Download Top-20 IBPS RRB PO Ratio and Proportion Questions PDF. Ratio and Proportion questions based on asked questions in previous year exam papers very important for the IBPS RRB PO (Officer Scale-I, II & III) exam.<\/p>\n
Download Ratio And Proportion Qestions For IBPS RRB PO<\/a><\/p>\n 35 IBPS RRB PO Mocks @ Rs. 149. Enroll Now<\/a><\/p>\n 70 IBPS RRB (PO + Clerk) Mocks @ Rs. 199<\/a><\/p>\n Take a free mock test for IBPS RRB PO<\/a><\/p>\n Download IBPS RRB PO Previous Papers PDF<\/a><\/p>\n Question 1:\u00a0<\/b>A solution contains 3 liquids A,B and C.The ratio of volumes of B and C is 7:2.It contains 15 litres of A.If 5 litres of B and 4 litres of C is replaced by equal volumes of A then the ratio of volumes of A and B becomes 4:5. What is the total volume of the solution?<\/p>\n a)\u00a060 litres<\/p>\n b)\u00a050 litres<\/p>\n c)\u00a045 litres<\/p>\n d)\u00a030 litres<\/p>\n e)\u00a070 litres<\/p>\n Question 2:\u00a0<\/b>How many kilograms of white rice costing Rs 30 per kg should be mixed with 42 kgs plain rice costing Rs 20 per kg so that he gets 50% profit on selling it at Rs 34.50 per kilogram ?<\/p>\n a)\u00a012 kgs<\/p>\n b)\u00a015 kgs<\/p>\n c)\u00a018 kgs<\/p>\n d)\u00a021 kgs<\/p>\n e)\u00a024 kgs<\/p>\n Question 3:\u00a0<\/b>If \u2018x\u2019 litres of pure milk is added to a solution of 40 litres containing milk to water in the ratio of 3:5 to make the ratio 1:1 then what will be the ratio of water to milk if \u20192x\u2019 of water is added to the final solution formed ?<\/p>\n a)\u00a012:7<\/p>\n b)\u00a09:4<\/p>\n c)\u00a07:4<\/p>\n d)\u00a04:7<\/p>\n e)\u00a04:9<\/p>\n Question 4:\u00a0<\/b>A 55 litre solution contains water and milk in the ratio of 3:8 and \u2018x\u2019 litres of either milk or water is added to the solution so that the ratio of water to milk becomes 3:2 and if \u2018x\u2019 litres of same type is added to the solution then what is the ratio of water to milk in the resulting ratio ?<\/p>\n a)\u00a04:3<\/p>\n b)\u00a08:19<\/p>\n c)\u00a08:21<\/p>\n d)\u00a021:8<\/p>\n e)\u00a019:8<\/p>\n Question 5:\u00a0<\/b>Ram purchased three variety of barley at Rs. 100 per kg, Rs. 140 per kg and Rs. 180 per kg respectively. In what ratio he should mix these three varieties in that order so that the average cost of the mixture is Rs. 150 per kg?<\/p>\n a)\u00a02 : 4 : 7<\/p>\n b)\u00a01 : 5 : 10<\/p>\n c)\u00a01 : 2 : 3<\/p>\n d)\u00a02 : 5 : 5<\/p>\n e)\u00a0None of the above<\/p>\n Question 6:\u00a0<\/b>Ram mixes acid and water in 3:5 to get solution X whereas he mixes water and acid in 2:3 to get solution Y. In what ratio he should mix solution X and Y to make another solution which contains 50% acid?<\/p>\n a)\u00a03 : 5<\/p>\n b)\u00a04 : 5<\/p>\n c)\u00a05 : 4<\/p>\n d)\u00a05 : 3<\/p>\n e)\u00a01 : 1<\/p>\n Free Mock Test for IBPS RRB PO<\/a><\/p>\n IBPS RRB Clerk Previous Papers<\/a><\/p>\n Question 7:\u00a0<\/b>Jar A contains 70% milk and the rest is water whereas Jar B contains 60% water and the rest is milk. How many liters of solution A should be mixed with 100 liters of solution B to make 50% water-milk solution?<\/p>\n a)\u00a020<\/p>\n b)\u00a0100<\/p>\n c)\u00a080<\/p>\n d)\u00a040<\/p>\n e)\u00a050<\/p>\n Question 8:\u00a0<\/b>A milkman mixed water in the pure milk in the ratio of 2 : 3. If water is available at one-sixth of the price of pure milk then find out the profit percentage made by the milkman when he sold the entire mixture at the cost price of pure milk?<\/p>\n a)\u00a025 percent<\/p>\n b)\u00a033.33 percent<\/p>\n c)\u00a050 percent<\/p>\n d)\u00a040 percent<\/p>\n e)\u00a066.66 percent<\/p>\n Question 9:\u00a0<\/b>Two varieties of rice cost Rs. 40 and Rs. 60 per kg. Another two varieties Haffa and Jaffa are created by mixing the first two varieties in 2:3 and 3:1 ratio. Find out the difference between the cost price of Haffa and Jaffa?