>GC, CH, IC, CJ, ?<\/p>\n a)\u00a0CK<\/p>\n b)\u00a0KC<\/p>\n c)\u00a0LD<\/p>\n d)\u00a0KD<\/p>\n Question 13:\u00a0<\/b>KT, UL, MV, WN, ?<\/p>\n a)\u00a0OY<\/p>\n b)\u00a0PX<\/p>\n c)\u00a0OZ<\/p>\n d)\u00a0OX<\/p>\n Question 14:\u00a0<\/b>CA, BD, EC, DF, ?<\/p>\n a)\u00a0FE<\/p>\n b)\u00a0GF<\/p>\n c)\u00a0GD<\/p>\n d)\u00a0GE<\/p>\n Question 15:\u00a0<\/b>LT, UM, NV, WO, ?<\/p>\n a)\u00a0RX<\/p>\n b)\u00a0PZ<\/p>\n c)\u00a0PX<\/p>\n d)\u00a0PY<\/p>\n Question 16:\u00a0<\/b>NP, OR, QU, TY, ?<\/p>\n a)\u00a0XD<\/p>\n b)\u00a0YC<\/p>\n c)\u00a0ZD<\/p>\n d)\u00a0YD<\/p>\n Question 17:\u00a0<\/b>LB, MC, OE, RH, ?<\/p>\n a)\u00a0VK<\/p>\n b)\u00a0UL<\/p>\n c)\u00a0UK<\/p>\n d)\u00a0VL<\/p>\n Question 18:\u00a0<\/b>SA, TB, VD, YG, ?<\/p>\n a)\u00a0CK<\/p>\n b)\u00a0DJ<\/p>\n c)\u00a0CJ<\/p>\n d)\u00a0BK<\/p>\n Question 19:\u00a0<\/b>KP, LO, MN, NM, ?<\/p>\n a)\u00a0OK<\/p>\n b)\u00a0LO<\/p>\n c)\u00a0OL<\/p>\n d)\u00a0PK<\/p>\n Question 20:\u00a0<\/b>MB, OD, QF, SH, ?<\/p>\n a)\u00a0UK<\/p>\n b)\u00a0TJ<\/p>\n c)\u00a0UJ<\/p>\n d)\u00a0KT<\/p>\n 200+ SSC Important Practice Sets<\/a><\/p>\n General Knowledge Q&A for Competitive Exams (Download PDF)<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n In this series 1st term in 1st element is i and in 2nd element 1st term is j and so 5th element 1st term is m 2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n In this alternate places are moving in a series LM and then PQ leaving NO similarly leaving RS we have TU and the second series we have WV and then SR leaving UT and then ON leaving QP and so the correct answer is ON<\/p>\n 3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n In this series three vowels are taken at a time in the order a,e,i,o,u and so in each term one of the vowel adds and the other gets removed and so the next term in the series is addition of e and subtraction of o and so correct answer is uae.<\/p>\n 4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n In this series place value of A is 1 and that of D is 4 and I is 9 and P is 16 and so next term is 25 and Y has the place value of 25.<\/p>\n 5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n In this series 1st term in 1st element is a and in 2nd element 1st term is b and so 5th element 1st term is e 6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n In this alternate places are moving in a series AB and then EF leaving BC similarly leaving GH we have IJ and the second series we have ZY and then VU leaving XW and then RQ leaving TS and so the correct answer is RQ<\/p>\n 7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n In this reverse alphabet series in the each next term 1,2,3,4\u2026 alphabets are left..i.e M and K\u2026.L is left 8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n In this series in each term 1,2,3,…alphabets are left i.e in X and Z…Y is left 9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n In this series D and W are the 4th elements from beginning and ending of english alphabets respectively and then F and U are 6th elements from beginning and ending of english alphabets and so similarly h is the 8th element from the beginning and so 8th element from the end is S.<\/p>\n 10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n In this series alternate places are following a trend i.e A,C,E,G…so on 11)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Here, L changes its position in the term. 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Here, C changes its place in the term. Similarly, Missing term in the series will be 13)\u00a0Answer\u00a0(D)<\/strong><\/p>\n K+1 = L 14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n C+1 =D 15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n L+1 = M 16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n N+1 = O 17)\u00a0Answer\u00a0(D)<\/strong><\/p>\n L+1 = M 18)\u00a0Answer\u00a0(A)<\/strong><\/p>\n S+1 = T 19)\u00a0Answer\u00a0(C)<\/strong><\/p>\n K+1 = L 20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n M+2 = O
\n1st term 2nd element is k and then 2nd term 2nd element is l and so 5th term 2nd element is o
\n1st term 3rd element is m and the 2nd term 3rd element is n and so 5th term 3rd element is q
\nAnd so required answer is moq.<\/p>\n
\n1st term 2nd element is c and then 2nd term 2nd element is d and so 5th term 2nd element is g
\n1st term 3rd element is e and the 2nd term 3rd element is f and so 5th term 3rd element is i
\nAnd so required answer is egi.<\/p>\n
\nK and H\u2026.I and J are left
\nH and D…E,F and G are left and so from D we leave Z,A,B and C and so the correct answer is Y.<\/p>\n
\nand in Z and C\u2026.A and B are left
\nIn C and G \u2026.D,E and F are left
\nSo 4 alphabets i.e H,I,J,K are left and so the correct answer is L<\/p>\n
\nSimilarly Y,W,U,S\u2026.so on
\nRequire answer is U<\/p>\n
\nM+2 = O
\nIn ML, L is in second position. Then, in next term, L will be in first position.