<\/p>\n a)\u00a0Rs. 5 per kg<\/p>\n b)\u00a0Rs. 4 per kg<\/p>\n c)\u00a0Rs. 6 per kg<\/p>\n d)\u00a0Rs. 7 per kg<\/p>\n e)\u00a0None of the above<\/p>\n Question 10:\u00a0<\/b>A solution containing alcohol and water in the ratio 7 : 2 is mixed with twice the amount of another solution containing alcohol and water in the ratio 5 : 1. What is the percentage of alcohol in the final mixture?<\/p>\n a)\u00a078.91%<\/p>\n b)\u00a090%<\/p>\n c)\u00a075.12%<\/p>\n d)\u00a079.38%<\/p>\n e)\u00a081.48%<\/p>\n Question 11:\u00a0<\/b>Two varieties of rice A and B are mixed in the ratio 4 : 5 to form a mixture X and in the ratio 3 : 4 to form another mixture Y. When X and Y are mixed in equal quantities, a new mixture Z is formed. When 3 kg of rice A is mixed in Z, the ratio of both the varieties of rice in Z becomes equal. What was the quantity of X and Y mixed to form Z?<\/p>\n a)\u00a011.8125 kg<\/p>\n b)\u00a013.225 kg<\/p>\n c)\u00a018 kg<\/p>\n d)\u00a019.75 kg<\/p>\n e)\u00a010.1125 kg<\/p>\n Question 12:\u00a0<\/b>A solution containing milk and water in the ratio 3 : 1 is mixed with twice the amount of another solution containing milk and water in the ratio 2 : 1. What is the percentage of milk in the final mixture?<\/p>\n a)\u00a077.11%<\/p>\n b)\u00a069.44%<\/p>\n c)\u00a057.2%<\/p>\n d)\u00a056%<\/p>\n e)\u00a060.36%<\/p>\n Question 13:\u00a0<\/b>A solution containing milk and water in the ratio 5 : 1 is mixed with 20 litres of milk. After removing 10.7 litres of the new mixture, the ratio of water and milk in the remaining mixture is found to be 3 : 25. What was the initial quantity of mixture?<\/p>\n a)\u00a023.4 litres<\/p>\n b)\u00a036 litres<\/p>\n c)\u00a030.6 litres<\/p>\n d)\u00a024 litres<\/p>\n e)\u00a021.6 litres<\/p>\n Question 14:\u00a0<\/b>A milkman has some quantity of milk with him. He sells 20% of the milk and replaces it water. He realized that the mixture is too dilute and hence, he adds 20L of pure milk to the mixture. He then again sells 40% of the mixture and replaces it water. He adds 48L of pure milk to the mixture. If he now has 300L of pure milk with him then what is the quantity of the milk with which he started?<\/p>\n a)\u00a0520L<\/p>\n b)\u00a0550L<\/p>\n c)\u00a0500L<\/p>\n d)\u00a0480L<\/p>\n e)\u00a0450L<\/p>\n Question 15:\u00a0<\/b>The cost of two different varieties of rice A and B Rs. 40\/kg and Rs. 60\/kg respectively. If A and B are mixed together in the ratio of 5 : 7 what will be the total cost of the mixture?<\/p>\n a)\u00a0Rs. $\\frac{155}{3}$\/kg<\/p>\n b)\u00a0Rs. 50\/kg<\/p>\n c)\u00a0Rs. 80\/kg<\/p>\n d)\u00a0Rs. 53\/kg<\/p>\n e)\u00a0Cannot be determined<\/p>\n Quantitative Aptitude formulas PDF<\/a><\/p>\n 520 Banking Mocks – Just Rs. 499<\/a><\/p>\n Question 16:\u00a0<\/b>The cost of three different varieties of milk A, B, and C is Rs. 20\/litre, Rs. 25\/litre and Rs. 30\/litre respectively. If A, B and C are mixed together in the ratio of 2 : 1 : 3, what will be the total cost of the mixture?<\/p>\n a)\u00a0Rs. $\\frac{155}{6}$\/litre<\/p>\n b)\u00a0Rs. 25\/litre<\/p>\n c)\u00a0Rs. $\\frac{155}{12}$\/litre<\/p>\n d)\u00a0Rs. 29\/litre<\/p>\n e)\u00a0Cannot be determined<\/p>\n Question 17:\u00a0<\/b>The cost of three different varieties of rice A, B, and C is Rs. 20\/kg, Rs. 25\/kg and Rs. 30\/kg respectively. If A, B and C are mixed together in the ratio of 2 : 1 : 2, what will be the cost of the mixture per kg?<\/p>\n a)\u00a0Rs. 75<\/p>\n b)\u00a0Rs. 25<\/p>\n c)\u00a0Rs. 30<\/p>\n d)\u00a0Rs. 125<\/p>\n e)\u00a0Rs. 100<\/p>\n Question 18:\u00a0<\/b>A mixture contains water and milk in the ratio of 3 : 5. If 4 litres of water and 5 litres of milk are added to the mixture, the ratio of water and milk becomes 2 : 3. What is the quantity of water in the final mixture?<\/p>\n a)\u00a011 litres<\/p>\n b)\u00a012 litres<\/p>\n c)\u00a08 litres<\/p>\n d)\u00a010 litres<\/p>\n e)\u00a09 litres<\/p>\n Question 19:\u00a0<\/b>A mixture contains water and alcohol in the ratio of 5 : 2. If 5 litres of water and 4 litres of alcohol are added to the mixture, the ratio of water and alcohol becomes 2 : 1. What is the quantity of alcohol in the final mixture?<\/p>\n a)\u00a010 litres<\/p>\n b)\u00a07 litres<\/p>\n c)\u00a08 litres<\/p>\n d)\u00a012 litres<\/p>\n e)\u00a0Cannot be determined<\/p>\n Question 20:\u00a0<\/b>A mixture A contains milk and water in the ratio of 7 : 2. Another mixture B contains milk and water in the ratio of 2 : 1. If A and B are mixed in the ratio of 1 : 3, what is the ratio of milk and water in the final mixture?<\/p>\n a)\u00a012 : 7<\/p>\n b)\u00a023 : 17<\/p>\n c)\u00a025 : 11<\/p>\n d)\u00a029 : 11<\/p>\n e)\u00a013 : 5<\/p>\n 18000 Free Solved Questions – Banking Study Material<\/a><\/p>\n 35 IBPS RRB PO Mocks @ Rs. 149. Enroll Now<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the initial volumes be A,B and C 2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Given profit percent=50 3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n In the given solution quantity of milk=(3\/8)*40 =15 litres 4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Since the ratio in the resulting mixture in case 1 has water in greater quantity the solution that is added should definitely be water and so 5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let us check the options. 6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let \u2018a\u2019 and \u2018b\u2019 be the quantity of solution X and Y mixed by Ram. It is given that the solution contains 50% acid hence, $\\Rightarrow$ $\\dfrac{15a+24b}{40(a+b)} = \\dfrac{1}{2}$<\/p>\n $\\Rightarrow$ $30a+48b = 40a+40b$<\/p>\n $\\Rightarrow$ $\\dfrac{a}{b} = \\dfrac{4}{5}$<\/p>\n Hence, option B is the correct answer.<\/p>\n 7)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let \u2018X\u2019 liters of solution A is mixed with 100 liters of solution B. 8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let \u2018$\\text{P}$\u2019 be the cost price of pure milk per liter. Therefore, cost price of water = $\\dfrac{\\text{P}}{6}$. 9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Cost price of Haffa per kg = $\\frac{2*40+3*60}{2+3}$ = Rs. 52 per kg.<\/p>\n Cost price of Jaffa per kg = $\\frac{3*40+1*60}{3+1}$ = Rs. 45 per kg.<\/p>\n Hence, the difference between the cost price of Haffa and Jaffa = 52 – 45 = Rs. 7 per kg. 10)\u00a0Answer\u00a0(E)<\/strong><\/p>\n Let 9 litres of the first solution be mixed with 18 litres of the second solution. 11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let there be 4k kg of rice A and 5k kg of rice B in mixture X and 12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let 12 litres of the first solution be mixed with 24 litres of the second solution. 13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let the milk and water in the original mixture be 5$k$ and $k$. 14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Let the quantity of milk with the milkman be xL. He sells 20% of it and thus he is left with 0.8x. 15)\u00a0Answer\u00a0(E)<\/strong><\/p>\n As the total quantity of the mixture is not known, we cannot calculate the total cost of the mixture. 16)\u00a0Answer\u00a0(E)<\/strong><\/p>\n As the total quantity of the mixture is not known, we cannot calculate the total cost of the mixture. 17)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Let 2 kg of A, 1 kg of B and 2 kg of C are mixed together. 18)\u00a0Answer\u00a0(D)<\/strong><\/p>\n Let the quantity of water and milk be $3x$ and $5x$ 19)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the quantity of water and alcohol be $5x$ and $2x$ 20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n As A and B are mixed in the ratio of 1 : 3, let us assume that 9 litres of A and 27 litres of B are mixed.