\n\u21d2 LO
\nNext term:
\nO+2 = Q
\nIn LO, L is in first position. Then, in next term, L will be in second position.
\n\u21d2 QL
\nNext term:
\nQ+2 = S
\nIn QL, L is in second position. Then, in next term, L will be in first position.
\n\u21d2 LS.
\nThen, Next term will be:
\nS+2 = U
\nIn LS, L is in first position. Then, in next term, L will be in second position.
\n\u21d2 UL<\/p>\n
\nG+1 = H
\nC is in second place in GC. Now it comes to first place.
\n\u21d2 CH
\nNext term:
\nH+1 = I
\nHere, C is in first place in CH. Now it comes to second place.
\n\u21d2 IC
\nNext term:
\nI+1 = J
\nHere, In IC, C is in second place. In next term, C comes to first place.
\n\u21d2 CJ<\/p>\n
\nJ+1 = K
\nIn CJ, C is in first place, then in next term, C comes to second place.
\n\u21d2 KC<\/p>\n
\nT+1 = U \u2192 LU
\nReversing LU \u2192 UL
\nNext term:
\nU+1 = V
\nL+1 = M \u2192 VM
\nReversing VM \u2192 MV
\nNext term:
\nM+1 = N
\nV+1 = W \u2192 NW
\nReversing NW \u2192 WN
\nSimilarly, Missing term in the series will be
\nW+1 = X
\nN+1 = O \u2192 XO
\nReversing XO \u2192 OX.<\/p>\n
\nA+1 = B \u2192 DB
\nReversing DB \u2192 BD
\nNext term:
\nB+1 = C
\nD+1 = E \u2192 CE
\nReversing CE \u2192 EC
\nNext term:
\nE+1 = F
\nC+1 = D \u2192 FD
\nReversing FD \u2192 DF
\nNext term:
\nD+1 = E
\nF+1 = G \u2192 EG
\nReversing EG \u2192 GE<\/p>\n
\nT+1 = U \u2192 MU
\nReversing MU \u2192 UM
\nNext term:
\nU+1 = V
\nM+1 = N \u2192 VN
\nReversing VN \u2192 NV
\nNext term:
\nN+1 = O
\nV+1 = W \u2192 OW
\nReversing OW \u2192 WO
\nThen, Next term in the series will be
\nW+1 = X
\nO+1 = P \u2192 XP
\nReversing XP \u2192 PX<\/p>\n
\nP+2 = R \u2192 OR
\nNext term:
\nO+2 = Q
\nR+3 = U \u2192 QU
\nNext term:
\nQ+3 = T
\nU+4 = Y \u2192 TY
\nSimilarly, Next term in the series will be
\nT+4 = X
\nY+5 = D \u2192 XD<\/p>\n
\nB+1 = C \u2192 MC
\nNext term:
\nM+2 = O
\nC+2 = E \u2192 OE
\nNext term:
\nO+3 = R
\nE+3 = H \u2192 RH
\nSimilarly, Next term will be
\nR+4 = V
\nH+4 = L \u2192 VL<\/p>\n
\nA+1 = B \u2192 TB
\nNext term:
\nT+2 = V
\nB+2 = D \u2192 VD
\nNext term:
\nV+3 = Y
\nD+3 = G \u2192 YG
\nSimilarly, Missing term in the series will be
\nY+4 = C
\nG+4 = K \u2192 CK<\/p>\n
\nP-1 = O \u2192 LO
\nNext term:
\nL+1 = M
\nO-1 = N \u2192 MN
\nSimilarly, Missing term in the series will be
\nN+1 = O
\nM-1 = L \u2192 OL<\/p>\n
\nB+2 = D \u2192 OD
\nNext term:
\nO+2 = Q
\nD+2 = F \u2192 QF
\nSimilarly, Missing term in the series will be
\nS+2 = U
\nH+2 = J \u2192 UJ<\/p>\n