\nA=15 litres
\nB=7x and C=2x
\nA=15+5+4=24 litres
\nB=7x-5
\nC=2x-4
\nGiven 24\/(7x-5)=4:5
\n120=28x-20
\n28x=1440
\nx=5 litres
\nB=7(5)-5=30 litres
\nC=2(5)-4=6 litres
\nTotal volume=24+30+6=60 litres<\/p>\n
\nSelling price=34.50
\nSP=1.5 *CP
\n34.50=1.5*CP
\nCP=34.5\/1.5
\nCP=Rs 23
\nlet the ratio of number of kg\u2019s of white rice to plain rice be x
\nBy applying the rule of allegations we have
\nx=(23-20)\/(30-23)
\nx=3:7
\nSo 42 kgs of plain rice is added and let \u2018y\u2019 kgs of white rice be added
\nTherefore 3\/7 =y\/42
\ny=3*6
\ny=18 kgs<\/p>\n
\nQuantity of water=(5\/8)*40=25 litres
\nGiven x litres of milk is added and so
\n(15+x)\/(25) =1\/1
\n15+x=25
\nx=10 litres
\nNow 2x=20 litres of water is added to the final solution
\ni.e water =25 +20
\n=45 litres
\nMilk=15+10=25 litres
\nratio=45:20
\n=9:4<\/p>\n
\nGiven solution has (3\/11)*55=15 litres of water
\n(8\/11)*55=40 litres of milk
\n\u2018X\u2019 litres of water is added to it
\nTherefore (15+x)\/(40)=3:2
\n30+2x=120
\n2x=90
\nx=45 litres
\nAnd then again 45 litres of water is added to the solution and so total water in the solution =60+45=105 litres
\nmilk=40 litres
\nRatio of water to milk=105:40
\n=21:8<\/p>\n
\nOption (A): Average cost price of the mixture = $\\dfrac{200+560+1260}{2+4+7}$ = Rs. 155.38
\nOption (B): Average cost price of the mixture = $\\dfrac{100+700+1800}{1+5+10}$ = Rs. 162.50
\nOption (C): Average cost price of the mixture = $\\dfrac{100+280+540}{1+2+3}$ = Rs. 153.33
\nOption (D): Average cost price of the mixture = $\\dfrac{200+700+900}{2+5+5}$ = Rs. 150
\nTherefore, option D is the correct answer.<\/p>\n
\n$\\Rightarrow$ $\\dfrac{\\dfrac{3a}{8}+\\dfrac{3b}{5}}{a+b} = \\dfrac{50}{100}$<\/p>\n
\nConcentration of milk in solution B = 100 – 60 = 40%.
\nThe resultant solution is a 50% water-milk solution.
\nHence,
\n$\\dfrac{0.70*X + 0.40*100}{X+100} = \\dfrac{50}{100}$
\n$70*X + 4000 = 50*X + 5000$
\n$20X= 1000$
\n$X= 50$liters.
\nHence, option E is the correct answer.<\/p>\n
\nLet us assume that milkman mixed $\\text{2L}$ and $\\text{3L}$ volume of water and pure milk.
\nHence, total cost incurred by the milkman = $2\\text{L}*\\dfrac{\\text{P}}{6} + 3\\text{L*P}$ = $\\dfrac{10\\text{LP}}{3}$
\nProfit made by the milkman in the transaction = $5\\text{L*P} – \\dfrac{10\\text{LP}}{3}$ = $\\dfrac{5\\text{LP}}{3}$
\nTherefore, the profit percentage made by the milkman = $\\dfrac{\\dfrac{5\\text{LP}}{3}}{\\dfrac{10\\text{LP}}{3}}\\times 100$ = 50 percent.
\nTherefore, option C is the correct answer.<\/p>\n
\nTherefore, option D is the correct answer.<\/p>\n
\nTherefore, total volume of the solution = (9 + 18) litres = 27 litres
\nQuantity of alcohol in the first solution = $\\frac{7}{9} * 9$ litres = 7 litres
\nQuantity of alcohol in the second solution = $\\frac{5}{6} * 18$ litres = 15 litres
\nTotal quantity of alcohol = (7 + 15) litres = 22 litres
\n% of milk = $\\frac{22}{27} * 100$% = 81.48%
\nHence, option E is the correct answer.<\/p>\n
\nlet there be 3m kg of rice A and 4m kg of rice B in mixture Y
\nTotal quantity of X = (4k + 5k)\u00a0kg = 9k\u00a0kg
\nTotal quantity of Y = (3m + 4m)\u00a0kg = 7m\u00a0kg
\nWhen X and Y are mixed in equal quantities to form Z,
\nQuantity of rice A in Z = (4k + 3m)\u00a0kg
\nQuantity of rice B in Z = (5k + 4m) kg
\nIt is given that, 4k + 3m + 3 = 5k + 4m
\nor, k + m = 3……………(i)
\nAlso, Quantity of X = Quantity of Y
\n=> 9k = 7m…………….(ii)
\nOn solving (i) and (ii), we get
\nk = $\\dfrac{21}{16}$ and m = $\\dfrac{27}{16}$
\nQuantity of X and Y mixed = 9k or 7m = 11.8125 kg
\nHence, option A is the correct answer.<\/p>\n
\nTherefore, total volume of the solution = (12 + 24) litres = 36 litres
\nQuantity of milk in the first solution = $\\frac{3}{4} * 12$ litres = 9 litres
\nQuantity of milk in the second solution = $\\frac{2}{3} * 24$ litres = 16 litres
\nTotal quantity of milk = (9 + 16) litres = 25 litres
\n% of milk = $\\frac{25}{36} * 100$% = 69.44%<\/p>\n
\nAfter adding 20 litres of milk, the ratio of milk and water changed to 25 : 3
\n(Removing 10.7 litres of the mixture is irrelevant as it will not change the ratio of milk and water in the mixture)
\nSo, $\\frac{5k + 20}{k} = \\frac{25}{3}$
\nOn solving, we get $k$ = 6
\nTotal volume of the initial mixture = $5k + k$ = 36 litres
\nHence, option B is the correct answer.<\/p>\n
\nHe adds 20L of pure milk and thus. he now has 0.8x+20 L of milk with him.
\nOut of this he sells 40% of the milk.
\nHe is now left with (0.8x+20)*0.6 = 0.48x+12 L of milk.
\nHe adds 48L of pure milk and he now has 0.48x+12+48 = 0.48x+60 L of milk.
\nGiven, 0.48x+60 = 300
\nThus, x = 240\/0.48 = 500L
\nHence, option C is the correct answer.<\/p>\n
\nHence, option E is the correct answer.<\/p>\n
\nHence, option E is the correct answer.<\/p>\n
\nTotal rice = (2 + 1 + 2) kg = 5 kg
\nCost of A in the mixture = Rs. (2 * 20) = Rs. 40
\nCost of B in the mixture = Rs. (1 * 25) = Rs. 25
\nCost of C in the mixture = Rs. (2 * 30) = Rs. 60
\nTotal cost of the mixture = Rs. (40 + 25 + 60) = Rs. 125
\nCost per kg = Rs. $\\frac{125}{5}$ = Rs. 25
\nHence, option B is the correct answer.<\/p>\n
\nIt is given that, $\\frac{3x + 4}{5x + 5} = \\frac{2}{3}$
\nOn solving, we get $x$ = 2
\nTherefore, the quantity of water in the final mixture = (3 * 2 + 4) litres = 10 litres.
\nHence, option D is the correct answer.<\/p>\n
\nIt is given that, $\\frac{5x + 5}{2x + 4} = \\frac{2}{1}$
\nOn solving, we get $x$ = 3
\nTherefore, the quantity of alcohol in the final mixture = (3 * 2 + 4) litres = 10 litres.
\nHence, option A is the correct answer.<\/p>\n
\nIn 9 litres of A, milk is 7 litres, and water is 2 litres.
\nIn 27 litres of B, milk is 18 litres, and water is 9 litres.
\nWhen A and B are mixed, quantity of milk = (7 + 18) litres = 25 litres
\nWhen A and B are mixed, quantity of water = (2 + 9) litres = 11 litres
\nRequired ratio is 25 : 11
\nHence, option C is the correct answer.<\/p>\n